I have a simple socket written in python to send a request to the server(Virtualbox Kali Linux) and receive some data from it. It seems like, it is connecting, but receiving no data. Screenshot of behaviour - https://prnt.sc/ragj7q
Here you can see a network config of the Virtualbox
Sever code:
import socket
def SocketMon():
serversocket = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
serversocket.bind((socket.gethostname(),1234))
serversocket.listen(5)
while True:
clientsocket,address = serversocket.accept()
clientsocket.send(bytes("welcome"),"utf-8")
SocketMon()
Client code:
import socket
s = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
s.connect(("127.0.0.1",1234))
msg = s.recv(1024)
print(msg.decode("utf-8"))
Related
I am trying to transfer scapy packets between two python apps that I wrote. My first python code is sending packet using scapy to the localhost on port 9000. My second python code is listening on the localhost using sockets. But for some reason I can't get the packet on the second code although its shows me that the packet was sent.
Can someone tell me how can I achived this goal?
This is my 'Server':
import socket
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as sock:
sock.bind(("127.0.0.1", 9000))
sock.listen(1)
csock, addr = sock.accept()
data = csock.recv(2048)
print(data)
This is my 'Client' code:
import scapy.all as scapy
def main():
packet = scapy.IP(dst="127.0.0.1") / scapy.TCP(dport=9000) / scapy.Raw(load="data")
scapy.send(packet)
if __name__ == "__main__":
main()
The output is that the client shows that the packet sent and stop running.
And the server stays on the csock, addr = sock.accept
I'm trying to make a console chat app in python using socket library.
Whenever I send a message to the server, the server code crashes with the following message:
OSError: [WinError 10057] A request to send or receive data was disallowed because the socket is not connected and (when sending on a datagram socket using a sendto call) no address was supplied
Server code
import socket
HOST = socket.gethostbyname(socket.gethostname()) # get the ip address of PC
PORT = 5050
ADDRESS = (HOST, PORT)
socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
socket.bind(ADDRESS)
while True:
socket.listen()
conn, addr = socket.accept()
print(f"Connected by {addr}")
while True:
data = conn.recv(64)
print(data.decode('utf-8'))
socket.send(data)
Client code
import socket
HOST = socket.gethostbyname(socket.gethostname()) # get the ip address of PC
PORT = 5050
ADDRESS = (HOST, PORT)
socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
socket.connect(ADDRESS)
while True:
msg = input("Enter your message")
socket.send(msg.encode('utf-8'))
data = socket.recv(64)
print(data.decode('utf-8'))
What I am trying to achieve is whenever I send a message to the server, the client script should print the sent message. How can I fix that?
You're attempting to send data to your own server socket. You instead want to send to the client that you accepted.
socket.send(data)
Should be:
conn.send(data)
If you think about it, if you had multiple clients, how would you send data to a specific client? By using the socket that accept gave you.
As a side note, you probably don't want to import the module as socket, and also call your variable socket. It's fine here, but if you were to make a more complicated project, you may accidentally refer to the object when you meant to refer to the module. I'd rename the socket object to sock or server_socket to avoid shadowing.
I know that similar questions have been raised but they don't seem to work for me! I have tried serializing the dictionary then converting that to a string then encoding it before I send it over the socket. No success so far!
This is my server code:
#library
import socket
import pickle
#socket initialization
host = "127.0.0.1"
port = 5000
mainAddr = (host, port)
#dict initialization
dataDict = {} #just imagine that dict has content
#create socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) #TCP
s.bind((mainAddr))
s.listen(4)
print('program started')
print('listening..')
while True:
try:
conn, addr = s.accept()
print("connection from: "+str(addr))
print("sending message..")
pickle.dumps(dataDict)
print('pickled!')
dataS = str(dataP)
print('stringed!')
dataE = dataS.encode('UTF-8')
print('encoded!')
s.sendto(dataE,addr)
print('data sent!')
except:
pass
s.close()
For the socket initialization, I've tried other types:
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) #UDP
s = socket.socket()
For the sending part, I've tried these alternatives:
s.send(dataE)
s.send(dataE,addr)
s.sendall(dataE)
s.sendall(dataE,addr)
When I run the program, these get printed out:
program started
listening..
connection from:<insert addr here>
sending message..
pickled!
stringed!
encoded!
