How to import from module_utils when running VScode Debugger - python

I'm trying to develop custom ansible modules using the VSCode Debugger and have run into an import problem.
My ansible role structure looks like this:
.
├── defaults
├── library
│   └── dl_script
├── meta
├── module_utils
│   ├── dl_script2
│   └── dl_script3
├── tasks
├── templates
└── vars
The way ansible works is that the library folder should be where we define custom modules, with the module_utils folder the location for supporting libraries.
When I run my role with ansible it works fine because the ansible packages is supporting these libraries and makes them available to the module, in this case dt_script.
When I try to run this in vscode it falls over.
from ansible.module_utils.dt_script2 import DTScript2
from ansible.module_utils.dt_script3 import DTScript3
Error:
No module named 'ansible.module_utils.dt_script2'
What I'd like to do is figure out a way to import the code from the module_utils folder and make it do so only when it can't do it the ansible way.
I've had a go at doing this myself, but with no success:
try:
from ansible.module_utils.dt_script2 import DTScript2
from ansible.module_utils.dt_script3 import DTScript3
except:
from ..module_utils.dt_script2 import dt_script2
from ..module_utils.dt_script3 import dt_script3
Error:
attempted relative import with no known parent package
EDIT1:
I have a solution, but I don't like it.
try:
from ansible.module_utils.dt_script2 import DTScript2
from ansible.module_utils.dt_script3 import DTScript3
except:
import sys
import os
# I don't like this, but it seems to be the only way to get VScode to look for these files.
sys.path.insert(0,os.path.dirname(os.path.abspath(__file__)).replace('library', 'module_utils'))
from dt_script2 import *
from dt_script3 import *
The reason this works is the by default python only searches the dir and subdir of the place you are running the script from, or certain package locations, like pyenv if you have it. What I'm doing here is amending the path list object to include another path to check from.
Reason this is bad in my mind is that this relies on path manipulation, which makes this very reliant on the host pathing not being really odd. I'd much prefer a safer solution for this, but this is only for when people want to use vscode to debug it.
If anyone has a better solution I'd love to see it.

Related

Importing module from subfolder

This is the structure of my project
final
├── common
├── __init__.py
├── batch_data_processing.py
├── processing_utility.py
├── post_processing.py
├── Processing_raw_data
├── batch_process_raw_data.py
so i want to import from common.batch_data_processing in batch_process_raw_data.py
but when I try it I get ModuleNotFoundError: No module named 'common'
is there a way to import this module without the need to install it ?
Note : this is intended to be used by "non python users"
here is pictures to better discribe the problem.
Add the following code above your import code to indicate the path:
# The following is a relative path,
# it can also be replaced with the absolute path
# of the directory where common is located.
# sys.path.append("C:\\Users\\Admin\\Desktop\\Final")
import sys
sys.path.append("./")
When all your scripts are in the same folder, importing modules is almost impossible to go wrong. If you need to import scripts from external folders, you can specify the path using the above method.

Import libraries from ROOT directory in python

I have the following structure of my program:
MainDir
├── __init__.py
├── main.py
├── Routine.py
└── Folder1
├── __init__.py
└──function.py
I know that I can import a function from folder 1 to my main.py program writing this statement:
from Folder1.function import foo
But, I am looking for a way to do so in the other direction. How could I import a function defined in Routine.py to function.py?
It depends on how you are invoking your program.
Invoking as a module
Do you do something like
python -m MainDir.main
and whatever code is in your MainDir.main calls out to MainDir/Folder1/function.py?
In this case, you can simply add the following import to MainDir/Folder1/function.py:
from ..Routine import RoutineFunction
Invoking as a script
If you are instead invoking MainDir/Folder1/function.py as a script using:
python MainDir/Folder1/function.py
you will not be able to use relative imports as suggested above. There are still many options available to you, as described here: How to import other Python files?
Suggested reading
Python imports can be very confusing. Here is a great post on the topic, which could be useful to you: https://stackoverflow.com/a/14132912/4905625

