How to reinitialize console when clicking the close button? - python

I am building a simple GUI for selecting files using PYQT, and I am working with the Spyder IDE. When I try to close the GUI with the red "X" button and run the file again, a warning message pops up that says:
No Python shell is currently selected to run **readFile.py**
Please select or open a new Python interpreter and try again
How can I make the red X button reinitialize the interpreter and console without having to manually do it every time? Here is my code:
from PyQt4 import QtGui
class Example(QtGui.QWidget):
def __init__(self):
super(Example, self).__init__()
self.initUI()
def initUI(self):
vbox = QtGui.QVBoxLayout()
lbl = QtGui.QLabel('Please Choose Excel File',self)
openButton = QtGui.QPushButton('Choose File')
openButton.clicked.connect(self.showDialog)
vbox.addWidget(lbl)
vbox.addWidget(openButton)
self.setLayout(vbox)
self.setGeometry(300,300,350,300)
self.setWindowTitle('file Dialog')
self.show()
def showDialog(self):
fname = QtGui.QFileDialog.getOpenFileName(self, 'Open file', '/home')
print(fname)
def main():
app = QtGui.QApplication(sys.argv)
ex = Example()
sys.exit(app.exec_())
if __name__ == '__main__':
main()

Related

QApplication.clipboard().dataChanged not work in background

I am trying to write a dictionary program that can auto search the word when I copy some words into the clipboard.
I need the program to detect the clipboard change and search in the background.(menubar app)
but my program only updates when I click it.
(for example no use in Mac OS fullscreen mode)
is there any way to lettuce program work even when it is in the background?
mac os catalina , PYQT5
I use QApplication.clipboard().dataChanged.connect() to detect the clipboard change
class MyMainWindow(QMainWindow,Ui_MainWindow):
def __init__(self, parent=None):
super(MyMainWindow, self).__init__(parent)
self.setupUi(self)
QApplication.clipboard().dataChanged.connect(self.clipboardChange)
def clipboardChange(self):
print(QApplication.clipboard().text())
self.raise_()
in main file:
if __name__ == "__main__":
app = QApplication(sys.argv)
#app.setQuitOnLastWindowClosed(False)
icon = QIcon("dic.png")
tray = QSystemTrayIcon()
tray.setIcon(icon)
tray.setVisible(True)
#menu = QMenu()
action = QAction("A menu item")
#menu.addAction(action)
#tray.setContextMenu(menu)
myWin = MyMainWindow()
myWin.show()
sys.exit(app.exec_())
the program only update when I click it

