File "import.py", line 64, in unzip
File "zipfile.py", line 1647, in extractall
File "zipfile.py", line 1701, in _extract_member
FileNotFoundError: [Errno 2] No such file or directory:
Getting this error for a file while unzipping, The character length for the entire path is 271 characters. Can this be due to long path >? Longpath value is 1 in the registry for Longpathenabled variable.
Related
I'm try to set path for map using this line
world.save('maps_htmls/world_empty.html')
and i got error :-
File "e:\Monty Python Project\ALL TASK\Task\Individual programming project.py", line 35, in <module>
world.save('../maps_htmls/world_empty.html')
File "C:\Users\singh\AppData\Local\Programs\Python\Python310\lib\site-packages\branca\element.py", line 164, in save
fid = open(outfile, 'wb')
FileNotFoundError: [Errno 2] No such file or directory: '../maps_htmls/world_empty.html'
Somebody managed somehow to add a new line character \r\n to the name of a file in a zip, and that makes ZipFile fail when it tries to extract the zip:
2019-07-23 14:05:12,285 - __main__ - ERROR - Error desconocido: [Errno 22] Invalid argument: 'descargados\\03_26298_19\\ANEXO\r\n.pdf'. Saliendo.
Traceback (most recent call last):
File "motor.py", line 51, in main
procesar_descarga(zip_object, ruta_temp, ruta_final)
File "C:\Users\david\pycharmProjects\descargueitor2\volcado.py", line 90, in procesar_descarga
zip_object.extractall(str(ruta_temp))
File "C:\Users\david\Anaconda3\lib\zipfile.py", line 1616, in extractall
self._extract_member(zipinfo, path, pwd)
File "C:\Users\david\Anaconda3\lib\zipfile.py", line 1670, in _extract_member
open(targetpath, "wb") as target:
OSError: [Errno 22] Invalid argument: 'descargados\\03_26298_19\\ANEXO\r\n.pdf'
I tried the same file with several programs:
The built-in compressed files reader in Windows explorer just ignores the file: it is not listed nor extracted.
WinZip lists the file, but throws an error when opening or extracting the file.
7Zip can read and extract the file: it just converts the bad characters to underscores.
Is there any way to deal with this in Python? It looks like files in a zip cannot be renamed using the library.
My two line code for moving a file into the cwd is as follows:
import os, shutil
shutil.move(os.path.abspath('hello_file.txt'),os.getcwd())
I do have the file just one up the cwd but I get this traceback:
Traceback (most recent call last):
File "<ipython-input-333-f012757a9dca>", line 1, in <module>
shutil.move(os.path.abspath('hello_file.txt'),os.getcwd())
File "/Users/deepayanbhadra/anaconda3/lib/python3.6/shutil.py", line 558, in move
copy_function(src, real_dst)
File "/Users/deepayanbhadra/anaconda3/lib/python3.6/shutil.py", line 257, in copy2
copyfile(src, dst, follow_symlinks=follow_symlinks)
File "/Users/deepayanbhadra/anaconda3/lib/python3.6/shutil.py", line 120, in copyfile
with open(src, 'rb') as fsrc:
FileNotFoundError: [Errno 2] No such file or directory: '/Users/deepayanbhadra/Desktop/DIY-Python-Projects/Automating Tasks/hello_file.txt'
The file path you have provided is the current directory. You first have to change to the directory up. One of the ways you can do this is
import os
os.chdir(“..”)
That’s the simplest way but will take you quite a number of lines of code to achieve the same
Traceback (most recent call last):
File "C:/my_python/read1.py", line 3, in <module>
book = open_workbook('Book1.xls',on_demand=True)
File "C:\Python27\lib\site-packages\xlrd\__init__.py", line 449, in open_workbook
ragged_rows=ragged_rows,
File "C:\Python27\lib\site-packages\xlrd\__init__.py", line 941, in biff2_8_load
f = open(filename, open_mode)
IOError: [Errno 2] No such file or directory: 'Book1.xls'
I am getting this error message in python while trying to open an excel sheet.....How can i solve this ?
Either make sure Book1.xls is in "C:\my_python\", which is also where your script is, or use the full path to where Bool1.xls is located. For example:
book = open_workbook('C:\\Users\\Jeeva\\Documents\\Book1.xls',on_demand=True)
I'm attempting to download all the files in an SFTP directory to a local folder using the pysftp library. My code looks like this:
import pysftp
sftp = pysftp.Connection('server', username = 'name', password = 'password')
sftp.get_d('Daily_Reports', '/home/jchrysostom/Documents/SupplyChain/Daily_Reports/')
Daily_Reports is a folder that exists on the SFTP server - I have verified this. I have also verified that /home/jchrysostom/Documents/SupplyChain/Daily_Reports/ exists. I can cd to it in terminal with no problems.
However, when I run this python script, I get the following error: IOError: [Errno 2] File not found.
Any ideas what may be causing this?
UPDATE: A little investigation shows that the files actually have downloaded. In fact, all of them have downloaded just fine. However, I'm unable to run the rest of the script, because it's erroring out for some reason. Is this just a bug in the library?
UPDATE 2 - Full Traceback, as requested:
Traceback (most recent call last):
File "supplychain.py", line 20, in <module>
sftp.get_d('Daily_Reports','/home/jchrysostom/Documents/SupplyChain/Daily_Reports/')
File "/usr/local/lib/python2.7/dist-packages/pysftp.py", line 255, in get_d
preserve_mtime=preserve_mtime)
File "/usr/lib/python2.7/contextlib.py", line 24, in __exit__
self.gen.next()
File "/usr/local/lib/python2.7/dist-packages/pysftp.py", line 497, in cd
self.cwd(original_path)
File "/usr/local/lib/python2.7/dist-packages/pysftp.py", line 510, in chdir
self._sftp.chdir(remotepath)
File "/usr/local/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 580, in chdir
if not stat.S_ISDIR(self.stat(path).st_mode):
File "/usr/local/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 413, in stat
t, msg = self._request(CMD_STAT, path)
File "/usr/local/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 729, in _request
return self._read_response(num)
File "/usr/local/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 776, in _read_response
self._convert_status(msg)
File "/usr/local/lib/python2.7/dist-packages/paramiko/sftp_client.py", line 802, in _convert_status
raise IOError(errno.ENOENT, text)
IOError: [Errno 2] File not found
As best as I can tell, this is a bug in pysftp. The files are being copied successfully, but (at least according to the traceback here) the library is blowing up when it tries to change back to the original remote working directory on the FTP server.
Workaround is to iterate over the files in the directory and get() each individually...
for filename in sftp.listdir('Daily_Reports'):
sftp.get('Daily_Reports/' + filename, localpath = '/home/jchrysostom/Documents/SupplyChain/Daily_Reports/' + filename)