I have got an email multipart message object, and I want to convert the attachment in that email message into python file object. Is this possible? If it is possible, what method or class in Python I should look into to do such task?
I don't really understand what you mean by "email multipart message object". Do you mean an object belonging to the email.message.Message class?
If that is what you mean, it's straightforward. On a multipart message, the get_payload method returns a list of message parts (each of which is itself a Message object). You can iterate over these parts and examine their properties: for example, the get_content_type method returns the part's MIME type, and the get_filename method returns the part's filename (if any is specified in the message). Then when you've found the correct message part, you can call get_payload(decode=True) to get the decoded contents.
>>> import email
>>> msg = email.message_from_file(open('message.txt'))
>>> len(msg.get_payload())
2
>>> attachment = msg.get_payload()[1]
>>> attachment.get_content_type()
'image/png'
>>> open('attachment.png', 'wb').write(attachment.get_payload(decode=True))
If you're programmatically extracting attachments from email messages you have received, you might want to take precautions against viruses and trojans. In particular, you probably ought only to extract attachments whose MIME types you know are safe, and you probably want to pick your own filename, or at least sanitize the output of get_filename.
Here is working solution, messages are form IMAP server
self.imap.select()
typ, data = self.imap.uid('SEARCH', 'ALL')
msgs = data[0].split()
print "Found {0} msgs".format(len(msgs))
for uid in msgs:
typ, s = self.imap.uid('FETCH', uid, '(RFC822)')
mail = email.message_from_string(s[0][1])
print "From: {0}, Subject: {1}, Date: {2}\n".format(mail["From"], mail["Subject"], mail["Date"])
if mail.is_multipart():
print 'multipart'
for part in mail.walk():
ctype = part.get_content_type()
if ctype in ['image/jpeg', 'image/png']:
open(part.get_filename(), 'wb').write(part.get_payload(decode=True))
Actually using now-suggested email.EmailMessage API (don't confuse with old email.Message API) it is fairly easy to:
Iterate over all message elements and select only attachments
Iterate over just attachments
Let's assume that you have your message stored as byte content in envelope variable
Solution no.1:
import email
from email.message import EmailMessage
email_message: EmailMessage = email.message_from_bytes(envelope, _class=EmailMessage)
for email_message_part in email_message.walk():
if email_message.is_attachment():
# Do something with your attachment
Solution no.2: (preferable since you don't have to walk through other parts of your message object)
import email
from email.message import EmailMessage
email_message: EmailMessage = email.message_from_bytes(envelope, _class=EmailMessage)
for email_message_attachment in email_message.iter_attachments():
# Do something with your attachment
Couple things to note:
We explicitly tell to use new EmailMessage class in our byte read method through _class=EmailMessage parameter
You can read your email message (aka envelope) from sources such as bytes-like object, binary file object or string thanks to built-in methods in message.Parser API
Related
I've tried with no conclusions to resend emails with Python.
Once I've logged in SMTP and IMAP with TLS, this is what I have written:
status, data = self._imapserver.fetch(id, "(RFC822)")
email_data = data[0][1]
# create a Message instance from the email data
message = email.message_from_string(email_data)
# replace headers (could do other processing here)
message.replace_header("From", 'blablabla#bliblibli.com')
message.replace_header("To", 'blobloblo#blublublu.com')
self._smtpserver.sendmail('blablabla#bliblibli.com', 'blobloblo#blublublu.com', message.as_string())
But the problem is that the variable data doesn't catch the information from the email, even if the ID is the one I need.
It tells me:
b'The specified message set is invalid.'
How can I transfer an email with Python?
Like the error message says, whatever you have in id is invalid. We don't know what you put there, so all we can tell you is what's already in the error message.
(Also, probably don't use id as a variable name, as you will shadow the built-in function with the same name.)
