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Python list of dictionaries search
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First, I am new to Python and working with JSON.
I am trying to extract just one value from an API request response, and I am having a difficult time parsing out the data I need.
I have done a lot of searching on how to do this, but most all the examples use a string or file that is formatted is much more basic than what I am getting.
I understand the key - value pair concept but I am unsure how to reference the key-value I want. I think it has something to do with the response having multiple objects having the same kay names. Or maybe the first line "Bookmark" is making things goofy.
The value I want is for the model name in the response example below.
That's all I need from this. Any help would be greatly appreciated.
{
"Bookmark": "<B><P><p>SerNum</p><p>Item</p></P><D><f>false</f><f>false</f></D><F><v>1101666</v><v>ADDMASTER IJ7102-23E</v></F><L><v>123456</v><v>Model Name</v></L></B>",
"Items": [
[
{
"Name": "SerNum",
"Value": "123456"
},
{
"Name": "Item",
"Value": "Model Name"
},
{
"Name": "_ItemId",
"Value": "PBT=[unit] unt.DT=[2021-07-28 08:20:33.513] unt.ID=[eae2621d-3e9f-4515-9763-55e67f65fae6]"
}
]
],
"Message": "Success",
"MessageCode": 0
}
If you want to find value of dictionary with key 'Name' and value 'Item' you can do:
import json
with open('your_data.json', 'r') as f_in:
data = json.load(f_in)
model_name = next((i['Value'] for lst in data['Items'] for i in lst if i['Name'] == 'Item'), 'Model name not found.')
print(model_name)
Prints:
Model Name
Note: if the dictionary is not found string 'Model name not found.' is returned
First, load the JSON into a python dict:
import json
x = '''{
"Bookmark": "<B><P><p>SerNum</p><p>Item</p></P><D><f>false</f><f>false</f></D><F><v>1101666</v><v>ADDMASTER IJ7102-23E</v></F><L><v>123456</v><v>Model Name</v></L></B>",
"Items": [
[
{
"Name": "SerNum",
"Value": "123456"
},
{
"Name": "Item",
"Value": "Model Name"
},
{
"Name": "_ItemId",
"Value": "PBT=[unit] unt.DT=[2021-07-28 08:20:33.513] unt.ID=[eae2621d-3e9f-4515-9763-55e67f65fae6]"
}
]
],
"Message": "Success",
"MessageCode": 0
}'''
# parse x:
y = json.loads(x)
# The result is a Python dictionary.
Now if you want the value 'Model Name', you would do:
print(y['Items'][0][1]['Value'])
Related
Im working on big json data . In every data set ther will be Name,Type,Value. Im actually need to parse the all type which as equal to "Shirt". I don't know to parse the inside json data.
x={
"Data": "Ecommerce",
"Host":{
"Items": [
[
{
"Name": "cot",
"Value": 99,
"Type": "Shirt"
},
{
"Name": "ploy",
"Value": 90,
"Type": "Pant"
},
{
"Name": "lyc",
"Value": 22,
"Type":"Shirt"
}
]
],
}}
k=x.get("Host")
print(k)
The above code will Display all data inside the Host.
What I'm trying to get output as parse only the Type: Shirt and Value of the Shirt .
I tried with some Def ,loop concepts but i can't able to achieve my output.
Output I'm looking for :-
If Type = Shirt , need parse that json data
Cot:90
Lyc:22
In dict format
This shows how to access the data. I assume you can change this to create a dictionary.
for item in x['Host']['Items'][0]:
if item['Type'] == 'Shirt':
print(item['Name'],':',item['Value'])
This is an example to do it with short for
items = x["Host"]["Items"]
shirt_values = {item["Name"]: item["Value"] for sublist in items for item in sublist if item["Type"] == "Shirt"}
I am working on a new project in HubSpot that returns nested JSON like the sample below. I am trying to access the associated contacts id, but am struggling to reference it correctly (the id I am looking for is the value '201' in the example below). I've put together this script, but this script only returns the entire associations portion of the JSON and I only want the id. How do I reference the id correctly?
