I'm tring to create an app with flask with WTForms.
In the controller.py i have:
#mod_private.route('/portfolio/', methods=['GET', 'POST'])
#login_required
def portfolio():
print "in portfolio" # I read this
form = CreateCoinsForm(request.form)
if request.method == 'POST' and form.validate_on_submit():
print form.coins.data #I cannot take this value
return render_template("private/portfolio.html",form=form)
return render_template("private/portfolio.html",form=form)
in the forms.py:
class CreateCoinsForm(Form):
coins = IntegerField('coins',
[DataRequired('num required'),
NumberRange(min=0, max=10)])
and the template
<form method="post" action="/private/portfolio/" accept-charset="UTF-8" role="form">
<p> {{ form.coins }}</p>
<p><input type=submit value=Generate>
</form>
my problem, as i wrote in the code is that I cannot retrieve the string inserted in the template.
Your problem suggests that you are using the built-in CSRF protection on your form, and your form actually isn't validating because you haven't included the CSRF token.
Try adjusting your template like so:
<form method="post" action="/private/portfolio/" accept-charset="UTF-8" role="form">
{{ form.hidden_tag() }}
<p> {{ form.coins }}</p>
<p><input type=submit value=Generate>
</form>
Related
Hi im trying to pass a name from a form to a view in django using POST. There are no errors in the execution but its passing nothing from the template and dont know if i doing something wrong here. Im starting with django so i can have newbie errors. If u need more information tell me pls.
Views.py
def crear_pdf(request):
empresa_selec = ""
form = EmpModelForm()
if request.method == 'POST':
form = EmpModelForm(data=request.POST)
if form.is_valid():
empresa_selec = form.cleaned_data['nombre']
#"empresa_selec" that's the empty variable
Models.py
class Empresa_modelo(models.Model):
nombre = models.CharField(max_length=100,blank=True,null=True)
Forms.py
class EmpModelForm(forms.ModelForm):
class Meta:
model = Empresa_modelo
fields = ["nombre"]
template.html
<div class="container-fluid">
<form method="POST" enctype="multipart/form-data" action="{% url 'crear_pdf' %}">{% csrf_token %}
<p>Empresa</p>
<input type="text" name="empresa">
<br>
<button type="submit">Subir</button>
</form>
<br>
<a class="btn btn-primary" href="{% url 'crear_pdf' %}">Atras</a>
</div>
You haven't got a field called nombre in your template; you only have empresa.
That's presumably because you don't ouput your EmpModelForm in the template. You don't show your render call in the view, but assuming you pass it as form, you should just do {{ form.as_p }} in the template.
Try using:
<input type="text" name="nombre">
There is no field named empresa.
Had a look at your code,there are a couple of issues.First you are not using the model form defined in your forms.py file in your template. Second you have defined an input text box with the name that you are not referring in your views. Either use the model form or use the same name of your input text box in your views.
def crear_pdf(request):
empresa_selec = ""
form = EmpModelForm()
if request.method == 'POST':
form = EmpModelForm(data=request.POST)
if form.is_valid():
empresa_selec = form.cleaned_data['nombre']
else:
return render(request,"template.html",{"form":form})
And in your template you can edit as such:
<div class="container-fluid">
<form method="POST" enctype="multipart/form-data" action="{% url 'crear_pdf' %}">{% csrf_token %}
{{ form.as_p }}
<br>
<button type="submit">Subir</button>
</form>
<br>
<a class="btn btn-primary" href="{% url 'crear_pdf' %}">Atras</a>
</div>
Hope this helps.
I'm trying to show a confirmation/success message to the user in my Flask app, but I can't figure out how to display it in a modal.
#app.route("/", methods=["POST"]
def sendForm():
form = ContactForm(request.form)
if request.method == 'POST':
if form.validate():
# do stuff with form data
return render_template("contact.html", form=form)
else:
# display error message
else:
return render_template("index.html")
The part where I return the contact.html template is where I need help, I think. Because that page is basically refreshed and shown again after the POST request successfully completes. Need to display a confirm message to the user in a modal instead.
On the front-end, my form is looks like this:
<form method="POST" action="{{ url_for('sendForm') }}">
<input type="hidden" name="csrf_token" value="{{ csrf_token() }}" />
{{ render_field(form.email) }}
{{ render_field(form.name) }}
<input id="submit-form" type="submit" value="Send">
</form>
I would do some form of this...