Trying to copy text from other threads using a button

I am trying to figure out a way to make a decent copy to clipboard button function where I can copy text values from other threads inside a QTextEdit widget.
I pull the values from other threads and display them in a QTextEdit widget and have been trying to successfully copy to clipboard the contents of QTextEdit with a button but the only way I have been able to is my code below.
What I don't like is that the copy button makes a second call in order to copy the contents.
Is there some way that the values can be stored from the first request using the get_button button and be available to copy with the copy button without having to make the same call all over again? Thanks.
from PyQt4 import QtCore, QtGui
import sys
class WorkerThread(QtCore.QThread):
get_String = QtCore.pyqtSignal(str)
def __init__(self):
super(WorkerThread, self).__init__()
def run(self):
self.get_String.emit('Some text.')
class GUI(QtGui.QWidget):
def __init__(self):
super(GUI, self).__init__()
self.get_Button = QtGui.QPushButton('Get')
self.c_Button = QtGui.QPushButton('Copy')
self.text_Box = QtGui.QTextEdit(self)
vbox = QtGui.QVBoxLayout(self)
vbox.addWidget(self.get_Button)
vbox.addWidget(self.c_Button)
vbox.addWidget(self.text_Box)
vbox.addStretch()
self.setGeometry(300, 300, 300, 300)
self.show()
self._thread = WorkerThread()
self.get_Button.clicked.connect(self.doIt)
self._thread.get_String.connect(self.text_Box.append)
self.c_Button.clicked.connect(self.copy_Stuff)
def copy_Stuff(self):
self.clipboard = QtGui.QApplication.clipboard()
self._thread.get_String.connect(self.clipboard.setText)
self._thread.start()
def doIt(self):
self.text_Box.clear()
self.text_Box.setText('')
self._thread.start()
def main():
app = QtGui.QApplication(sys.argv)
gui = GUI()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
It turns out this was much easier than I initially thought. I was confused with how to copy text correctly because of all of the different ways I seen it done in other examples and posts. After reading the docs for awhile and trying to learn a bit more about pyqt I seen that it was as easy as using these 2 lines...
self.text_Box.selectAll()
self.text_Box.copy()
with those 2 lines and my button it seems to copy all the contents of the QTextEdit widget which is all I really needed. Here is my final working code in case someone else may find it useful.
from PyQt4 import QtCore, QtGui
import sys
class WorkerThread(QtCore.QThread):
get_String = QtCore.pyqtSignal(str)
def __init__(self):
super(WorkerThread, self).__init__()
def run(self):
self.get_String.emit('Some text.')
class GUI(QtGui.QWidget):
def __init__(self):
super(GUI, self).__init__()
self.get_Button = QtGui.QPushButton('Get')
self.c_Button = QtGui.QPushButton('Copy')
self.text_Box = QtGui.QTextEdit(self)
vbox = QtGui.QVBoxLayout(self)
vbox.addWidget(self.get_Button)
vbox.addWidget(self.c_Button)
vbox.addWidget(self.text_Box)
vbox.addStretch()
self.setGeometry(300, 300, 300, 300)
self.show()
self._thread = WorkerThread()
self.get_Button.clicked.connect(self.doIt)
self._thread.get_String.connect(self.text_Box.append)
self.c_Button.clicked.connect(self.copy_Stuff)
def copy_Stuff(self):
self.text_Box.selectAll()
self.text_Box.copy()
def doIt(self):
self.text_Box.clear()
self.text_Box.setText('')
self._thread.start()
def main():
app = QtGui.QApplication(sys.argv)
gui = GUI()
sys.exit(app.exec_())
if __name__ == '__main__':
main()
This code example shows a simple working thread with signal that returns a value to the main, displays the value in a QTextEdit widget and how to copy all of the contents of a QTextEdit widget with a single button click.

Right clicking on files and openning with PyQt application

I am using the code below for opening and reading text files in pyqt.
But what I want is:
I will choose any text file on my hard disk. Then right click on it and choose open with and browse for my pyqt script and the file will be open
with my sript.
I know that I can do it using 'sys.argv' in terminal. But how to do it with gui program? Please let me know.
Current code:
import sys
from PyQt4 import QtGui
from PyQt4 import QtCore
class OpenFile(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QMainWindow.__init__(self)
self.setGeometry(300, 300, 350, 300)
self.setWindowTitle('OpenFile')
self.textEdit = QtGui.QTextEdit()
self.setCentralWidget(self.textEdit)
self.statusBar()
self.setFocus()
exit = QtGui.QAction(QtGui.QIcon('open.png'), 'Open', self)
exit.setShortcut('Ctrl+O')
exit.setStatusTip('Open new File')
self.connect(exit, QtCore.SIGNAL('triggered()'), self.showDialog)
menubar = self.menuBar()
file = menubar.addMenu('&File')
file.addAction(exit)
def showDialog(self):
filename = QtGui.QFileDialog.getOpenFileName(self, 'Open file',
'/home')
file=open(filename)
data = file.read()
self.textEdit.setText(data)
app = QtGui.QApplication(sys.argv)
cd = OpenFile()
cd.show()
app.exec_()

How to open a window with a click of a button from another window using PyQt?

