Plot a gamut in cie1931 colour space Python 2.7 - python

Gamut I want to plot in CIE1931 space: https://www.google.co.uk/search?biw=1337&bih=1257&tbm=isch&sa=1&ei=9x3kW7rqBo3ygQb-8aWYBw&q=viewpixx+gamut&oq=viewpixx+gamut&gs_l=img.3...2319.2828.0.3036.5.5.0.0.0.0.76.270.5.5.0....0...1c.1.64.img..0.0.0....0.KT8w80tcZik#imgrc=77Ufw31S6UVlYM
I want to create a triangle plot of the ciexyY colours within the these coordinates: (.119,.113),(.162,.723),(.695,.304) as in the image - with a set luminance Y at 30.0.
I have created a 3d array of xy values between 0-1.
I then created a matrix with 1s inside the triangle and 0s outside the triangle.
I multiplied the triangle matrix by the xyY ndarray.
Then I looped through the xyY ndarray and converted xyY values to rgb, and displayed them.
The result is somewhat close but not correct. I think the error is in the last section when I convert to rgb, but I'm not sure why. This is the current image: https://imgur.com/a/7cWY0FI. Any recommendations would be really appreciated.
from __future__ import division
import numpy as np
from colormath.color_objects import sRGBColor, xyYColor
from colormath.color_conversions import convert_color
import matplotlib.pyplot as plt
def frange(x,y,jump):
while x < y:
yield x
x += jump
def onSameSide(p1,p2, A,B):
cp1 = np.cross(B-A, p1-A)
cp2 = np.cross(B-A, p2-A)
if(np.dot(cp1, cp2) >= 0):
return True
else:
return False
def isPointInTriangle(p,A,B,C):
if(onSameSide(p,A,B,C) and onSameSide(p,B,A,C) and onSameSide(p,C,A,B)):
return True
else:
return False
xlen = 400
ylen = 400
#CIExyY colour space
#Make an array (1,1,3) with each plane representing how x,y,Y vary in the coordinate space
ciexyY = np.zeros((3,xlen,ylen))
ciexyY[2,:,:]=30.0
for x in frange(0,1,1/xlen):
ciexyY[0,:,int(xlen*x)]=x
for y in frange(0,1,1/xlen):
ciexyY[1,int(ylen*y),:]=y
#coordinates from Viewpixx gamut, scaled up to 100
blue=np.array((.119,.113,30.0))
green=np.array((.162,.723,30.0))
red=np.array((.695,.304,30.0))
#scale up to size of image
blue = np.multiply(blue,xlen)
green = np.multiply(green,xlen)
red = np.multiply(red,xlen)
#make an array of zeros and ones to plot the shape of Viewpixx triangle
triangleZeros = np.zeros((xlen,ylen))
for x in frange(0,xlen,1):
for y in frange(0,ylen,1):
if(isPointInTriangle((x,y,0),blue,green,red)):
triangleZeros[x,y]=1
else:
triangleZeros[x,y]=0
#cieTriangle
cieTriangle = np.multiply(ciexyY,triangleZeros)
#convert cieTriangle xyY to rgb
rgbTriangle = np.zeros((3,xlen,ylen))
for x in frange(0,xlen,1):
for y in range(0,ylen,1):
xyYcolour = xyYColor(cieTriangle[0,x,y],cieTriangle[1,x,y],cieTriangle[2,x,y])
rgbColour = convert_color(xyYcolour,sRGBColor)
rgbTriangle[0,x,y] = rgbColour.rgb_r
rgbTriangle[1,x,y] = rgbColour.rgb_g
rgbTriangle[2,x,y] = rgbColour.rgb_b
rgbTriangle = np.transpose(rgbTriangle)
plt.imshow(rgbTriangle)
plt.show()

We have all the common Chromaticity Diagrams in Colour, I would recommend it over python-colormath because Colour is vectorised and thus much faster.
Do you have a render of your current image to share though?

from colour.plotting import plot_chromaticity_diagram_CIE1931
plot_chromaticity_diagram_CIE1931()