Import a custom module in the parent folder in python

Although I think this should be pretty simple I still can't make it run.
I have following folder structure:
├── apartment
│ ├── src
│ ├── train_model
│ ├── __init__.py
│ ├── train_model.py
│ ├── utils.py
│ ├── interference.py
│ └── __init__.py
In utils.py I tried:
from src.interference import create_sample
Error: ModuleNotFoundError: No module named 'src'
from .interference import create_sample
Error: ImportError: attempted relative import with no known parent package
from interference import create_features_sample
ModuleNotFoundError: No module named 'interference'
What is the way to make it work? I am not a huge fan of non-pythonic ways as it looks dirty.
The structure starting with a src/ is aimed explicitly at not enabling import by from src.intereference import ..., and you should not put an __init__.py file in src/ folder.
Instead, following nice explanation and examples here: https://blog.ionelmc.ro/2014/05/25/python-packaging/, here is what I recommend:
install the package:
add a setup.py file at root of your folder (this is clearly not as hard as it seems)
maybe create a virtual environment
using pip install -e . (with trailing dot!) command
then simply import your package by from interference import ...
To answer to your primary request, you could update src/__init__.py with from intereference import create_sample, to expose this function at a higher level, then the chained import would work. However, I do not recommend this, as it renders everything very rigid.
You need to add the directory that contains interference to PYTHONPATH.
You can use OS depending path in "module search path" which is listed in sys.path. So you can easily add parent directory like following:
import sys
sys.path.insert(0, '..')
from interference import create_features_sample
Note that the previous code uses a relative path, so you must launch the file inside the same location or it will likely not work.
To launch from anywhere, you can use Path from the pathlib module.
from pathlib import Path
import sys
path = str(Path(Path(__file__).parent.absolute()).parent.absolute())
sys.path.insert(0, path)
from interference import create_features_sample
If you want add a custom path to your PYTHONPATH permanently, go to the 'site-packages' folder of your current Python environment and add the file 'custompaths.pth' in which each line should consist of a directory which will then be checked if you try to import the module.
Assuming 'src' being the module you want to import you should add the following line to the .pth file:
your_preceding_path/apartment
Error because of python can't able to find the specific file or package. Python usually find only for the child packages or files, otherwise you need to specify the absolute path.
import sys, os
sys.path.append(os.path.abspath(os.path.join('../..', 'src')))
Please refer the "How to access a module from outside your file folder in Python?"
Have you tried from ..interference import create_sample ?
Or for the whole module from .. import interference.
I've checked here, that I'm using another command, something that is missing from the question at the time of writing this. The command that I'm using is python -m src.train_model.utils from apartment folder.
Thanks to RMPR for helping me.
This problem is similar to this one.

How do I permanently add paths to PYTHONPATH in a script? [duplicate]

