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Problem with flask using Python 3.7.6 with vscode on mac

I have a weird problem with some code I want to run. The code itself should not be the problem since it is downloaded from a Udemy class and not modified:
# coding=utf-8
from flask import Flask, render_template, request
app = Flask(__name__)
#app.route("/")
def hello():
items = ["Apfel", "Birne", "Banane"]
return render_template("start.html", name="Max Mustermann", items=items)
#app.route("/test")
def test():
name = request.args.get("name")
return render_template("test.html", name=name)
I found online that, to start the emulated webserver(?) I have to rund the following temrinal commands before I can see the output:
(base) Christophs-MBP:13-23 chris$ export FLASK_APP=run.py run flask
(base) Christophs-MBP:13-23 chris$ export FLASK_APP=run.py run flask
(base) Christophs-MBP:13-23 chris$ export FLASK_APP=run.py
(base) Christophs-MBP:13-23 chris$ run flask
bash: run: command not found
No reaction to my terminal commands
Basically there is no reaction to the command to start the server(?).It should reply with "Running on 127.0.0.1:5000" as soon as I've run the command once.
If I go to my browser, there is no page when I address http://127.0.0.1:5000. What am I doing wrong? I am pretty new to Python and an absolute rookie regarding the terminal. Not sure if I broke something there, since trying to install pyenv to manage my Python installs better as recommended by a friend does not work either (I cannot update the SDK headers as described on RealPython

What are the export statements?
On Mac, export key=value creates a new (or updates an existing one) environment variable - the tutorial most likely simply asked you to provide one where key is FLASK_APP and value is a path to your app.
To verify it's been saved correctly, you can list the variables by just typing export in the terminal and finding out what's inside each of the environment variables on your system (if you want to only view FLASK_APP you can type export | grep FLASK_APP).
Why do you need FLASK_APP?
When you call flask run in your terminal, you will see the following message:
Error: Could not locate a Flask application. You did not provide the "FLASK_APP" environment variable, and a "wsgi.py" or "app.py"
module was not found in the current directory.
I presume your file is called run.py, therefore none of the conditions are met. You could rename run.py to app.py and simply type flask run in the terminal, but you can also type export FLASK_APP=<path-to-run.py>. It seems the tutorial author decided to do the latter. Keep in mind that if you rename your file to app.py you will need to run flask run within the directory that file lives in. You can change directory in the terminal using cd command.
Why do you get bash: run: command not found?
bash is a language running inside your terminal, and it only knows of a few commands - it is not aware of any run commands. It does however know about flask command once you have installed it on your machine. Within the command's output there is a part which includes a run command:
Commands:
routes Show the routes for the app.
run Run a development server.
shell Run a shell in the app context.
Therefore, what you want to do is type flask run instead of just run in your terminal.

Running python script on xampp

I googled this and tried everything but I could not run my test.py on apache.
I have updated httpd.conf file to AddHandler .py
#!/usr/local/opt/python/bin/python3.7
print("Hello World!")
When I open this file in browser I am getting this error
Error message:
End of script output before headers: test.py

Have you tried to use Flask instead? It start a server that you can access via browser.
Here you can find an Hello world tutorial, or also here.
First, you have to install Flask: pip install Flask.
Then the server code, saved in a python file, for example your_server.py, has to look like this:
from flask import Flask
app = Flask(__name__)
#app.route("/")
def hello():
return "Hello World!"
if __name__ == "__main__":
app.run()
You can run the script, then go to http://localhost:5000/ and you'll see the 'Hello World!' message.
Now you can modify the method hello() to do what you need, or create other method/operations.
The tutorial can give you more details, but this is the main concept.

How do you execute a server-side python script using http.server?

I have a collection of python scripts, that I would like to be able to execute with a button press, from a web browser.
Currently, I run python -m http.server 8000 to start a server on port 8000. It serves up html pages well, but that's about all it does. Is it possible to have it execute a python script (via ajax) and return the output, instead of just returning the full text of the .py file.
Additionally, if not, is there a simple (as in only 1 or 2 files) way to make this work? I'm looking for the equivalent of PHP -s, but for python.
For completeness, this is my html
<h1>Hello World</h1>
<button>
Click me!
</button>
<script src="http://ajax.aspnetcdn.com/ajax/jQuery/jquery-3.3.1.js"> </script>
<script>
$('button').click(function(){
$.get('/gui/run_bash.py');
});
</script>

