python variable is none , whats the problem in this code [closed] - python

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Closed 27 days ago.
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this code is running fine on my device but its given error in my clients's device
i Am a beginner
for i in hashes:
wai = 1
while wai==1:
hsh=unhasherfull(i)
#print(hsh)
unhashedhashes=hashdec(hsh,proxym=None)
if unhashedhashes == "wait":
time.sleep(11)
continue
elif unhashedhashes == None:
continue
#print(unhashedhashes)
if unhashedhashes != None or unhashedhashes != "wait" or unhashedhashes != "Captcha Check" or unhashedhashes != " " or unhashedhashes != "":
wai=0
break
print("--------------------")
with open("results1.txt","a") as f:
f.write(f"{unhashedhashes}\n")
ERROR :
--------------------
Traceback (most recent call last):
File "c:\Users\Roberto\Downloads\final hashesh.com hash decryptor with capsolve (1)\final hashesh.com hash decryptor with capsolve\mainvari.py", line 193, in <module>
f.write(unhashedhashes+"\n")
i tried everything from chagning python version and changing little bit of code
i expected to run it like it runs on my pc

Related

How to fix the len() command returning TypeError? [closed]

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Closed 4 years ago.
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I am trying to work out the length of a string in python however I can't seem to get a correct response. If someone could tell me what I am doing wrong, I would be very grateful.
Code:
name = input("Type a string!")
name = name.upper
lenname = len(name)
if lenname == 3:
print("Success")
else:
print("Fail")
I expect the output to be Success when I enter abc however I receive:
TypeError Traceback (most recent
call last)
<ipython-input-20-1de45569cf05> in <module>
1 name = input("Type a string!")
2 name = name.upper
----> 3 lenname = len(name)
4 if lenname == 3:
5 print("Sucess")
TypeError: object of type 'builtin_function_or_method' has no len()
You're trying to access upper like it's a field, not a method. On the line above where you use len, do name = name.upper().

Program is not running in python [closed]

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Closed 6 years ago.
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My else and else if statements are not working. Every time it is showing incorrect syntax, whether I run it in shell or in file.
>>> num = 6
>>> if num == 4:
print("no is 4")
else:
SyntaxError: invalid syntax
Your indentation is bad :
if num == 4:
print("num is 4")
else:
print("num is not 4")
The following code will print True to the console.
num = 6
if num is 6:
print(True);
else:
print(False);

if/elif/else statement in a while loop with python [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 8 years ago.
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I'm new to python so this may be a beginner question. My 'else' statement in the code below gets a syntax error for a reason beyond my mind. I've looked up the syntax for it multiple times but I cannot find the error. This is my python code:
siteswap = input("Enter the siteswap you want to validate here:")
aantal_digits = len(siteswap)
i = 0
j = 1
while i != aantal_digits:
if (int(siteswap[i])+ (i + 1)) % aantal_digits == (int(siteswap[1:aantal_digits])+ (j + 1)) % aantal_digits:
print("This siteswap is invalid")
break
elif i != aantal_digits:
del (int(siteswap[i])
else:
print ("This siteswap is valid")
break
The else is highlighted and I get a "syntax error".
Your problem is
del (int(siteswap[i])
You are missing a closing parenthesis (but the parenthesis are unnecessary in the first place). Also, del int(siteswap[i]) will not work, because you cannot delete function calls: SyntaxError: can't delete function call
del siteswap[i]
will delete the actual item from your array.

Can't figure out "invalid syntax" message [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 8 years ago.
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I've got this piece of code that is a part of a student database I'm making for class and I really can't determine why I'm getting invalid syntax on a particular line (line 3, userints).
def userints():
choices = int(input("Choose Student ID 1-6:")
userints = int(choices)
print (userints)
if userints == 1:
for line_number, line in enumerate(fileinput.input('init2.txt', inplace=1)):
if line_number == 1:
continue
else:
sys.stdout.write(line)
You forgot about second brace.
You forgot a ) on the previous line. It should be:
choices = int(input("Choose Student ID 1-6:"))

IndentationError in Python [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 7 years ago.
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I am performing one python program and the part of the code is as follows
while 1:
data = conn.recv(BUFFER_SIZE)
if not data: break
print "received data:", data
com = "echo " + data
print com
conn.send(data)
conn.close()
but when i am trying to execute the code i am getting the following error.
File "server.py", line 17
com = "echo " + data
^
IndentationError: unexpected indent
I am not getting whats wrong with the code above.
check that you either consistently have tabs or spaces not a mix of both.

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