I have checked a lot of similar posts where users were having issues with the Pycharm debugger not working, but running it using the run button working fine, but none of them applied to an issue with opencv.
Here is my simple script:
import numpy as np
import cv2
image = cv2.imread('../FGVC/data/balloon/1548266469.88633.png')
image_2 = cv2.imread('../FGVC/data/balloon_mask/1.jpg')
cv2.imshow('img', image)
cv2.imshow('img2', image_2)
yo = np.bitwise_and(image, image_2)
ye = np.bitwise_or(image, image_2)
cv2.imshow('combined', yo)
cv2.imshow('combinedd', ye)
cv2.waitKey(0)
I get the following exception whenever I import cv2 through the python debugger.
[Errno 2] No such file or directory: '/home/user/anaconda3/envs/py36/lib/python3.6/site-packages/cv2/config-3.6.py'
I am using an anaconda virtual environment running Python 3.6. I did check that the cv2 directory and indeed there is no config-3.6.py file, but there was a config-3.py file, so I duplicated that and called it config-3.6.py, but then I started running into the following issue:
(<class 'KeyError'>, KeyError(b'LD_LIBRARY_PATH',), <traceback object at 0x7fe97dd32ac8>)
This is the content of my config-3.6.py file.
PYTHON_EXTENSIONS_PATHS = [
LOADER_DIR
] + PYTHON_EXTENSIONS_PATHS
ci_and_not_headless = False
try:
from .version import ci_build, headless
ci_and_not_headless = ci_build and not headless
except:
pass
# the Qt plugin is included currently only in the pre-built wheels
if sys.platform.startswith("linux") and ci_and_not_headless:
os.environ["QT_QPA_PLATFORM_PLUGIN_PATH"] = os.path.join(
os.path.dirname(os.path.abspath(__file__)), "qt", "plugins"
)
# Qt will throw warning on Linux if fonts are not found
if sys.platform.startswith("linux") and ci_and_not_headless:
os.environ["QT_QPA_FONTDIR"] = os.path.join(
os.path.dirname(os.path.abspath(__file__)), "qt", "fonts"
)
Edit: what is also strange is that after the exception being raised the rest of the open-cv script works as expected the same way it works with the run button.
I figured out that the issue was that I had made it so the Pycharm debugger would break "On Raise" of an exception for a different project and the settings carried over to this project.
I just unchecked the "On Raise" option and the problem was solved.
I tried loading a shapefile on Python using PyQgis API but to no avail. I double-checked the path to shapefile and found it to be correct. QGIS module also seems to be imported just fine. When I checked on the provider list in QgsRegistry, it returns nothing. May I know what I'm missing or how I should troubleshoot?
I am using Ubuntu 12.04, QGIS 2.4.0 Chugiak and Python 2.7.3.
Thank you in advance!
Following are my output and code:
"
/usr/bin/python2.7 /home/victorzhiyulee/IdeaProjects/Delineation/select_dun_calculate_print.py
Application state:
QGIS_PREFIX_PATH env var:
Prefix: /usr/bin/qgis
Plugin Path: /usr/bin/qgis/lib/qgis/plugins
Package Data Path: /usr/bin/qgis/share/qgis
Active Theme Name:
Active Theme Path: :/images/themes//
Default Theme Path: :/images/themes/default/
SVG Search Paths: /usr/bin/qgis/share/qgis/svg/
User DB Path: /usr/bin/qgis/share/qgis/resources/qgis.db
Provider List
Could not find OGR provider!
File exists; Path is correct
('/home/victorzhiyulee/Desktop/dun.shp', 'dun', 'ogr')
Layer failed to load!
Process finished with exit code 0
"
__author__ = 'victorzhiyulee'
# Importing QGis API
# Importing OGR & OSR
import os
import sys
import PyQt4.QtCore
import PyQt4.QtGui
import qgis.core
import qgis.gui
from qgis.core import *
from qgis.gui import *
from osgeo import ogr, osr
from PyQt4.QtCore import *
# Supply path to the QGis resources on your PC
# noinspection PyTypeChecker
QgsApplication.setPrefixPath("/usr/bin/qgis", True)
# Load providers
QgsApplication.initQgis()
# Show setting of parameters
print QgsApplication.showSettings()
# Load vector layer
data_source = "/home/victorzhiyulee/Desktop/dun.shp"
layer_name = "dun"
provider_name = "ogr"
fileInfo = QFileInfo(data_source)
print('Provider List')
print(QgsProviderRegistry.instance().providerList())
r = QgsProviderRegistry.instance()
if not 'ogr' in r.providerList():
print 'Could not find OGR provider!'
else:
print 'Providers found ok!'
