So i wanted the user to enter date and based on that day to get named day of the week, for example today's date is 2022.11.10, so wanted answer would be Thursday.
I know this is wrong, can anybody help?
import datetime
def dayOfTheWeek(day, month, year):
date = datetime.date(year, month, day)
weekday = date.weekday()
day_dict = { 0 : "Monday", 1 : "Tuesday", 2 : "Wednesday", 3 : "Thursday", 4 : "Friday", 5 : "Sturday", 6 : "Sunday"}
for key in day_dict.key():
if weekday == key:
return day[key]
year = int(input("Year: "))
month = int(input("Month: "))
day = int(input("Day: "))
dayOfTheWeek(day, month, year)
Instead of going through the dictionary with for loop, you can simply return the result already converted by dictionary:
import datetime
def dayOfTheWeek(day, month, year):
date = datetime.date(year, month, day)
weekday = date.weekday()
day_dict = { 0 : "Monday", 1 : "Tuesday", 2 : "Wednesday", 3 : "Thursday", 4 : "Friday", 5 : "Sturday", 6 : "Sunday"}
return day_dict[weekday]
year = int(input("Year: "))
month = int(input("Month: "))
day = int(input("Day: "))
dayOfTheWeek(day, month, year)
Try this
from datetime import datetime
date = datetime(year=2022, month=11, day=10)
weekday_name = date.strftime('%A')
print(weekday_name)
See here for further information about strftime function.
Related
I need to check if a given date is exactly a month ago from today, for example, if today is 01-Nov-2021 then exactly a month ago will be 01-Oct-2021 (not exactly 30 days.)
I wrote a code and it works fine
today = fields.Date.from_string(fields.Date.today())
if today.month == 1:
one_month_ago = today.replace(year=today.year - 1, month=12)
else:
extra_days = 0
while True:
try:
one_month_ago = today.replace(month=today.month - 1, day=today.day -
extra_days)
break
except ValueError:
extra_days += 1
if one_month_ago == given_date:
# do something
else:
# do something
It handles well mostly all the cases but mishandles some cases. For example, the given date is 31-March-2021 and today date is 30-April-2021 and 31-April-2021 will not come to compare. I need my code to run daily and check something. It also mishandles cases of 29-31 January because 29-31 February will not come to compare.
From the given date, you can find the previous month and year and using these two obtained values, find the length of the previous month. The last thing to be done will be to compare the day of the given date with the length of the previous month and accordingly, return the desired date.
Demo:
from datetime import date
from calendar import monthrange
def date_a_month_ago(today):
x = today.month - 1
previous_month = 12 if x == 0 else x
year = today.year - 1 if x == 0 else today.year
last_day_of_previous_month = monthrange(year, previous_month)[1]
day = last_day_of_previous_month if today.day > last_day_of_previous_month else today.day
return date(year, previous_month, day)
# Tests
print(date_a_month_ago(date(2021, 11, 1)))
print(date_a_month_ago(date(2021, 1, 31)))
print(date_a_month_ago(date(2021, 12, 31)))
print(date_a_month_ago(date(2021, 3, 29)))
print(date_a_month_ago(date(2020, 3, 29)))
print(date_a_month_ago(date(2021, 3, 30)))
print(date_a_month_ago(date(2020, 3, 30)))
Output:
2021-10-01
2020-12-31
2021-11-30
2021-02-28
2020-02-29
2021-02-28
2020-02-29
ONLINE DEMO
May be like this:
from typing import Tuple
def last_month(year: int, month: int) -> Tuple[int, int]:
y, m = year, month - 1
if m == 0:
y, m = y - 1, 12
return y, m
def one_month_ago(today: datetime) -> datetime:
y, m = last_month(today.year, today.month)
dt = today.replace(year=y, month=m)
for day in range(today.day, 0, -1):
try:
return dt.replace(day=day)
except ValueError:
...
I did this and it's giving me the required output:
from datetime import date
from calendar import monthrange
def is_one_month(given_date, today):
x = today.month - 1
previous_month = 12 if x == 0 else x
year = today.year - 1 if x == 0 else today.year
last_day_of_previous_month = monthrange(year, previous_month)[1]
day = last_day_of_previous_month if today.day > last_day_of_previous_month else today.day
one_month_ago = date(year, previous_month, day)
if today.month == 2:
if given_date.month == today.month-1 and given_date.year == today.year and given_date.day >= 28:
return 'it is one month before'
if today.month == 4 or today.month == 6 or today.month == 9 or today.month == 11:
if given_date.month == today.month-1 and given_date.day == 31:
return 'it is one month before'
if one_month_ago == given_date:
return 'it is one month before'
else:
return 'it is NOT one month before'
print(is_one_month(date(2021, 1, 30), date(2021, 2, 28)))
Output:
it is one month before
The program should prompt the user to enter the month and year (as integers) and display the number of days in the month, showing the month name. For example, if the user entered month 2 and the year 2000, the program should display:
Enter a month as an integer (1-12): 2
Enter a year: 2000
There are 29 days in February of 2000
def numberOfDays(month, year):
daysInMonths = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
if month > len(daysInMonths) or year < 0 or month < 0:
return "Please enter a valid month/year"
return daysInMonths[month-1] + int((year % 4) == 0 and month == 2)
def main():
year = int(input("Enter a year: "))
month = int(input("Enter a month in terms of a number: "))
print(month, year, "has", numberOfDays(month, year) , "days")
if __name__ == '__main__':
main()
In this program, I want to show the month's name and print it in the last.
