This question already has answers here:
How to declare many variables?
(5 answers)
Closed 3 years ago.
I would like to do something like this:
for i in range(0, 3):
if i == 0:
name_i = "A"
elif i == 1:
name_i = "B"
else:
name_i = "C"
to have name_o = "A", name_1 = "B", name_i = "C".
I know I cannot do it like that method but is there some trick I can use to achieve that?
Dict example:
names = ['A', 'B', 'C']
my_dict = {}
for n, i in enumerate(names):
name = 'name_{}'.format(n)
my_dict[name] = i
Output:
{'name_0': 'A', 'name_1': 'B', 'name_2': 'C'}
Depending on where you get your A, B, C from, you can simply take them out of a list.
# or wherever your letters / whatever come from
import string
abc = string.ascii_uppercase
name0, name1, name2 = abc[0: 3]
print(name0)
print(name1)
print(name2)
Related
This question already has answers here:
Why can't I iterate twice over the same iterator? How can I "reset" the iterator or reuse the data?
(5 answers)
Closed last month.
I have created 2 scripts in python : script 2 contains 3 functions one to create a dictionary second to return a dictionary and third is a random function . and script 1 contains 5 functions
fun1 is to call create dictionary function fun2 , fun3 , fun4 are random calculation function and fun5 calls and print the return dictionary function.
Script 1:
from p2 import *
def fun1(keys,values):
create_map(keys,values)
def fun2(n):
rand_fun(n)
def fun3(n):
rand_fun(n)
def fun4(n):
rand_fun(n)
def fun5(lst):
print(return_map(lst))
keys = [1,2,3]
values = ['a','b','c']
data = create_map(keys,values)
fun2(2)
fun3(3)
fun4(4)
dictionary = fun5(data)
dictionary1 = fun5(data)
dictionary2 = fun5(data)
Script 2:
def create_map(keys, values):
return zip(keys,values)
def return_map(data):
return dict(data)
def rand_fun(n):
return print((n+1)%2)
The output is:
1
0
1
{1: 'a', 2: 'b', 3: 'c'}
{}
{}
Why am i getting empty dictionary the second and third time and how can i fix this issue
reason:
zip can only use once.
reference:Python zip object 'disappears' after iterating through?
code:
keys = [1,2,3]
values = ['a','b','c']
data = create_map(keys,values)
fun2(2)
fun3(3)
fun4(4)
dictionary = fun5(create_map(keys,values))
dictionary1 = fun5(create_map(keys,values))
dictionary2 = fun5(create_map(keys,values))
result:
1
0
1
{1: 'a', 2: 'b', 3: 'c'}
{1: 'a', 2: 'b', 3: 'c'}
{1: 'a', 2: 'b', 3: 'c'}
change your create_map function to this.
def create_map(keys, values):
return dict(zip(keys,values))
like leaf_yakitori said zip can only be used once.
I'm working on this code that basically gives output based on the input (the users names) that the user give, i need help/ advice on how i can differentiate the output given based on the name.
i've tried if statements, but its really basic detecting, since i've only studied python not so long ago.
# var
import random
nopes = ("nope1", "nope2", "nope3")
list1 = 1
list2 = 2
list3 = 3
list4 = 4
list5 = 5
list6 = 6
list7 = 7
list8 = 8
list9 = 9
# functions
def mainfunc():
if a in "name1":
print(list1)
elif a in "name2":
print(list2)
elif a in "name3":
print(list3)
elif a in "name4":
print(list4)
elif a in "name5":
print(list5)
elif a in "name6":
print(list6)
elif a in "name7":
print(list7)
elif a in "name8":
print(list8)
elif a in "name9":
print(list9)
else:
talk()
def talk():
print(random.choice(nopes))
#syntax's
a = input("What's your name? : ")
mainfunc()
yes, it works. but with a single typo the code would not work as i expected, and im trying to avoid that.
I don't completely get the intention of your code, but if you want to print differnt lists based on the input, you could use a dictionary instead of the several list#-objects.
lists = {
"name1": ["a","b","c"],
"name2": ["d","e","f"]
}
a = "name1"
if (a in lists.keys()):
print(lists[a])
# Output: ['a', 'b', 'c']
That way, you just have to maintain the dictionary object and not many single objects and the elseifs
This question already has answers here:
Counting occurrences without using collections.Counter
(5 answers)
Closed 5 years ago.
I am using python to count the frequency of list WITHOUT using any collection just solely my own python basics functions.
My code is:
my_list = ['a', 'b','a', 'a','b','b', 'a','a','c']
def counting():
#Please help
Print out put should be like
a: 5
b: 3
c: 1
Please help thank you.
