Get only the name of a DataFrame - Python - Pandas - python

I'm actually working on a ETL project with crappy data I'm trying to get right.
For this, I'm trying to create a function that would take the names of my DFs and export them to CSV files that would be easy for me to deal with in Power BI.
I've started with a function that will take my DFs and clean the dates:
df_liste = []
def facture(x) :
x = pd.DataFrame(x)
for s in x.columns.values :
if s.__contains__("Fact") :
x.rename(columns= {s : 'periode_facture'}, inplace = True)
x['periode_facture'] = x[['periode_facture']].apply(lambda x : pd.to_datetime(x, format = '%Y%m'))
If I don't set 'x' as a DataFrame, it doesn't work but that's not my problem.
As you can see, I have set a list variable which I would like to increment with the names of the DFs, and the names only. Unfortunately, after a lot of tries, I haven't succeeded yet so... There it is, my first question on Stack ever!
Just in case, this is the first version of the function I would like to have:
def export(x) :
for df in x :
df.to_csv(f'{df}.csv', encoding='utf-8')

You'd have to set the name of your dataframe first using df.name (probably, when you are creating them / reading data into them)
Then you can access the name like a normal attribute
import pandas as pd
df = pd.DataFrame( data=[1, 2, 3])
df.name = 'my df'
and can use
df.to_csv(f'{df.name}.csv', encoding='utf-8')

Related

Pandas DF.output write to columns (current data is written all to one row or one column)

I am using Selenium to extract data from the HTML body of a webpage and am writing the data to a .csv file using pandas.
The data is extracted and written to the file, however I would like to manipulate the formatting of the data to write to specified columns, after reading many threads and docs I am not able to understand how to do this.
The current CSV file output is as follows, all data in one row or one column
0,
B09KBFH6HM,
dropdownAvailable,
90,
1,
B09KBNJ4F1,
dropdownAvailable,
100,
2,
B09KBPFPCL,
dropdownAvailable,
110
or if I use the [count] count +=1 method it will be one row
0,B09KBFH6HM,dropdownAvailable,90,1,B09KBNJ4F1,dropdownAvailable,100,2,B09KBPFPCL,dropdownAvailable,110
I would like the output to be formatted as follows,
/col1 /col2 /col3 /col4
0, B09KBFH6HM, dropdownAvailable, 90,
1, B09KBNJ4F1, dropdownAvailable, 100,
2, B09KBPFPCL, dropdownAvailable, 110
I have tried using columns= options but get errors in the terminal and don't understand what feature I should be using to achieve this in the docs under the append details
https://pandas.pydata.org/docs/reference/api/pandas.DataFrame.append.html?highlight=append#pandas.DataFrame.append
A simplified version is as follows
from selenium import webdriver
import pandas as pd
price = []
driver = webdriver.Chrome("./chromedriver")
driver.get("https://www.example.co.jp/dp/zzzzzzzzzz/")
select_box = driver.find_element_by_name("dropdown_selected_size_name")
options = [x for x in select_box.find_elements_by_tag_name("option")]
for element in options:
price.append(element.get_attribute("value"))
price.append(element.get_attribute("class"))
price.append(element.get_attribute("data-a-html-content"))
output = pd.DataFrame(price)
output.to_csv("Data.csv", encoding='utf-8-sig')
driver.close()
Do I need to parse each item separately and append?
I would like each of the .get_attribute values to be written to a new column.
Is there any advice you can offer for a solution to this as I am not very proficient at pandas, thank you for your helps
 Approach similar to #user17242583, but a little shorter:
data = [[e.get_attribute("value"), e.get_attribute("class"), e.get_attribute("data-a-html-content")] for e in options]
df = pd.DataFrame(data, columns=['ASIN', 'dropdownAvailable', 'size']) # third column maybe is the product size
df.to_csv("Data.csv", encoding='utf-8-sig')
Adding all your items to the price list is going to cause them all to be in one column. Instead, store separate lists for each column, in a dict, like this (name them whatever you want):
data = {
'values': [],
'classes': [],
'data_a_html_contents': [],
}
...
for element in options:
values.append(element.get_attribute("value"))
classes.append(element.get_attribute("class"))
data_a_html_contents.append(element.get_attribute("data-a-html-content"))
...
output = pd.DataFrame(data)
output.to_csv("Data.csv", encoding='utf-8-sig')
You were collecting the value, class and data-a-html-content and appending them to the same list price. Hence, the list becomes:
price = [value1, class1, data-a-html-content1, value2, class2, data-a-html-content2, ...]
Hence, within the dataframe it looks like:
Solution
To get value, class and data-a-html-content in seperate columns you can adopt any of the below two approaches:
Pass a dictionary to the dataframe.
Pass a list of lists to the dataframe.
While the #user17242583 and #h.devillefletcher suggests a dictionary, you can still achieve the same using list of lists as follows:
values = []
classes = []
data-a-html-contents = []
driver = webdriver.Chrome("./chromedriver")
driver.get("https://www.example.co.jp/dp/zzzzzzzzzz/")
select_box = driver.find_element_by_name("dropdown_selected_size_name")
options = [x for x in select_box.find_elements_by_tag_name("option")]
for element in options:
values.append(element.get_attribute("value"))
classes.append(element.get_attribute("class"))
data-a-html-contents.append(element.get_attribute("data-a-html-content"))
df = pd.DataFrame(data=list(zip(values, classes, data-a-html-contents)), columns=['Value', 'Class', 'Data-a-Html-Content'])
output = pd.DataFrame(my_list)
output.to_csv("Data.csv", encoding='utf-8-sig')
References
You can find a couple of relevant detailed discussions in:
Selenium: Web-Scraping Historical Data from Coincodex and transform into a Pandas Dataframe
Python Selenium: How do I print the values from a website in a text file?