How would the program be then? What should I do?
For example, if the input is 1, then 1 should be assigned as January and also be printed.
Use a dictionary:
dict_month = {1:"January", 2: "February"} # and so on ...
print(dict_month.get(month), year, "has", numberOfDays(month, year) , "days")
You may use the calendar module to get this done:
import calendar
months = list(calendar.month_name) #gets the list of months by name
obj = calendar.Calendar()
y, m = int(input('Enter year: ')), int(input('Enter a month as an integer (1-12): '))
days = calendar.monthrange(y, m)[1]
print(f'There are {days} days in {months[m]} of {y}')
And if all you want to do is to check if year is leap:
import calendar
print(calendar.isleap(int(input('Enter year: '))))
This is my first question here so please forgive and educate on any formatting errors. I am new to Python and going through automate the boring stuff. Decided to expand the date detection project by using the clipboard and formatting some things also. The problem I have is in any operation taken on the year part of the REGEX.
I have commented out my last attempt to validate the year and gave up and changed the REGEX to only find dates from 1000 to 2999 and skipped code validation of the dates.
I now need to validate leap years but I'm back to having to work with the year variable, but once again no operation has any effect.
Basically the problem is I can extract the year value and display it but I cannot modify it or do checks against it.
#! python3
#! detect dates in a block of text
import pyperclip
import re
#!import numpy as np
text = str(pyperclip.paste())
def datedetection(text):
dateRegex = re.compile(
r"""(
(\d|\d\d) #! match day
(/{1}) #! match /
(\d|\d\d) #! match month
(/{1}) #! match /
([1|2][0-9][0-9][0-9]) #! match year
)""",
re.VERBOSE,
)
matches = []
for groups in dateRegex.findall(text):
day = str(groups[1])
slash1 = str(groups[2])
month = str(groups[3])
slash2 = str(groups[4])
year = str(groups[5])
month_range_30 = ["04", "06", "09", "11"]
month_range_31 = ["01", "03", "05", "07", "08", "10", "12"]
month_range_Feb = ["02"]
#!year_range = np.arange(1000, 3000, 1).tolist()
if len(day) == 1:
day = "0" + day
else:
day = day
if len(month) == 1:
month = "0" + month
else:
month = month
if month in month_range_31:
if int(day) > 31:
day = "Too many days in a month with only 31 days."
slash1 = month = slash2 = year = ""
elif month in month_range_30:
if int(day) > 30:
day = "Too many days in a month with only 30 days."
slash1 = month = slash2 = year = ""
elif month in month_range_Feb:
if int(day) > 29:
day = "Too many days in February."
slash1 = month = slash2 = year = ""
elif int(month) > 12:
day = "Found an invalid month."
slash1 = month = slash2 = year = ""
elif month in month_range_Feb:
if (
int(day) == 29
and (int(year) % 4 == 0)
and (int(year) % 400 == 0)
and (int(year) % 100 == 0)
):
day = day
elif month in month_range_Feb:
if (
int(day) == 29
and (int(year) % 4 == 0)
and (int(year) % 100 != 0)
):
day = "Found an invalid leap year."
slash1 = month = slash2 = year = ""
#!elif year not in year_range:
#!day = "Year is out of range."
#!slash1 = month = slash2 = year = ""
dates = "".join([day, slash1, month, slash2, year])
matches.append(dates)
if len(matches) > 0:
pyperclip.copy("\n".join(matches))
print("Copied to clipboard:")
print("\n".join(matches))
else:
print("No dates found.")
datedetection(text)
In my approach to this project, I considered validating the days, months, and year ranges as part of the regular expression. I then defined functions to check for the leap year, and validate the number of days according to the months.
I found that way simpler and easier to understand and follow. As below:
dateRegex = re.compile(r'([0-3][0-9])/([0-1][0-9])/([1-2][0-9]{3})')
def is_leap_year(year):
year = int(year)
if year % 4 == 0:
if year % 100 == 0:
return year % 400 == 0
else:
return True
else:
return False
def is_valid_date(day, month, year):
if month == '02':
if is_leap_year(year):
return int(day) <= 29
else:
return int(day) <= 28
elif month in ['04', '06', '09', '11']:
return int(day) <= 30
else:
return int(day) <= 31
You can find the rest of my code below.
https://gist.github.com/alialbusaidi/f56e4c9342f622434f8bff0549f94884
The problem was the operations before the year operations. The day and month operations were overwriting the year values. Not entirely sure how or why at this point, but moving the year code above the day and month code has started to fix the issue.