Use count , an inbuilt list function.
def counting(my_list):
return { x:my_list.count(x) for x in my_list }
Just call it :
>>> counting(my_list)
=> {'a': 5, 'b': 3, 'c': 1}
#print it as per requirement
>>> for k,v in counting(my_list).items():
print(k,':',v)
a : 5
b : 3
c : 1
#driver value :
IN : my_list = ['a', 'b','a', 'a','b','b', 'a','a','c']
Create a dictionary to hold the results and check if the key exists increment the value, otherwise set the value of 1 (first occurrence).
my_list = ['a', 'b','a', 'a','b','b', 'a','a','c']
def counting(my_list):
counted = {}
for item in my_list:
if item in counted:
counted[item] += 1
else:
counted[item] = 1
return counted
print(counting(my_list))
This question already has answers here:
How to count the frequency of the elements in an unordered list? [duplicate]
(33 answers)
Closed 5 years ago.
i have one list wich has names in it:
names = ['test','hallo','test']
uniquenames = ['test','hallo']
with set i get the uniquenames so the unique names are in a different list
but now i want to count how many names there are of each so test:2 hallo:1
i have this:
for i in range(len(uniquenames)):
countname = name.count[i]
but it gives me this error:
TypeError: 'builtin_function_or_method' object is not subscriptable
how can i fix that?
You could use a dictionary:
names = ['test','hallo','test']
countnames = {}
for name in names:
countnames[name] = countnames.get(name, 0) + 1
print(countnames) # => {'test': 2, 'hallo': 1}
If you want to make it case-insensitive, use this:
names = ['test','hallo','test', 'HaLLo', 'tESt']
countnames = {}
for name in names:
name = name.lower() # => to make 'test' and 'Test' and 'TeST'...etc the same
countnames[name] = countnames.get(name, 0) + 1
print(countnames) # => {'test': 3, 'hallo': 2}
In case you want the keys to be the counts, use an array to store the names in:
names = ['test','hallo','test','name', 'HaLLo', 'tESt','name', 'Hi', 'hi', 'Name', 'once']
temp = {}
for name in names:
name = name.lower()
temp[name] = temp.get(name, 0) + 1
countnames = {}
for name, count in temp.items():
countnames.setdefault(count, []).append(name)
print(countnames) # => {3: ['test', 'name'], 2: ['hallo', 'hi'], 1: ['once']}
Use Counter from collections:
>>> from collections import Counter
>>> Counter(names)
Counter({'test': 2, 'hallo': 1})
Also, for your example to work you should change names.count[i] for names.count(i) as count is a function.
This question already has answers here:
How do I create variable variables?
(17 answers)
Closed 4 years ago.
I'm new to python, so I don't know if this is possible. I'm trying to create a list of variable names from a list of strings so I can then assign values to the newly created variables.
I saw another similar question, but there was already a dict pays of keys and values.
Here's my code:
def handy(self):
a = raw_input('How many hands? ')
for i in range(int(a)):
h = "hand" + str(i+ 1)
self.list_of_hands.append(h)
# would like to create variable names from self.list_of_hands
# something like "hand1 = self.do_something(i)"
print h
print self.list_of_hands
Given some of the answers, i'm adding the following comment:
I'm going to then assign dicts to each variable. So, can I create a dictionary of dictionaries?
Why don't you just construct a dictionary using the strings as keys?
>>> class test():
def handy(self):
a = raw_input('How many hands? ')
d = { "hand" + str(i + 1) : self.do_something(i) for i in range(int(a)) }
keys = d.keys()
keys.sort()
for x in keys:
print x, '=', d[x]
def do_something(self, i):
return "something " + str(i)
>>> test().handy()
How many hands? 4
hand1 = something 0
hand2 = something 1
hand3 = something 2
hand4 = something 3
Edit: You updated the question to ask if you can store a dictionary as a value in a dictionary. Yes, you can:
>>> d = { i : { j : str(i) + str(j) for j in range(5) } for i in range(5) }
>>> d[1][2]
'12'
>>> d[4][1]
'41'
>>> d[2]
{0: '20', 1: '21', 2: '22', 3: '23', 4: '24'}
>> d[5] = { 1 : '51' }
>> d[5][1]
'51'
If you ever have multiple variables that only differ by a number at the end (hand1, hand2, etc.), you need a container.
I think a dictionary would work best:
self.hands = {}
self.hands[h] = self.do_something(i)
You can access the individual keys in the dictionary easily:
self.hands['hand1']
h = "hand" + str(i+ 1)
vars()[h] = do_something(i)
Now you can call hand1 to call do_something()