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How to find an Element by index in selenium Webdriver for python

This is HTML code of that page
From there I want to access the 2nd element by using class name "maxbutton-1" as it has 3 same buttons and I can't use xpath or any constant selector so want to use the indexing with class and can't find anything to do that in python particular.
Also tried the method used in java to do same thing but it didn't worked.
Link of that same page
just trying to automate the movie downloading process for any movie.
Thank you.

To click on first, second or third button, try to change number of element:
el1 = driver.find_element_by_xpath("(//a[#class='maxbutton-1 maxbutton maxbutton-download-links'])[1]")
el2 = driver.find_element_by_xpath("(//a[#class='maxbutton-1 maxbutton maxbutton-download-links'])[2]")
el3 = driver.find_element_by_xpath("(//a[#class='maxbutton-1 maxbutton maxbutton-download-links'])[3]")
then you can extract element href/link attribute like that:
link = el.get_attribute('href')
or click it like that:
el.click()

Selenium Webdriver failing to click. Unsure why

I have the following code;
if united_states_hidden is not None:
print("Country removed successfully")
time.sleep(10)
print("type(united_states_hidden) = ")
print(type(united_states_hidden))
print("united_states_hidden.text = " + united_states_hidden.text)
print("united_states_hidden.id = " + united_states_hidden.id)
print(united_states_hidden.is_displayed())
print(united_states_hidden.is_enabled())
united_states_hidden.click()
The outputs to the console are as follows:
Country removed successfully
type(united_states_hidden) =
<class 'selenium.webdriver.remote.webelement.WebElement'>
united_states_hidden.text = United States
united_states_hidden.id = ccea7858-6a0b-4aa8-afd5-72f75636fa44
True
True
As far as I am aware this should work as it is a clickable web element, however, no click is delivered to the element. Any help would be appreciated as I can't seem to find anything anywhere else. The element I am attempting to click is within a selector box.

Seems like a valid WebElement given you can print all of the info. like you did in your example.
It's possible the element located is not the element that is meant to be clicked, so perhaps the click is succeeding, but not really clicking anything.
You could try using a Javascript click and see if that helps:
driver.execute_script("arguments[0].click();", united_states_hidden)
If this does not work for you, we may need to see the HTML on the page and the locator strategy you are using to find united_states_hidden so that we can proceed.

Python, Selenium + stale element reference

I'm trying to go on a webpage,
save a set of links of the page I would like to click on, and then
I would like to click on each of the link if a for loop (going back and forth on the page. Here is the code:
from selenium import webdriver
driver = webdriver.Chrome(executable_path='/Applications/chromedriver')
driver.get("webpage link") #insert link to webpage
list_links = driver.find_elements_by_xpath("//a[contains(#href,'activities')]")
for link in list_links:
print(link)
link.click()
driver.goback()
driver.implicitly_wait(10) # seconds
driver.quit()
However, the first time I go back to the homepage I get the error message:
StaleElementReferenceException: stale element reference: element is not attached to the page document.
Can anyone help me to understand why? Suggest a solution?
Thank you. much appreciated.

Your list_links works only on page where it was defined. After you made first click on link DOM re-created and references to elements of list_links becomes invalid. You can apply below solution:
driver.implicitly_wait(10) # seconds
list_links = [link.get_attribute('href') for link in driver.find_elements_by_xpath("//a[contains(#href,'activities')]")]
for link in list_links:
print(link)
driver.get(link)
driver.goback()
driver.quit()
P.S. I assume that goback() is your custom method that was defined already as there is no such method in Selenium built-ins, but just back()
P.P.S. Note that you can call driver.implicitly_wait(10) only once in your code and it will be applicable for all next find_element...() calls

Its simple, you trying to save the elements of an html(links) which cannot be referenced anymore by the code(the loop logic), thats why it throws this error. Most of all those are selenium objects you trying to save which you should not do. It should be that you save the exact value of the link in an array and then loop them.

no element found even if it was present on the webpage

from selenium import webdriver
browser=webdriver.Firefox()
browser.get("http://dollarupload.com/dl/08c646d60")
browser.find_element_by_id("reg_download").click()
elementlist=browser.find_elements_by_class_name("offer_title")
Actually I was trying to get all the class named offer_title and with that I would like to click the link.But as I can see elementlist is empty.Why?

I think the elements you want are in an iframe to a different page.
If you get the iframe element and try again from there you might have more luck.
elementlist=browser.find_element_by_tag_name("iframe").find_elements_by_class_name("offer_title")

Selenium + Python: StaleElementReferenceException (selecting by class)

I'm trying to write a simple Python script using Selenium, and while the loop runs once, I'm getting a StaleElementReferenceException.
Here's the script I'm running:
from selenium import webdriver
browser = webdriver.Firefox()
type(browser)
browser.get('http://digital2.library.ucla.edu/Search.do?keyWord=&selectedProjects=27&pager.offset=50&viewType=1&maxPageItems=1000')
links = browser.find_elements_by_class_name('searchTitle')
for link in links:
link.click()
print("clicked!")
browser.back()
I did try adding browser.refresh() to the loop, but it didn't seem to help.
I'm new to this, so please ... don't throw stuff at me, I guess.

It does not make sense to click through links inside of a loop. Once you click the first link, then you are no longer on the page where you got the links. Does that make sense?
Take the for loop out, and add something like link = links[0] to grab the first link, or something more specific to grab the specific link you want to click on.
If the intention is to click on every link on the page, then you can try something like the following:
links = browser.find_elements_by_class_name('searchTitle')
for i in range(len(links)):
links = browser.find_elements_by_class_name('searchTitle')
link = links[i] # specify the i'th link on the page
link.click()
print("clicked!")
browser.back()
EDIT: This might also be as simple as adding a pause after the browser.back(). You can do that with the following:
from time import sleep
...
sleep(5) # specify pause in seconds