Pass a boolean in your render_template:
submission_successful = True #or False. you can determine this.
render_template("contact.html", form=form, submission_successful=submission_successful))
Then in your template place an if statement
{% if submission_successful %}
// modal elements here
{% endif %}
I'm getting this error when submit:
CSRF verification failed. Request aborted.
I've got this far following the documentation, but I don't fully understand it and it's definitely wrong. I just want to take a query word from my search box(form) and pass it to a python script as an argument. I'm new to Django and getting stuck on the easiest things.
In models.py:
class QueryForm(forms.Form):
query = forms.CharField(label='query',max_length=100)
I added this line to my urls.py
url(r'^results/$', 'tweemo.views.results'),
On my homepage where my search box is I have this code for my form:
<form action="/home/results/" method="post">
<label for="query">Search:</label>
<input id="query" type="text" name="query" value="{{ current_query }}">
<input type="submit" value="ok">
</form>
In views.py I added these two functions:
def get_query(request):
if request.method == 'POST':
form = QueryForm(request.POST)
if form.isvalid():
return HttpResponseRedirect('/thanks/')
else:
form = QueryForm()
return render(request, 'results.html', {'form': form})
def results(request):
return render_to_response('results.html',{'here':TwitterStream.objects.all() })
MY results.html contains just this:
<form action="/home/results/" method="post">
{% csrf_token %}
{{ form }}
<input type="submit" value="Submit"/>
</form>
You must just add the {% csrf_token %} tag inside EVERY <form></form> tag which has method to be post in your template.
So the below markup should be corrected:
<form action="/home/results/" method="post">
{% csrf_token %}
<label for="query">Search:</label>
<input id="query" type="text" name="query" value="{{ current_query }}">
<input type="submit" value="ok">
</form>
Well the problem is that you are not passing the csrf token to the form , you need to pass the csrf token to the render function in order for it to be applied in the form . To accomplish this you need to associate the csrf token to the request.
def get_query(request):
if request.method == 'POST':
form = QueryForm(request.POST)
if form.isvalid():
return HttpResponseRedirect('/thanks/')
else:
form = QueryForm()
args = {}
args.update(csrf(request))
args['form'] = form
return render_to_response('results.html', args)
def results(request):
return render_to_response('results.html',{'here':TwitterStream.objects.all() })
I am working with Django forms and for some reason, this form will not validate! It submits alright, or at least the runserver shows an http post response with code 200 (ok). For some reason though, my form will not pass the is_valid test!
views.py:
def new_show(request):
if request.method == 'POST':
img_form = ImageForm(request.POST, request.FILES)
show_form = NewShowForm(request.POST)
if show_form.is_valid():
new_Show = Show()
new_Show.title=show_form.cleaned_data['title']
new_Show.body=show_form.cleaned_data['body']
new_Show.pub_date=timezone.now()
new_Show.location=show_form.cleaned_data['location']
new_Show.time=show_form.cleaned_data['time']
new_Show.save()
if img_form.is_valid():
image=Image(image=request.FILES['imageFile'])
new_Show.image_set.add(image)
return HttpResponseRedirect(reverse('shows'))
else:
return HttpResponseRedirect(reverse('shows'))
else:
show_form = NewShowForm()
img_form = ImageForm()
return render_to_response(
'shows/new_show.html',
{'show_form': show_form, 'img_form': img_form},
context_instance=RequestContext(request)
)
Here is my template snippet:
<form action="{% url "new_show" %}" method="post" enctype="multipart/form-data">
{% csrf_token %}
<p>{{ show_form.non_field_errors }}</p>
<p>
<label for="title">Title:</label>
<input type="text" name="title"/>
</p>
<p>
<label for="body">Body:</label>
<textarea type="text" name="body"> </textarea>
</p>
<p>
<label for="location">Location:</label>
<input type="text" name="location"/>
</p>
<p>
<label for="time">Date:</label>
<input type="text" id="time" maxlength="25" size="25" name="time"><img src="{{ STATIC_URL }}../../static/cal.gif" width="16" height="16" border="0" alt="Pick a date">
</p>
<!-- Upload Form. Note enctype attribute! -->
{% csrf_token %}
<p>{{ img_form.non_field_errors }}</p>
<p>{{ img_form.imageFile.label_tag }}</p>
<p>
{{ img_form.imageFile.errors }}
{{ img_form.imageFile }}
</p>
<p><input type="submit" value="Add Upcoming Show"></input></p>
</form>
Here is my form Class:
class NewShowForm(forms.Form):
title=forms.CharField()
body=forms.CharField(widget=forms.TextArea)
location=forms.CharField()
time=forms.DateTimeField(required=True)
class ImageForm(forms.Form):
imageFile = forms.FileField(required=False, label='Select an Image')
Please help me!