I've tried reading through questions about sibling imports and even the
package documentation, but I've yet to find an answer.
With the following structure:
├── LICENSE.md
├── README.md
├── api
│   ├── __init__.py
│   ├── api.py
│   └── api_key.py
├── examples
│   ├── __init__.py
│   ├── example_one.py
│   └── example_two.py
└── tests
│   ├── __init__.py
│   └── test_one.py
How can the scripts in the examples and tests directories import from the
api module and be run from the commandline?
Also, I'd like to avoid the ugly sys.path.insert hack for every file. Surely
this can be done in Python, right?
Tired of sys.path hacks?
There are plenty of sys.path.append -hacks available, but I found an alternative way of solving the problem in hand.
Summary
Wrap the code into one folder (e.g. packaged_stuff)
Create setup.py script where you use setuptools.setup(). (see minimal setup.py below)
Pip install the package in editable state with pip install -e <myproject_folder>
Import using from packaged_stuff.modulename import function_name
Setup
The starting point is the file structure you have provided, wrapped in a folder called myproject.
.
└── myproject
├── api
│ ├── api_key.py
│ ├── api.py
│ └── __init__.py
├── examples
│ ├── example_one.py
│ ├── example_two.py
│ └── __init__.py
├── LICENCE.md
├── README.md
└── tests
├── __init__.py
└── test_one.py
I will call the . the root folder, and in my example case it is located at C:\tmp\test_imports\.
api.py
As a test case, let's use the following ./api/api.py
def function_from_api():
return 'I am the return value from api.api!'
test_one.py
from api.api import function_from_api
def test_function():
print(function_from_api())
if __name__ == '__main__':
test_function()
Try to run test_one:
PS C:\tmp\test_imports> python .\myproject\tests\test_one.py
Traceback (most recent call last):
File ".\myproject\tests\test_one.py", line 1, in <module>
from api.api import function_from_api
ModuleNotFoundError: No module named 'api'
Also trying relative imports wont work:
Using from ..api.api import function_from_api would result into
PS C:\tmp\test_imports> python .\myproject\tests\test_one.py
Traceback (most recent call last):
File ".\tests\test_one.py", line 1, in <module>
from ..api.api import function_from_api
ValueError: attempted relative import beyond top-level package
Steps
Make a setup.py file to the root level directory
The contents for the setup.py would be*
from setuptools import setup, find_packages
setup(name='myproject', version='1.0', packages=find_packages())
Use a virtual environment
If you are familiar with virtual environments, activate one, and skip to the next step. Usage of virtual environments are not absolutely required, but they will really help you out in the long run (when you have more than 1 project ongoing..). The most basic steps are (run in the root folder)
Create virtual env
python -m venv venv
Activate virtual env
source ./venv/bin/activate (Linux, macOS) or ./venv/Scripts/activate (Win)
To learn more about this, just Google out "python virtual env tutorial" or similar. You probably never need any other commands than creating, activating and deactivating.
Once you have made and activated a virtual environment, your console should give the name of the virtual environment in parenthesis
PS C:\tmp\test_imports> python -m venv venv
PS C:\tmp\test_imports> .\venv\Scripts\activate
(venv) PS C:\tmp\test_imports>
and your folder tree should look like this**
.
├── myproject
│ ├── api
│ │ ├── api_key.py
│ │ ├── api.py
│ │ └── __init__.py
│ ├── examples
│ │ ├── example_one.py
│ │ ├── example_two.py
│ │ └── __init__.py
│ ├── LICENCE.md
│ ├── README.md
│ └── tests
│ ├── __init__.py
│ └── test_one.py
├── setup.py
└── venv
├── Include
├── Lib
├── pyvenv.cfg
└── Scripts [87 entries exceeds filelimit, not opening dir]
pip install your project in editable state
Install your top level package myproject using pip. The trick is to use the -e flag when doing the install. This way it is installed in an editable state, and all the edits made to the .py files will be automatically included in the installed package.
In the root directory, run
pip install -e . (note the dot, it stands for "current directory")
You can also see that it is installed by using pip freeze
(venv) PS C:\tmp\test_imports> pip install -e .
Obtaining file:///C:/tmp/test_imports
Installing collected packages: myproject
Running setup.py develop for myproject
Successfully installed myproject
(venv) PS C:\tmp\test_imports> pip freeze
myproject==1.0
Add myproject. into your imports
Note that you will have to add myproject. only into imports that would not work otherwise. Imports that worked without the setup.py & pip install will work still work fine. See an example below.
Test the solution
Now, let's test the solution using api.py defined above, and test_one.py defined below.
test_one.py
from myproject.api.api import function_from_api
def test_function():
print(function_from_api())
if __name__ == '__main__':
test_function()
running the test
(venv) PS C:\tmp\test_imports> python .\myproject\tests\test_one.py
I am the return value from api.api!
* See the setuptools docs for more verbose setup.py examples.
** In reality, you could put your virtual environment anywhere on your hard disk.
Seven years after
Since I wrote the answer below, modifying sys.path is still a quick-and-dirty trick that works well for private scripts, but there has been several improvements
Installing the package (in a virtualenv or not) will give you what you want, though I would suggest using pip to do it rather than using setuptools directly (and using setup.cfg to store the metadata)
Using the -m flag and running as a package works too (but will turn out a bit awkward if you want to convert your working directory into an installable package).
For the tests, specifically, pytest is able to find the api package in this situation and takes care of the sys.path hacks for you
So it really depends on what you want to do. In your case, though, since it seems that your goal is to make a proper package at some point, installing through pip -e is probably your best bet, even if it is not perfect yet.