Related

Pixel is there but .getpixel isn't detecting it

I'm currently having an issues with my program that im not too sure how to fix.
I am doing the following:
x = 0
y = 0
im = ImageGrab.grab()
time.sleep(1)
while True:
xy = (x, y)
x = x + 1
if im.getpixel(xy) == (0,158,187):
time.sleep(0.3)
pyautogui.click(x,y)
break
if x >= 1200:
x = 0
y = y + 1
print('cant find pixel')
if y >= 950:
y = 0
x = 0
And it works about 90% of the time and then theres this random time it just says it can't detect the pixel despite the pixel being there 100%.
EDIT: Managed to catch the following error in the 10% it happens:
AttributeError: 'NoneType' object has no attribute 'getpixel'
Which makes no sense since I'm doing im = ImageGrab.grab() beforehand and it works 90% of the time
You should check your ImageGrab() was successful before using the data, so something like:
im = ImageGrab.grab()
if im is not None:
processImage
You'll be there all day if you run double for loops over an image and call a function for every one! Try to get in the habit of using Numpy vectorised code for images in Python.
Basically, you appear to be testing if any pixel in your 1200x950 image matches all three RGB components (0,158,187).
You can do that with Numpy like this:
np.any(np.all(na==(0,158,187), axis=-1))
In the demo below the double for loops take 800ms and the Numpy test takes 20ms, so 40x faster.
#!/usr/bin/env python3
import numpy as np
from PIL import Image
def loopy(im):
for x in range(im.width):
for y in range(im.height):
if im.getpixel((x,y)) == crucialPixel:
return True
return False
def me(im):
# Make image into Numpy array
na = np.array(im)
# Test if there is any pixel where all RGB components match crucialPixel
return np.any(np.all(na==crucialPixel, axis=-1))
# Define our beloved crucial pixel
crucialPixel = (0,158,187)
# Construct a new, solid black image
im = Image.new('RGB', (1200,950))
# Neither should find crucialPixel in black image
result = loopy(im)
result = me(im)
# Insert the crucial pixel
im.putpixel((600,475), crucialPixel)
# Both should find crucialPixel
result = loopy(im)
result = me(im)

NameError: name 'IMG_H' is not defined

I am a new programming Interface. I am using the PIL and Matplotlib libraries for the contract streaching.When I am using the Histogram Equalizer I am getting the error as name 'IMG_H' is not defined.I am also Converting my image to numpy array, calculate the histogram, cumulative sum, mapping and then apply the mapping to create a new image.
You can see my code below -
# HISTOGRAM EQUALIZATION
from PIL import Image
import matplotlib.pyplot as plt
import numpy as np
def make_histogram(img):
""" Take an image and create a historgram from it's luma values """
y_vals = img[:,:,0].flatten()
histogram = np.zeros(256, dtype=int)
for y_index in range(y_vals.size):
histogram[y_vals[y_index]] += 1
return histogram
def make_cumsum(histogram):
""" Create an array that represents the cumulative sum of the histogram """
cumsum = np.zeros(256, dtype=int)
cumsum[0] = histogram[0]
for i in range(1, histogram.size):
cumsum[i] = cumsum[i-1] + histogram[i]
return cumsum
def make_mapping(histogram, cumsum):
mapping = np.zeros(256, dtype=int)
luma_levels = 256
for i in range(histogram.size):
mapping[i] = max(0, round((luma_levels*cumsum[i])/(IMG_H*IMG_W))-1)
return mapping
def apply_mapping(img, mapping):
""" Apply the mapping to our image """
new_image = img.copy()
new_image[:,:,0] = list(map(lambda a : mapping[a], img[:,:,0]))
return new_image
# Load image
pillow_img = Image.open('pout.jpg')
# Convert our image to numpy array, calculate the histogram, cumulative sum,
# mapping and then apply the mapping to create a new image
img = np.array(pillow_img)
histogram = make_histogram(img)
cumsum = make_cumsum(histogram)
mapping = make_mapping(histogram, cumsum)
new_image = apply_mapping(img, mapping)
output_image = Image.fromarray(np.uint8(new_image))
imshow(output_image, cmap='gray')
# Display the old (black) and new (red) histograms next to eachother
x_axis = np.arange(256)
fig = plt.figure()
fig.add_subplot(1,2,1)
plt.bar(x_axis , histogram, color = "black")
fig.add_subplot(1,2,2)
plt.bar(x_axis , make_histogram(new_image), color = "red")
plt.show()
You have this variable here:
mapping[i] = max(0, round((luma_levels*cumsum[i])/(IMG_H*IMG_W))-1)
But you didn't define it (or import) before, therefore you get this error.
for i in range(histogram.size):
mapping[i] = max(0, round((luma_levels*cumsum[i])/(IMG_H*IMG_W))-1)
In above stated line. you are using 2 Variables, IMG_H and IMG_W.
where you defined these variables?
EDITED PART
for i in range(histogram.size):
mapping[i] = max(0, round((luma_levels*cumsum[i])/(IMG_H*IMG_W))-1)
in the above stated line you are using 2 variables try to do multiplication (IMG_H*IMG_W) but you did not define and import these variables in the whole code.
You can do like this.
you can define these variables on the top of the code.
your code shows that these variables are defined for Image width and height
IMG_W = 120 #Any value in integer for Image Width
IMG_H = 124 #Any value in integer for Image Height