I'm trying to make an application but I keep getting punched by the "simple" things like this one, how do I open a new window though a button click? I tried using new_lib_btn.clicked.connect(newlib), newlib is the file that contains my second window and new_lib_btn is the button that should open the window, it's in my main window as you can see down here:
mainwindow.py
from PyQt4 import QtCore, QtGui
import newlib
import sys
# Main Window
class Window (QtGui.QMainWindow):
def __init__(self):
super(Window, self).__init__()
centralwidget = QtGui.QWidget(self)
self.mainLayout = QtGui.QVBoxLayout(centralwidget)
self.mainLayout.setAlignment(QtCore.Qt.AlignCenter)
self.setCentralWidget(centralwidget)
self.resize(800, 600)
self.setWindowTitle("Virtual Library")
self.setStyleSheet("Window {border-image: url(lib.jpg);}")
# ExitOption
menu_action1 = QtGui.QAction("Exit", self)
menu_action1.setShortcut("Ctrl+Q")
menu_action1.setStatusTip('Exit The App')
menu_action1.triggered.connect(self.close_application)
self.statusBar()
# MenuBar
main_menu = self.menuBar()
file_menu = main_menu.addMenu('Options')
file_menu.addAction(menu_action1)
self.home()
def home(self):
# NewLibrary btn
new_lib_btn = QtGui.QPushButton("New Library", self)
new_lib_btn.setGeometry(QtCore.QRect(310, 180, 141, 41))
new_lib_btn.setStyleSheet("color: black;")
# AccessLibrary btn
access_lib_btn = QtGui.QPushButton("Access Library", self)
access_lib_btn.setGeometry(QtCore.QRect(310, 250, 141, 41))
access_lib_btn.setStyleSheet("color: black;")
# FindNewBooks btn
find_nbooks = QtGui.QPushButton("Find New Books*", self)
find_nbooks.setGeometry(QtCore.QRect(310, 320, 141, 41))
find_nbooks.setStyleSheet("color: black;")
self.mainLayout.addWidget(new_lib_btn)
self.mainLayout.addWidget(access_lib_btn)
self.mainLayout.addWidget(find_nbooks_btn)
self.show()
def close_application(self):
choice = QtGui.QMessageBox.question(self, 'Exit',
"Close the application?",
QtGui.QMessageBox.Yes | QtGui.QMessageBox.No)
if choice == QtGui.QMessageBox.Yes:
sys.exit()
else:
pass
def run():
app = QtGui.QApplication(sys.argv)
GUI = Window()
sys.exit(app.exec_())
run()
And here's my second window, the one I want to open with the new_lib_btn
newlib.py
class NewLibrary (QtGui.QMainWindow):
def __init__(self):
super(NewLibrary, self).__init__()
self.resize(800,600)
self.setWindowTitle("New Library")
self.setStyleSheet("NewLibrary {border-image: url(wood.jpg);}")
# File Options
file_action1 = QtGui.QAction("New Library", self)
file_action1.setShortcut("Ctrl+N")
file_action1.setStatusTip("Creates a new library")
file_action2 = QtGui.QAction("Exit this!", self)
file_action2.setShortcut("Ctrl+Q")
file_action2.setStatusTip("Closes The App")
file_action2.triggered.connect(self.close_application)
#File Menu
main_menu = self.menuBar()
file_menu = main_menu.addMenu("File")
file_menu.addAction(file_action1)
file_menu.addAction(file_action2)
self.newLib()
self.newLib()
def newLib(self):
centralwidget = QtGui.QWidget(self)
self.mainLayout = QtGui.QVBoxLayout(centralwidget)
self.mainLayout.setAlignment(QtCore.Qt.AlignCenter)
#some useful buttons in the future
self.setCentralWidget(centralwidget)
self.show()
def close_application(self):
choice = QtGui.QMessageBox.question(self, 'Exit',
"Close the application?",
QtGui.QMessageBox.Yes | QtGui.QMessageBox.No)
if choice == QtGui.QMessageBox.Yes:
sys.exit()
else:
pass
def runNewLib():
app = QtGui.QApplication(sys.argv)
gui = NewLibrary()
sys.exit(app.exec_())
runNewLib()
I searched a lot about this but I couldn't understand the few ones that were somewhat close to my situation, so I'm asking for help, It seems so simple but I'm not getting it :/, what should I do to open the second window by clicking new_lib_btn? pls help.
I think there are several issues with the code that you've posted. First, there are two calls to self.newLib() in the NewLibrary constructor. Second, you probably want to put that call to runNewLib() at the bottom of newlib.py behind an if __name__... block, like so:
if __name__ == '__main__':
runNewLib()
Otherwise, every time you try to import newlib.py, it will attempt to run NewLibrary as a separate application.
Getting to the question you asked, I don't think you actually want to call self.show() in either Window.home() or NewLibrary.newLib(). A more typical pattern would be to create an instance of either Window or NewLibrary and then call show() on that instance. So, in your Window class, you'd add a function to create an instance of NewLibrary and then call show on it, like this
def create_new_library_window(self):
self.new_lib = newlib.NewLibrary()
self.new_lib.show()
Note that, as ekhumoro points out, you have to keep a reference to new_lib around, otherwise it will get garbage collected when the function exits. Then in NewLibrary.home() after you've created the new_lib_btn connect it to this new function:
new_lib_btn.clicked.connect(self.create_new_library_window)
Working example
This example creates a main window with one big button that, when clicked will open a second window. It uses two classes that inherit from QMainWindow, as in your question. First, in main.py:
from PyQt4 import QtGui
from new_window import NewWindow
class Window(QtGui.QMainWindow):
def __init__(self):
super(Window, self).__init__()
self._new_window = None
self._button = QtGui.QPushButton('New Window', self)
self._button.clicked.connect(self.create_new_window)
self.setCentralWidget(self._button)
def create_new_window(self):
self._new_window = NewWindow()
self._new_window.show()
if __name__ == '__main__':
app = QtGui.QApplication([])
gui = Window()
gui.show()
app.exec_()
The __init__ function creates a button and connects it to the create_new_window function. When the button is clicked, create_new_window will be called. Inside of create_new_window, we create an instance of NewWindow and assign it to a class member to maintain a reference to the window and prevent it from being garbage collected. We then call show on this new window to display it.
At the bottom, we use the usual if __name__ == '__main__': pattern to control whether this file runs the application or not. If this file is executed from the command line (like python main.py) __name__ == '__main__' evaluates to true and the GUI application will be started. This has the advantage of allowing the file to serve a dual purpose: it can be imported as a standard python package, or executed as an application, all using the same file.
Then in new_window.py:
from PyQt4 import QtGui
class NewWindow(QtGui.QMainWindow):
def __init__(self):
super(NewWindow, self).__init__()
self._new_window = None
self._label = QtGui.QLabel('Hello, is it me you\'re looking for?')
self.setCentralWidget(self._label)
if __name__ == '__main__':
app = QtGui.QApplication([])
gui = NewWindow()
gui.show()
app.exec_()
This file defines a second QMainWindow that uses a label as its central widget. It also uses the __name__ == '__main__' pattern; this file can also be executed as a standalone application or imported as in main.py above.

