I'm currently having some issues removing a file in python. I am creating a temporary file for pdf to image conversion. It is housed in a folder that holds a .ppm file and converts it to a .jpg file. It then deletes the temporary .ppm file. Here is the code:
import pdf2image
from PIL import Image
import os
images = pdf2image.convert_from_path('Path to pdf.pdf', output_folder='./folder name')
file = ''
for files in os.listdir('./folder name'):
if files.endswith(".ppm"):
file = files
path = os.path.join('folder name',file)
im = Image.open(path)
im.save("Path to image.jpg")
im.close()
os.remove(path)
The issue is at the end in the os.remove(path). I get the following error:
PermissionError: [WinError 32] The process cannot access the file because it is being used by another process: 'path to ppm file'
I would appreciate any help and thanks in advance.
Not really the answer to your question, but you can just output in the correct format at the start, and avoid the issue in the first place:
pdf2image.convert_from_path('Path to pdf.pdf', output_folder='./folder name', fmt='jpg')
To actually answer your question, I'm not sure why you're having the issue, because really the close() should prevent this problem. Perhaps check out this answer and try using a with statement? Or maybe the permissions release is just delayed, I'm curious what throwing that remove in a loop for as long as it throws an exception would do.
Edit: To set the name, you'll want to do something like:
images = pdf2image.convert_from_path('Path to pdf.pdf', output_folder='./folder name', fmt='jpg')
for image in images:
# Save the image
The pdf2image documentation looks like it recommends using a temporary folder, like in this example, and then you can just .save(...) the PIL image:
import tempfile
with tempfile.TemporaryDirectory() as path:
images_from_path = convert_from_path('/home/kankroc/example.pdf', output_folder=path)
# Do something here
Edit: I realized that the reason it was in use is probably because you need to close() all the images in images. You should read up on the pdf2image documentation and about the PIL images that it spits out for more details.
Related
Recently, I have been working on one of my python3 programs and then I wanted to to open a picture. Here is the code that I used to do it:
from PIL import Image
r = Image.open('C:/Users/sudam/OneDrive/Desktop/programming/python/projects/good night app/morning.png' )
r.show()
But as soon as I run this code,the windows photo viewer opens and gives and error saying that the specified file was moved. I tried googling this question but all of the answers I got only worked for python2, but not for python3.
Because you have whitespace in your path you need to use the r"string" format.
Also you need to use:
PIL.ImageShow.show(r)
to show your image.
It's also recommended to check if the file exist before opening any file.
You can do like this:
from pathlib import Path
from PIL import Image, ImageShow
path =r"C:/Users/sudam/OneDrive/Desktop/programming/python/projects/good night app/morning.png"
if Path(path).is_file():
r = Image.open(path)
ImageShow.show(r)
else:
print(f'{path} not exist')
I need to convert .ps files to .png files as part of an image recognition program I am making. I know I can use Ghostscript or other programs, but could someone give a specific example of how to write something like this:
def ps_to_png(ps_file):
file = ghostscript.read(ps_file)
png_file = ghostscript.save(file, "png")
return png_file
(This code is pseudo code- I want to know how to write something that actually does what this code looks like it will do.)
Thanks in advance! Stack is a great community and I appreciate it.
EDIT (Attempted solutions): When running this line:
os.system("ghostscript file.ps file.png")
I get the following Error:
'ghostscript' is not recognized as an internal or external command, operable program or batch file.
When attempting to use Pillow:
from PIL import Image
def convert_to_png(ps_file):
img = Image.open(ps_file)
img.save("img.png")
I get the following error:
OSError: Unable to locate Ghostscript on paths
You can use Pillow.
from PIL import Image
psimage=Image.open('myImage.ps')
psimage.save('myImage.png')
If you want to wrap it to a function:
from PIL import Image
def convert_to_png(path):
img = Image.open(path)
img.save("img.png")
path='/path_to_your_file'
convert_to_png(path)
Honest warning—I'm a total beginner.
I'm using Python 3.8.2 in IDLE and sometimes in Spyder.
My goal: to open an image (located in a folder) in Preview using Pillow
My code:
from PIL import Image
my_image = Image.open("flower.jpg")
my_image.show(r"/Users/User/Desktop/flower.jpg")
I run this, and it works! But it only works if the jpg is on the Desktop. I want to put the image in a folder. So I changed my last line of code to something like this:
my_image.show(r"/Users/User/Desktop/folder/flower.jpg")
I put the image in the folder, run the program, and get this error:
**FileNotFoundError: [Errno 2] No such file or directory: 'flower.jpg'**
Oddly, if I put the jpg back onto the Desktop and still use the path with "folder" in it, the program runs successfully and shows me the image.