Old answer
As already stated elsewhere, the awful truth is that you have to do ugly hacks to allow imports from siblings modules or parents package from a __main__ module. The issue is detailed in PEP 366. PEP 3122 attempted to handle imports in a more rational way but Guido has rejected it one the account of
The only use case seems to be running scripts that happen
to be living inside a module's directory, which I've always seen as an
antipattern.
(here)
Though, I use this pattern on a regular basis with
# Ugly hack to allow absolute import from the root folder
# whatever its name is. Please forgive the heresy.
if __name__ == "__main__" and __package__ is None:
from sys import path
from os.path import dirname as dir
path.append(dir(path[0]))
__package__ = "examples"
import api
Here path[0] is your running script's parent folder and dir(path[0]) your top level folder.
I have still not been able to use relative imports with this, though, but it does allow absolute imports from the top level (in your example api's parent folder).
Here is another alternative that I insert at top of the Python files in tests folder:
# Path hack.
import sys, os
sys.path.insert(0, os.path.abspath('..'))
You don't need and shouldn't hack sys.path unless it is necessary and in this case it is not. Use:
import api.api_key # in tests, examples
Run from the project directory: python -m tests.test_one.
You should probably move tests (if they are api's unittests) inside api and run python -m api.test to run all tests (assuming there is __main__.py) or python -m api.test.test_one to run test_one instead.
You could also remove __init__.py from examples (it is not a Python package) and run the examples in a virtualenv where api is installed e.g., pip install -e . in a virtualenv would install inplace api package if you have proper setup.py.
I don't yet have the comprehension of Pythonology necessary to see the intended way of sharing code amongst unrelated projects without a sibling/relative import hack. Until that day, this is my solution. For examples or tests to import stuff from ..\api, it would look like:
import sys.path
import os.path
# Import from sibling directory ..\api
sys.path.append(os.path.dirname(os.path.abspath(__file__)) + "/..")
import api.api
import api.api_key
For siblings package imports, you can use either the insert or the append method of the [sys.path][2] module:
if __name__ == '__main__' and if __package__ is None:
import sys
from os import path
sys.path.append( path.dirname( path.dirname( path.abspath(__file__) ) ) )
import api
This will work if you are launching your scripts as follows:
python examples/example_one.py
python tests/test_one.py
On the other hand, you can also use the relative import:
if __name__ == '__main__' and if __package__ is not None:
import ..api.api
In this case you will have to launch your script with the '-m' argument (note that, in this case, you must not give the '.py' extension):
python -m packageName.examples.example_one
python -m packageName.tests.test_one
Of course, you can mix the two approaches, so that your script will work no matter how it is called:
if __name__ == '__main__':
if __package__ is None:
import sys
from os import path
sys.path.append( path.dirname( path.dirname( path.abspath(__file__) ) ) )
import api
else:
import ..api.api
For readers in 2021: If you're not confident with pip install -e :
Consider this hierarchy, as recommended by an answer from Relative imports in Python 3:
MyProject
├── src
│ ├── bot
│ │   ├── __init__.py
│ │   ├── main.py
│ │   └── sib1.py
│ └── mod
│ ├── __init__.py
│ └── module1.py
└── main.py
The content of main.py, which is the starting point and we use absolute import (no leading dots) here:
from src.bot import main
if __name__ == '__main__':
main.magic_tricks()
The content of bot/main.py, which takes advantage of explicit relative imports:
from .sib1 import my_drink # Both are explicit-relative-imports.
from ..mod.module1 import relative_magic
def magic_tricks():
# Using sub-magic
relative_magic(in=["newbie", "pain"], advice="cheer_up")
my_drink()
# Do your work
...
Now here comes the reasoning:
When executing python MyProject/main.py, the path/to/MyProject is added into the sys.path.
The absolute import import src.bot will read it.
The from ..mod part means it will go up one level to MyProject/src.
Can we see it? YES, since path/to/MyProject is added into the sys.path.
So the point is:
We should put the main script next to MyProject/src, since that when doing relative-referencing, we won't go out of the src, and the absolute import import src. provides the just-fit scope for us: the src/ scope.
See also: ModuleNotFoundError: No module named 'sib1'
TLDR
This method does not require setuptools, path hacks, additional command line arguments, or specifying the top level of the package in every single file of your project.
Just make a script in the parent directory of whatever your are calling to be your __main__ and run everything from there. For further explanation continue reading.
Explanation
This can be accomplished without hacking a new path together, extra command line args, or adding code to each of your programs to recognize its siblings.
The reason this fails as I believe was mentioned before is the programs being called have their __name__ set as __main__. When this occurs the script being called accepts itself to be on the top level of the package and refuses to recognize scripts in sibling directories.
However, everything under the top level of the directory will still recognize ANYTHING ELSE under the top level. This means the ONLY thing you have to do to get files in sibling directories to recognize/utilize each other is to call them from a script in their parent directory.
Proof of Concept
In a dir with the following structure:
.
|__Main.py
|
|__Siblings
|
|___sib1
| |
| |__call.py
|
|___sib2
|
|__callsib.py
Main.py contains the following code:
import sib1.call as call
def main():
call.Call()
if __name__ == '__main__':
main()
sib1/call.py contains:
import sib2.callsib as callsib
def Call():
callsib.CallSib()
if __name__ == '__main__':
Call()