I am trying to program a calendar that checks how many days from now/ ago (past and present) from raw_input. I need a loop that counts the days through the current year and adds it to a variable called: Total_days and this loop has to go through each year until it hits the current date that the code ran on. The end result is that the output gives you the date you entered in a complete sentence: eg. "10/08/1700 was ___ days ago" Basically my teacher explained that the past days has to add up until it hits that certain date using a loop(loops are required. This is an assignment, i cant use any other functions like delta, but loops and datetime stuff is good!) and then for the future it has to say how many days from now until that futuristic date happens using loops. I am very stumped and i need your guys' help.
Heres what i got so far:
import datetime
input_date = raw_input("Enter in full format (mm/dd/yyyy):")
year = input_date[6:10]
yeara = int(year)
montha = int(input_date[1:2])
daya = int(input_date[4:5])
from datetime import datetime
from datetime import date
now = datetime.now()
year = now.year
month = now.month
day = now.day
def isleapYear(year):
if year % 4 == 0:
check = True
if year % 100 == 0:
check = False
if year % 400 == 0:
check = True
total_days = 0
n = 12
moNum = [0,31,28,31,30,31,30,31,31,30,31,30,31]
while n > montha:
if yeara > year:
if year == isleapYear(year):
total_days += 366
elif year != isleapYear(year):
total_days += 365
if montha == month:
break
total_days += int(moNum[n])
if n == 02:
if isleapYear(year) == True:
total_days += 1
n -= 1
ny = 365
h = total_days
if yeara > year:
if year == isleapYear(year):
total_days += 366
elif year != isleapYear(year):
total_days += 365
if yeara>year:
time = "future"
if yeara<year:
time = "past"
if yeara==year:
if montha>month:
time = "future"
if montha<month:
time = past
if montha == month:
if daya>day:
time = "future"
if daya<day:
time = "past"
if daya==day:
time = "present"
print str(h.days) + " days in the " + str(time)
Thanks for helping out! i appreciate your help :)
Must you use a loop? Else, you can build from the following:
refdatestr = "2010/08/23"
refdate = datetime.strptime(refdatestr, "%Y/%m/%d")
now = datetime.now()
difference_days = (now-refdate).days
difference_days is a datetime.timedelta object. If refdate (or refdatestr) was in the future, this would be negative.
Here is an updated code, with everything fixed:
import datetime
input_date = raw_input("Enter in full format (mm/dd/yyyy):")
year = input_date[6:10]
yeara = int(year)
montha = int(input_date[1:2])
daya = int(input_date[4:5])
from datetime import datetime
from datetime import date
now = datetime.now()
year = now.year
month = now.month
day = now.day
def isleapYear(year):
if year % 4 == 0:
check = True
if year % 100 == 0:
check = False
if year % 400 == 0:
check = True
end_date = input_date
start_date = now
delta = date(year,month,day)
delta2 = date(yeara,montha,daya)
h = delta-delta2
if yeara>year:
time = "future"
if yeara<year:
time = "past"
if yeara==year:
if montha>month:
time = "future"
if montha<month:
time = past
if montha == month:
if daya>day:
time = "future"
if daya<day:
time = "past"
if daya==day:
time = "present"
print str(h.days) + " in the " + str(time)
The most important thing that you forgot is that there are functions in datetime that will automatically find the number of days till the input...
Hope this helps!!!
import datetime
def main():
date_string = input('Enter a date in mm/dd/yy format: ')
date_list = date_string.split('/')
month = int(date_list[0])
day = int(date_list[1])
year = int(date_list[2])
while month < 1 or month > 12:
print('Month entered is out of range')
date_string = input('Re-enter a date in mm/dd/yy format: ')
date_list = date_string.split('/')
month = int(date_list[0])
day = int(date_list[1])
year = int(date_list[2])
while day < 1 or day > 31:
print('Day entered is out of range')
date_string = input('Re-enter a date in mm/dd/yy format: ')
date_list = date_string.split('/')
month = int(date_list[0])
day = int(date_list[1])
year = int(date_list[2])
while year != 13:
print('Year does not represent 2013')
date_string = input('Re-enter a date in mm/dd/yy format: ')
date_list = date_string.split('/')
month = int(date_list[0])
day = int(date_list[1])
year = int(date_list[2])
print(month, day, year)
main()
When I run the program and enter months and days that are invalid, it progresses down until the year validation and will keep posting that prompt even if the input is invalid for one of the other inputs.
You could arrange this differently:
while True:
date_string = input('Enter a date in mm/dd/yy format: ')
date_list = date_string.split('/')
month = int(date_list[0])
day = int(date_list[1])
year = int(date_list[2])
if month < 1 or month > 12:
print('Month entered is out of range')
elif day < 1 or day > 31:
print('Day entered is out of range')
elif year != 13:
print('Year does not represent 2013')
else:
break
print(month, day, year)
Start again.
You don't want three little while loops. You want one big while loops ( while not success ) with three if statement to make the three checks and if any one fails, set success to false.