Is this a problem with the path? How can I use Image.show() to open an image that is located somewhere other than the Desktop?
Thank you!
If you want to open and view an image using an absolute path, you'll have to change this line:
my_image = Image.open(path_to_image_dir)
You've incorrectly passed a string to PIL.Image.show. This doesn't throw an error, since PIL.Image.show happens to take an optional string parameter title, which it will use as a title in the image window. Don't pass any parameters to show, and change "flower.jpg" in the line above to the actual path.
I've downloaded a bunch of .krn files, and I'd like to convert them into images - either pngs or jpgs - using music21. I've tried this:
When I do this:
from music21 import *
op = krnfile
s = converter.parse(op)
s.show()
I see a great image file in the Jupyter Notebook I'm using, but when I try to save that file programatically like this:
s.write(fp = 'outputfile.png', fmt = 'png')
It says:
Music21ObjectException: cannot support showing in this format yet: png
Which seems a little weird since it obviously manages to make an image for display in the notebook.
It looks like maybe I could use LilypondConverter.createPNG(fileName=None) from this, but is installing Lilypond required? I already have MuseScore2 installed, which opens when I call s.show().
Thanks a lot!
Alex
Install musescore on your computer, re-run python -m music21.configure to help it find it and then do:
from music21 import *
op = 'krnfile.krn'
s = converter.parse(op)
fp = s.write('musicxml.png')
# or just s.show('musicxml.png') to test that it works.
If it's a multi-page file, fp will be the path to the first page. It will end in -1 or -01 or -001 etc. You can read through the directory to find other files with the same name until there are no more to get all the images.
If you use n.show('lily.png'), it should create a temporary png file somewhere. Try to use it and an image may open.
Sorry i don't know much yet, I hope it helps.
I've looked around and read the docs, and found no way or solution, so I ask here. Is there any packages available to use Python to convert a JPG image to a PNG image?
You could always use the Python Image Library (PIL) for this purpose. There might be other packages/libraries too, but I've used this before to convert between formats.
This works with Python 2.7 under Windows (Python Imaging Library 1.1.7 for Python 2.7), I'm using it with 2.7.1 and 2.7.2
from PIL import Image
im = Image.open('Foto.jpg')
im.save('Foto.png')
Note your original question didn't mention the version of Python or the OS you are using. That may make a difference of course :)
Python Image Library: http://www.pythonware.com/products/pil/
From: http://effbot.org/imagingbook/image.htm
import Image
im = Image.open("file.png")
im.save("file.jpg", "JPEG")
save
im.save(outfile, options...)
im.save(outfile, format, options...)
Saves the image under the given filename. If format is omitted, the
format is determined from the filename extension, if possible. This
method returns None.
Keyword options can be used to provide additional instructions to the
writer. If a writer doesn't recognise an option, it is silently
ignored. The available options are described later in this handbook.
You can use a file object instead of a filename. In this case, you
must always specify the format. The file object must implement the
seek, tell, and write methods, and be opened in binary mode.
If the save fails, for some reason, the method will raise an exception
(usually an IOError exception). If this happens, the method may have
created the file, and may have written data to it. It's up to your
application to remove incomplete files, if necessary.
As I searched for a quick converter of files in a single directory, I wanted to share this short snippet that converts any file in the current directory into .png or whatever target you specify.
from PIL import Image
from os import listdir
from os.path import splitext
target_directory = '.'
target = '.png'
for file in listdir(target_directory):
filename, extension = splitext(file)
try:
if extension not in ['.py', target]:
im = Image.open(filename + extension)
im.save(filename + target)
except OSError:
print('Cannot convert %s' % file)
from glob import glob
import cv2
pngs = glob('./*.png')
for j in pngs:
img = cv2.imread(j)
cv2.imwrite(j[:-3] + 'jpg', img)
this url: https://gist.github.com/qingswu/1a58c9d66dfc0a6aaac45528bbe01b82
import cv2
image =cv2.imread("test_image.jpg", 1)
cv2.imwrite("test_image.png", image)
I don't use python myself, but try looking into:
http://www.pythonware.com/products/pil/
import Image
im = Image.open("infile.png")
im.save("outfile.jpg")
(taken from http://mail.python.org/pipermail/python-list/2001-April/700256.html )