Adding hour to date/time in pandas using conditions - python

I have a dataframe with a Date/Time column
0 2020-01-07 09:00:00
1 2020-01-15 13:00:00
2 2020-01-22 14:00:00
3 2020-01-30 09:00:00
4 2020-02-05 14:00:00
5 2020-02-12 10:00:00
6 2020-05-12 07:00:00
7 2020-05-12 08:00:00
8 2020-05-12 09:00:00
9 2020-05-12 10:00:00
10 2020-05-12 11:00:00
11 2020-05-12 12:00:00
12 2020-05-12 13:00:00
13 2020-05-12 14:00:00
14 2020-05-12 15:00:00
15 2020-05-12 16:00:00
16 2020-07-02 08:00:00
17 2020-07-02 09:00:00
18 2020-07-02 10:00:00
19 2020-07-02 11:00:00
20 2020-07-02 12:00:00
what I am trying to do is to add 2 hours to the time where the date is between 3/14/2020 & 11/07/2020, and add 1 hour to the time everywhere else.
I have been able to add the hour by using the following:
df['Date/Time'] = df['Date/Time'] + pd.DateOffset(hours=1)
however, I can't seem to figure out how to do it via df.loc.
what I have tried:
df.loc[(df['Date/Time'] >= start_date) & (df['Date/Time'] <= end_date), ['Date/Time']] = (['Date/Time'] + pd.DateOffset(hours=1))
I have also tried iterating over the dataframe using For and nested IF statements, but that throws me the following error.
ValueError: The truth value of a DataFrame is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
any help would be appreciated. Thank you

Let's try:
start_time, end_time = '3/14/2020', '11/07/2020'
df['Date/Time'] += np.where(df['Date/Time'].between(start_time, end_time),
pd.Timedelta('2H'),
pd.Timedelta('1H')
)
start_time, end_time = 314, 1107
month_day = df['Date/Time'].dt.month * 100 + df['Date/Time'].dt.day
df['Date/Time'] += np.where(month_day.between(start_time, end_time),
pd.Timedelta('2H'),
pd.Timedelta('1H')
)

Related

Measure different between timestamps using conditions - python

I'm trying to measure the difference between timestamps using certain conditions. Using below, for each unique ID, I'm hoping to subtract the End Time where Item == A and the Start Time where Item == D.
So the timestamps are actually located on separate rows.
At the moment my process is returning an error. I'm also hoping to drop the .shift() for something more robust as each unique ID will have different combinations. For ex, A,B,C,D - A,B,D - A,D etc.
df = pd.DataFrame({'ID': [10,10,10,20,20,30],
'Start Time': ['2019-08-02 09:00:00','2019-08-03 10:50:00','2019-08-05 16:00:00','2019-08-04 08:00:00','2019-08-04 15:30:00','2019-08-06 11:00:00'],
'End Time': ['2019-08-04 15:00:00','2019-08-04 16:00:00','2019-08-05 16:00:00','2019-08-04 14:00:00','2019-08-05 20:30:00','2019-08-07 10:00:00'],
'Item': ['A','B','D','A','D','A'],
})
df['Start Time'] = pd.to_datetime(df['Start Time'])
df['End Time'] = pd.to_datetime(df['End Time'])
df['diff'] = (df.groupby('ID')
.apply(lambda x: x['End Time'].shift(1) - x['Start Time'].shift(1))
.reset_index(drop=True))
Intended Output:
ID Start Time End Time Item diff
0 10 2019-08-02 09:00:00 2019-08-04 15:00:00 A NaT
1 10 2019-08-03 10:50:00 2019-08-04 16:00:00 B NaT
2 10 2019-08-05 16:00:00 2019-08-05 16:00:00 D 1 days 01:00:00
3 20 2019-08-04 08:00:00 2019-08-04 14:00:00 A NaT
4 20 2019-08-04 15:30:00 2019-08-05 20:30:00 D 0 days 01:30:00
5 30 2019-08-06 11:00:00 2019-08-07 10:00:00 A NaT
df2 = df.set_index('ID')
df2.query('Item == "D"')['Start Time']-df2.query('Item == "A"')['End Time']
output:
ID
10 2 days 05:30:00
20 0 days 20:30:00
30 NaT
dtype: timedelta64[ns]
older answer
The issue is your fillna, you can't have strings in a timedelta column:
df['diff'] = (df.groupby('ID')
.apply(lambda x: x['End Time'].shift(1) - x['Start Time'].shift(1))
#.fillna('-') # the issue is here
.reset_index(drop=True))
output:
ID Start Time End Time Item diff
0 10 2019-08-02 09:00:00 2019-08-02 09:30:00 A NaT
1 10 2019-08-03 10:50:00 2019-08-03 11:00:00 B 0 days 00:30:00
2 10 2019-08-04 15:00:00 2019-08-05 16:00:00 C 0 days 00:10:00
3 20 2019-08-04 08:00:00 2019-08-04 14:00:00 B NaT
4 20 2019-08-05 10:30:00 2019-08-05 20:30:00 C 0 days 06:00:00
5 30 2019-08-06 11:00:00 2019-08-07 10:00:00 A NaT
IIUC use:
df1 = df.pivot('ID','Item')
print (df1)
Start Time \
Item A B D
ID
10 2019-08-02 09:00:00 2019-08-03 10:50:00 2019-08-04 15:00:00
20 2019-08-04 08:00:00 NaT 2019-08-05 10:30:00
30 2019-08-06 11:00:00 NaT NaT
End Time
Item A B D
ID
10 2019-08-02 09:30:00 2019-08-03 11:00:00 2019-08-05 16:00:00
20 2019-08-04 14:00:00 NaT 2019-08-05 20:30:00
30 2019-08-07 10:00:00 NaT NaT
a = df1[('Start Time','D')].sub(df1[('End Time','A')])
print (a)
ID
10 2 days 05:30:00
20 0 days 20:30:00
30 NaT
dtype: timedelta64[ns]

