How can I change the display name of a file using Python?
Details:
Using Mac OS X Mojave
Python 3.7
To be precise, I want to hide the file extension of a file so that textfile.txt is seen as textfile only, without actually removing the file extension.
EDIT:
The display name of a file looks like this:
And I want it to look like this:
What you want is
import os
print(os.path.splitext("/path/to/textfile.txt")[0])
The output will be
/path/to/textfile
EDIT:
from your last edit i figured that what you're looking for is to hide extensions directly in the OS using Python. Well, this is more a task to do modifying your system settings, i don't think that you will be able to change this type of system settings directly from Python.
Related
suppose the below text is present in the file
1.a=2
2.b=3
3.print(a+b)
if i change the value of b to 5, how to print that in this line this field is changed in python
I think you could use gif for version control of your source code and some library like GitPython to be able to interact from python.
I am trying to make a python program that creates and writes in a txt file.
the program works, but I want it to cross the "hidden" thing in the txt file's properties, so that the txt can't be seen without using the python program I made. I have no clues how to do that, please understand I am a beginner in python.
I'm not 100% sure but I don't think you can do this in Python. I'd suggest finding a simple Visual Basic script and running it from your Python file.
Assuming you mean the file-properties, where you can set a file as "hidden". Like in Windows as seen in screenshot below:
Use operating-system's command-line from Python
For example in Windows command-line attrib +h Secret_File.txt to hide a file in CMD.
import subprocess
subprocess.run(["attrib", "+h", "Secret_File.txt"])
See also:
How to execute a program or call a system command?
Directly call OS functions (Windows)
import ctypes
path = "my_hidden_file.txt"
ctypes.windll.kernel32.SetFileAttributesW(path, 2)
See also:
Hide Folders/ File with Python
Rename the file (Linux)
import os
filename = "my_hidden_file.txt"
os.rename(filename, '.'+filename) # the prefix dot means hidden in Linux
See also:
How to rename a file using Python
I have this small program and it needs to create a small .txt file in their 'My Documents' Folder. Here's the code I have for that:
textfile=open('C:\Users\MYNAME\Documents','w')
lines=['stuff goes here']
textfile.writelines(lines)
textfile.close()
The problem is that if other people use it, how do I change the MYNAME to their account name?
Use os.path.expanduser(path), see http://docs.python.org/library/os.path.html
e.g. expanduser('~/filename')
This works on both Unix and Windows, according to the docs.
Edit: forward slash due to Sven's comment.
This works without any extra libs:
import ctypes.wintypes
CSIDL_PERSONAL = 5 # My Documents
SHGFP_TYPE_CURRENT = 0 # Get current, not default value
buf= ctypes.create_unicode_buffer(ctypes.wintypes.MAX_PATH)
ctypes.windll.shell32.SHGetFolderPathW(None, CSIDL_PERSONAL, None, SHGFP_TYPE_CURRENT, buf)
print(buf.value)
Also works if documents location and/or default save location is changed by user.
On Windows, you can use something similar what is shown in the accepted answer to the question: Python, get windows special folders for currently logged-in user.
For the My Documents folder path, useshellcon.CSIDL_PERSONALin the shell.SHGetFolderPath() function call instead of shellcon.CSIDL_MYPICTURES.
So, assuming you have the PyWin32 extensions1 installed, this might work (see caveat in Update section below):
>>> from win32com.shell import shell, shellcon
>>> shell.SHGetFolderPath(0, shellcon.CSIDL_PERSONAL, None, 0)
u'<path\\to\\folder>'
Update: I just read something that said that CSIDL_PERSONAL won't return the correct folder if the user has changed the default save folder in the Win7 Documents library. This is referring to what you can do in library's Properties dialog:
The checkmark means that the path is set as the default save location.
I currently am unware of a way to call the SHLoadLibraryFromKnownFolder() function through PyWin32 (there currently isn't a shell.SHLoadLibraryFromKnownFolder. However it should be possible to do so using the ctypes module.
1Installers for the latest versions of the Python for Windows Extensions are currently available from: http://sourceforge.net/projects/pywin32
I want to create a startup configuration that runs a file that I request. So far, my configuration file is as follows:
path1=input('What folder would you like to open?')
os.chdir('C:\\Users\\Owner\\Documents\\Spring 2013\\CSCI_278\\'+path1)
doc=input('What file would you like to open and run?')
open(doc)
execfile(doc)
but the execfile doesn't work for some reason, and I end having to use %run in pylab anyway. Is there a way around this?
Does using raw_input instead of input solve your problem?
Not sure you need the open(doc) line.
The code below works on my machine:
doc = raw_input('What file would you like to open and run?')
execfile(doc)
Note that you can also use the line below instead, if you do not want to type the ".py" each time
doc = "%s.py" % raw_input('What file would you like to open and run?')
I have this small program and it needs to create a small .txt file in their 'My Documents' Folder. Here's the code I have for that:
textfile=open('C:\Users\MYNAME\Documents','w')
lines=['stuff goes here']
textfile.writelines(lines)
textfile.close()
The problem is that if other people use it, how do I change the MYNAME to their account name?
Use os.path.expanduser(path), see http://docs.python.org/library/os.path.html
e.g. expanduser('~/filename')
This works on both Unix and Windows, according to the docs.
Edit: forward slash due to Sven's comment.
This works without any extra libs:
import ctypes.wintypes
CSIDL_PERSONAL = 5 # My Documents
SHGFP_TYPE_CURRENT = 0 # Get current, not default value
buf= ctypes.create_unicode_buffer(ctypes.wintypes.MAX_PATH)
ctypes.windll.shell32.SHGetFolderPathW(None, CSIDL_PERSONAL, None, SHGFP_TYPE_CURRENT, buf)
print(buf.value)
Also works if documents location and/or default save location is changed by user.
On Windows, you can use something similar what is shown in the accepted answer to the question: Python, get windows special folders for currently logged-in user.
For the My Documents folder path, useshellcon.CSIDL_PERSONALin the shell.SHGetFolderPath() function call instead of shellcon.CSIDL_MYPICTURES.
So, assuming you have the PyWin32 extensions1 installed, this might work (see caveat in Update section below):
>>> from win32com.shell import shell, shellcon
>>> shell.SHGetFolderPath(0, shellcon.CSIDL_PERSONAL, None, 0)
u'<path\\to\\folder>'
Update: I just read something that said that CSIDL_PERSONAL won't return the correct folder if the user has changed the default save folder in the Win7 Documents library. This is referring to what you can do in library's Properties dialog:
The checkmark means that the path is set as the default save location.
I currently am unware of a way to call the SHLoadLibraryFromKnownFolder() function through PyWin32 (there currently isn't a shell.SHLoadLibraryFromKnownFolder. However it should be possible to do so using the ctypes module.
1Installers for the latest versions of the Python for Windows Extensions are currently available from: http://sourceforge.net/projects/pywin32