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Hi I'm using ipaddress library.
Do you know why the IP 249.153.153.178 is considered to be True when using is_private?
import ipaddress
ipaddress.ip_address('249.153.153.178').is_private
True
I think IANA don't use this IP as part of its range:
https://www.iana.org/assignments/iana-ipv4-special-registry/iana-ipv4-special-registry.xhtml
Any idea? maybe something I've been missing?
Thank you!
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Sh
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text = "Today I went to the {1N}".format(1N="zoo")
Keyword arguments have to be a valid Python identifier, so not starting with a number.
You could pass a dictionary with the ** operator:
"Today I went to the {1N}".format(**{'1N':"zoo"})
but it's probably easier to use a valid identifier instead.
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elif not in records:
print('File was empty'.format(fname))
I get a syntax error on this line, specifically on the "in" part. Im not sure what is wrong so I would appreciate some help
Although this is valid English, it's missing an operand "something"
elif something not in records:
print('File was empty'.format(fname))
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The question
I began a Python course about 3 weeks ago. Although struggling, I would like to know what I am doing wrong in line 3.
Missing : to indent the if statement -
if "LOL" in user_tweet:
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I have this code, but for the line "if c=a and d=b+1:", it says SyntaxError: invalid syntax. What is wrong with it?
if c=a and d=b+1:
print("YES")
You need to use == for comparison. = is for assignment to a variable
if c==a and d==b+1:
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Why isn't this giving an output? It is meant to take a sentence as an input and then output the identification of each word.
You never call the function. You do need to run the function to get the output:
print word_identify(words)