python tkinter entry widget wait_window in GUI not time.sleep - python

I have a code snippet. Entry widget creates itself with text, then waits seconds then destroys itself.
entry_var_temporary = tk.StringVar()
entry_var_temporary.set(varsoundTitle_usernameHeroContainer)
entry_shtname_temp=tk.Entry(canvas2,width=30,textvariable=entry_var_temporary)
entry_shtname_temp.pack()
entry_shtname_temp.focus_set()
root.update()
time.sleep(10)
entry_shtname_temp.destroy()
root.update()
I have put 10 seconds to wait, and let user to modify the text, if it wants so. But as I see, time.sleep does not let the entry widget to be modified.
How can I get around this problem?
With wait.window() I realized I can edit text inside widget, but my problem is, it is not compulsory. So, if user doesn't put any text on it, it then after 10 sec needs to be destroyed

This seems to be an extension of a previous question you asked. You only need to add one more line of code to that example in order to automatically delete the entry widget after 10 seconds.
In the following example, notice how I use after to destroy the window in 10 seconds. This call must be done before waiting for the window. This is the example I gave in your previous question, with just that one new statement added:
entry_var = tk.StringVar()
new_sheetname_entryBox=tk.Entry(canvas2,width=30, textvariable=entry_var)
new_sheetname_entryBox.pack()
new_sheetname_entryBox.bind("<Return>", lambda event: new_sheetname_entryBox.destroy())
new_sheetname_entryBox.focus_set()
# wait for the entry widget to be deleted, but automatically
# delete it after 10 seconds if the user doesn't respond.
root.after(10000, new_sheetname_entryBox.destroy)
new_sheetname_entryBox.wait_window()

Use the after method with the destroy method as the callback.
The main reason to use root.after vs time.sleep is the time.sleep stops the thread causing the code to completely stop compared to root.after which is thread-safe because it is implemented in terms of call.
Your widget will destroy itself automatically after a set amount of time.
for example:
import tkinter as tk
root = tk.Tk()
entry_var_temporary = tk.StringVar()
entry = tk.Entry(root, textvariable=entry_var_temporary)
entry.pack()
root.after(10000, entry.destroy) # 10000 milliseconds
root.mainloop()

Related

Which code does the mainloop() processes infinitely until any event occurs?

To understand my question kindly follow the paragraphs written below:
What code does the mainloop processes infinitely? Like does it read the code of the entire program again and again?
consider the code:
from tkinter import *
window = Tk()
print("lol")
print("Hello World")
window.mainloop()
the output didn't print "Hello World" or "lol" infinite number of times, so the mainloop() doesn't loop the code of the current module.
Now consider this code:
from tkinter import *
print("lol")
window = Tk()
print("Hello World")
while True:
window.update()
Now, even this code executes the same output, so now we can consider the mainloop() loops the code "window.update()" infite number of times, but more efficiently(somehow).
Now the first question arises what does the window.update() function do to update the values in the GUI, does it re-read the code from top to bottom again, or how does the update function update the GUI widget vaules.
The second question is :
I read this article
"Mainloop in Python Tkinter is an infinite loop of the application window which runs forever so that we can see the still screen.
The application window is like a frame that keeps on destroying every microsecond but the main loop keeps on creating a new updated window.
This process of destroying old window screens and creating a new one happens so fast that human eyes don’t even realize it.
Since the process runs infinite time that is why we are able to see the application in front of us and when we close the window then the loop terminates or exits."
Now if this is true then to recreate an updated window the root.mainloop() must read the entire root GUI code again and again entirely or is there another explanation to it.
I have been trying to understand this for the past 6hrs and I have visited every site and I cannot find the solution for the life of me.
Regards,
Rashik
What code does the mainloop processes infinitely? Like does it read the code of the entire program again and again?
No.
Via this function, it calls this C code which has the embedded Tcl interpreter process one event, or wait for Tkinter_busywaitinterval before trying to process another event
Now, even this code executes the same output, so now we can consider the mainloop() loops the code "window.update()" infite number of times, but more efficiently(somehow).
window.update() calls TCL update, which is described to
[...] bring the application “up to date” by entering the event loop repeatedly until all pending events (including idle callbacks) have been processed.
Your infinite loop doesn't have a sleep, so it's spinning your CPU as hard as possible to do practically nothing.
[...] Does it re-read the code from top to bottom again, or how does the update function update the GUI widget vaules.
It certainly doesn't re-read your code. It processes any pending widget updates, which may have happened by running e.g. window.text("...") in e.g. a click callback or an .after() timeout, etc.
I read this article [...]
That article seems wrong and/or at least over-simplifies things.
This simple example clock should clarify how things work:
import time
import tkinter as tk
root = tk.Tk()
text = tk.Label(root)
text.pack()
def tick():
text["text"] = time.ctime() # update `text` widget's content
root.after(1000, tick) # schedule for this function to be called after 1 second
if __name__ == '__main__':
tick() # call the `tick` function once before entering main loop
root.mainloop()

