I am trying to scrape data from CME but the code seems to freeze at requests.get() function.
import requests
from bs4 import BeautifulSoup
URL = 'https://www.cmegroup.com/markets/interest-rates/us-treasury/2-year-us-treasury-note.settlements.html'
page = requests.get(URL)
Seems that they are checking for user-agent
The User-Agent request header is a characteristic string that lets servers and network peers identify the application, operating system, vendor, and/or version of the requesting user agent.
Not a specific one, so just give them your favorite agent:
requests.get(URL, headers={'user-agent':'SALT'}).text
More about user-agent check the docs
Related
I'm new to webscraping and have been trying for fun to scrape a boxing website.
My code below was working on the first attempt, and when I tried to re-run it, it was no longer retrieving the link data any more.
I can still access the website from my browser, so not sure what the error is!
Appreciate any pointers.
import os
from urllib.request import urlopen, Request
from bs4 import BeautifulSoup
import re
os.system('cls')
heavy = 'https://boxrec.com/en/ratings?r%5Brole%5D=box-pro&r%5Bsex%5D=M&r%5Bstatus%5D=a&r%5Bdivision%5D=Heavyweight&r%5Bcountry%5D=&r_go='
pages = set()
def get_links(page_url):
print("running crawler...")
global pages
req = Request(heavy, headers = {'User-Agent':'Mozilla/5.0'})
html = urlopen(req)
bs = BeautifulSoup(html.read(), 'html.parser')
for link in bs.find_all('a', href=re.compile('^(/en/box-pro/)')):
if 'href' in link.attrs:
if link.attrs['href'] not in pages:
new_page = link.attrs['href']
print(new_page)
pages.add(new_page)
get_links(new_page)
get_links('')
print("crawling done.")
If you inspect html.read() you will find that the page displays a login form. It might be that a detection system picks up your bot and tries to prevent (or at least make it harder for) you to scrape.
As an engineer at WebScrapingAPI I've tested your URL using our API and it passes each time (it returns the data, not the login page). That is because we've implemented a number of detection evasion features, including an IP rotation system. So by sending the request from another IP with a completely different browser fingerprint, the targeted website 'thinks' it's another person and passes on the information. If you want to test it yourself, here is the script you can use:
import requests
API_KEY = '<YOUR_API_KEY>'
SCRAPER_URL = 'https://api.webscrapingapi.com/v1'
TARGET_URL = 'https://boxrec.com/en/ratings?r%5Brole%5D=box-pro&r%5Bsex%5D=M&r%5Bstatus%5D=a&r%5Bdivision%5D=Heavyweight&r%5Bcountry%5D=&r_go='
PARAMS = {
"api_key":API_KEY,
"url": TARGET_URL,
"render_js":1,
}
response = requests.get(SCRAPER_URL, params=PARAMS)
print(response.text)
If you want to build your own scraper, I suggest you implement some of the techniques in this article. You might also want to actualyy create an account on your targeted website, log in using the credentials, collect the cookies and pass them to your request.
In order to collect the cookies:
Navigate to the login screen
Open developer tools in your browser (Network tab)
Log in and check the login request:
(Note that I have a failed attempt, because I didn't use real credentials to log in)
To pass the cookies to your request, simply add it as a header to your req. Example: req = Request(url, headers={'User-Agent': 'Mozilla/5.0', 'Cookie':'myCookie=lovely'}). Also, try to use the same User-Agent as the original request (the one made when you logged in). It can be found in the same login request from where you picked up the cookies.
Novice web scraper here:
I am trying to scrape the name and address from this website https://propertyinfo.knoxcountytn.gov/Datalets/Datalet.aspx?sIndex=1&idx=1. I have attempted the following code which only returns 'None' or an empty array if I replace find() with find_all(). I would like it to return the html of this particular section so I can extract the text and later add it to a csv file. If the link doesn't work, or take to you where I'm working, simply go to the knox county tn website > property search > select a property.
Much appreciation in advance!
from splinter import Browser
import pandas as pd
from bs4 import BeautifulSoup as soup
import requests
from webdriver_manager.chrome import ChromeDriverManager
owner_soup = soup(html, 'html.parser')
owner_elem = owner_soup.find('td', class_='DataletData')
owner_elem
OR
# this being the tag and class of the whole section where the info is located
owner_soup = soup(html, 'html.parser')
owner_elem = owner_soup.find_all('div', class_='datalet_div_2')
owner_elem
OR when I try:
browser.find_by_css('td.DataletData')[15]
it returns:
<splinter.driver.webdriver.WebDriverElement at 0x11a763160>
and I can't pull the html contents from that element.
There's a few issues I see, but it could be that you didn't include your code as you actually have it.
Splinter works on its own to get page data by letting you control a browser. You don't need BeautifulSoup or requests if you're using splinter. You use requests if you want the raw response without running any of the things that browsers do for you automatically.