How to get odd hours to even hours in pandas dataframe?

I have such a dataframe with "normal" steps of two hours between the timestamps. But sometimes there are unfortunately gaps within my data. Because of that I would like to round timestamps with odd hours (01:00, 03:00 etc.) to even hours (02:00, 04:00 etc.). Time is my index column.
My dataframe looks like this:
Time Values
2021-10-24 22:00:00 2
2021-10-25 00:00:00 4
2021-10-25 02:00:00 78
2021-10-25 05:00:00 90
2021-10-25 07:00:00 1
How can I get a dataframe like this?
Time Values
2021-10-24 22:00:00 2
2021-10-25 00:00:00 4
2021-10-25 02:00:00 78
2021-10-25 06:00:00 90
2021-10-25 08:00:00 1
Use DateTimeIndex.floor or DateTimeIndex.ceil with a frequency string 2H depending if you want to down or upsample.
df.index = df.index.ceil('2H')
>>> df
Values
Time
2021-10-24 22:00:00 2
2021-10-25 00:00:00 4
2021-10-25 02:00:00 78
2021-10-25 06:00:00 90
2021-10-25 08:00:00 1
If "Time" is a column (and not the index), you can use dt.ceil:
df["Time"] = df["Time"].dt.ceil("2H")
>>> df
Time Values
0 2021-10-24 22:00:00 2
1 2021-10-25 00:00:00 4
2 2021-10-25 02:00:00 78
3 2021-10-25 06:00:00 90
4 2021-10-25 08:00:00 2
Alternatively, if you want to ensure that the data contains every 2-hour interval, you could resample:
df = df.resample("2H", on="Time", closed="right").sum()
>>> df
Values
Time
2021-10-24 22:00:00 2
2021-10-25 00:00:00 4
2021-10-25 02:00:00 78
2021-10-25 04:00:00 0
2021-10-25 06:00:00 90
2021-10-25 08:00:00 2

Reverse position of entries in pandas dataframe based on condition

Here I have an extract from my pandas dataframe which is survey data with two datetime fields. It appears that some of the start times and end times were filled in the wrong position in the survey. Here is an example from my dataframe. The start and end time in the 8th row, I suspect were entered the wrong way round.
Just to give context, I generated the third column like this:
df_time['trip_duration'] = df_time['tripEnd_time'] - df_time['tripStart_time']
The three columns are in timedelta64 format.
Here is the top of my dataframe:
tripStart_time tripEnd_time trip_duration
1 22:30:00 23:15:00 00:45:00
2 11:00:00 11:30:00 00:30:00
3 09:00:00 09:15:00 00:15:00
4 13:30:00 14:25:00 00:55:00
5 09:00:00 10:15:00 01:15:00
6 12:00:00 12:15:00 00:15:00
7 08:00:00 08:30:00 00:30:00
8 11:00:00 09:15:00 -1 days +22:15:00
9 14:00:00 14:30:00 00:30:00
10 14:55:00 15:20:00 00:25:00
What I am trying to do is, loop through these two columns, and for each time 'tripEnd_time' is less than 'tripStart_time' swap the positions of these two entries. So in the case of row 8 above, I would make tripStart_time = tripEnd_time and tripEnd_time = tripStart_time.
I am not quite sure the best way to approach this. Should I use nested for loop where i compare each entry in the two columns?
Thanks
Use Series.abs:
df_time['trip_duration'] = (df_time['tripEnd_time'] - df_time['tripStart_time']).abs()
print (df_time)
1 22:30:00 23:15:00 00:45:00
2 11:00:00 11:30:00 00:30:00
3 09:00:00 09:15:00 00:15:00
4 13:30:00 14:25:00 00:55:00
5 09:00:00 10:15:00 01:15:00
6 12:00:00 12:15:00 00:15:00
7 08:00:00 08:30:00 00:30:00
8 11:00:00 09:15:00 01:45:00
9 14:00:00 14:30:00 00:30:00
10 14:55:00 15:20:00 00:25:00
What is same like:
a = df_time['tripEnd_time'] - df_time['tripStart_time']
b = df_time['tripStart_time'] - df_time['tripEnd_time']
mask = df_time['tripEnd_time'] > df_time['tripStart_time']
df_time['trip_duration'] = np.where(mask, a, b)
print (df_time)
tripStart_time tripEnd_time trip_duration
1 22:30:00 23:15:00 00:45:00
2 11:00:00 11:30:00 00:30:00
3 09:00:00 09:15:00 00:15:00
4 13:30:00 14:25:00 00:55:00
5 09:00:00 10:15:00 01:15:00
6 12:00:00 12:15:00 00:15:00
7 08:00:00 08:30:00 00:30:00
8 11:00:00 09:15:00 01:45:00
9 14:00:00 14:30:00 00:30:00
10 14:55:00 15:20:00 00:25:00
You can switch column values on selected rows:
df_time.loc[df_time['tripEnd_time'] < df_time['tripStart_time'],
['tripStart_time', 'tripEnd_time']] = df_time.loc[
df_time['tripEnd_time'] < df_time['tripStart_time'],
['tripEnd_time', 'tripStart_time']].values