Problems with update and update_idletasks

I've been learning python for a month now and run into my first brick wall. I have a large art viewer GUI program and at one point want to put an image on screen with a countdown counter-approx every 5 secs. I thought of a code such as the one below The problem is that this uses update and all my reading says that update is bad (starts a new event loop (?)) and that I should use update_idletasks. when I replace update with update_idletasks in the code below the countdown button is not visible until it reaches single figures, update superficially works fine. But also the q bound key calls the subroutine but has no effect
from tkinter import *
import sys
import time
root = Tk()
def q_key(event):
sys.exit()
frame=Frame(root, padx=100, pady=100, bd=10, relief=FLAT)
frame.pack()
button=Button(frame,relief="flat",bg="grey",fg="white",font="-size 18",text="60")
button.pack()
root.bind("q",q_key)
for x in range(30, -1, -5) :
button.configure(text=str(x))
button.update()
print(x)
button.after(5000)
root.mainloop()
In this case you don't need update nor update_idletasks. You also don't need the loop, because tkinter is already running in a loop: mainloop.
Instead, move the body of the loop to a function, and call the function via after. What happens is that you do whatever work you want to do, and then schedule your function to run again after a delay. Since your function exits, tkinter returns to the event loop and is able to process events as normal. When the delay is up, tkinter calls your function and the whole process starts over again.
It looks something like this:
def show(x):
button.configure(text=x)
if x > 0:
button.after(5000, show, x-5)
show(30)

Why does my progress bar work with "print" command and not with tkinter?

I would like to understand why this code:
import time
for i in range(1,11):
print(i)
time.sleep(1)
shows (as it should!) numbers from 1 to 10, each every 1 second, while this code:
from tkinter import *
import time
root = Tk()
for i in range(1,11):
Label(root, text = i).grid(row=0, column=i-1, padx=5, pady =5)
time.sleep(1)
root.mainloop()
waits for 10 seconds, and then displays a window with the 10 numbers (instead of adding them one by one).
I am aware this is a silly question, but I really can't understand! Many Thanks! Alessandro
Most GUI's work differently to what you expect.
They work in an asynchronous way, which means, that you setup your windows and start an event loop.
This event loop will display all widgets, labels, etc, that you set up before calling the event loop and wait for any events (GUI events like mouse or keyboard events, timer events and perhaps network events).
When any event is encountered code associated to that event will be called and this code can request to change the GUI (show or hide elements, change labels or attributes of graphical widgets) However the change to the GUI will only be performed when you give control back to the event loop (when the code handling an event finished)
In your given code you change a label in a for loop with sleep statements, but only after the for loop is finished your main loop is being called and this is the moment, where the final state of your GUI will be displayed.
So what you encounter is a know issue for almost all GUI / asynhronous kind of applications.
You have to rewrite your code such, that you start a timer event, and when the timer event fires a function will set a label and increase the counter by 1. And if the counter is not 11 it will restart another timer
This is because the time.sleep function is before the root.mainloop function.
root.mainloop is what causes the window to appear on-screen and start doing things. Instead, I'd recommend using window.after, as that tells the window to run a function after some time when it's on-screen.
Here's an example of a modification you could make (it's not that good but it works):
from tkinter import *
import time
root = Tk()
progress = 0
end = 10
def update_progress():
global progress
progress += 1
Label(root, text = progress).grid(row=0, column=progress-1, padx=5, pady =5)
if progress < end: root.after(1000,update_progress) # Tell the window to call this function in 1000ms (1 second)
root.after(0,update_progress) # Tell the window to run the update_progress function 0ms after now.
root.mainloop()
I'd recommend looking at gelonida's answer for an explanation of why your original code didn't work, and what you need to keep in mind when programming with GUIs in the future.

