I am working with a dict which is structured like this inside a function:
listOfInformation = [{123456789: {'PokemonId': '123456789', 'PokemonName': 'Pikachu', 'PokemonAttack': 'thunderbolt'}}]
In that function, I'm passing an integer as an argument (pokemon_id) and then trying to test if the key-value pair exists like this:
listOfInformation(pokemon_id)
But I am getting an error of IndexError, list index out of range. I can't figure out why would I get this error. how can I fix this?
I should be getting back the whole value of this:
{'PokemonId': '123456789', 'PokemonName': 'Pikachu', 'PokemonAttack': 'thunderbolt'}
Your data structure appears to be a list containing one element, which is a dictionary. If so, you should be using:
listOfInformation = [{123456789: {'PokemonId': '123456789', 'PokemonName': 'Pikachu', 'PokemonAttack': 'thunderbolt'}}]
if 123456789 in listOfInformation[0]:
print(listOfInformation[0][123456789])
The above prints:
{'PokemonId': '123456789', 'PokemonAttack': 'thunderbolt', 'PokemonName': 'Pikachu'}
Related
I have this problem where I would like to add a value to a dictionary but the key is duplicate.
I would like the key to to hold a list with multiple values
this is what I have tried
def storingPassword():
username=("bob")#key,
password=("PASSWROD1")#value
allpasswords={
"jeff":"jeff 123 ",
"bob" : "bob 123"
}
if username not in allpasswords:
allpasswords[username]=password
else:
allpasswords[username].append(password)
return allpasswords
but i keep getting this error
"AttributeError: 'str' object has no attribute 'append'"
I expect a output something like this;
"jeff":"jeff 123 ",
"bob" : ["bob 123","PASSWORD1"]
That's because the value in your allpasswords dict is a string and you are trying to treat it like a list. Why are you trying to make your data structure complex with few values as list and few as string? I recommend to convert everything to list for a simpler logic.
Hence your code should be like this:
allpasswords={
"jeff": ["jeff 123 "],
"bob" : ["bob 123"]
}
allpasswords[username].append(password)
Instead of using dict object, you can use collections.defaultdict. It will let you define a dict with default value as list. So you don't need to even explicitly initialise value of new key as list. For example:
from collections import defaultdict
my_dict = defaultdict(list)
my_dict['new_key'].append('new_value')
# dictionary will hold the value:
# {'new_key': ['new_value']})
Initiate your dictionary entry with a list instead of just a string.
allpasswords[username] = [password] # List containing a single password
You will then be able to append to it.
(Having some entries contain a string while others contain a list of strings is best avoided - when it is time to look them up or print them, you would have to check each time whether it is a list or string.)
So I am struggling with getting a value from a JSON response. Looking in other post I have managed to write this code but when I try to search for the key (character_id) that I want in the dictionary python says that the key doesn't exist. My solution consists in getting the JSON object from the response, converting it into a string with json.dumps() and the converting it into a dictionary with json.loads(). Then I try to get 'character_id' from the dictionary but it doesn't exist. I am guessing it is related with the format of the dictionary but I have little to none experience in python. The code that makes the query and tries to get the values is this: (dataRequest is a fuction that makes the request and return the response from the api)
characterName = sys.argv[1];
response = dataRequest('http://census.daybreakgames.com/s:888/get/ps2:v2/character/?name.first_lower=' + characterName + '&c:show=character_id')
jsonString = json.dumps(response.json())
print(jsonString)
dic = json.loads(jsonString)
print(dic)
if 'character_id' in dic:
print(dic['character_id'])
The output of the code is:
{"character_list": [{"character_id": "5428662532301799649"}], "returned": 1}
{'character_list': [{'character_id': '5428662532301799649'}], 'returned': 1}
Welcome #Prieto! From what I can see, you probably don't need to serialize/de-serialize the JSON -- response.json() returns a python dictionary object already.