Here is the output from the script:
{'contacts': {'paging': None, 'results': [{'id': '201', 'type': 'ticket_to_contact'}]}}
And here is the script I put together:
import hubspot
from pprint import pprint
client = hubspot.Client.create(api_key="API_KEY")
try:
api_response = client.crm.tickets.basic_api.get_page(limit=2, associations=["contacts"], archived=False)
for x in range(2):
pprint(api_response.results[x].associations)
except ApiException as e:
print("Exception when calling basic_api->get_page: %s\n" % e)
Here is what the full JSON looks like ('contacts' property shortened for readability):
{
"results": [
{
"id": "34018123",
"properties": {
"content": "Hi xxxxx,\r\n\r\nCan you clarify on how the blocking of script happens? Is it because of any CSP (or) the script will decide run time for every URL’s getting triggered from browser?\r\n\r\nRegards,\r\nLogan",
"createdate": "2019-07-03T04:20:12.366Z",
"hs_lastmodifieddate": "2020-12-09T01:16:12.974Z",
"hs_object_id": "34018123",
"hs_pipeline": "0",
"hs_pipeline_stage": "4",
"hs_ticket_category": null,
"hs_ticket_priority": null,
"subject": "RE: call followup"
},
"createdAt": "2019-07-03T04:20:12.366Z",
"updatedAt": "2020-12-09T01:16:12.974Z",
"archived": false
},
{
"id": "34018892",
"properties": {
"content": "Hi Guys,\r\n\r\nI see that we were placed back on the staging and then removed again.",
"createdate": "2019-07-03T07:59:10.606Z",
"hs_lastmodifieddate": "2021-12-17T09:04:46.316Z",
"hs_object_id": "34018892",
"hs_pipeline": "0",
"hs_pipeline_stage": "3",
"hs_ticket_category": null,
"hs_ticket_priority": null,
"subject": "Re: Issue due to server"
},
"createdAt": "2019-07-03T07:59:10.606Z",
"updatedAt": "2021-12-17T09:04:46.316Z",
"archived": false,
"associations": {
"contacts": {
"results": [
{
"id": "201",
"type": "ticket_to_contact"
}
]
}
}
}
],
"paging": {
"next": {
"after": "35406270",
"link": "https://api.hubapi.com/crm/v3/objects/tickets?associations=contacts&archived=false&hs_static_app=developer-docs-ui&limit=2&after=35406270&hs_static_app_version=1.3488"
}
}
}
You can do api_response.results[x].associations["contacts"]["results"][0]["id"].
Sorted this out, posting in case anyone else is struggling with the response from the HubSpot v3 Api. The response schema for this call is:
Response schema type: Object
String results[].id
Object results[].properties
String results[].createdAt
String results[].updatedAt
Boolean results[].archived
String results[].archivedAt
Object results[].associations
Object paging
Object paging.next
String paging.next.after
String paging.next.linkResponse schema type: Object
String results[].id
Object results[].properties
String results[].createdAt
String results[].updatedAt
Boolean results[].archived
String results[].archivedAt
Object results[].associations
Object paging
Object paging.next
String paging.next.after
String paging.next.link
So to access the id of the contact associated with the ticket, you need to reference it using this notation:
api_response.results[1].associations["contacts"].results[0].id
notes:
results[x] - reference the result in the index
associations["contacts"] -
associations is a dictionary object, you can access the contacts item
by it's name
associations["contacts"].results is a list - reference
by the index []
id - is a string
In my case type was ModelProperty or CollectionResponseProperty couldn't reach dict anyhow.
For the record this got me to go through the results.
for result in list(api_response.results):
ID = result.id
I hope everyone is doing well.
I need a little help where I need to get all the strings from a variable and need to store into a single list in python.