# Add layer to the registry
layer = QgsVectorLayer(data_source, fileInfo.fileName(), provider_name)
QgsMapLayerRegistry.instance().addMapLayer(layer)
if fileInfo.exists():
print("File exists; Path is correct")
print(data_source, layer_name, provider_name)
layer = QgsVectorLayer(data_source, fileInfo.fileName(), provider_name)
if not layer.isValid():
print("Layer failed to load!")
else:
print("Yes, layer loads successfully")
features = layer.getFeatures()
else:
print("Check if your path is correct")
QgsApplication.exitQgis()
iteration = layer.getFeatures()
for features in iteration:
# Fetch attributes
attris = features.attributes()
print(attris)
QgsApplication.exitQgis()
I think that the prefix path isn't correct, the path shuld be "/usr/share/qgis", so the prefix for me is only "/usr".
I have check the paths in the output of print QgsApplication.showSettings() to discover this.
How do I convert an svg to png, in Python? I am storing the svg in an instance of StringIO. Should I use the pyCairo library? How do I write that code?
Here is what I did using cairosvg:
from cairosvg import svg2png
svg_code = """
<svg xmlns="http://www.w3.org/2000/svg" width="24" height="24" viewBox="0 0 24 24" fill="none" stroke="#000" stroke-width="2" stroke-linecap="round" stroke-linejoin="round">
<circle cx="12" cy="12" r="10"/>
<line x1="12" y1="8" x2="12" y2="12"/>
<line x1="12" y1="16" x2="12" y2="16"/>
</svg>
"""
svg2png(bytestring=svg_code,write_to='output.png')
And it works like a charm!
See more: cairosvg document
The answer is "pyrsvg" - a Python binding for librsvg.
There is an Ubuntu python-rsvg package providing it. Searching Google for its name is poor because its source code seems to be contained inside the "gnome-python-desktop" Gnome project GIT repository.
I made a minimalist "hello world" that renders SVG to a cairo
surface and writes it to disk:
import cairo
import rsvg
img = cairo.ImageSurface(cairo.FORMAT_ARGB32, 640,480)
ctx = cairo.Context(img)
## handle = rsvg.Handle(<svg filename>)
# or, for in memory SVG data:
handle= rsvg.Handle(None, str(<svg data>))
handle.render_cairo(ctx)
img.write_to_png("svg.png")
Update: as of 2014 the needed package for Fedora Linux distribution is: gnome-python2-rsvg. The above snippet listing still works as-is.
Install Inkscape and call it as command line:
${INKSCAPE_PATH} -z -f ${source_svg} -w ${width} -j -e ${dest_png}
You can also snap specific rectangular area only using parameter -j, e.g. co-ordinate "0:125:451:217"
${INKSCAPE_PATH} -z -f ${source_svg} -w ${width} -j -a ${coordinates} -e ${dest_png}
If you want to show only one object in the SVG file, you can specify the parameter -i with the object id that you have setup in the SVG. It hides everything else.
${INKSCAPE_PATH} -z -f ${source_svg} -w ${width} -i ${object} -j -a ${coordinates} -e ${dest_png}
I'm using Wand-py (an implementation of the Wand wrapper around ImageMagick) to import some pretty advanced SVGs and so far have seen great results! This is all the code it takes:
with wand.image.Image( blob=svg_file.read(), format="svg" ) as image:
png_image = image.make_blob("png")
I just discovered this today, and felt like it was worth sharing for anyone else who might straggle across this answer as it's been a while since most of these questions were answered.
NOTE: Technically in testing I discovered you don't even actually have to pass in the format parameter for ImageMagick, so with wand.image.Image( blob=svg_file.read() ) as image: was all that was really needed.
