Let's say we have this file structure (downloadable MCVE here .zip):
xyz/
xyz/__init__.py <empty>
xyz/app.py from xyz import XYZ
xyz/xyz.py import ghi; print("hello xyz.py");
class XYZ: pass
xyz/ghi/__init__.py from .ghi_main import *
xyz/ghi/ghi_main.py print("hello ghi_main.py")
From the parent folder, running
python xyz/app.py
with the system-wide python works without error.
On the other hand, if we use an embedded python.exe:
python.exe
<+ other files from python-3.8.10-embed-amd64.zip>
xyz/
xyz/__init__.py
xyz/app.py
etc.
then it fails with:
Traceback (most recent call last):
File "xyz\app.py", line 1, in
from xyz import XYZ
ImportError: cannot import name 'XYZ' from 'xyz' (D:\Temp\xyz_init_.py)
Why?
Related
Trying to call a function yamlCreation() which is in another directory into this python file ..
the path of this file is
path:bss_micro_svcs/bss_micro_svcs/kubectl.py
Calling File: "kubectl.py"
from bss_micro_svcs.kubectl_utils.templating_to_yaml import yamlCreation
class Kube(Svcs):
def startService(self, cluster_info, service, service_profile):
yamlCreation()
k=Kube()
k.startService()
yamlCreation() function is in this python file named "templating_to_yaml.py"
the path of the file is..
path:bss_micro_svcs/kubectl_utils/templating_to_yaml.py
function to be called is inside this file:"templating_to_yaml.py"
file_loader = FileSystemLoader('bss_micro_svcs/bss_micro_svcs/yamls/templates')
env = Environment(loader=file_loader)
#deployment.yaml templating
deployment_template=env.get_template('deployment.tmpl')
deployment_output=deployment_template.render(deployment_name='nginx-deployment',deployment_app='nginx',deployment_replicas='3',deployment_container_name='nginx',deployment_image='nginx:1.14.2',deployment_container_port=80)
deployment_outfile=open('bss_micro_svcs/bss_micro_svcs/yamls/services/integration/deployment.yaml','w')
deployment_outfile.write(deployment_output)
deployment_outfile.close()
#*********************************************************************************************************************************************************#
#service.yaml templating
service_template=env.get_template('services.tmpl')
service_output=service_template.render(service_name='integration-service',service_name_space='demo-sandbox',service_app='integration',service_port=8090,target_port=8090)
service_outfile=open('bss_micro_svcs/bss_micro_svcs/yamls/services/integration/services.yaml','w')
service_outfile.write(service_output)
service_outfile.close()
GETTING AN ERROR:
┌──(bss_micro_svcs-jnO67Li7)(RK㉿kali)-[~/Desktop/servicelaunchmgr]
└─$ /home/RK/.local/share/virtualenvs/bss_micro_svcs-jnO67Li7/bin/python /home/RK/Desktop/servicelaunchmgr/bss_micro_svcs/bss_micro_svcs/kubectl.py
Traceback (most recent call last):
File "/home/RK/Desktop/servicelaunchmgr/bss_micro_svcs/bss_micro_svcs/kubectl.py", line 2, in <module>
from bss_micro_svcs.kubectl_utils.templating_to_yaml import yamlCreation
ModuleNotFoundError: No module named 'bss_micro_svcs'
You could set environment variable PYTHONPATH so the interpreter could know where to start looking for the module to import. I would suggest to set it in the root module.
Reference: https://bic-berkeley.github.io/psych-214-fall-2016/using_pythonpath.html
The structure needs for python 3.8+
That x.py contains x class with a 'display' method
concept one:
from p_abcd import a as A
''' call display '''
A.x.x().display()
Got an error
Traceback (most recent call last):
File "w.py", line 4, in
A.x.x().display()
AttributeError: module 'p_abcd.a' has no attribute 'x'
concept two:
import p_abcd.a as A
''' call display '''
A.x.x().display()
Got the same error
You can import only .py files. Not folders.
So you need something like
from p_abcd.a import x
x.display()
So I'm just starting to learn Python, and I am learning classes and imports, but for some reason even when I follow the same code as my book say to do, I get a traceback error.
Traceback (most recent call last):
File "C:/Users/Programming/Desktop/Programs/EX40/main.py", line 1, in <module>
import objects.py
ModuleNotFoundError: No module named 'objects.py'; 'objects' is not a package
Here is both my Python files in which I'm trying to link:
main.py
import objects.py
print(MyStuff.tangerine)
objects.py
class MyStuff(object):
def __init__(self, arm):
self.tangerine = 'And now a thousand years between'
self.arm = arm
def apple(self):
print('I AM CLASSY APPLES!')
Try using
import objects
Because it takes py as a module in the objects file which does not exist
import objects.py is not a valid import
https://docs.python.org/3/reference/import.html
Try
from objects import MyStuff
Instantiating the class:
mystuff = MyStuff("arm value")
print(mystuff.tangerine)
I have a following directory structure:
source
source_1.py
__init__.py
source1.py has class Source defined
source1.py
class Source(object):
pass
I am able to import using this
>>> from source.source1 import Source
>>> Source
<class 'source.source1.Source'>
However when trying to import using the below method it fails.
>>> from source import *
>>> source1.Source
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
NameError: name 'source1' is not defined
Please let me know how can we use the 2nd import ?
For importing from a package (unlike importing from a module) you need to specify what * means. To do that, in __init__.py add a line like this:
__all__ = ["source1"]
See the Python documentation for Importing * From a Package.
Summary:
The same import statement that works when __name__ == "__main__" stops working when imported from another module outside the immediate package. If I fix it so that it works when imported, it stops working when __name__ == "__main__". Is there a win-win solution for these conflicting scopes?
In more detail:
Say I have the following system layout.
package/
__init__.py
outer_module.py
subpackage/
__init__.py
inner_module_1.py
inner_module_2.py
And say that all modules are empty except for the following two.
# inner_module_1
import inner_module_2
&
# outer_module
import subpackage.inner_module_1
import subpackage.inner_module_2
If I run inner_module_1, there is no error.
If I run outer_module, I get the following ImportError from inner_module_1.
Traceback (most recent call last):
File "C:\package\outer_module.py", line 1, in <module>
import subpackage.inner_module_1
File "C:\package\subpackage\inner_module_1.py", line 1, in <module>
import inner_module_2
ImportError: No module named 'inner_module_2'
I can prevent that error by adding the package name to the import statement in inner_module_1 as follows.
# inner_module_1
import subpackage.inner_module_2
Although this change allows outer_module to run without an error, now running inner_module_1, which had before run without error, raises the following error.
Traceback (most recent call last):
File "C:\package\subpackage\inner_module_1.py", line 1, in <module>
import subpackage.inner_module_2
ImportError: No module named 'subpackage'
So here are my questions.
Is the import statement in inner_module_1 interpreted differently when accessed by outer_module than when run in inner_module_1, and if so, how so?
Can I write an import statement in inner_module_1 that works both when inner_module_1 is run and also when outer_module is run, and if so, what is that statement?
Thanks,
Victor