One of these automatic things is redirects. The link you provided does not provide the HTML that you are seeing. This link just has a response header that redirects you to https://propertyinfo.knoxcountytn.gov/, which redirects you again to https://propertyinfo.knoxcountytn.gov/search/commonsearch.aspx?mode=realprop, which redirects again to https://propertyinfo.knoxcountytn.gov/Search/Disclaimer.aspx?FromUrl=../search/commonsearch.aspx?mode=realprop
On this page you have to hit the 'agree' button to get redirected to https://propertyinfo.knoxcountytn.gov/search/commonsearch.aspx?mode=realprop, this time with these cookies set:
Cookie: ASP.NET_SessionId=phom3bvodsgfz2etah1wwwjk; DISCLAIMER=1
I'm assuming the session id is autogenerated, and the Disclaimer value just needs to be '1' for the server to know you agreed to their terms.
So you really have to study a page and understand what's going on to know how to do it on your own using just the requests and beautifulsoup libraries. Besides the redirects I mentioned, you still have to figure out what network request gives you that session id to manually add it to the cookie header you send on all future requests. You can avoid doing some requests, and so this way is a lot faster, but you do need to be able to follow along in the developer tools 'network' tab.
Postman is a good tool to help you set up requests yourself and see their result. Then you can bring all the set up from there into your code.
I'm trying to scrape Gold stock ticker from Yahoo! Finance.
from bs4 import BeautifulSoup
import requests, lxml
response = requests.get('https://finance.yahoo.com/quote/GC=F?p=GC=F')
soup = BeautifulSoup(response.text, 'lxml')
gold_price = soup.findAll("div", class_='My(6px) Pos(r) smartphone_Mt(6px)')[2].find_all('p').text
Whenever I run this it returns: list index out of range.
When I do print(len(ssoup)) it returns 4.
Any ideas?
Thank you.
You can make a direct request to the yahoo server. To locate the query URL you need to open Network tab via Dev tools (F12) -> Fetch/XHR -> find name: spark?symbols= (refresh page if you don't see any), find the needed symbol, and see the response (preview tab) on the newly opened tab on the right.
You can make direct requests to all of these links if the request method is GET since POST methods are much more complicated.
You need json and requests library, no need for bs4. Note that making a lot of such requests might block your IP (or set an IP rate limit) or you won't get any response because their system might detect that it's a bot since the regular user won't make such requests to the server, repeatedly. So you need to figure out how to bypass it.
Update:
There's possibly a hard limit on how many requests can be made in an X period of time.
Code and example in the online IDE (contains full JSON response):
import requests, json
response = requests.get('https://query1.finance.yahoo.com/v7/finance/spark?symbols=GC%3DF&range=1d&interval=5m&indicators=close&includeTimestamps=false&includePrePost=false&corsDomain=finance.yahoo.com&.tsrc=finance').text
data_1 = json.loads(response)
gold_price = data_1['spark']['result'][0]['response'][0]['meta']['previousClose']
print(gold_price)
# 1830.8
P.S. There's a blog about scraping Yahoo! Finance Home Page of mine, which is kind of relevant.
I am a very beginner of Python. And I tried to crawl some product information from my www.Alibaba.com console. When I came to the visitor details page, I found the cookie changed every time when I clicked the search button. I found the cookie changed for each request. I can not crawl the data in the way I crawled from other pages where the cookies were fixed in a certain period.
After comparing the cookie data, I found here were only 3 key-value pairs were changed. I think those 3 values made me fail to crawl the data. So I want to know how to handle such situation.
For python3 the http.client in the standard library can be configured to use an http.cookiejar CookieJar which will keep track of cookies within the client automatically.
You can set this up like this:
import http.cookiejar, urllib.request
cj = http.cookiejar.CookieJar()
opener = urllib.request.build_opener(urllib.request.HTTPCookieProcessor(cj))
r = opener.open("http://example.com/")
If you're using pyhton2 then a similar approach works with urllib:
import urllib2
opener = urllib2.build_opener(urllib2.HTTPCookieProcessor())
r = opener.open("http://example.com/")
I'm trying to crawl a website using the requests library. However, the particular website I am trying to access (http://www.vi.nl/matchcenter/vandaag.shtml) has a very intrusive cookie statement.
I am trying to access the website as follows:
from bs4 import BeautifulSoup as soup
import requests
website = r"http://www.vi.nl/matchcenter/vandaag.shtml"
html = requests.get(website, headers={"User-Agent": "Mozilla/5.0"})
htmlsoup = soup(html.text, "html.parser")
This returns a web page that consists of just the cookie statement with a big button to accept. If you try accessing this page in a browser, you find that pressing the button redirects you to the requested page. How can I do this using requests?
I considered using mechanize.Browser but that seems a pretty roundabout way of doing it.
Try setting:
cookies = dict(BCPermissionLevel='PERSONAL')
html = requests.get(website, headers={"User-Agent": "Mozilla/5.0"}, cookies=cookies)
This will bypass the cookie consent page and will land you staight to the page.
Note: You could find the above by analyzing the javascript code that is run on the cookie concent page, it is a bit obfuscated but it should not be difficult. If you run into the same type of problem again, take a look at what kind of cookies does the javascript code that is executed upon a event's handling sets.
I have found this SO question which asks how to send cookies in a post using requests. The accepted answer states that the latest build of Requests will build CookieJars for you from simple dictionaries. Below is the POC code included in the original answer.
import requests
cookie = {'enwiki_session': '17ab96bd8ffbe8ca58a78657a918558'}
r = requests.post('http://wikipedia.org', cookies=cookie)