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how I can How can I do it the other hay around, for example, I want my program to be able to ask me for the value of r1 and vote for the level like this Input is 10000000 and the result is 10001, which would be the level
nivel = 10001 - 1
re = nivel**2
re1 = re *10
print (f"\nnivel 7014 : {re1}")
I don't know how I can solve it
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I try getgfs to list forecast for tomorrow hourly.
import getgfs
f=getgfs.Forecast("0p25")
print(f)
print(f.times)
f.search("temperature")
print(f)
print(f.times)
res=f.get(["gustsfc"],date_time="20230213 "+"{:02d}".format(x)+":00", lat=42.13551084674774,lon=21.721419433353784)
for x in range(18, 23): #23):
f=getgfs.Forecast("0p25")
res=f.datetime_to_forecast('20230211')
res=f.get(["tcdcaveclm"],date_time="20230214 "+"{:02d}".format(x)+":00", lat=42.13551084674774,lon=21.721419433353784)
print("20230214 "+"{:02d}".format(x)+":00",res.variables["tcdcaveclm"].data[0][0][0])
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What code should I use to write a program that stores the following content in a variable?
I cannot use an external file.
{'title':'El Más Allá','aka':'E tu vivrai nel terrore - Laldilà','director':'Lucio Fulci', 'year':1981, 'country':'Italia'}
just store it in a dict like this
import json
instr = input(">>>")
myDict = json.loads(instr)
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Request:
data['Churn'].value_counts(0)
Output:
0 7963
1 2037
Request:
data['Churn'].value_counts(1)
Output:
0 79.63
1 20.37
Could you please explain how parameters of 1, 0 for value_counts work?
You can find an answer when reading documentation:
value_counts(0)
is the same as:
value_counts(normalize=0)
which is interpreted as:
value_counts(normalize=False)
While 1 is interpreted as True in the opposite case.
That's why.
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answer=input(print('What s the capital',country,'?'))
RETURN
What s the capital of South Africa ?
None
And I have to put my answer just after the 'none'
You are printing inside the input function and print returns None.
You should do something like this:
country = "Italy"
answer = input(f"What's the capital of {country}? ")
print(answer)
Read the documentation here.
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card_travel2 - 3 yrslocation_onKolkata
From above string I want to get 2 - 3 yrs which regular expression can I use?
Hope you are looking something like this,
import re
pattern = r'\d+\s+-\s+\d+\s+yrs'
text = 'card_travel2 - 3 yrslocation_onKolkata'
re.findall(pattern, text)
output
['2 - 3 yrs']