and sib2/callsib.py contains:
def CallSib():
print("Got Called")
if __name__ == '__main__':
CallSib()
If you reproduce this example you will notice that calling Main.py will result in "Got Called" being printed as is defined in sib2/callsib.py even though sib2/callsib.py got called through sib1/call.py. However if one were to directly call sib1/call.py (after making appropriate changes to the imports) it throws an exception. Even though it worked when called by the script in its parent directory, it will not work if it believes itself to be on the top level of the package.
You need to look to see how the import statements are written in the related code. If examples/example_one.py uses the following import statement:
import api.api
...then it expects the root directory of the project to be in the system path.
The easiest way to support this without any hacks (as you put it) would be to run the examples from the top level directory, like this:
PYTHONPATH=$PYTHONPATH:. python examples/example_one.py
Just in case someone using Pydev on Eclipse end up here: you can add the sibling's parent path (and thus the calling module's parent) as an external library folder using Project->Properties and setting External Libraries under the left menu Pydev-PYTHONPATH. Then you can import from your sibling, e. g. from sibling import some_class.
I wanted to comment on the solution provided by np8 but I don't have enough reputation so I'll just mention that you can create a setup.py file exactly as they suggested, and then do pipenv install --dev -e . from the project root directory to turn it into an editable dependency. Then your absolute imports will work e.g. from api.api import foo and you don't have to mess around with system-wide installations.
Documentation
If you're using pytest then the pytest docs describe a method of how to reference source packages from a separate test package.
The suggested project directory structure is:
setup.py
src/
mypkg/
__init__.py
app.py
view.py
tests/
__init__.py
foo/
__init__.py
test_view.py
bar/
__init__.py
test_view.py
Contents of the setup.py file:
from setuptools import setup, find_packages
setup(name="PACKAGENAME", packages=find_packages())
Install the packages in editable mode:
pip install -e .
The pytest article references this blog post by Ionel Cristian Mărieș.
I made a sample project to demonstrate how I handled this, which is indeed another sys.path hack as indicated above. Python Sibling Import Example, which relies on:
if __name__ == '__main__': import os import sys sys.path.append(os.getcwd())
This seems to be pretty effective so long as your working directory remains at the root of the Python project.
in your main file add this:
import sys
import os
sys.path.append(os.path.abspath(os.path.join(__file__,mainScriptDepth)))
mainScriptDepth = the depth of the main file from the root of the project.
Here is your case mainScriptDepth = "../../". Then you can import by specifying the path (from api.api import * ) from the root of your project.
The problem:
You simply can not get import mypackage to work in test.py. You will need either an editable install, change to path, or changes to __name__ and path
demo
├── dev
│ └── test.py
└── src
└── mypackage
├── __init__.py
└── module_of_mypackage.py
--------------------------------------------------------------
ValueError: attempted relative import beyond top-level package
The solution:
import sys; sys.path += [sys.path[0][:-3]+"src"]
Put the above before attempting imports in test.py. Thats it. You can now import mypackage.
This will work both on Windows and Linux. It will also not care from which path you run your script. It is short enough to slap it anywhere you might need it.
Why it works:
The sys.path contains the places, in order, where to look for packages when attempting imports if they are not found in installed site packages. When you run test.py the first item in sys.path will be something like /mnt/c/Users/username/Desktop/demo/dev i.e.: where you ran your file. The oneliner will simply add the sibling folder to path and everything works. You will not have to worry about Windows vs Linux file paths since we are only editing the last folder name and nothing else. If you project structure is already set in stone for your repository we can also reasonably just use the magic number 3 to slice away dev and substitute src
for the main question:
call sibling folder as module:
from .. import siblingfolder
call a_file.py from sibling folder as module:
from ..siblingfolder import a_file
call a_function inside a file in sibling folder as module:
from..siblingmodule.a_file import func_name_exists_in_a_file
The easiest way.
go to lib/site-packages folder.
if exists 'easy_install.pth' file, just edit it and add your directory that you have script that you want make it as module.
if not exists, just make it one...and put your folder that you want there
after you add it..., python will be automatically perceive that folder as similar like site-packages and you can call every script from that folder or subfolder as a module.
i wrote this by my phone, and hard to set it to make everyone comfortable to read.
First, you should avoid having files with the same name as the module itself. It may break other imports.
When you import a file, first the interpreter checks the current directory and then searchs global directories.
Inside examples or tests you can call:
from ..api import api
Project
1.1 User
1.1.1 about.py
1.1.2 init.py
1.2 Tech
1.2.1 info.py
1.1.2 init.py
Now, if you want to access about.py module in the User package, from the info.py module in Tech package then you have to bring the cmd (in windows) path to Project i.e.
**C:\Users\Personal\Desktop\Project>**as per the above Package example. And from this path you have to enter, python -m Package_name.module_name
For example for the above Package we have to do,
C:\Users\Personal\Desktop\Project>python -m Tech.info
Imp Points
Don't use .py extension after info module i.e. python -m Tech.info.py
Enter this, where the siblings packages are in the same level.
-m is the flag, to check about it you can type from the cmd python --help