Pandas : merge on date and hour from datetime index

I have two data frames like following, data frame A has datetime even with minutes, data frame B only has hour.
df:A
dataDate original
2018-09-30 11:20:00 3
2018-10-01 12:40:00 10
2018-10-02 07:00:00 5
2018-10-27 12:50:00 5
2018-11-28 19:45:00 7
df:B
dataDate count
2018-09-30 10:00:00 300
2018-10-01 12:00:00 50
2018-10-02 07:00:00 120
2018-10-27 12:00:00 234
2018-11-28 19:05:00 714
I like to merge the two on the basis of hour date and hour, so that now in dataframe A should have all the rows filled on the basis of merge on date and hour
I can try to do it via
A['date'] = A.dataDate.date
B['date'] = B.dataDate.date
A['hour'] = A.dataDate.hour
B['hour'] = B.dataDate.hour
and then merge
merge_df = pd.merge(A,B, how='left', left_on=['date', 'hour'],
right_on=['date', 'hour'])
but its a very long process, Is their an efficient way to perform the same operation with the help of pandas time series or date functionality?
Use map if need append only one column from B to A with floor for set minutes and seconds if exist to 0:
d = dict(zip(B.dataDate.dt.floor('H'), B['count']))
A['count'] = A.dataDate.dt.floor('H').map(d)
print (A)
dataDate original count
0 2018-09-30 11:20:00 3 NaN
1 2018-10-01 12:40:00 10 50.0
2 2018-10-02 07:00:00 5 120.0
3 2018-10-27 12:50:00 5 234.0
4 2018-11-28 19:45:00 7 714.0
For general solution use DataFrame.join:
A.index = A.dataDate.dt.floor('H')
B.index = B.dataDate.dt.floor('H')
A = A.join(B, lsuffix='_left')
print (A)
dataDate_left original dataDate count
dataDate
2018-09-30 11:00:00 2018-09-30 11:20:00 3 NaT NaN
2018-10-01 12:00:00 2018-10-01 12:40:00 10 2018-10-01 12:00:00 50.0
2018-10-02 07:00:00 2018-10-02 07:00:00 5 2018-10-02 07:00:00 120.0
2018-10-27 12:00:00 2018-10-27 12:50:00 5 2018-10-27 12:00:00 234.0
2018-11-28 19:00:00 2018-11-28 19:45:00 7 2018-11-28 19:05:00 714.0

Python: Grouping by time interval

I have a dataframe that looks like this:
I'm using python 3.6.5 and a datetime.time object for the index
print(sum_by_time)
Trips
Time
00:00:00 10
01:00:00 10
02:00:00 10
03:00:00 10
04:00:00 20
05:00:00 20
06:00:00 20
07:00:00 20
08:00:00 30
09:00:00 30
10:00:00 30
11:00:00 30
How can I group this dataframe by time interval to get something like this:
Trips
Time
00:00:00 - 03:00:00 40
04:00:00 - 07:00:00 80
08:00:00 - 11:00:00 120
I think need convert index values to timedeltas by to_timedelta and then resample:
df.index = pd.to_timedelta(df.index.astype(str))
df = df.resample('4H').sum()
print (df)
Trips
00:00:00 40
04:00:00 80
08:00:00 120
EDIT:
For your format need:
df['d'] = pd.to_datetime(df.index.astype(str))
df = df.groupby(pd.Grouper(freq='4H', key='d')).agg({'Trips':'sum', 'd':['first','last']})
df.columns = df.columns.map('_'.join)
df = df.set_index(df['d_first'].dt.strftime('%H:%M:%S') + ' - ' + df['d_last'].dt.strftime('%H:%M:%S'))[['Trips_sum']]
print (df)
Trips_sum
00:00:00 - 03:00:00 40
04:00:00 - 07:00:00 80
08:00:00 - 11:00:00 120

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