Python PyQt4 how to open image using QFileDialog

I have to write a program with an option to open an image from a file. I have to use QFileDialog and display image in QLabel, using QPixmap. I am able to use them individually but I didn't manage to combine them.
I think I need to take my image name from dlg.selectedFiles but I don't know how to choose the moment when there is useful data in it. Do I need to make a loop in my main program, and constantly check if there is image to open? Can I send a signal to my label using openAction.triggered.connect(...)?
from PyQt4 import QtGui
import sys
class MainWindow(QtGui.QMainWindow):
def __init__(self, parent = None):
super(MainWindow, self).__init__(parent)
menubar = self.menuBar()
fileMenu = menubar.addMenu('File')
dlg = QtGui.QFileDialog(self)
openAction = QtGui.QAction('Open', self)
openAction.triggered.connect(dlg.open)
fileMenu.addAction(openAction)
#label = QtGui.QLabel(self)
#pixmap = QtGui.QPixmap('')
#label.setPixmap(pixmap)
def main():
app = QtGui.QApplication(sys.argv)
win = MainWindow()
win.show()
app.exec_()
if __name__ == '__main__':
sys.exit(main())
You need to make your own slot and connect it to the openAction signal.
In your __init__ function do:
openAction.triggered.connect(self.openSlot)
In your class MainWindow define the following function:
def openSlot(self):
# This function is called when the user clicks File->Open.
filename = QtGui.QFileDialog.getOpenFileName()
print(filename)
# Do your pixmap stuff here.

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