Python: Importing from your project without setting PYTHONPATH manually

How can I import packages and modules from different places in my project without resetting the PYTHONPATH (because that seems like a 'hacky' solution).
For example if I have the following directory structure:
proj
├── __init__.py
├── important_file.py
└── subdirectory/
├── __init__.py
└── script.py
How can I import important_file.py from inside script.py? Can I somehow specify in my project that proj is my root directory, so that I can import important file with import proj.important_file?
You can use
import sys
sys.path.append('/path/to/root/directory')
to import from whatever directory you like. At least, this worked for me in the past. Maybe there are even less "hacky" solutions :)
I tend to prefer "pythonic" solutions, not necessarily what #Gijs suggested which I would call more of a work around.
So this is something I haven't done much of but when I've needed to do it, I've spent a lot of time on it. Take a look at this my repo. In it, I have a unit testing directory, which I import core.py into test_core.py.
The project folder is structured as follows.
SNA (this is called first-repo on git, but SNA on my machine)
├── bin/
└── sna/
├── core.py
└── test/
└── test_core.py
In text_core.py, I import my functions from core.py. I do this by using the following line.
from SNA.sna.core import *
So a general format is this.
from PROJECTNAME.DIR.FILE import * (or specific functions)
Hopefully this helps!
You can use relative imports
# inside subdirectory/script.py
from .. import important_file
but really the best solution is to add it to your PYTHONPATH and do
import proj.important_file

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