If new_Show is a model, why not create a ModelForm instead of forms.Form?
So, instead of
class NewShowForm(forms.Form):
title=forms.CharField()
body=forms.CharField(widget=forms.TextArea)
location=forms.CharField()
time=forms.DateTimeField(required=True)
class ImageForm(forms.Form):
imageFile = forms.FileField(required=False, label='Select an Image')
why not using,
from django.forms import ModelForm
class NewShowForm(ModelForm):
class Meta:
model = NewShow
class ImageForm(ModelForm):
class Meta:
model = Image
?
Using ModelForm will ensure that form validation meets that of model. Moreover, it can cut off your code (especially line 6 to 11).
It will help to add these two lines to your view before if is_valid() to see the errors it's giving:
if request.method == 'POST':
img_form = ImageForm(request.POST, request.FILES)
show_form = NewShowForm(request.POST)
print(form.is_valid())
print(form.errors)
if show_form.is_valid():
You can paste the errors here and we can see what's the issue
Since you've put 2 Django forms together under one HTML form tag, when you submit the form on the front-end you're sending an extra field through request.POST that your NewShowForm doesn't have. If you combine both forms into a single Django form, you should be able to get this to work.
I have looked all over stackoverflow and the Internet about this so I will just show my code.
views.py
def UserSell(request,username):
theuser=User.objects.get(username=username)
thegigform=GigForm()
#if the user is submitting a form
if request.method=='POST':
#bind form with form inputs and image
gigform=GigForm(request.POST,request.FILES)
if gigform.is_valid():
gigform.title=gigform.cleaned_data['title']
gigform.description=gigform.cleaned_data['description']
gigform.more_info=gigform.cleaned_data['more_info']
gigform.time_for_completion=gigform.cleaned_data['time_for_completion']
gigform.gig_image=gigform.cleaned_data['gig_image']
finalgigform=gigform.save(commit=False)
finalgigform.from_user=theuser
finalgigform.save()
return HttpResponseRedirect('done')
thegigform=GigForm()
context=RequestContext(request)
return render_to_response('sell.html',{'theuser':theuser,'thegigform':thegigform},context_instance=context)
template
<form action="{% url sell user.username %}" method="post" enctype="multipart/form-data">
{% csrf_token %}
<fieldset>
<legend><h2>Sell A Gig</h2></legend>
{% for f in thegigform %}
<div class="formWrapper">
{{f.errors}}
{{f.label_tag}}: {{f}}
{{f.help_text}}
</div>
{% endfor %}
</fieldset>
<input type="submit" value="Sell Now!" />
This code seems to follow normal django form protocol so please tell me why my django template doesnt show the errors. Thanks
It looks like you are missing an else block.
if gigform.valid() returns false, you are overwriting the variable "thegigform". Try restructuring your code like this:
if request.method=='POST':
#bind form with form inputs and image
thegigform=GigForm(request.POST,request.FILES)
if thegigform.is_valid():
thegigform.title=gigform.cleaned_data['title']
thegigform.description=gigform.cleaned_data['description']
thegigform.more_info=gigform.cleaned_data['more_info']
thegigform.time_for_completion=gigform.cleaned_data['time_for_completion']
thegigform.gig_image=gigform.cleaned_data['gig_image']
finalgigform=gigform.save(commit=False)
finalgigform.from_user=theuser
finalgigform.save()
return HttpResponseRedirect('done')
else:
thegigform=GigForm()
context=RequestContext(request)
return render_to_response('sell.html',{'theuser':theuser,'thegigform':thegigform},context_instance=context)