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Trim String Characters in Pyspark dataframe

Suppose if I have dataframe in which I have the values in a column like :
ABC00909083888
ABC93890380380
XYZ7394949
XYZ3898302
PQR3799_ABZ
MGE8983_ABZ
I want to trim these values like, remove first 3 characters and remove last 3 characters if it ends with ABZ.
00909083888
93890380380
7394949
3898302
3799
8983
Tried some methods but did not work.
from pyspark.sql import functions as f
new_df = df.withColumn("new_column", f.when((condition on some column),
f.substring('Existing_COL', 4, f.length(f.col("Existing_COL"))), ))
Can anyone please tell me which function I can use in pyspark.
Trim only removes white space or tab something characters.

Based upon your input and expected output. See below logic -
from pyspark.sql.functions import *
df = spark.createDataFrame(data = [("ABC00909083888",) ,("ABC93890380380",) ,("XYZ7394949",) ,("XYZ3898302",) ,("PQR3799_ABZ",) ,("MGE8983_ABZ",)], schema = ["values",])
(df.withColumn("new_vals", when(col('values').rlike("(_ABZ$)"), regexp_replace(col('values'),r'(_ABZ$)', '')).otherwise(col('values')))
.withColumn("final_vals", expr(("substring(new_vals, 4 ,length(new_vals))")))
).show()
Output
+--------------+--------------+-----------+
| values| new_vals| final_vals|
+--------------+--------------+-----------+
|ABC00909083888|ABC00909083888|00909083888|
|ABC93890380380|ABC93890380380|93890380380|
| XYZ7394949| XYZ7394949| 7394949|
| XYZ3898302| XYZ3898302| 3898302|
| PQR3799_ABZ| PQR3799| 3799|
| MGE8983_ABZ| MGE8983| 8983|
+--------------+--------------+-----------+

If I get you correctly and if you don't insist on using pyspark substring or trim functions, you can easily define a function to do what you want and then make use of that with udfs in spark:
from pyspark.sql.types import StringType
from pyspark.sql.functions import udf
def mysub(word):
if word.endswith('_ABZ'):
word = word[:-4]
return word[3:]
udf1 = udf(lambda x: mysub(x), StringType())
df.withColumn('new_label',udf1('label')).show()
The output will be like:
+---+--------------+-----------+
| id| label| new_label|
+---+--------------+-----------+
| 1|ABC00909083888|00909083888|
| 2|ABC93890380380|93890380380|
| 3| XYZ7394949| 7394949|
| 4| XYZ3898302| 3898302|
| 5| PQR3799_ABZ| 3799|
| 6| MGE8983_ABZ| 8983|
+---+--------------+-----------+
Please let me know if I got you wrong in some cases.

Databricks pyspark, Difference in result of Dataframe.count() and Display(Dataframe) while using header='false'

I am reading CSV (present on Azure datalake store) file in dataframe by following code:
df = spark.read.load(filepath, format="csv", schema = mySchema, header="false", mode="DROPMALFORMED");
File filepath contain 100 rows and header. I want to ignore header from file while reading so I defined header="false" . (As sometimes file come with header and sometimes not)
After reading in dataframe when I display dataframe by display(df) statement I got all the data and showed 100 rows which is correct. But when I used to check count of dataframe by using df.count() It displayed me 101 rows. Does dataframe show count with header? or Am I missing something?
mySchema and filepath already separately defined in cells.

You have mode="DROPMALFORMED" while reading csv file.
When there are some malformed records spark drops them out in df.show() but counts them in df.count().
In your case as header is false and schema specified so spark reads data as per your specified types if there are issues then records will not be shown
Example:
#sample data
#cat employee.csv
#id,name,salary,deptid
#1,a,1000,101
#2,b,2000,201
ss=StructType([StructField("id",IntegerType()),StructField("name",StringType()),StructField("salary",StringType()),StructField("deptid",StringType())])
df=spark.read.load("employee.csv",format="csv",schema=ss,header="false",mode="DROPMALFORMED")
df.show()
#+---+----+------+------+
#| id|name|salary|deptid|
#+---+----+------+------+
#| 1| a| 1000| 101|
#| 2| b| 2000| 201|
#+---+----+------+------+
#issue in df.count
df.count()
#3 #has to be 2
To Fix:
Add notNull filter while reading as dataframe.
df=spark.read.load("employee.csv",format="csv",schema=ss,header="false",mode="DROPMALFORMED").filter(col("id").isNotNull())
df.show()
#+---+----+------+------+
#| id|name|salary|deptid|
#+---+----+------+------+
#| 1| a| 1000| 101|
#| 2| b| 2000| 201|
#+---+----+------+------+
#fixed count
df.count()
#2
To view malformed data remove mode:
spark.read.load("employee.csv",format="csv",schema= mySchema,header="false").show(100,False)

As per the pyspark documentation,
https://spark.apache.org/docs/latest/api/python/pyspark.sql.html#pyspark.sql.DataFrameReader
header – uses the first line as names of columns. If None is set, it uses the default value, false.
You might need to standardize the way you get your data, either with headers or without headers, and then set the flag.
If you set header=False, then the spark engine will simply read the first row as a data row.
To answer your question, Dataframe count does not count header.
I would recommend reading the data first and then dropping the headers for debugging purposes.
Also, display(df) is a python operation provided by Ipython, I would use dataframe.show() which a spark provided utility for debugging purposes.