The issue is that you are looking for the 'character_id' key at the top-level of the dictionary, when it seems to be embedded inside another dictionary, that is inside a list. Try something like this:
#...omitted code
for char_obj in dic["character_list"]:
if "character_id" in char_obj:
print(char_obj["character_id"])
if your dic is like {"character_list": [{"character_id": "5428662532301799649"}], "returned": 1}
you get the value of character_id by
print(dic['character_list'][0][character_id])
The problem here is that you're trying to access a dictionary where the key is actually character_list.
What you need to do is to access the character_list value and iterate over or filter the character_id you want.
Like this:
print(jsonString)
dic = json.loads(jsonString)
print(dic)
character_information = dic['character_list'][0] # we access the character list and assume it is the first value
print(character_information["character_id"]) # this is your character id
The way I see it, the only hiccup with the code is this :
if 'character_id' in dic:
print(dic['character_id'])
The problem is that, the JSON file actually consists of actually 2 dictionaries , first is the main one, which has two keys, character_list and returned. There is a second sub-dictionary inside the array, which is the value for the key character_list.
So, what your code should actually look like is something like this:
for i in dic["character_list"]:
print(i["character_id"])
On a side-note, it will help to look at JSON file in this way :
{
"character_list": [
{
"character_id": "5428662532301799649"
}
],
"returned": 1
}
,where, elements enclosed in curly-brackets'{}' imply they are in a dictionary, whereas elements enclosed in curly-brackets'[]' imply they are in a list
I have a list like this, i need to get the value of the dictionary for both the keys inside the dictionary(dict)
dict = [{'module': 'https://svn.domain.com/svn/reponame/branchname', 'revision': 22295}]
expected output :
https://svn.domain.com/svn/reponame/branchname
22295
Your dict is actually a dictionary within a list. Try:
print(dict[0]['module'])
print(dict[0]['revision'])
I have a list of dicts ('sortings') that I am trying to iterate through to access a values in one specific key of each dict. My code keeps saying that there is a key error for the desired value in the dict. If I print inside the for loop, it prints with the values entered but once I exit the for loop it says there is a key error.
for i in range(sort_len):
sentence = sortings[i]['content']
containing_messages.append(sentence)
print(containing_messages)
This is an answer for my understanding of the question. I would require the given input and expected output to provide a better answer.
list_of_dicts = [{'keya':'value1_1','keyb':'value2_1','keyc':'value3_1'},
{'keya':'value1_2','keyb':'value2_2','keyc':'value3_2'},
{'keya':'value1_3','keyb':'value2_3','keyc':'value3_3'}]
list_of_key_values = [my_dict['keyb'] for my_dict in list_of_dicts]
print list_of_key_values
Currently my code is like this:
.append("Last Name {}, First Name {} Stats: {}".format(result["L_Name"], result["F_Name"], result["Stats"]))
this code works but the output isn't exactly the ones I want the code to display.
the problem is that the Stats has another list
L_Name: Doe
F_Name: John
Contribution:
Month
Value
Returns
is there a way to just pick out only the Value from the Stats by just adding or changing something in my append?
specifically in this part?
, result["Stats"]))
If you are only after one value of Stats, you can get the value at a certain index. Assuming Value is at index 1 and Stats is a standard Python list:
, result["Stats"][1]))
Notice that you can access the items of the JSON structure in the format string itself. This is clearer than using positional arguments if the format string is very complicated. Additionally, you can pass the whole dictionary into format_map:
l.append("Last Name {L_Name}, First Name {F_Name} Stats: {Stats[Value]}"
.format_map(result))
(In Python 2, format_map doesn't exist, use format(**result) instead.
In the future please consider posting working code only so we can reproduce your issue. I am going to assume result['stats'] is a dictionary and the bulleted list are key:value pairs.
You can access the "Contribution" key of your result["Stats"] dictionary which results in list. You can then slice the second element of the list with [1].
_.append("Last Name {}, First Name {} Stats: {}".format(
result["L_Name"],
result["F_Name"],
result["Stats"]["Contribution"][1]))
This assumes result['stats'] looks like:
result['stats'] = {
'L_Name': 'Doe',
'F_Name': 'John',
'Contribution': [Month, Value, Returns]}
Thanks everyone I was able to get a hint from your answers
result["Stats"]["Contribution"][1]
worked well for me