I would like to store each value of price in an array, getting it from a dict. I am a fresh at python, I spent hours trying to figure this out...
for item in world_dict:
if item[1] == 'House':
price = float(item[2])
print p
The output is like:
200.5
100.7
300.9
...
n+100
However, I want to store it on this format : [200.5, 100.7, 300.9, ..., n+100]
Define a list and append to it:
prices = []
for item in world_dict:
if item[1] == 'House':
price = float(item[2])
prices.append(price)
print(prices)
or, you can write it in a shorter way by using list comprehension:
prices = [float(item[2]) for item in world_dict if item[1] == 'House']
print(prices)
This a simple example of how to store values into an array using for loop in python
Hope this will help freshers to gain something when they search the above question
list = [] #define the array
#Fucntion gets called here
def gameConfiguration():
n= int(input("Enter Number of Players : "))
for i in range(0, n):
ele = (input("Name : "))
list.append(ele) # adding the element to the array
print(list[0]) #so you can print the element 1
print(list[1]) #so you can print the element 2 so on and soforth
gameConfiguration() # starts the execution of the fuction
In simplest way, to store the value of for loop in array.
from array import *
ar = []
for i in range (0, 5, 1) :
x = 3.0*i+1
ar.append(x)
print(ar)
Output like this;
[1.0, 4.0, 7.0, 10.0, 13.0]
Related
I make a bunch of matrices that I want to store in python dictionaries and I always find myself typing the same thing for every state that I want to build, i.e.
Ne21_1st_state = {}
Ne21_2nd_state = {}
Ne21_3rd_state = {}
Ne21_4th_state = {}
Ne21_5th_state = {}
Ne21_6th_state = {}
...
Ne21_29th_state = {}
Ne21_30th_state = {}
Can somebody help me automate this using python for loops?
Thanks in advance!
I want something like this:
for i in range(3, 11):
states = f'Ar36_{i}th_state'
print(states)
where the output would be:
Ar36_3th_state
Ar36_4th_state
Ar36_5th_state
Ar36_6th_state
Ar36_7th_state
Ar36_8th_state
Ar36_9th_state
Ar36_10th_state
but instead of printing it it would create individual dictionaries named Ar36_3th_state, Ar36_4th_state, Ar36_5th_state, ...
can't we make a List of dictionaries
List of 30 (or any N) elements where each element is a dictionary with key = "Ar36_{i}th_state" and value = {whatever value you want}
You can create "name" of pseudo variable and use it as key in dictionary like:
my_dic = {1: 'a', 2: 'b', 3: 'c', 4: 'd', 5: 'e'}
my_empty_dic = {}
solution = {}
for i in range(1, 31):
name = 'Ne21_'+str(i)+'st_state'
#solution[name] = my_dic
solution[name] = my_empty_dic
for pseudo_variable in solution:
print(pseudo_variable, solution[pseudo_variable])
print(solution['Ne21_16st_state'])
for pseudo_variable in solution:
if '_16st' in pseudo_variable:
print(pseudo_variable, solution[pseudo_variable])
One way I've done this is using list comprehension.
key = list(
str(input(f"Please enter a Key for value {x + 1}: "))
if x == 0
else str(input(f"\nPlease enter a Key for value {x + 1}: "))
for x in range(3))
value = list(str(input(f"\nPlease enter a Bool for value {x + 1}: "))
for x in range(3))
BoolValues = dict(zip(key, value))
I first create a list of keys followed by a list of the values to be stored in the keys. Then I just zip them together into a dictionary. The conditional statements in the first list are only for a slightly better user-experience with \n being added if it's passed the first input.
Actually now that I look back on the question it may be slightly different to what I was thinking, are you trying to create new dictionaries for every matrix? If that is the case, is it something similar to this?: How do you create different variable names while in a loop?
I wanna achieve this without any libraries or special functions just loops. I wanna have a main program that takes in 2 inputs which are the 2 lists and returns the dictionary like shown below.
Please enter the item names: Cans, bottles, boxes, jugs
please enter quantities : 20,34,10
output : {'Cans':'20','bottles':'34','boxes':'10','jugs':'0'}
If the list of items is longer than the quantities then the quantity becomes automatically 0 as it did with the jugs above.
