i'm getting started with scikit-geometry and am trying to reproduce some of the examples, but the plot function doesn't work as expected.
i'm working in VSCode and managing my environment with Anaconda on Windows 10.
i'm just reading through the samples in the notebook. the snippet runs, but no graphic is displayed.
import skgeom
from skgeom.draw import draw
from matplotlib import pyplot as plt
import math
a = skgeom.Point2(4, 5)
print('a:', a)
draw(a, color='purple')
the docs indicate that the draw function is built from the matplotlib plot function, but it doesn't support the .show() method, so i'm not really sure what i'm doing wrong.
suggestions?
Related
I have a simple python script which plots some graphs in the same figure. All graphs are created by the draw() and in the end I call the show() function to block.
The script used to work with Python 2.6.6, Matplotlib 0.99.3, and Ubuntu 11.04. Tried to run it under Python 2.7.2, Matplotlib 1.0.1, and Ubuntu 11.10 but the show() function returns immediately without waiting to kill the figure.
Is this a bug? Or a new feature and we'll have to change our scripts? Any ideas?
EDIT: It does keep the plot open under interactive mode, i.e., python -i ..., but it used to work without that, and tried to have plt.ion() in the script and run it in normal mode but no luck.
I had this same problem, and it was caused by calling show() on the Figure object instead of the pyplot object.
Incorrect code. Causes the graph to flash on screen for a brief instant:
import matplotlib.pyplot as plt
x = [1,2,3]
y = [5,6,7]
fig = plt.figure()
plt.plot(x, y)
fig.show()
Last line should be as follows to show the graph until it is dismissed:
plt.show()
I think that using show(block=True) should fix your problem.
Had the inverse problem, and it seems that matplotlib will work in interactive or non-interaxctive mode based on a number of things that I could not trace (One way in IDLE, another in system console, one way in normal spyder console, another in a dedicated one ...)
This worked for me:
import matplotlib
matplotlib.interactive(False)
(Actually, I wanted interactive mode, but in your case the inverse should help.)
ion() and ioff() should do the same but the above is on matplotlib's level, not just pyplot or pylab. This works for me although I'm (later) importing pyplot separately and never call matplotlib as such again. I'm thinking that plt.ion() only has an effect on pyplot, not other components of matplotlib that may or may not be involved when using pyplot.
This method works for me on Windows 7, using both Python 2.65 with matplotlib 0.99 and Python 2.75 with matplotlib 1.3.1, across all available python consoles and IDEs on both systems (64-bit, both of them). It did, however, not work on Linux (SuSe 11.3, 64 bit), so there is definitely some platform dependency at play here
To replicate the matplotlib.show() behaviour with the tkagg backend when calling show() on the Figure object:
import Tkinter as Tk
import matplotlib.pyplot as plt
fig = plt.figure()
... your plot commands...
fig.show()
Tk.mainloop()
I had the same problem with this code below.
import matplotlib.pyplot as plt
plt.ion()
fig,ax0 = plt.subplots(figsize=(5.3,4))
plt.show()
I removed plt.ion(), and the plot stays without closing automatically.
I'd like to plot a figure using matplotlib using PyCharm, show the figure for a few seconds, and then close the plot window.
After a simple search I've got the following code. This works when Python is run in IDLE/terminal.
import matplotlib.pyplot as plt
import numpy as np
plt.imshow(np.zeros((256,256)))
plt.show(block=False)
plt.pause(10)
plt.close('all')
However plt.close('all') doesn't seem to close any plot windows produced by PyCharm.
How can I close plot windows produced by PyCharm programmatically? The question had been asked (Close a figure - PyCharm ), but the accepted solution doesn't work.
I guess you use the SciView. So you need to change the setting in the pycharm.
Settings | Tools | Python Scientific | Show Plots in Toolwindow - box has to be unticked to back to the usual matplotlib figure window
After this, try again.
I am creating a bar chart with seaborn, and it's not generating any sort of error, but nothing happens either.
This is the code I have:
import pandas
import numpy
import matplotlib.pyplot as plt
import seaborn
data = pandas.read_csv('fy15crime.csv', low_memory = False)
seaborn.countplot(x="primary_type", data=data)
plt.xlabel('crime')
plt.ylabel('amount')
seaborn.plt.show()
I added "seaborn.plt.show() in an effort to have it show up, but it isn't working still.
You should place this line somewhere in the top cell in Jupyter to enable inline plotting:
%matplotlib inline
It's simply plt.show() you were close. No need for seaborn
I was using PyCharm using a standard Python file and I had the best luck with the following:
Move code to a Jupyter notebook (which can you do inside of PyCharm by right clicking on the project and choosing new - Jupyter Notebook)
If running a chart that takes a lot of processing time it might not have been obvious before, but in Jupyter mode you can easily see when the cell has finished processing.
I have a simple python script which plots some graphs in the same figure. All graphs are created by the draw() and in the end I call the show() function to block.