EDIT: From an attempted edit by qris, here's some helpful code that lets you use ImageMagick with an SVG that has a transparent background:
from wand.api import library
import wand.color
import wand.image
with wand.image.Image() as image:
with wand.color.Color('transparent') as background_color:
library.MagickSetBackgroundColor(image.wand,
background_color.resource)
image.read(blob=svg_file.read(), format="svg")
png_image = image.make_blob("png32")
with open(output_filename, "wb") as out:
out.write(png_image)
I did not find any of the answers satisfactory. All the mentioned libraries have some problem or the other like Cairo dropping support for python 3.6 (they dropped Python 2 support some 3 years ago!). Also, installing the mentioned libraries on the Mac was a pain.
Finally, I found the best solution was svglib + reportlab. Both installed without a hitch using pip and first call to convert from svg to png worked beautifully! Very happy with the solution.
Just 2 commands do the trick:
from svglib.svglib import svg2rlg
from reportlab.graphics import renderPM
drawing = svg2rlg("my.svg")
renderPM.drawToFile(drawing, "my.png", fmt="PNG")
Are there any limitations with these I should be aware of?
Try this: http://cairosvg.org/
The site says:
CairoSVG is written in pure python and only depends on Pycairo. It is
known to work on Python 2.6 and 2.7.
Update November 25, 2016:
2.0.0 is a new major version, its changelog includes:
Drop Python 2 support
Another solution I've just found here How to render a scaled SVG to a QImage?
from PySide.QtSvg import *
from PySide.QtGui import *
def convertSvgToPng(svgFilepath,pngFilepath,width):
r=QSvgRenderer(svgFilepath)
height=r.defaultSize().height()*width/r.defaultSize().width()
i=QImage(width,height,QImage.Format_ARGB32)
p=QPainter(i)
r.render(p)
i.save(pngFilepath)
p.end()
PySide is easily installed from a binary package in Windows (and I use it for other things so is easy for me).
However, I noticed a few problems when converting country flags from Wikimedia, so perhaps not the most robust svg parser/renderer.
A little extension on the answer of jsbueno:
#!/usr/bin/env python
import cairo
import rsvg
from xml.dom import minidom
def convert_svg_to_png(svg_file, output_file):
# Get the svg files content
with open(svg_file) as f:
svg_data = f.read()
# Get the width / height inside of the SVG
doc = minidom.parse(svg_file)
width = int([path.getAttribute('width') for path
in doc.getElementsByTagName('svg')][0])
height = int([path.getAttribute('height') for path
in doc.getElementsByTagName('svg')][0])
doc.unlink()
# create the png
img = cairo.ImageSurface(cairo.FORMAT_ARGB32, width, height)
ctx = cairo.Context(img)
handler = rsvg.Handle(None, str(svg_data))
handler.render_cairo(ctx)
img.write_to_png(output_file)
if __name__ == '__main__':
from argparse import ArgumentParser
parser = ArgumentParser()
parser.add_argument("-f", "--file", dest="svg_file",
help="SVG input file", metavar="FILE")
parser.add_argument("-o", "--output", dest="output", default="svg.png",
help="PNG output file", metavar="FILE")
args = parser.parse_args()
convert_svg_to_png(args.svg_file, args.output)
Here is a another solution without using rsvg(which is currently not available for windows).Only install cairosvg using pip install CairoSVG
svg2png.py
from cairosvg import svg2png
svg_code = open("input.svg", 'rt').read()
svg2png(bytestring=svg_code,write_to='output.png')
SVG scaling and PNG rendering
Using pycairo and librsvg I was able to achieve SVG scaling and rendering to a bitmap. Assuming your SVG is not exactly 256x256 pixels, the desired output, you can read in the SVG to a Cairo context using rsvg and then scale it and write to a PNG.