Extract N number of patches from an image

I have an image of dimension 155 x 240. Like the following:
I want to extract certain shape of patchs (25 x 25).
I don't want to patch from the whole image.
I want to extract N number of patch from non-zero (not background) area of the image. How can I do that? Any idea or suggestion or implementation will be appreciated. You can try with either Matlab or Python.
Note:
I have generated a random image so that you can process it for patching. image_process variable is that image in this code.
import numpy as np
from scipy.ndimage.filters import convolve
import matplotlib.pyplot as plt
background = np.ones((155,240))
background[78,120] = 2
n_d = 50
y,x = np.ogrid[-n_d: n_d+1, -n_d: n_d+1]
mask = x**2+y**2 <= n_d**2
mask = 254*mask.astype(float)
image_process = convolve(background, mask)-sum(sum(mask))+1
image_process[image_process==1] = 0
image_process[image_process==255] = 1
plt.imshow(image_process)
Lets assume that the pixels values you want to omit is 0.
In this case what you could do, is first find the indices of the non-zero values, then slice the image in the min/max position to get only the desired area, and then simply apply extract_patches_2d with the desired window size and number of patches.
For example, given the dummy image you supplied:
import numpy as np
from scipy.ndimage.filters import convolve
import matplotlib.pyplot as plt
background = np.ones((155,240))
background[78,120] = 2
n_d = 50
y,x = np.ogrid[-n_d: n_d+1, -n_d: n_d+1]
mask = x**2+y**2 <= n_d**2
mask = 254*mask.astype(float)
image_process = convolve(background, mask)-sum(sum(mask))+1
image_process[image_process==1] = 0
image_process[image_process==255] = 1
plt.figure()
plt.imshow(image_process)
plt.show()
from sklearn.feature_extraction.image import extract_patches_2d
x, y = np.nonzero(image_process)
xl,xr = x.min(),x.max()
yl,yr = y.min(),y.max()
only_desired_area = image_process[xl:xr+1, yl:yr+1]
window_shape = (25, 25)
B = extract_patches_2d(only_desired_area, window_shape, max_patches=100) # B shape will be (100, 25, 25)
If you plot the only_desired_area you will get the following image:
This is the main logic if you wish an even tighter bound you should adjust the slicing properly.

Rotate, scale and translate 2D coordinates?

