open a secondary window from button , from two .ui files - python

I created two .ui files with Qtdesigner: the first "interface.ui" which is the main interface and the second "param.ui" a secondary window. I'm trying to boot directly from file.ui without converting the file to python format..
I'm starting the program from main.py and the problem starts when I try to open "param.ui" with a button (called "puls") present in "interface.ui".
The secondary window is not going to open after pressing "puls". I can not understand where is the problem ... If someone wants to help me I thank him in advance.
from PyQt5 import QtWidgets, uic
class ParamWindow(QtWidgets.QWidget):
def __init__(self):
super().__init__()
uic.loadUi("param.ui", self)
print("ParamWindow init")
class MainWindow(QtWidgets.QMainWindow):
def __init__(self):
super().__init__()
uic.loadUi("interface.ui", self)
self.puls = self.findChild(QtWidgets.QPushButton, "puls")
self.puls.clicked.connect(self.openParamWindow)
print("MainWindow init")
def openParamWindow(self):
paramWindow = ParamWindow()
paramWindow.show()
app = QtWidgets.QApplication([])
window = MainWindow()
window.show()
app.exec_()

Related

PyQt5 Getting second screen functions to work

how are you doing?
I have been coding for a couple months. I started with Python, now I am trying to learn PyQt5.
I have created two windows using the Designer Tool. I created a subclass for each specific page, so that it wont mess up my software once i make changes in the Designer.
I managed to make my second window open from the first window. It works well. However, nothing works in window 2 when its opened by window 1. However, when i run window 2 by itself, it does not work.
I am sure it is a inheritance problem that I am messing up. It seems my sofware is inheriting the window 2 layout but not its functions.
I have attached the code. Is it possible for someone to help me out? If possible, i would like a brief explanation on how to fix it too. I want to learn so I can teach others as well.
This is my main window:
from nonregusrscreen1 import NonReg
from Main import Ui_MainWindow # needs to import from the main file
from PyQt5 import QtCore, QtGui, QtWidgets #importing PyQt functionality
class mainWin(QtWidgets.QMainWindow, Ui_MainWindow): #mainWin is new subclass. QtWidgets.Whatever the window was / you need to get inheritance from Ui_MainWindow, otherwise you wil lahve to use self.ui.pushbutton....
def __init__(self, *args, **kwargs): #passing arguments from whatever was called
super().__init__(*args, **kwargs)
self.ui = Ui_MainWindow()
self.setupUi(self)
self.pushButton_2.clicked.connect(self.openwindow) # you have to include UI, otherwise it will not work.
def openwindow(self):
self.window = QtWidgets.QDialog()
self.ui = NonReg()
self.ui.setupUi(self.window)
self.window.show()
if __name__ == '__main__':
app = QtWidgets.QApplication([])
w = mainWin()
w.show()
app.exec_()
This is my second window, here you can see the pushbutton_2 function that only works when the file is opened by itself (not opened using the first window)
from nonregusrscreen import Ui_NonRegUserScreen
from PyQt5 import QtCore, QtGui, QtWidgets
class NonReg(QtWidgets.QDialog, Ui_NonRegUserScreen):
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
self.ui = Ui_NonRegUserScreen
self.setupUi(self)
self.pushButton_2.clicked.connect(self.closewindow)
def closewindow(self):
self.window = exit()
if __name__ == '__main__':
app = QtWidgets.QApplication([])
w = NonReg()
w.show()
app.exec_()
Thank you, i truly appreciate your help.

In python, how do I open a new window by clicking a button in a main window using .py files created from .ui files made in QtDesigner?

I have two .py files created from .ui files made in QtDesigner. One is a main window for the program, and the other is a widget that allows users to input information and I'm calling it the "evaluation" widget.
I have a button in the main window called "btn_StartNew", which is meant to open the widget window to allow the user to start a new evaluation. I'm having troubles with opening the main window, and adding the function to the "btn_StartNew" button that opens the "evaluation" widget.
The code I have right now opens both the main window and the evaluation widget in the same window when I run the code:
import sys
from PyQt4 import QtCore, QtGui
from wid_Main import Ui_wid_Main
from wid_Eval_v2 import Ui_wid_Eval
class Win_Eval(QtGui.QWidget):
def __init__(self, parent=None):
super(Win_Eval, self).__init__(parent)
self.ui=Ui_wid_Eval()
self.ui.setupUi(self)
class Win_Main(QtGui.QMainWindow):
def __init__(self, parent=None):
super(Win_Main, self).__init__(parent)
self.ui=Ui_wid_Main()
self.ui.setupUi(self)
#RUN "start new eval" button
self.ui.btn_StartNew.clicked.connect(self.btn_StartNew_click)
self.dialog = Win_Eval(self)
def btn_StartNew_click(self):
self.dialog.show()
def main():
app = QtGui.QApplication(sys.argv)
main = Win_Main()
main.show()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
Where wid_Main and Ui_wid_Main are the main window file and the main window class, respectively. And wid_Eval_v2 and Ui_wid_Eval are the evaluation widget file and class, respectively.
Any help would be much appreciated!
You must change:
self.dialog = Win_Eval(self)
to
self.dialog = Win_Eval()