If the List of Quantity is longer than the items list then the item should automatically become 'unknown object_1' with the number changing accordingly.
Split with comma as delimiter. Fill values with zero for a number of iterations equal to the difference in length between keys and values.
Then use dict comprehension to build your dict. This with the zip built-in function.
keys = 'a,b,c,d'
values = '1,2,3'
keys = keys.split(',')
values = values.split(',')
for i in range(len(keys) - len(values)):
values.append('0')
dct = {}
for i in range(len(keys)):
dct[keys[i]] = values[i]
print(dct)
Output:
{'a': '1', 'b': '2', 'c': '3', 'd': '0'}
This uses only built-in calls so it fits your requirements at best. At the OP requirements it is not using the zip function.
item_names = ['Cans', 'Bottles', 'boxes', 'jugs']
quantities = [20, 34, 10]
output_dict = {}
for i, item in enumerate(item_names):
if i > len(quantities) - 1:
output_dict.update({item : 0})
else:
output_dict.update({item : quantities[i]})
a = list(input().split(','))
b = list(map(int, input().split(',')))
res = {}
for i in range(len(a)):
res[a[i]] = b[i] if i < len(b) else 0
print(res)
list1 = ['cans','Bottles','Boxes','Jugs']
list2 = [1,2,3]
res = {}
for i, element in enumerate(list1):
try:
res[element] = list2[i]
except IndexError:
res[element] = 0
print(res)
Edited code without enumerate or zip:
list1 = ['cans','Bottles','Boxes','Jugs']
list2 = [1,2,3]
res = {}
i=0
for element in list1:
try:
res[element] = list2[i]
except IndexError:
res[element] = 0
i+=1
print(res)
```
Creating list of name and price, this will be the given list:
alist = [["Chanel-1000, Dior-2000, Prada"],["Chloe-200,Givenchy-400,LV-600"],["Bag-1,Bagg-2,Baggg-3"]]
To get minimum value of each element
This will be the output:
chanel-1000,chloe-200,bag-1
Check out this code:
1 .If u want output based on integer tag of each name then use the method.
alist = [["Chanel-1000, Dior-2000, Prada-500"],
["Chloe-200,Givenchy-400,LV-600"], ["Bag-1,Bagg-2,Baggg-3"]]
alist_min = [
min(map(str.strip, x[0].split(',')),
key=lambda i: int(str.strip(i).split('-')[-1])) for x in alist
]
print(alist_min)
OUTPUT :
['Prada-500', 'Chloe-200', 'Bag-1']
2 .If u want output based on name tag of each name then use the method.
alist = [
["Chanel-1000, Dior-2000, Prada"],
["Chloe-200,Givenchy-400,LV-600"],
["Bag-1,Bagg-2,Baggg-3"]]
alist_min = [min(map(str.strip, x[0].split(','))) for x in alist]
print(alist_min)
Now u can use this alist_min object to get required output.
Use min() along with a list comprehension:
alist = [["Chanel-1000, Dior-2000, Prada"],["Chloe-200,Givenchy-400,LV-600"],["Bag-1,Bagg-2,Baggg-3"]]
alist_min = [min(re.split(r',\s*', x[0])) for x in alist]
print(alist_min) # ['Chanel-1000', 'Chloe-200', 'Bag-1']
I'm totally beginner with coding and just need help with some stuff.
My dream was to write a smart shopping list that automatically detects duplicates and increases the weight of duplicate products.
I get the shopping list from an external file which has the following form:
weight\n
ingredient\n
eg.
60
eggs
120
beef meat
25
pasta
120
eggs
etc...
After converting this files to dictionaries by this code:
final_list = []
def get_list(day_list):
for day in range(len(day_list)):
day += 1
day_to_open = f'Days/day{str(day)}.txt'
with open(day_to_open, 'r') as file:
day1 = file.readlines()
day1 = [item.rstrip() for item in day1]
x = 0
y = 1
list = []
for item in range(0, len(day1), 2):
dictio = {day1[y]: day1[x]}
x += 2
y += 2
list.append(dictio)
final_list.append(list)
list = []
for item in final_list:
list += item
return list
days = [1, 2, 3]
list = get_list(day_list=days)
Finally I get list of dictionaries like that:
[{'eggs': '60'}, {'beef meat': '120'}, {'pasta': '25'}, {'eggs': '120'}]
How can I iterate through the dictionary to check if any products are repeating, and if so leave one with the added weight?