Only data sent! is not sent. So I am guessing that it's the sending part that has a problem.
For the client side, here's the code:
#library
import socket
import pickle
#initialization
host = '127.0.0.1'
port = 5000
buffer = 1024
#create socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) #TCP
s.connect((host,port))
print('connected!')
#receive dictionary
print('receiving message..')
while True:
data, addr = s.recvfrom(buffer)
print('received!')
dataD = data.decode("UTF-8")
print('decoded!')
dataP = pickle.loads(dataD)
print('unpickled!')
print(str(dataP))
s.close()
In the client terminal, only the following prints:
connected!
receiving message..
On the client side, I've tried changing the order of unpickling and decoding but still, to no avail.
A TCP server socket is not actually used for sending/receiving data; I'm surprised you're not getting an error when calling s.send() or similar on it. Instead, it's a factory for producing individual sockets for each client that connects to the server - conn, in your code. So, conn.sendall() is what you should be using. No address parameter is required, the individual socket already knows who it is talking to. (.send() is unreliable without some extra work on your part; .sendto() is only used with UDP sockets that have not been connected to a particular client.)
I've tried to connect two computers with a socket in Python and I don't know why it doesn't work. The files are from internet and it compiles for me but without any results.
The server.py:
#!/usr/bin/python
import socket
s = socket.socket()
host = ''
port = 12345
s.bind((host, port))
s.listen(5)
while True:
c, addr = s.accept()
print 'Got connection from', addr
c.send('Thank you for connecting')
c.close()
and the client.py:
#!/usr/bin/python
import socket
s = socket.socket()
host = # here I put the ip of the server's laptop
port = 12345
s.connect((host, port))
print s.recv(1024)
s.close()
What's wrong?
You have to run the server first. Then run the client at the same time with the IP of the server (I used localhost because it was running on one computer, maybe you should try if that works). The code worked fine for me, every time I ran the client, the server printed a message. If it doesn't work for you, maybe your firewall is not letting you open ports.
Just for the future, please always post any error messages you see.
BTW, isn't this the Python Documentation example for sockets?
I'm trying the following client and server chat program. Although I get an error whenever I try to run the server program, when the client program runs it stays on a blank screen not allowing me to type anything. I've tried running server first and running client first and I get the same results. I can't read the error from the server program because it flashes the error and closes the window. Here is my code:
server:
#server
import socket
import time
HOST = ''
PORT = 8065
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.bind((HOST,PORT))
s.listen(1)
conn, addr = s.accept()
print 'Connected by', addr
while 1:
data = conn.recv(1024)
if not data: break
conn.sendall(data)
conn.close()
client:
#client
import socket
import time
HOST = "localhost"
PORT = 8065
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.connect((HOST,PORT))
s.sendall('Helloworld')
data = s.recv(1024)
s.close()
print 'Recieved', repr(data)
Im not an expert but I was able to make your examples work by changing the socket from datagram to stream connection, and then encoding message being sent because strings aren't supported (although this might not effect you since I think that change was made in Python 3...I'm not 100% sure).
I believe the main issue is that you're trying to listen() but SOCK_DGRAM (UDP) doesn't support listen(), you just bind and go from there, whereas SOCK_STREAM (TCP) uses connections.
If you're just trying to get the program going, use the below code, unless there is a specific reason you'd like to use SOCK_DGRAM.
The code is below:
client
#client
import socket
import time
HOST = "localhost"
PORT = 8065
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((HOST,PORT))
test = 'Helloworld'
s.sendall(test.encode())
data = s.recv(1024)
s.close()
print 'Recieved', repr(data)
server
#server
import socket
import time
HOST = ''
PORT = 8065
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((HOST,PORT))
s.listen(1)
conn, addr = s.accept()
print ('Connected by', addr)
while 1:
data = conn.recv(1024)
if not data: break
conn.sendall(data)
conn.close()