There are additional bugs further on in your code; you need to use message_from_bytes if you want to parse it, though there is really no need to replace the headers just to resend it.
status, data = self._imapserver.fetch(correct_id, "(RFC822)")
self._smtpserver.sendmail('blablabla#bliblibli.com', 'blobloblo#blublublu.com', data[0][1])
If you want to parse the message, you should perhaps add a policy argument; this selects the modern EmailMessage API which was introduced in Python 3.6.
from email.policy import default
...
message = email.message_from_bytes(data[0][1], policy=default)
message["From"] = "blablabla#bliblibli.com"
message["To"] = "blobloblo#blublublu.com"
self._smtpserver.send_message(message)
The send_message method is an addition to the new API. If the message could contain other recipient headers like Cc:, Bcc: etc, perhaps using the good old sendmail method would be better, as it ignores the message's headers entirely.
I'm trying to work with email messages in Python 3.7 and struggling with what looks like compatibility issues. The docs mention email.message.Message having an iter_parts method that should allow me to do a non-recursive walk of message parts.
This doesn't exist on messages returned from mailbox messages and it's taken me a while to get it behaving. For example, I can generate a dummy message with:
from email.message import EmailMessage
msg = EmailMessage()
msg['Subject'] = 'msg 1'
msg.add_alternative("Plain text body", subtype='plain')
msg.add_alternative("<html><body><p>HTML body</p></body></html>", subtype='html')
msg.add_attachment(b"Nothing to see here!", maintype='data', subtype='raw')
and then dump out the parts with:
def iter_parts(msg):
ret = msg.get_content_type()
if msg.is_multipart():
parts = ', '.join(iter_parts(m) for m in msg.iter_parts())
ret = f'{ret} [{parts}]'
return ret
iter_parts(msg)
which gives me: multipart/mixed [multipart/alternative [text/plain, text/plain], data/raw]
but if I save this to a mbox file and reload it:
import mailbox
mbox = mailbox.mbox('/tmp/test.eml')
mbox.add(msg)
iter_parts(mbox[0])
it tells me AttributeError: 'mboxMessage' object has no attribute 'iter_parts'
Initially I thought it might be related to https://stackoverflow.com/a/45804980/1358308 but setting factory=None doesn't seem to do much in Python 3.7.
Am posting my solution, but would like to know if there are better options!
After much poking and reading of source I found that I can instead do:
from email import policy
from email.parser import BytesParser
mbox = mailbox.mbox('/tmp/test.eml', factory=BytesParser(policy=policy.default).parse)
and then I get objects with an iter_parts method.
I already know how to send email messages with Django EmailMessage object:
msg = EmailMessage(title, body, from, [to], headers=headers)
msg.send()
Now I need to get a textual representation of MIME message as a python string (to pass to 3rd-party system).
like
mime_text = msg.as_string()
Unfortunately, documentation doesn't shed any light on how to do it (https://docs.djangoproject.com/en/1.8/topics/email/).
There is a clue of custom email backend implementation, but i'm sure, there should be a simpler way (also i need just specific messages, not all of them)
Thank you.
The EmailMessage class has a method message(), which returns a SafeMIMEText instance which in turn has an as_string() method. So:
mime_text = msg.message().as_string()
I would like to receive email using python. So far I have been able to get the subject but not the body. Here is the code I have been using:
import poplib
from email import parser
pop_conn = poplib.POP3_SSL('pop.gmail.com')
pop_conn.user('myusername')
pop_conn.pass_('mypassword')
#Get messages from server:
messages = [pop_conn.retr(i) for i in range(1, len(pop_conn.list()[1]) + 1)]
# Concat message pieces:
messages = ["\n".join(mssg[1]) for mssg in messages]
#Parse message intom an email object:
messages = [parser.Parser().parsestr(mssg) for mssg in messages]
for message in messages:
print message['subject']
print message['body']
pop_conn.quit()
My issue is that when I run this code it properly returns the Subject but not the body. So if I send an email with the subject "Tester" and the body "This is a test message" it looks like this in IDLE.