The script used to work with Python 2.6.6, Matplotlib 0.99.3, and Ubuntu 11.04. Tried to run it under Python 2.7.2, Matplotlib 1.0.1, and Ubuntu 11.10 but the show() function returns immediately without waiting to kill the figure.
Is this a bug? Or a new feature and we'll have to change our scripts? Any ideas?
EDIT: It does keep the plot open under interactive mode, i.e., python -i ..., but it used to work without that, and tried to have plt.ion() in the script and run it in normal mode but no luck.
I had this same problem, and it was caused by calling show() on the Figure object instead of the pyplot object.
Incorrect code. Causes the graph to flash on screen for a brief instant:
import matplotlib.pyplot as plt
x = [1,2,3]
y = [5,6,7]
fig = plt.figure()
plt.plot(x, y)
fig.show()
Last line should be as follows to show the graph until it is dismissed:
plt.show()
I think that using show(block=True) should fix your problem.
Had the inverse problem, and it seems that matplotlib will work in interactive or non-interaxctive mode based on a number of things that I could not trace (One way in IDLE, another in system console, one way in normal spyder console, another in a dedicated one ...)
This worked for me:
import matplotlib
matplotlib.interactive(False)
(Actually, I wanted interactive mode, but in your case the inverse should help.)
ion() and ioff() should do the same but the above is on matplotlib's level, not just pyplot or pylab. This works for me although I'm (later) importing pyplot separately and never call matplotlib as such again. I'm thinking that plt.ion() only has an effect on pyplot, not other components of matplotlib that may or may not be involved when using pyplot.
This method works for me on Windows 7, using both Python 2.65 with matplotlib 0.99 and Python 2.75 with matplotlib 1.3.1, across all available python consoles and IDEs on both systems (64-bit, both of them). It did, however, not work on Linux (SuSe 11.3, 64 bit), so there is definitely some platform dependency at play here
To replicate the matplotlib.show() behaviour with the tkagg backend when calling show() on the Figure object:
import Tkinter as Tk
import matplotlib.pyplot as plt
fig = plt.figure()
... your plot commands...
fig.show()
Tk.mainloop()
I had the same problem with this code below.
import matplotlib.pyplot as plt
plt.ion()
fig,ax0 = plt.subplots(figsize=(5.3,4))
plt.show()
I removed plt.ion(), and the plot stays without closing automatically.
I have a simple python script which plots some graphs in the same figure. All graphs are created by the draw() and in the end I call the show() function to block.
The script used to work with Python 2.6.6, Matplotlib 0.99.3, and Ubuntu 11.04. Tried to run it under Python 2.7.2, Matplotlib 1.0.1, and Ubuntu 11.10 but the show() function returns immediately without waiting to kill the figure.
Is this a bug? Or a new feature and we'll have to change our scripts? Any ideas?
EDIT: It does keep the plot open under interactive mode, i.e., python -i ..., but it used to work without that, and tried to have plt.ion() in the script and run it in normal mode but no luck.
I had this same problem, and it was caused by calling show() on the Figure object instead of the pyplot object.
Incorrect code. Causes the graph to flash on screen for a brief instant:
import matplotlib.pyplot as plt
x = [1,2,3]
y = [5,6,7]
fig = plt.figure()
plt.plot(x, y)
fig.show()
Last line should be as follows to show the graph until it is dismissed:
plt.show()
I think that using show(block=True) should fix your problem.
Had the inverse problem, and it seems that matplotlib will work in interactive or non-interaxctive mode based on a number of things that I could not trace (One way in IDLE, another in system console, one way in normal spyder console, another in a dedicated one ...)
This worked for me:
import matplotlib
matplotlib.interactive(False)
(Actually, I wanted interactive mode, but in your case the inverse should help.)
ion() and ioff() should do the same but the above is on matplotlib's level, not just pyplot or pylab. This works for me although I'm (later) importing pyplot separately and never call matplotlib as such again. I'm thinking that plt.ion() only has an effect on pyplot, not other components of matplotlib that may or may not be involved when using pyplot.
This method works for me on Windows 7, using both Python 2.65 with matplotlib 0.99 and Python 2.75 with matplotlib 1.3.1, across all available python consoles and IDEs on both systems (64-bit, both of them). It did, however, not work on Linux (SuSe 11.3, 64 bit), so there is definitely some platform dependency at play here
To replicate the matplotlib.show() behaviour with the tkagg backend when calling show() on the Figure object:
import Tkinter as Tk
import matplotlib.pyplot as plt
fig = plt.figure()
... your plot commands...
fig.show()
Tk.mainloop()
I had the same problem with this code below.
import matplotlib.pyplot as plt
plt.ion()
fig,ax0 = plt.subplots(figsize=(5.3,4))
plt.show()
I removed plt.ion(), and the plot stays without closing automatically.