main.py
import cairo
import rsvg
width = 256
height = 256
svg = rsvg.Handle('cool.svg')
unscaled_width = svg.props.width
unscaled_height = svg.props.height
svg_surface = cairo.SVGSurface(None, width, height)
svg_context = cairo.Context(svg_surface)
svg_context.save()
svg_context.scale(width/unscaled_width, height/unscaled_height)
svg.render_cairo(svg_context)
svg_context.restore()
svg_surface.write_to_png('cool.png')
RSVG C binding
From the Cario website with some minor modification. Also a good example of how to call a C-library from Python
from ctypes import CDLL, POINTER, Structure, byref, util
from ctypes import c_bool, c_byte, c_void_p, c_int, c_double, c_uint32, c_char_p
class _PycairoContext(Structure):
_fields_ = [("PyObject_HEAD", c_byte * object.__basicsize__),
("ctx", c_void_p),
("base", c_void_p)]
class _RsvgProps(Structure):
_fields_ = [("width", c_int), ("height", c_int),
("em", c_double), ("ex", c_double)]
class _GError(Structure):
_fields_ = [("domain", c_uint32), ("code", c_int), ("message", c_char_p)]
def _load_rsvg(rsvg_lib_path=None, gobject_lib_path=None):
if rsvg_lib_path is None:
rsvg_lib_path = util.find_library('rsvg-2')
if gobject_lib_path is None:
gobject_lib_path = util.find_library('gobject-2.0')
l = CDLL(rsvg_lib_path)
g = CDLL(gobject_lib_path)
g.g_type_init()
l.rsvg_handle_new_from_file.argtypes = [c_char_p, POINTER(POINTER(_GError))]
l.rsvg_handle_new_from_file.restype = c_void_p
l.rsvg_handle_render_cairo.argtypes = [c_void_p, c_void_p]
l.rsvg_handle_render_cairo.restype = c_bool
l.rsvg_handle_get_dimensions.argtypes = [c_void_p, POINTER(_RsvgProps)]
return l
_librsvg = _load_rsvg()
class Handle(object):
def __init__(self, path):
lib = _librsvg
err = POINTER(_GError)()
self.handle = lib.rsvg_handle_new_from_file(path.encode(), byref(err))
if self.handle is None:
gerr = err.contents
raise Exception(gerr.message)
self.props = _RsvgProps()
lib.rsvg_handle_get_dimensions(self.handle, byref(self.props))
def get_dimension_data(self):
svgDim = self.RsvgDimensionData()
_librsvg.rsvg_handle_get_dimensions(self.handle, byref(svgDim))
return (svgDim.width, svgDim.height)
def render_cairo(self, ctx):
"""Returns True is drawing succeeded."""
z = _PycairoContext.from_address(id(ctx))
return _librsvg.rsvg_handle_render_cairo(self.handle, z.ctx)
Here is an approach where Inkscape is called by Python.
Note that it suppresses certain crufty output that Inkscape writes to the console (specifically, stderr and stdout) during normal error-free operation. The output is captured in two string variables, out and err.
import subprocess # May want to use subprocess32 instead
cmd_list = [ '/full/path/to/inkscape', '-z',
'--export-png', '/path/to/output.png',
'--export-width', 100,
'--export-height', 100,
'/path/to/input.svg' ]
# Invoke the command. Divert output that normally goes to stdout or stderr.
p = subprocess.Popen( cmd_list, stdout=subprocess.PIPE, stderr=subprocess.PIPE )
# Below, < out > and < err > are strings or < None >, derived from stdout and stderr.
out, err = p.communicate() # Waits for process to terminate
# Maybe do something with stdout output that is in < out >
# Maybe do something with stderr output that is in < err >
if p.returncode:
raise Exception( 'Inkscape error: ' + (err or '?') )
For example, when running a particular job on my Mac OS system, out ended up being:
Background RRGGBBAA: ffffff00
Area 0:0:339:339 exported to 100 x 100 pixels (72.4584 dpi)
Bitmap saved as: /path/to/output.png
(The input svg file had a size of 339 by 339 pixels.)