Filtering Spark Dataframe

I've created a dataframe as:
ratings = imdb_data.sort('imdbRating').select('imdbRating').filter('imdbRating is NOT NULL')
Upon doing ratings.show() as shown below, i can see that
the imdbRating field has a mixed type of data such as random strings, movie title, movie url and actual ratings. So the dirty data looks this:
+--------------------+
| imdbRating|
+--------------------+
|Mary (TV Episode...|
| Paranormal Activ...|
| Sons (TV Episode...|
| Spion (2011)|
| Winter... und Fr...|
| and Gays (TV Epi...|
| grAs - Die Serie...|
| hat die Wahl (2000)|
| 1.0|
| 1.3|
| 1.4|
| 1.5|
| 1.5|
| 1.5|
| 1.6|
| 1.6|
| 1.7|
| 1.9|
| 1.9|
| 1.9|
+--------------------+
only showing top 20 rows
Is there anyway i can filter out the unwanted strings and all just get the ratings ? I tried using UDF as:
ratings_udf = udf(lambda imdbRating: imdbRating if isinstance(imdbRating, float) else None)
and tried calling it as:
ratings = imdb_data.sort('imdbRating').select('imdbRating')
filtered = rating.withColumn('imdbRating',ratings_udf(ratings.imdbRating))
The problem with above is, since it tried calling the udf on each row, each row of the dataframe mapped to a Row type and hence returning None on all the values.
Is there any straightforward way to filter out those data ?
Any help will be much appreciated. Thank you

Finally, i was able to resolve it.The problem was there was some corrupt data with not all fields present. Firstly, i tried is using pandas by reading the csv files in pandas as:
pd_frame = pd.read_csv('imdb.csv', error_bad_lines=False)
This skipped/dropped the corrupt rows which had less columns than the actual. I tried to read the above panda dataframe, pd_frame, to spark using:
imdb_data= spark.createDataFrame(pd_frame)
but got some error because of mismatch while inferring schema. Turns out spark csv reader has something similar which drops the corrupt rows as:
imdb_data = spark.read.csv('imdb.csv', header='true', mode='DROPMALFORMED')

pySpark - Add list to a dataframe as a column [duplicate]

I want to add a column in a DataFrame with some arbitrary value (that is the same for each row). I get an error when I use withColumn as follows:
dt.withColumn('new_column', 10).head(5)
---------------------------------------------------------------------------
AttributeError Traceback (most recent call last)
<ipython-input-50-a6d0257ca2be> in <module>()
1 dt = (messages
2 .select(messages.fromuserid, messages.messagetype, floor(messages.datetime/(1000*60*5)).alias("dt")))
----> 3 dt.withColumn('new_column', 10).head(5)
/Users/evanzamir/spark-1.4.1/python/pyspark/sql/dataframe.pyc in withColumn(self, colName, col)
1166 [Row(age=2, name=u'Alice', age2=4), Row(age=5, name=u'Bob', age2=7)]
1167 """
-> 1168 return self.select('*', col.alias(colName))
1169
1170 #ignore_unicode_prefix
AttributeError: 'int' object has no attribute 'alias'
It seems that I can trick the function into working as I want by adding and subtracting one of the other columns (so they add to zero) and then adding the number I want (10 in this case):
dt.withColumn('new_column', dt.messagetype - dt.messagetype + 10).head(5)
[Row(fromuserid=425, messagetype=1, dt=4809600.0, new_column=10),
Row(fromuserid=47019141, messagetype=1, dt=4809600.0, new_column=10),
Row(fromuserid=49746356, messagetype=1, dt=4809600.0, new_column=10),
Row(fromuserid=93506471, messagetype=1, dt=4809600.0, new_column=10),
Row(fromuserid=80488242, messagetype=1, dt=4809600.0, new_column=10)]
This is supremely hacky, right? I assume there is a more legit way to do this?

Spark 2.2+
Spark 2.2 introduces typedLit to support Seq, Map, and Tuples (SPARK-19254) and following calls should be supported (Scala):
import org.apache.spark.sql.functions.typedLit
df.withColumn("some_array", typedLit(Seq(1, 2, 3)))
df.withColumn("some_struct", typedLit(("foo", 1, 0.3)))
df.withColumn("some_map", typedLit(Map("key1" -> 1, "key2" -> 2)))
Spark 1.3+ (lit), 1.4+ (array, struct), 2.0+ (map):
The second argument for DataFrame.withColumn should be a Column so you have to use a literal:
from pyspark.sql.functions import lit
df.withColumn('new_column', lit(10))
If you need complex columns you can build these using blocks like array:
from pyspark.sql.functions import array, create_map, struct
df.withColumn("some_array", array(lit(1), lit(2), lit(3)))
df.withColumn("some_struct", struct(lit("foo"), lit(1), lit(.3)))
df.withColumn("some_map", create_map(lit("key1"), lit(1), lit("key2"), lit(2)))
Exactly the same methods can be used in Scala.
import org.apache.spark.sql.functions.{array, lit, map, struct}
df.withColumn("new_column", lit(10))
df.withColumn("map", map(lit("key1"), lit(1), lit("key2"), lit(2)))
To provide names for structs use either alias on each field:
df.withColumn(
"some_struct",
struct(lit("foo").alias("x"), lit(1).alias("y"), lit(0.3).alias("z"))
)
or cast on the whole object
df.withColumn(
"some_struct",
struct(lit("foo"), lit(1), lit(0.3)).cast("struct<x: string, y: integer, z: double>")
)
It is also possible, although slower, to use an UDF.
Note:
The same constructs can be used to pass constant arguments to UDFs or SQL functions.