For example -
I have json file from where I am getting ids and all the ids are getting stored into a variable called id as below when I run print(id)
17298626-991c-e490-bae6-47079c6e2202
17298496-19bd-2f89-7b5f-881921abc632
17298698-3e17-7a9b-b337-aacfd9483b1b
172986ac-d91d-c4ea-2e50-d53700480dd0
172986d0-18aa-6f51-9c62-6cb087ad31e5
172986f4-80f0-5c21-3aee-12f22a5f4322
17298712-a4ac-7b36-08e9-8512fa8322dd
17298747-8cc6-d9d0-8d05-50adf228c029
1729875c-050f-9a99-4850-bb0e6ad35fb0
1729875f-0d50-dc94-5515-b4891c40d81c
17298761-c26b-3ce5-e77e-db412c38a5b4
172987c8-2b5d-0d94-c365-e8407b0a8860
1729881a-e583-2b54-3a52-d092020d9c1d
1729881c-64a2-67cf-d561-6e5e38ed14cb
172987ec-7a20-7eb6-3ebe-a9fb621bb566
17298813-7ac4-258b-d6f9-aaf43f9147b1
17298813-f1ef-d28a-0817-5f3b86c3cf23
17298828-b62b-9ee6-248b-521b0663226e
17298825-7449-2fcb-378e-13671cb4688a
I want these all values to be stored into a single list.
Can some please help me out with this.
Below is the code I am using:
import json
with open('requests.json') as f:
data = json.load(f)
print(type(data))
for i in data:
if 'traceId' in i:
id = i['traceId']
newid = id.split()
#print(type(newid))
print(newid)
And below is my json file looks like:
[
{
"id": "376287298-hjd8-jfjb-khkf-6479280283e9",
"submittedTime": 1591692502558,
"traceId": "17298626-991c-e490-bae6-47079c6e2202",
"userName": "ABC",
"onlyChanged": true,
"description": "Not Required",
"startTime": 1591694487929,
"result": "NONE",
"state": "EXECUTING",
"paused": false,
"application": {
"id": "16b22a09-a840-f4d9-f42a-64fd73fece57",
"name": "XYZ"
},
"applicationProcess": {
"id": "dihihdosfj9279278yrie8ue",
"name": "Deploy",
"version": 12
},
"environment": {
"id": "fkjdshkjdshglkjdshgldshldsh03r937837",
"name": "DEV"
},
"snapshot": {
"id": "djnglkfdglki98478yhgjh48yr844h",
"name": "DEV_snapshot"
},
},
{
"id": "17298495-f060-3e9d-7097-1f86d5160789",
"submittedTime": 1591692844597,
"traceId": "17298496-19bd-2f89-7b5f-881921abc632",
"userName": "UYT,
"onlyChanged": true,
"startTime": 1591692845543,
"result": "NONE",
"state": "EXECUTING",
"paused": false,
"application": {
"id": "osfodsho883793hgjbv98r3098w",
"name": "QA"
},
"applicationProcess": {
"id": "owjfoew028r2uoieroiehojehfoef",
"name": "EDC",
"version": 5
},
"environment": {
"id": "16cf69c5-4194-e557-707d-0663afdbceba",
"name": "DTESTU"
},
}
]
From where I am trying to get the traceId.