Function to print dataframe, that uses df name as an argument

In function, I can't use argument to define the name of the df in df.to_csv().
I have a long script to pull apart and understand. To do so I want to save the different dataframes it uses and store them in order. I created a function to do this and add the order number 01 (number_of_interim_exports) to the name (from argument).
My problem is that I need to use this for multiple dataframe names, but the df.to_csv part won't accept an argument in place of df...
def print_interim_results_any(name, num_exports, df_name):
global number_of_interim_exports
global print_interim_outputs
if print_interim_outputs == 1:
csvName = str(number_of_interim_exports).zfill(2) + "_" +name
interimFileName = "interim_export_"+csvName+".csv"
df.to_csv(interimFileName, sep=;, encoding='utf-8', index=False)
number_of_interim_exports += 1
I think i just screwed something else up: this works fine:
import pandas as pd
df = pd.DataFrame({1:[1,2,3]})
def f(frame):
frame.to_csv("interimFileName.csv")
f(df)

Append model output to pd df rows

I'm trying to put Pyomo model output into pandas.DataFrame rows. I'm accomplishing it now by saving data as a .csv, then reading the .csv file as a DataFrame. I would like to skip the .csv step and put output directly into a DataFrame.
When I accomplish an optimization solution with Pyomo, the optimal assignments are 1 in the model.x[i] output data (0 otherwise). model.x[i] is indexed by dict keys in v. model.x is specific syntax to Pyomo
Pyomo assigns a timeItem[i], platItem[i], payItem[i], demItem[i], v[i] for each value that presents an optimal solution. The 0807results.csv file produces an accurate file of the optimal assignments showing the value of timeItem[i], platItem[i], payItem[i], demItem[i], v[i] for each valid assignment in the optimal solution.
When model.x[i] is 1, how can I get timeItem[i], platItem[i], payItem[i], demItem[i], v[i] directly into a DataFrame? Your assistance is greatly appreciated. My current code is below.
index=sorted(v.keys())
with open('0807results.csv', 'w') as f:
for i in index:
if value(model.x[i])>0:
f.write("%s,%s,%s,%s,%s\n"%(timeItem[i],platItem[i],payItem[i], demItem[i],v[i]))
from pandas import read_csv
now = datetime.datetime.now()
dtg=(now.strftime("%Y%m%d_%H%M"))
df = read_csv('0807results.csv')
df.columns = ['Time', 'Platform','Payload','DemandType','Value']
# convert payload types to string so not summed
df['Payload'] = df['Payload'].astype(str)
df = df.sort_values('Time')
df.to_csv('results'+(dtg)+'.csv')
# do stats & visualization with pandas df
I have no idea what is in the timeItem etc iterables from the code you've posted. However, I suspect that something similar to:
import pandas as pd
results = pd.DataFrame([timeItem, platItem, payItem, demItem, v], index=["time", "plat", "pay", "dem", "v"]).T
Will work.
If you want to filter on 1s in model.x, you might add it as a column as well, and do a filter with pandas directly:
import pandas as pd
results = pd.DataFrame([timeItem, platItem, payItem, demItem, v, model.x], index=["time", "plat", "pay", "dem", "v", "x"]).T
filtered_results = results[results["x"]>0]
You can also use the DataFrame.from_records() function:
def record_generator():
for i in sorted(v.keys()):
if value(model.x[i] > 1E-6): # integer tolerance
yield (timeItem[i], platItem[i], payItem[i], demItem[i], v[i])
df = pandas.DataFrame.from_records(
record_generator(), columns=['Time', 'Platform', 'Payload', 'DemandType', 'Value'])