Try this python script:
Don't forget to install cairosvg: pip3 install cairosvg
#!/usr/bin/env python3
import os
import cairosvg
for file in os.listdir('.'):
if os.path.isfile(file) and file.endswith(".svg"):
name = file.split('.svg')[0]
cairosvg.svg2png(url=name+'.svg',write_to=name+'.png')
Try using Gtk.Image and Gdk.Pixbuf
import gi
gi.require_version('Gtk', '3.0')
gi.require_version('Gdk', '3.0')
from gi.repository import Gdk, Gtk
from PIL import Image
image = Gtk.Image()
image.set_from_file("path/to/image.svg")
pb = image.get_pixbuf()
pb.savev("path/to/convented/image.jpeg","jpeg",[],[])
im = Image.open("path/to/convented/image.jpeg")
pix = im.load()
print(pix[1,1])
Actually, I did not want to be dependent of anything else but Python (Cairo, Ink.., etc.)
My requirements were to be as simple as possible, at most, a simple pip install "savior" would suffice, that's why any of those above didn't suit for me.
I came through this (going further than Stackoverflow on the research).
https://www.tutorialexample.com/best-practice-to-python-convert-svg-to-png-with-svglib-python-tutorial/
Looks good, so far. So I share it in case anyone in the same situation.
All the answer's here are great, but I figure I'll mention that I have made a simple library that loads SVG's files as pillow Image instances which can then be exported. It uses inkscape like in blj's answer, but renders to stdout so that no temporary files are made. There's some basic usage stuff in the README.
https://github.com/jlwoolf/pillow-svg
EDIT:
As suggested, here's a brief explanation, since the link could become invalid:
The library uses inkscape's command line interface to convert the image to a png of a specific size or dpi using the python subprocess library. By setting --export-filename to -, inkscape redirects the output to the stdout. The first two lines are discarded, and the remaining output is passed to PIL.Image.open, converting it to pillow image instance.
import subprocess
from PIL import Image
options = ["inkscape", "--export-filename=-", "--export-type=png", "file.svg"]
pipe = subprocess.Popen(options, stdout=subprocess.PIPE)
pipe.stdout.readline()
pipe.stdout.readline()
img = Image.open(pipe.stdout)
From there you can do whatever pillow image operations you need (like export as a jpg, resize, crop, etc).
EDIT 2:
Just added support for skia-python (haven't fully tested it, but seems to work so far). This way you can convert an svg to png with only a single pip install (no need to use inkscape).
Here is an explanation of how the library uses skia-python:
First, the svg file is loaded into a skia.SVGDOM. From there you can grab the SVGDOM's dimensions, using containerSize. Then a skia.Surface of the desired image output size is made. The canvas is scaled to fit the svg to the surface, and then the svg is rendered. From there, an image snapshot can be made, which can then be fed to PIL.Image.open.
import skia
from PIL import Image
skia_stream = skia.Stream.MakeFromFile("file.svg")
skia_svg = skia.SVGDOM.MakeFromStream(skia_stream)
svg_width, svg_height = skia_svg.containerSize()
surface_width, surface_height = 512, 512
surface = skia.Surface(surface_width, surface_height)
with surface as canvas:
canvas.scale(surface_width / svg_width, surface_height / svg_height)
skia_svg.render(canvas)
with io.BytesIO(surface.makeImageSnapshot().encodeToData()) as f:
img = Image.open(f)
img.load()
Edit 3:
I have fleshed out the library much much more. There is a command line utility now for easy svg conversion, along with more documentation explaining usage. Hope it helps!
Posting my code from this StackOverflow answer. It's a workaround to svglib+reportlib not supporting a transparent background and no scaling (see #sarang's answer and #ualter-jr's answer as well as these Github issues on scaling not working and this one on transparency)
This uses pyMuPDF to render an intermediate pdf from reportlab to PNG.
The big advantage is that it doesn't need any external libraries as pymupdf comes with precompiled wheels for Windows, Linux and MacOS.
The whole thing is as easy as
pip install pymupdf svglib
and then executing the following lines
import fitz
from svglib import svglib
from reportlab.graphics import renderPDF
# Convert svg to pdf in memory with svglib+reportlab
# directly rendering to png does not support transparency nor scaling
drawing = svglib.svg2rlg(path="input.svg")
pdf = renderPDF.drawToString(drawing)
# Open pdf with fitz (pyMuPdf) to convert to PNG
doc = fitz.Document(stream=pdf)
pix = doc.load_page(0).get_pixmap(alpha=True, dpi=300)
pix.save("output.png")