In spark 2.2 there are two ways to add constant value in a column in DataFrame:
1) Using lit
2) Using typedLit.
The difference between the two is that typedLit can also handle parameterized scala types e.g. List, Seq, and Map
Sample DataFrame:
val df = spark.createDataFrame(Seq((0,"a"),(1,"b"),(2,"c"))).toDF("id", "col1")
+---+----+
| id|col1|
+---+----+
| 0| a|
| 1| b|
+---+----+
1) Using lit: Adding constant string value in new column named newcol:
import org.apache.spark.sql.functions.lit
val newdf = df.withColumn("newcol",lit("myval"))
Result:
+---+----+------+
| id|col1|newcol|
+---+----+------+
| 0| a| myval|
| 1| b| myval|
+---+----+------+
2) Using typedLit:
import org.apache.spark.sql.functions.typedLit
df.withColumn("newcol", typedLit(("sample", 10, .044)))
Result:
+---+----+-----------------+
| id|col1| newcol|
+---+----+-----------------+
| 0| a|[sample,10,0.044]|
| 1| b|[sample,10,0.044]|
| 2| c|[sample,10,0.044]|
+---+----+-----------------+

As the other answers have described, lit and typedLit are how to add constant columns to DataFrames. lit is an important Spark function that you will use frequently, but not for adding constant columns to DataFrames.
You'll commonly be using lit to create org.apache.spark.sql.Column objects because that's the column type required by most of the org.apache.spark.sql.functions.
Suppose you have a DataFrame with a some_date DateType column and would like to add a column with the days between December 31, 2020 and some_date.
Here's your DataFrame:
+----------+
| some_date|
+----------+
|2020-09-23|
|2020-01-05|
|2020-04-12|
+----------+
Here's how to calculate the days till the year end:
val diff = datediff(lit(Date.valueOf("2020-12-31")), col("some_date"))
df
.withColumn("days_till_yearend", diff)
.show()
+----------+-----------------+
| some_date|days_till_yearend|
+----------+-----------------+
|2020-09-23| 99|
|2020-01-05| 361|
|2020-04-12| 263|
+----------+-----------------+
You could also use lit to create a year_end column and compute the days_till_yearend like so:
import java.sql.Date
df
.withColumn("yearend", lit(Date.valueOf("2020-12-31")))
.withColumn("days_till_yearend", datediff(col("yearend"), col("some_date")))
.show()
+----------+----------+-----------------+
| some_date| yearend|days_till_yearend|
+----------+----------+-----------------+
|2020-09-23|2020-12-31| 99|
|2020-01-05|2020-12-31| 361|
|2020-04-12|2020-12-31| 263|
+----------+----------+-----------------+
Most of the time, you don't need to use lit to append a constant column to a DataFrame. You just need to use lit to convert a Scala type to a org.apache.spark.sql.Column object because that's what's required by the function.
See the datediff function signature:
As you can see, datediff requires two Column arguments.

Remove column names from spark dataframe while storing it as textfile

My dataframe output is as below,
DF.show(2)
+--------------+
|col1|col2|col3|
+--------------+
| 10| 20| 30|
| 11| 21| 31|
+--------------+
after saving it as textfile - DF.rdd.saveAsTextFile("path")
Row(col1=u'10', col2=u'20', col3=u'30')
Row(col1=u'11', col2=u'21', col3=u'31')
the dataframe has millions of rows and 20 columns, how can i save it as textfile as below, i.e., without column names and python unicodes
10|20|30
11|21|31
while creating initial RDD i used below code to remove unicodes, though still getting the unicodes,
data = sc.textFile("file.txt")
trans = data.map(lambda x: x.encode("ascii", "ignore").split("|"))
Thanks in advance !

I think you can do just
.map(lambda l: (l[0] + '|' + l[1] + '|' + l[3])).saveAsTextFile(...)

In spark 2.0 you can write dataframes out directly to csv, which is all I think you need here. See: https://spark.apache.org/docs/2.0.0/api/java/org/apache/spark/sql/DataFrameWriter.html
So in you're case, could just do something like
df.write.option("sep", "|").option("header", "false").csv("some/path/")
There is a databricks plugin that provides this functionality in spark 1.x
https://github.com/databricks/spark-csv
As far as converting your unicode strings to ascii, see this question: Convert a Unicode string to a string in Python (containing extra symbols)