Get the name of a pandas DataFrame

How do I get the name of a DataFrame and print it as a string?
Example:
boston (var name assigned to a csv file)
import pandas as pd
boston = pd.read_csv('boston.csv')
print('The winner is team A based on the %s table.) % boston
You can name the dataframe with the following, and then call the name wherever you like:
import pandas as pd
df = pd.DataFrame( data=np.ones([4,4]) )
df.name = 'Ones'
print df.name
>>>
Ones
Sometimes df.name doesn't work.
you might get an error message:
'DataFrame' object has no attribute 'name'
try the below function:
def get_df_name(df):
name =[x for x in globals() if globals()[x] is df][0]
return name
In many situations, a custom attribute attached to a pd.DataFrame object is not necessary. In addition, note that pandas-object attributes may not serialize. So pickling will lose this data.
Instead, consider creating a dictionary with appropriately named keys and access the dataframe via dfs['some_label'].
df = pd.DataFrame()
dfs = {'some_label': df}
From here what I understand DataFrames are:
DataFrame is a 2-dimensional labeled data structure with columns of potentially different types. You can think of it like a spreadsheet or SQL table, or a dict of Series objects.
And Series are:
Series is a one-dimensional labeled array capable of holding any data type (integers, strings, floating point numbers, Python objects, etc.).
Series have a name attribute which can be accessed like so:
In [27]: s = pd.Series(np.random.randn(5), name='something')
In [28]: s
Out[28]:
0 0.541
1 -1.175
2 0.129
3 0.043
4 -0.429
Name: something, dtype: float64
In [29]: s.name
Out[29]: 'something'
EDIT: Based on OP's comments, I think OP was looking for something like:
>>> df = pd.DataFrame(...)
>>> df.name = 'df' # making a custom attribute that DataFrame doesn't intrinsically have
>>> print(df.name)
'df'
DataFrames don't have names, but you have an (experimental) attribute dictionary you can use. For example:
df.attrs['name'] = "My name" # Can be retrieved later
attributes are retained through some operations.
Here is a sample function:
'df.name = file` : Sixth line in the code below
def df_list():
filename_list = current_stage_files(PATH)
df_list = []
for file in filename_list:
df = pd.read_csv(PATH+file)
df.name = file
df_list.append(df)
return df_list
I am working on a module for feature analysis and I had the same need as yours, as I would like to generate a report with the name of the pandas.Dataframe being analyzed. To solve this, I used the same solution presented by #scohe001 and #LeopardShark, originally in https://stackoverflow.com/a/18425523/8508275, implemented with the inspect library:
import inspect
def aux_retrieve_name(var):
callers_local_vars = inspect.currentframe().f_back.f_back.f_locals.items()
return [var_name for var_name, var_val in callers_local_vars if var_val is var]
Note the additional .f_back term since I intend to call it from another function:
def header_generator(df):
print('--------- Feature Analyzer ----------')
print('Dataframe name: "{}"'.format(aux_retrieve_name(df)))
print('Memory usage: {:03.2f} MB'.format(df.memory_usage(deep=True).sum() / 1024 ** 2))
return
Running this code with a given dataframe, I get the following output:
header_generator(trial_dataframe)
--------- Feature Analyzer ----------
Dataframe name: "trial_dataframe"
Memory usage: 63.08 MB

Exporting Pandas DataFrame with MultiIndex

I have just discovered pandas and am impressed by its capabilities.
I am having difficulties understanding how to work with DataFrame with MultiIndex.
I have two questions :
(1) Exporting the DataFrame
Here my problem:
This dataset
import pandas as pd
import StringIO
d1 = StringIO.StringIO(
"""Gender,Employed,Region,Degree
m,yes,east,ba
m,yes,north,ba
f,yes,south,ba
f,no,east,ba
f,no,east,bsc
m,no,north,bsc
m,yes,south,ma
f,yes,west,phd
m,no,west,phd
m,yes,west,phd """
)
df = pd.read_csv(d1)
# Frequencies tables
tab1 = pd.crosstab(df.Gender, df.Region)
tab2 = pd.crosstab(df.Gender, [df.Region, df.Degree])
tab3 = pd.crosstab([df.Gender, df.Employed], [df.Region, df.Degree])
# Now we export the datasets
tab1.to_excel('H:/test_tab1.xlsx') # OK
tab2.to_excel('H:/test_tab2.xlsx') # fails
tab3.to_excel('H:/test_tab3.xlsx') # fails
One work-around I could think of is to change the columns (The way R does)
def NewColums(DFwithMultiIndex):
NewCol = []
for item in DFwithMultiIndex.columns:
NewCol.append('-'.join(item))
return NewCol
# New Columns
tab2.columns = NewColums(tab2)
tab3.columns = NewColums(tab3)
# New export
tab2.to_excel('H:/test_tab2.xlsx') # OK
tab3.to_excel('H:/test_tab3.xlsx') # OK
My question is : Is there a more efficient way to do this in Pandas that I missed in the documentation ?
2) Selecting columns
This new structure does not allow to select colums on a given variable (the advantage of hierarchical indexing in first place). How can I select columns containing a given string (e.g. '-ba') ?
P.S: I have seen this question which is related but have not understood the reply proposed
This looks like a bug in to_excel, for the moment as a workaround I would recommend using to_csv (which seems not to show this issue).
I added this as an issue on github.
To answer the second question, if you really need to use to_excel...
You can use filter to select only those columns which include '-ba':
In [21]: filter(lambda x: '-ba' in x, tab2.columns)
Out[21]: ['east-ba', 'north-ba', 'south-ba']
In [22]: tab2[filter(lambda x: '-ba' in x, tab2.columns)]
Out[22]:
east-ba north-ba south-ba
Gender
f 1 0 1
m 1 1 0

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