I'm am working on a project at the moment where I am trying to create a Hilbert curve using the Python Imaging Library. I have created a function which will generate new coordinates for the curve through each iteration and place them into various lists which then I want to be able to move, rotate and scale. I was wondering if anyone could give me some tips or a way to do this as I am completely clueless. Still working on the a lot of the code.
#! usr/bin/python
import Image, ImageDraw
import math
# Set the starting shape
img = Image.new('RGB', (1000, 1000))
draw = ImageDraw.Draw(img)
curve_X = [0, 0, 1, 1]
curve_Y = [0, 1, 1, 0]
combinedCurve = zip(curve_X, curve_Y)
draw.line((combinedCurve), fill=(220, 255, 250))
iterations = 5
# Start the loop
for i in range(0, iterations):
# Make 4 copies of the curve
copy1_X = list(curve_X)
copy1_Y = list(curve_Y)
copy2_X = list(curve_X)
copy2_Y = list(curve_Y)
copy3_X = list(curve_X)
copy3_Y = list(curve_Y)
copy4_X = list(curve_X)
copy4_Y = list(curve_Y)
# For copy 1, rotate it by 90 degree clockwise
# Then move it to the bottom left
# For copy 2, move it to the top left
# For copy 3, move it to the top right
# For copy 4, rotate it by 90 degrees anticlockwise
# Then move it to the bottom right
# Finally, combine all the copies into a big list
combinedCurve_X = copy1_X + copy2_X + copy3_X + copy4_X
combinedCurve_Y = copy1_Y + copy2_Y + copy3_Y + copy4_Y
# Make the initial curve equal to the combined one
curve_X = combinedCurve_X[:]
curve_Y = combinedCurve_Y[:]
# Repeat the loop
# Scale it to fit the canvas
curve_X = [x * xSize for x in curve_X]
curve_Y = [y * ySize for y in curve_Y]
# Draw it with something that connects the dots
curveCoordinates = zip(curve_X, curve_Y)
draw.line((curveCoordinates), fill=(255, 255, 255))
img2=img.rotate(180)
img2.show()
Here is a solution working on matrices (which makes sense for this type of calculations, and in the end, 2D coordinates are matrices with 1 column!),
Scaling is pretty easy, just have to multiply each element of the matrix by the scale factor:
scaled = copy.deepcopy(original)
for i in range(len(scaled[0])):
scaled[0][i]=scaled[0][i]*scaleFactor
scaled[1][i]=scaled[1][i]*scaleFactor
Moving is pretty easy to, all you have to do is to add the offset to each element of the matrix, here's a method using matrix multiplication:
import numpy as np
# Matrix multiplication
def mult(matrix1,matrix2):
# Matrix multiplication
if len(matrix1[0]) != len(matrix2):
# Check matrix dimensions
print 'Matrices must be m*n and n*p to multiply!'
else:
# Multiply if correct dimensions
new_matrix = np.zeros(len(matrix1),len(matrix2[0]))
for i in range(len(matrix1)):
for j in range(len(matrix2[0])):
for k in range(len(matrix2)):
new_matrix[i][j] += matrix1[i][k]*matrix2[k][j]
return new_matrix
Then create your translation matrix
import numpy as np
TranMatrix = np.zeros((3,3))
TranMatrix[0][0]=1
TranMatrix[0][2]=Tx
TranMatrix[1][1]=1
TranMatrix[1][2]=Ty
TranMatrix[2][2]=1
translated=mult(TranMatrix, original)
And finally, rotation is a tiny bit trickier (do you know your angle of rotation?):
import numpy as np
RotMatrix = np.zeros((3,3))
RotMatrix[0][0]=cos(Theta)
RotMatrix[0][1]=-1*sin(Theta)
RotMatrix[1][0]=sin(Theta)
RotMatrix[1][1]=cos(Theta)
RotMatrix[2][2]=1
rotated=mult(RotMatrix, original)
Some further reading on what I've done:
http://en.wikipedia.org/wiki/Transformation_matrix#Affine_transformations
http://en.wikipedia.org/wiki/Homogeneous_coordinates
http://www.essentialmath.com/tutorial.htm (concerning all the algebra transformations)
So basically, it should work if you insert those operations inside your code, multiplying your vectors by the rotation / translation matrices
EDIT
I just found this Python library that seems to provide all type of transformations: http://toblerity.org/shapely/index.html