you could use simple split method like the follwing:
ids = '''17298626-991c-e490-bae6-47079c6e2202 17298496-19bd-2f89-7b5f-881921abc632 17298698-3e17-7a9b-b337-aacfd9483b1b 172986ac-d91d-c4ea-2e50-d53700480dd0 172986d0-18aa-6f51-9c62-6cb087ad31e5 172986f4-80f0-5c21-3aee-12f22a5f4322 17298712-a4ac-7b36-08e9-8512fa8322dd 17298747-8cc6-d9d0-8d05-50adf228c029 1729875c-050f-9a99-4850-bb0e6ad35fb0 1729875f-0d50-dc94-5515-b4891c40d81c 17298761-c26b-3ce5-e77e-db412c38a5b4 172987c8-2b5d-0d94-c365-e8407b0a8860 1729881a-e583-2b54-3a52-d092020d9c1d 1729881c-64a2-67cf-d561-6e5e38ed14cb 172987ec-7a20-7eb6-3ebe-a9fb621bb566 17298813-7ac4-258b-d6f9-aaf43f9147b1 17298813-f1ef-d28a-0817-5f3b86c3cf23 17298828-b62b-9ee6-248b-521b0663226e 17298825-7449-2fcb-378e-13671cb4688a'''
l = ids.split(" ")
print(l)
This will give the following result, I assumed that the separator needed is simple space you can adjust properly:
['17298626-991c-e490-bae6-47079c6e2202', '17298496-19bd-2f89-7b5f-881921abc632', '17298698-3e17-7a9b-b337-aacfd9483b1b', '172986ac-d91d-c4ea-2e50-d53700480dd0', '172986d0-18aa-6f51-9c62-6cb087ad31e5', '172986f4-80f0-5c21-3aee-12f22a5f4322', '17298712-a4ac-7b36-08e9-8512fa8322dd', '17298747-8cc6-d9d0-8d05-50adf228c029', '1729875c-050f-9a99-4850-bb0e6ad35fb0', '1729875f-0d50-dc94-5515-b4891c40d81c', '17298761-c26b-3ce5-e77e-db412c38a5b4', '172987c8-2b5d-0d94-c365-e8407b0a8860', '1729881a-e583-2b54-3a52-d092020d9c1d', '1729881c-64a2-67cf-d561-6e5e38ed14cb', '172987ec-7a20-7eb6-3ebe-a9fb621bb566', '17298813-7ac4-258b-d6f9-aaf43f9147b1', '17298813-f1ef-d28a-0817-5f3b86c3cf23', '17298828-b62b-9ee6-248b-521b0663226e', '17298825-7449-2fcb-378e-13671cb4688a']
Edit
You get list of lists because each iteration you read only 1 id, so what you need to do is to initiate an empty list and append each id to it in the following way:
l = []
for i in data
if 'traceId' in i:
id = i['traceId']
l.append(id)
you can append the ids variable to the list such as,
#list declaration
l1=[]
#this must be in your loop
l1.append(ids)
I'm assuming you get the id as a str type value. Using id.split() will return a list of all ids in one single Python list, as each id is separated by space here in your example.
id = """17298626-991c-e490-bae6-47079c6e2202 17298496-19bd-2f89-7b5f-881921abc632
17298698-3e17-7a9b-b337-aacfd9483b1b 172986ac-d91d-c4ea-2e50-d53700480dd0
172986d0-18aa-6f51-9c62-6cb087ad31e5 172986f4-80f0-5c21-3aee-12f22a5f4322
17298712-a4ac-7b36-08e9-8512fa8322dd 17298747-8cc6-d9d0-8d05-50adf228c029
1729875c-050f-9a99-4850-bb0e6ad35fb0 1729875f-0d50-dc94-5515-b4891c40d81c
17298761-c26b-3ce5-e77e-db412c38a5b4 172987c8-2b5d-0d94-c365-e8407b0a8860
1729881a-e583-2b54-3a52-d092020d9c1d 1729881c-64a2-67cf-d561-6e5e38ed14cb
172987ec-7a20-7eb6-3ebe-a9fb621bb566 17298813-7ac4-258b-d6f9-aaf43f9147b1
17298813-f1ef-d28a-0817-5f3b86c3cf23 17298828-b62b-9ee6-248b-521b0663226e
17298825-7449-2fcb-378e-13671cb4688a"""
id_list = id.split()
print(id_list)
Output:
['17298626-991c-e490-bae6-47079c6e2202', '17298496-19bd-2f89-7b5f-881921abc632',
'17298698-3e17-7a9b-b337-aacfd9483b1b', '172986ac-d91d-c4ea-2e50-d53700480dd0',
'172986d0-18aa-6f51-9c62-6cb087ad31e5', '172986f4-80f0-5c21-3aee-12f22a5f4322',
'17298712-a4ac-7b36-08e9-8512fa8322dd', '17298747-8cc6-d9d0-8d05-50adf228c029',
'1729875c-050f-9a99-4850-bb0e6ad35fb0', '1729875f-0d50-dc94-5515-b4891c40d81c',
'17298761-c26b-3ce5-e77e-db412c38a5b4', '172987c8-2b5d-0d94-c365-e8407b0a8860',
'1729881a-e583-2b54-3a52-d092020d9c1d', '1729881c-64a2-67cf-d561-6e5e38ed14cb',
'172987ec-7a20-7eb6-3ebe-a9fb621bb566', '17298813-7ac4-258b-d6f9-aaf43f9147b1',
'17298813-f1ef-d28a-0817-5f3b86c3cf23', '17298828-b62b-9ee6-248b-521b0663226e',
'17298825-7449-2fcb-378e-13671cb4688a']
split() splits by default with space as a separator. You can use the sep argument to use any other separator if needed.