Tkinter box packing in loop is slow

I'm running a slowish process of building a set of PDFs using LaTeX that's put together by my script.
The PDFs are built in a for loop. I wanted to show a status window that would add a line for each student that the loop goes through, so that you could see the progress. I have been doing this with print, but I wanted something that integrated well with the Tkinter interface that I have moved to.
I have this:
ReStatuswin = Toplevel(takefocus=True)
ReStatuswin.geometry('800x300')
ReStatuswin.title("Creating Reassessments...")
Rebox2 = MultiListbox(ReStatuswin, (("Student", 15), ("Standard", 25), ("Problems", 25) ))
Rebox2.pack(side = TOP)
OKR = Button(ReStatuswin, text='OK', command=lambda:ReStatuswin.destroy())
OKR.pack(side = BOTTOM)
and then the loop:
for row in todaylist:
and then, inside the loop, after the PDF has been made,
Rebox2.insert(END, listy)
It inserts the row fine, but they all show up (along with the ReBox2 window itself) only after the entire loop is finished.
Any idea about what's causing the delay in display?
Thanks!
Yes, from what I can tell, there are two problems. First, you are not updating the display with each new entry. Second, you are not triggering the for loop with a button but instead having it run on startup (which means that the display won't be created until after the loop exits). Unfortunately however, I can't really work with the code you gave because it is a snippet of a much larger thing. However, I made a little script that should demonstrate how to do what you want:
from Tkinter import Button, END, Listbox, Tk
from time import sleep
root = Tk()
# My version of Tkinter doesn't have a MultiListbox
# So, I use its closest alternative, a regular Listbox
listbox = Listbox(root)
listbox.pack()
def start():
"""This is where your loop would go"""
for i in xrange(100):
# The sleeping here represents a time consuming process
# such as making a PDF
sleep(2)
listbox.insert(END, i)
# You must update the listbox after each entry
listbox.update()
# You must create a button to call a function that will start the loop
# Otherwise, the display won't appear until after the loop exits
Button(root, text="Start", command=start).pack()
root.mainloop()

Automatically close window after a certain time

In a class, in a function I am creating a Tkinter Canvas. This function is being called by another class, I would like for the Tkinter window to pop up for 30 seconds and then close itself. I have it call
master.mainloop()
time.sleep(30)
master.destroy()
But I get an error
"elf.tk.call('destroy', self._w)
_tkinter.TclError: can't invoke "destroy" command: application has been destroyed"
So how can I have it close itself?
Don't use time.sleep() with tkinter. Instead, call the function after on the widget you want to close.
Here it is the most simple example:
import tkinter as tk
w = tk.Tk()
w.after(30000, lambda: w.destroy()) # Destroy the widget after 30 seconds
w.mainloop()
The problem here is that mainloop() does not return until the GUI has shut down.
So, 30 seconds after the GUI has shut down and destroyed itself, you try to destroy it. And obviously that fails.
But you can't just move the sleep and destroy calls inside the main loop, because if you sleep in the middle of the main loop, the GUI will freeze up.
So, you need some kind of timer that will not stop the main loop. tkinter includes the after method for exactly that purpose. This answer gives a detailed example of using it.

Categories