Shape recognition with numpy/scipy (perhaps watershed)

My goal is to trace drawings that have a lot of separate shapes in them and to split these shapes into individual images. It is black on white. I'm quite new to numpy,opencv&co - but here is my current thought:
scan for black pixels
black pixel found -> watershed
find watershed boundary (as polygon path)
continue searching, but ignore points within the already found boundaries
I'm not very good at these kind of things, is there a better way?
First I tried to find the rectangular bounding box of the watershed results (this is more or less a collage of examples):
from numpy import *
import numpy as np
from scipy import ndimage
np.set_printoptions(threshold=np.nan)
a = np.zeros((512, 512)).astype(np.uint8) #unsigned integer type needed by watershed
y, x = np.ogrid[0:512, 0:512]
m1 = ((y-200)**2 + (x-100)**2 < 30**2)
m2 = ((y-350)**2 + (x-400)**2 < 20**2)
m3 = ((y-260)**2 + (x-200)**2 < 20**2)
a[m1+m2+m3]=1
markers = np.zeros_like(a).astype(int16)
markers[0, 0] = 1
markers[200, 100] = 2
markers[350, 400] = 3
markers[260, 200] = 4
res = ndimage.watershed_ift(a.astype(uint8), markers)
unique(res)
B = argwhere(res.astype(uint8))
(ystart, xstart), (ystop, xstop) = B.min(0), B.max(0) + 1
tr = a[ystart:ystop, xstart:xstop]
print tr
Somehow, when I use the original array (a) then argwhere seems to work, but after the watershed (res) it just outputs the complete array again.
The next step could be to find the polygon path around the shape, but the bounding box would be great for now!
Please help!
#Hooked has already answered most of your question, but I was in the middle of writing this up when he answered, so I'll post it in the hopes that it's still useful...
You're trying to jump through a few too many hoops. You don't need watershed_ift.
You use scipy.ndimage.label to differentiate separate objects in a boolean array and scipy.ndimage.find_objects to find the bounding box of each object.
Let's break things down a bit.
import numpy as np
from scipy import ndimage
import matplotlib.pyplot as plt
def draw_circle(grid, x0, y0, radius):
ny, nx = grid.shape
y, x = np.ogrid[:ny, :nx]
dist = np.hypot(x - x0, y - y0)
grid[dist < radius] = True
return grid
# Generate 3 circles...
a = np.zeros((512, 512), dtype=np.bool)
draw_circle(a, 100, 200, 30)
draw_circle(a, 400, 350, 20)
draw_circle(a, 200, 260, 20)
# Label the objects in the array.
labels, numobjects = ndimage.label(a)
# Now find their bounding boxes (This will be a tuple of slice objects)
# You can use each one to directly index your data.
# E.g. a[slices[0]] gives you the original data within the bounding box of the
# first object.
slices = ndimage.find_objects(labels)
#-- Plotting... -------------------------------------
fig, ax = plt.subplots()
ax.imshow(a)
ax.set_title('Original Data')
fig, ax = plt.subplots()
ax.imshow(labels)
ax.set_title('Labeled objects')
fig, axes = plt.subplots(ncols=numobjects)
for ax, sli in zip(axes.flat, slices):
ax.imshow(labels[sli], vmin=0, vmax=numobjects)
tpl = 'BBox:\nymin:{0.start}, ymax:{0.stop}\nxmin:{1.start}, xmax:{1.stop}'
ax.set_title(tpl.format(*sli))
fig.suptitle('Individual Objects')
plt.show()
Hopefully that makes it a bit clearer how to find the bounding boxes of the objects.
Use the ndimage library from scipy. The function label places a unique tag on each block of pixels that are within a threshold. This identifies the unique clusters (shapes). Starting with your definition of a:
from scipy import ndimage
image_threshold = .5
label_array, n_features = ndimage.label(a>image_threshold)
# Plot the resulting shapes
import pylab as plt
plt.subplot(121)
plt.imshow(a)
plt.subplot(122)
plt.imshow(label_array)
plt.show()

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