I am using a python and getting the data from an API the data formatted as listed in the example I have a problem getting out Cust_id and name put of the API
Below is one of the things I tried and one of the things answered by SimonR. I am sure I am doing something really dumb right now but I get the error
typeError: the JSON object must be str, bytes or bytearray, not dict. Thank you everyone in advance for your answers
import json
a = {
"count": 5,
"Customers": {
"32759": {
"cust_id": "1234",
"name": "Mickey Mouse"
},
"11053": {
"cust_id": "1235",
"name": "Mini Mouse"
},
"21483": {
"cust_id": "1236",
"name": "Goofy"
},
"12441": {
"cust_id": "1237",
"name": "Pluto"
},
"16640": {
"cust_id": "1238",
"name": "Donald Duck"
}
}
}
d = json.loads(a)
customers = {v["cust_id"]: v["name"] for v in d["Customers"].values()}
Is this what you're trying to do ?
import json
d = json.loads(a)
customers = {v["cust_id"]: v["name"] for v in d["Customers"].values()}
outputs :
{'1234': 'Mickey Mouse',
'1235': 'Mini Mouse',
'1236': 'Goofy',
'1237': 'Pluto',
'1238': 'Donald Duck'}
Well if I understood correctly you can do this:
# d is the API response in your post
# This will give you the list of customers
customers = d['Customers']
Then you can iterate over the customers dictionary and save them to any data structure you want:
# This will print out the name and cust_id
for k, v in customers.items():
print(v['cust_id'], v['name'])
Hope it helps!
import json
# convert json to python dict
response = json.loads(json_string)
# loop through all customers
for key, customer in response['Customers'].items():
# get customer id
customer['cust_id']
# get customer name
custoemr['name']
I'm reading in a JSON string which is littered with u'string' style strings. Example:
[
{
"!\/award\/award_honor\/honored_for": {
"award": {
"id": "\/en\/spiel_des_jahres"
},
"year": {
"value": "1996"
}
},
"guid": "#9202a8c04000641f80000000003a0ee6",
"type": "\/games\/game",
"id": "\/en\/el_grande",
"name": "El Grande"
},
{
"!\/award\/award_honor\/honored_for": {
"award": {
"id": "\/en\/spiel_des_jahres"
},
"year": {
"value": "1995"
}
},
"guid": "#9202a8c04000641f80000000000495ec",
"type": "\/games\/game",
"id": "\/en\/settlers_of_catan",
"name": "Settlers of Catan"
}
]
If I assign name = result.name. Then when I log of pass that value to a Django template, it displays as u'Dominion'
How do I format it to display as Dominion?
++ UPDATE ++
I think the problem has to do with printing values from a list or dictionary. For example:
result = freebase.mqlread(query)
games = {}
count = 0
r = result[0]
name = r.name
games["name"] = name,
self.response.out.write(games["name"])
self.response.out.write(name)
This displays as:
(u'Dominion',) // saved response to dictionary, and then printed
Dominion // when calling the value directly from the response
I need to iterate through an array of JSON items and the values are being shown with the unicode. Why?
The comma at the end of games["name"] = name, makes it a 1-tuple. Remove it.
>>> # example
>>> s = u"Jägermütze"
>>> s.encode("utf-8")
'J\xc3\xa4germ\xc3\xbctze'
>>> print s.encode("utf-8") # on a utf-8 terminal
Jägermütze
Don't know much about Django, but not accepting snicode strings seems unpythonic to me.
You can use str(your string) to do this.