For three weeks I have been trying to solve it, unfortunately to no avail.
Thank you very much for all your help!
#Edit
my goal is to make it look like this:
[{'eggs': 180}, {'beef meat': 120}, {'pasta': 25}]
#egg weight added (120 + 60)#
lis = [{'eggs': '60'}, {'beef meat': '120'}, {'pasta': '25'}, {'eggs': '120'}]
# make 1 dict from list of dicts and update max value
new = {}
for d in lis:
for k, v in d.items():
if (k not in new) or (int(v) > int(new[k])):
new[k] = v
# rebuild list of dicts
lis = [{k:v} for k, v in new.items()]
print(lis)
# [{'eggs': '120'}, {'beef meat': '120'}, {'pasta': '25'}]
As ShadowRanger has pointed out, it's not common practice to have a list of multiple dictionaries as you have done. Dictionaries are very useful if used correctly.
I'm not entirely sure the structure of the files you are reading, so I will just explain a way forward and leave it up to you to implement it. What I would suggest is that you first initiate a dictionary with all the necessary keys (ingredients in your case) with each of the values set to 0 (as an integer or float, rather than a string), so you would get a dictionary like this:
shopping_list = {'eggs': 0, 'beef meat': 0, 'pasta': 0}
Then, you will be able to access each of the values by calling the shopping_list dictionary and specifying the key of interest. For example, if you wanted to print the value of eggs, you would write:
print(shopping_list['eggs']) # this would return 0
You can then easily increase/decrease a value of interest; for example, to add 10 to pasta, you would write:
shopping_list['eggs'] += 10
Using this method, you can then iterate through each of your items, select the ingredient of interest and add the weight. So if you have duplicates, it will just add to the same ingredient. Again, I'm not sure the structure of the files you are reading, but it would be something along the lines of:
for ingredient, weight in file:
shopping_list[ingredient] += weight
Good luck for your dream - all the best!
I'm trying to take list of lists and convert in to dictionary. See code below
yearend = [['empl','rating1','rating2','rating3'],['mike','4','4','5'],
['sam','3','2','5'],['doug','5','5','5']]
extract the employee names
employee = [item[0] for item in yearend] #select 1st item from each list
employee.pop(0) # pop out the empl
print(employee)
### output##################################################
##['mike', 'sam', 'doug']###################################
###Output###################################################
###extract the various rating types
yearend1 = yearend [:] # make a copy
rating = yearend1.pop(0) # Pop out the 1st list
rating.pop(0)
print(rating)
### output##################################################
##['rating1', 'rating2', 'rating3']#########################
###Output###################################################
# pick employee and rating and convert rating to numeric
empl_rating = {t[0]:t[1:] for t in yearend1}
for key,value in empl_rating.items():
value = list(map(int, value))
empl_rating[key] = value
print(empl_rating)
### output##################################################
##{'mike': [4, 4, 5], 'sam': [3, 2, 5], 'doug': [5, 5, 5]}##
###Output###################################################
I extracted the data like above and now Iam trying to put together in to dict (New_dicts) so that when
New_dicts['sam']['rating1']
I get 3 or
New_dicts['doug']['rating3']
I get 5. What I'm struggling is how to put this data together?
def todict(ratings) :
a ={}
a["rating1"] = ratings [0]
a["rating2"] = ratings [1]
a["rating3"] = ratings [2]
return a
One way to solve your problem is to get rid of the first row with the headings then just do:
{item[0] : todict(item[1:])
for item in your_list}
BTW this sol is based of off how you wanted to index it. I'm sure there is a more generic sol out there.
Because what you want is essentially just a nested dict
You can use a dict comprehension:
New_dicts = {line[0]: {yearend[0][i + 1]: int(rating) for i, rating in enumerate(line[1:])} for line in yearend[1:]}