show Qwidget window without MainWindow

I am having problems showing a QWidget window for the user to input some data.
My script has not GUI, but I just want to show this small QWidget window.
I created the window with QtDesigner, and now I am trying to show the QWidget window like this:
from PyQt4 import QtGui
from input_data_window import Ui_Form
class childInputData(QtGui.QWidget ):
def __init__(self, parent=None):
super(childInputData, self).__init__()
self.ui = Ui_Form()
self.ui.setupUi(self)
self.setFocus(True)
self.show()
And then, from my main class, I am doing like that:
class myMainClass():
childWindow = childInputData()
That gave me the error:
QWidget: Must construct a QApplication before a QPaintDevice
So now I am doing, from my main class:
class myMainClass():
app = QtGui.QApplication(sys.argv)
childWindow = childInputData()
Now there is no error, but the window is showed twice and the script does not wait until the data is entered, it just shows the window and continues without waiting.
What is wrong here?
It's perfectly normal that the window is shown and the script goes on: you never told the script to wait for the user to answer. You just told it to show a window.
What you would like is the script to stop until the user is done and the window is closed.
Here's one way to do it:
from PyQt4 import QtGui,QtCore
import sys
class childInputData(QtGui.QWidget):
def __init__(self, parent=None):
super(childInputData, self).__init__()
self.show()
class mainClass():
def __init__(self):
app=QtGui.QApplication(sys.argv)
win=childInputData()
print("this will print even if the window is not closed")
app.exec_()
print("this will be print after the window is closed")
if __name__ == "__main__":
m=mainClass()
The exec() method "Enters the main event loop and waits until exit() is called" (doc):
the script will be blocked on the line app.exec_() until the window is closed.
NB: using sys.exit(app.exec_()) would cause the script to end when the window is closed.
An other way is to use QDialog instead of QWidget. You then replace self.show() by self.exec(), which will block the script
From the doc:
int QDialog::exec()
Shows the dialog as a modal dialog, blocking until the user closes it
Finally, this answer of a related question advocates not to use exec, but to set the window modality with win.setWindowModality(QtCore.Qt.ApplicationModal). However this doesn't work here: it blocks inputs in other windows, but do not block the script.
you dont need the myMainClass...do something like this:
import sys
from PyQt4 import QtGui
from input_data_window import Ui_Form
class childInputData(QtGui.QWidget):
def __init__(self, parent=None):
super(childInputData, self).__init__(parent)
self.ui = Ui_Form()
self.ui.setupUi(self)
self.setFocus(True)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
win = childInputData()
win.show()
sys.exit(app.exec_())

How does one make a button in the main window open a different window?

I am very new to this and have used the Qt Designer to make a very simple main window ui. The first functionality I want in my project is for a button to open a different window when clicked.
So basically I have the file autoGenUI.py that is generated using pyside-uic which includes
from PySide import QtCore, QtGui
class AutoGeneratedUI(object):
def setupUi(self, MainWindow):
#Auto generated code
def retranslateUi(self, MainWindow):
#Auto generated code
This all works fine of course because the Qt designer made it. I then have my own .py file that is basically my application stuff.
It looks like this:
import sys
from PySide.QtCore import *
from PySide.QtGui import *
from autoGenUI import *
class MyMainWindow(QtGui.QMainWindow):
def __init__(self, parent=None):
super(MyMainWindow, self).__init__(parent)
self.ui = AutoGeneratedUI()
self.ui.setupUi(self)
if __name__ == "__main__":
app = QApplication(sys.argv)
myMainWindow = MyMainWindow()
myMainWindow.show()
sys.exit(app.exec_())
My button is called self.pushButton in the auto generated python UI. I would like to design another window and then call that window but for now anything will do. I just don't know where to put the code to make my button do something.
I tried to follow the docs but couldn't get anything to work.
Any help is greatly appreciated.
Thanks
You need to connect the clicked signal of pushButton to a method such as on_button_clicked():
def __init__(self, parent=None):
super(MyMainWindow, self).__init__(parent)
self.ui = AutoGeneratedUI()
self.ui.setupUi(self)
# connect the clicked signal to on_button_clicked() method
self.pushButton.clicked.connect(self.on_button_clicked)
def on_button_clicked(self):
print "button clicked"
# here is the code to open a new window

PyQt5: How to open a new window and close the current window?

I would like to ask, as I write in the title, how to open a new window and close (completely) the current window?
There are two .py files. They are independent from each other, that means, each of them can be run on its own.
In MyApp.py there is a button. If the button is clicked, I want to close the current window/file and open the new window/file.
In my code below I can open the new window/file, but the old window is not closed. And if I close the second window, the old window will be closed as well. I have tried some methods with my knowledge/search, but none of them worked fine.
Here is the code for MyApp.py
import sys
from PyQt5.QtWidgets import *
from PyQt5.QtGui import *
from PyQt5.QtCore import *
import NewApp
# NewApp.py in the same folder
# in NewApp.py there is a class NewApp
qtCreatorFile_MyApp = "F:\\MyApp.ui"
class MyApp(QWidget):
def __init__(self):
super(MyApp, self).__init__()
uic.loadUi(qtCreatorFile_MyApp, self)
self.show()
self.btn_inMyApp.clicked.connect(self.closeMyApp_OpenNewApp)
def closeMyApp_OpenNewApp(self):
self.Open = NewApp.NewApp()
self.Open.show()
# My Problem: How to close the MyApp completely and open NewApp?
if __name__ == "__main__":
app = QtWidgets.QApplication(sys.argv)
window = MyApp()
sys.exit(app.exec_())
NewApp.py has similar code structure. For the purpose of integrity of this quesiton, I paste the code as follows.
qtCreatorFile_NewApp = "F:\\NewApp.ui"
class NewApp(QWidget):
def __init__(self):
super(NewApp, self).__init__()
uic.loadUi(qtCreatorFile_NewApp, self)
self.show()
if __name__ == "__main__":
app = QtWidgets.QApplication(sys.argv)
window = NewApp()
sys.exit(app.exec_())
Thank you for the help!

Categories