>>>>Tester >>>>None
So it appears to be accurately assessing the subject but not the body, I think it is in the parsing method right? The issue is that I don't know enough about these libraries to figure out how to change it so that it returns both a subject and a body.
The object message does not have a body, you will need to parse the multiple parts, like this:
for part in message.walk():
if part.get_content_type():
body = part.get_payload(decode=True)
The walk() function iterates depth-first through the parts of the email, and you are looking for the parts that have a content-type. The content types can be either text/plain or text/html, and sometimes one e-mail can contain both (if the message content_type is set to multipart/alternative).
The email parser returns an email.message.Message object, which does not contain a body key, as you'll see if you run
print message.keys()
What you want is the get_payload() method:
for message in messages:
print message['subject']
print message.get_payload()
pop_conn.quit()
But this gets complicated when it comes to multi-part messages; get_payload() returns a list of parts, each of which is a Message object. You can get a particular part of the multipart message by using get_payload(i), which returns the ith part, raises an IndexError if i is out of range, or raises a TypeError if the message is not multipart.
As Gustavo Costa De Oliveir points out, you can use the walk() method to get the parts in order -- it does a depth-first traversal of the parts and subparts of the message.
There's more about the email.parser module at http://docs.python.org/library/email.message.html#email.message.Message.
it also good return data in correct encoding in message contains some multilingual content
charset = part.get_content_charset()
content = part.get_payload(decode=True)
content = content.decode(charset).encode('utf-8')
Here is how I solved the problem using python 3 new capabilities:
import imaplib
import email
mail = imaplib.IMAP4_SSL('imap.gmail.com')
mail.login(username, password)
mail.select(readonly=True) # refresh inbox
status, message_ids = mail.search(None, 'ALL') # get all emails
for message_id in message_ids[0].split(): # returns all message ids
# for every id get the actual email
status, message_data = mail.fetch(message_id, '(RFC822)')
actual_message = email.message_from_bytes(message_data[0][1])
# extract the needed fields
email_date = actual_message["Date"]
subject = actual_message["Subject"]
message_body = get_message_body(actual_message)
Now get_message_body is actually pretty tricky due to MIME format. I used the function suggested in this answer.
This particular example works with Gmail, but IMAP is a standard protocol, so it should work for other email providers as well, possibly with minor changes.
if u want to use IMAP4. Use outlook python library, download here : https://github.com/awangga/outlook
to retrieve unread email from your inbox :
import outlook
mail = outlook.Outlook()
mail.login('emailaccount#live.com','yourpassword')
mail.inbox()
print mail.unread()
to retrive email element :
print mail.mailbody()
print mail.mailsubject()
print mail.mailfrom()
print mail.mailto()
I am relatively new to programming and to python, but I think I have done ok so far. This is the code I have, and it works fine, except it gets the entire message in MIME format. I only want the text body of unread emails, but I can't quite figure it out how to strip out all of the formatting and header info. If I send a basic email using a smtp python script that I made it works fine, and only prints the body, but if I send the email using outlook it prints a bunch of extra garbage. Any help is very much appreciated.
client = imaplib.IMAP4_SSL(PopServer)
client.login(USER, PASSWORD)
client.select('INBOX')
status, email_ids = client.search(None, '(UNSEEN SUBJECT "%s")' % PrintSubject)
print email_ids
client.store(email_ids[0].replace(' ',','),'+FLAGS','\Seen')
for email in get_emails(email_ids):
get_emails()
def get_emails(email_ids):
data = []
for e_id in email_ids[0].split():
_, response = client.fetch(e_id, '(UID BODY[TEXT])')
data.append(response[0][1])
return data
Sounds like you're looking for the email package:
The email package provides a standard parser that understands most email document structures, including MIME documents. You can pass the parser a string or a file object, and the parser will return to you the root Message instance of the object structure. For simple, non-MIME messages the payload of this root object will likely be a string containing the text of the message. For MIME messages, the root object will return True from its is_multipart() method, and the subparts can be accessed via the get_payload() and walk() methods.