Add --cgi to your command line.
python -m http.server --cgi 8000
Then place your python scripts in ./cgi-bin and mark them as executable.
$ mkdir cgi-bin
$ cp hello.py cgi-bin/hello.py
$ chmod +x cgi-bin/hello.py
You may need to slightly modify your python scripts to support the CGI protocol.
Here is the server running:
$ cat cgi-bin/hello.py
#! /usr/bin/env python3
print("Content-Type: application/json")
print()
print('{"hello": "world"}')
radams#wombat:/tmp/z/h$ python -m http.server --cgi
Serving HTTP on 0.0.0.0 port 8000 (http://0.0.0.0:8000/) ...
127.0.0.1 - - [20/Mar/2018 18:04:16] "GET /cgi-bin/hello.py HTTP/1.1" 200 -
Reference: https://docs.python.org/3/library/http.server.html#http.server.CGIHTTPRequestHandler

http.server merely serves static files, it does not do any serverside processing or execute any code when you hit a python file. If you want to run some python code, you'll have to write an application to do that. Flask is a Python web framework that is probably well-suited to this task.
Your flask application might look something like this for executing scripts...
import subprocess
from flask import Flask
app = Flask(__name__)
SCRIPTS_ROOT = '/path/to/script_dir'
#app.route('/run/<script_name>')
def run_script(script_name):
fp = os.path.join(SCRIPTS_ROOT, script_name)
try:
output = subprocess.check_output(['python', fp])
except subprocess.CalledProcessError as call:
output = call.output # if exit code was non-zero
return output.encode('utf-8') # or your system encoding
if __name__ == '__main__':
app.run(host='127.0.0.1', port=8000)
And of course, I should include an obligatory warning 'having a webserver execute commands like this is insecure', etc, etc. Check out the Flask quickstart for more details.

СGI python3 403 error

I am asking it because I write very simply app but IT DON'T WORK.
I wrote this command in terminal in the /dir:
python3 -m http.server --cgi
My script is in dir/cgi-bin/hp.py and that code:
#!/usr/bin/env python3
print"Content-type: text/html"
print()
print"<h1>Hello world!</h1>"
This I saw in window of browser:
Error response
Error code: 403
Message: CGI script is not executable ('/cgi-bin/hp.py').
Error code explanation: HTTPStatus.FORBIDDEN - Request forbidden --
authorization will not help."
How can I fix it?

Here are the following steps which I tried to reproduce the problem:
# app.py
print("Content-type: text/html")
print()
print("<h1>Hello world!</h1>")
Created a file app.py in cgi-bin directory
Used command to run http.server with cgi
python -m http.server --bind localhost --cgi 8000
I tried accessing the path "http:localhost/cgi-bin/" got Error 403
Now the resolving part, which is opening the link in browser.
I ran the command:
python -mwebbrowser http://localhost:8000/cgi-bin/app.py
After the while it gave me the result, and I was able to access the link for the step 2 also.
I hope that helps you.
Result:

Run python files through browser on localhost [duplicate]

When I run python -m SimpleHTTPServer 8000 or python -m CGIHTTPServer 8000 in my shell I am hosting the content of my current directory to the internet.
I would like to make the following cgi_script.py work correctly using the above command in the command line when I browse to 192.xxx.x.xx:8000/cgi_script.py
#!/usr/bin/env python
print "Content-Type: text/html"
print
print """\
<html>
<body>
<h2>Hello World!</h2>
</body>
</html>
"""
But this script is displayed literally and not only the "Hello World!" part.
Btw I changed the file permissions to 755 for cgi_script.py as well as the folder I am hosting it from.

Try with python -m CGIHTTPServer 8000.
Note that you have to move the script to a cgi-bin or htbin directory in order to be runnable.

SO doesn't allow me to comment so I'm adding this as a separate answer, addition to rodrigo's.
You can use another parameter cgi_directories which defaults to ['/cgi-bin', '/htbin']. More info here

In Python3 the command line is simply
python3 -m http.server --cgi 8000

When I ran into this issue I found that depending on which directory you are in when you run the python -m CGIHTTPServer 8000 command yields different results. When attempting to run the command while in the cgi-bin directory the browser continued to return the raw script code. once I cd'ed one level higher and ran the python -m CGIHTTPServer 8000 command again my script began executing.

#Bentley4 -ifyou are still not able to do,
try importing cgi.
#!C:\Python34\python.exe -u
import cgi
print ("Content-type:text/html")
HTH

This work for me, run the python -m CGIHTTPServer 8000 command same menu level with cgi-bin,and move cgi_script.py into cgi-bin folder.In browser type http://localhost:8000/cgi-bin/cgi_script.py