Finished creating the models file, typed python manage.py makemigrations main and I get a reply back, 'no installed app with label 'main'. when I do python manage.py migrate, it says Apply all migrations: admin, auth, contenttypes, sessions. I even spent considerable time double checking my spelling and it is correct. Any ideas on how I can fix it?
your app.py must look like this:
from django.apps import AppConfig
class MainConfig(AppConfig):
name = 'main'
verbose_name = 'Some Name'
You need to add your app main to the INSTALLED_APPS setting [Django-doc] in the settings.py:
# settings.py
INSTALLED_APPS = [
# …,
'main'
]
I have Django models Driver and Trip. Nothing in my views and no urls. I'm using Django as mere Database, using scripts to store stuff there in DB.
Here is my tree of how every thing looks:
loadmngr/
models.py
views.py
urls.py
management/
commands/
> it.py <
Assume I have init.py inside management and commands.
All I'm doing is a simple import of my Django models. Here is it.py:
import sys
parent = '/Users/work/TM/loadmngr'
sys.path.insert(0, parent)
from models import Trip
I run python manage.py it and I get a RunTimeError:
RunTimeError: Model class models.Driver doesn't declare an explicit app_label and either isn't in an application in INSTALLED_APPS or else was imported before its application was loaded.
The latter part of the error ...or else was imported before its application was loaded is what I believe could be the problem.
Question is: How can I properly use my Django models externally with properly configured settings?
the django doc says to change the sites name and domain in the django.contrib.sites framework one should use a migration [1].
But they forgot to mention where I should put this migration. I tried to create a directory named "sites" and a directory named "django.contrib.sites". But no matter in which directory I put my migration, manage.py migration always says there is nothing to update.
I also tried to run python manage.py makemigrations --empty sites, but then the migration is created in the lib directory: ve/lib/python3.5/site-packages/django/contrib/sites/migrations/0003_auto_20160904_2144.py. This may be correct behaviour, but then I cannot set my change under source control.
In case something is wrong with my migration, here it is:
from __future__ import unicode_literals
from django.db import migrations, models
def set_site_name(apps, schema_editor):
Sites = apps.get_model('django.contrib.sites', 'site')
site = Sites.objects.filter(id=1).first()
if site != None:
site.name = "name"
site.domain = "name.com"
class Migration(migrations.Migration):
initial = True
operations = [
migrations.RunPython(set_site_name),
]
So my question is: where does django expect to find those migrations?
Thank you very much in advance for your help.
[1] https://docs.djangoproject.com/en/1.10/ref/contrib/sites/#enabling-the-sites-framework
Each app in a Django project must have a unique label. Naming your app sites isn't a good idea - it will clash with the django.contrib.sites app unless you change the label in the app config class.
If you have an existing app specific to your project, you could use that app to store the data migration.
Alternatively choose a different name like mysites. Create the app with ./manage.py startapp mysite, add the app to your INSTALLED_APPS, then create a blank migration.
Is it possible to dynamically load Django apps at runtime? Usually, apps are loaded at initialization, using the INSTALLED_APPS tuple in settings.py. However, is it possible to load additional apps at runtime? I am encountering this issue in different situations. One situation, for example, arises during testing, when I would like to dynamically load or unload apps.
In order to make the problem more concrete, imagine I have a directory called apps where I put my apps and I would like to automatically install any new app that goes in there without manually editing the settings.py.
This is easy enough. Following the example code in
Django: Dynamically add apps as plugin, building urls and other settings automatically
we put the following code in settings.py to could loop over the names of all sub-directories in the app directory and increment the INSTALLED_APPS tuple in settings.py like this:
APPS_DIR = '/path_to/apps/'
for item in os.listdir(APPS_DIR):
if os.path.isdir(os.path.join(APPS_DIR, item)):
app_name = 'apps.%s' % item
if app_name not in INSTALLED_APPS:
INSTALLED_APPS += (app_name, )
After that, if I was in a Django shell, I could something like
from django.conf import settings
and the apps would be listed in settings.INSTALLED_APPS. And if I did
from django.core import management
management.call_command('syncdb', interactive=False)
that would create the necessary DB tables for the apps.
However, if I were to now add some more apps to the apps/ directory, without re-starting, these would not be listed in settings.INSTALLED_APPS, and so a subsequent call to the syncdb would have no effect.
What I would like to know is if there is something I could do --- without restarting --- to reload the settings and load/install new apps.
I have tried to directly import my settings.py, i.e.
from myproject import settings
and then reload that settings using the python builtin after any app directory changes. Although settings.INSTALLED_APPS is now changed to include the newly added apps, this ultimately makes no difference. For example,
from django.db import models
models.get_apps()
shows only the original apps in apps and not the newly added ones and likewise
management.call_command('syncdb', interactive=False)
will not see the newly added apps.
As I stated above, I am thinking about this situation particularly in the context of testings where I dynamically would add or remove apps.
Ps. I working with Django 1.6, but on the advice of #RickyA, I see that there are some substantial changes to Django's treatment of applications in 1.7
https://docs.djangoproject.com/en/1.7/ref/applications/
I'm still not sure what this might mean for the problem I am facing.
Update for Django 1.8 on how to load an app that is not loaded yet
from collections import OrderedDict
from django.apps import apps
from django.conf import settings
from django.core import management
new_app_name = "my_new_app"
settings.INSTALLED_APPS += (new_app_name, )
# To load the new app let's reset app_configs, the dictionary
# with the configuration of loaded apps
apps.app_configs = OrderedDict()
# set ready to false so that populate will work
apps.ready = False
# re-initialize them all; is there a way to add just one without reloading them all?
apps.populate(settings.INSTALLED_APPS)
# now I can generate the migrations for the new app
management.call_command('makemigrations', new_app_name, interactive=False)
# and migrate it
management.call_command('migrate', new_app_name, interactive=False)
With Django 2.2 this work for me
from collections import OrderedDict
from django.apps import apps
from django.conf import settings
from django.core import management
new_app_name = "my_new_app"
settings.INSTALLED_APPS += (new_app_name, )
apps.app_configs = OrderedDict()
apps.apps_ready = apps.models_ready = apps.loading = apps.ready = False
apps.clear_cache()
apps.populate(settings.INSTALLED_APPS)
management.call_command('makemigrations', new_app_name, interactive=False)
management.call_command('migrate', new_app_name, interactive=False)
To answer my own question...
While I do not have a completely general solution to this problem, I do have one that is sufficient for the purposes of dynamically loading apps during testing.
The basic solution is simple, and I found it at a wee little bixly blog.
Continuing with my example above, if I was in a django shell and wanted to add and load some new apps that were added to my apps directory, I could do
import os
from django.conf import settings
from django.db.models import loading
from django.core import management
APPS_DIR = '/path_to/apps/'
for item in os.listdir(APPS_DIR):
if os.path.isdir(os.path.join(APPS_DIR, item)):
app_name = 'apps.%s' % item
if app_name not in settings.INSTALLED_APPS:
settings.INSTALLED_APPS += (app_name, )
and then
loading.cache.loaded = False
management.call_command('syncdb', interactive=False)
It is possible to dynamically load and unload applications in tests in Django >= 1.7 (and also in the current 4.1) by a override_settings() decorator:
#override_settings(INSTALLED_APPS=[...]) # added or removed some apps
class MyTest(TestCase):
# some tests with these apps
def test_foo(self):
pass
It has been possible since September 2014, not before the question.
Many other topics from the question are solved by django.apps also in Django >= 1.7. Generally: Dynamic configuration at startup is easy in the current Django. Dynamic loading and unloading after startup can't be recommended in production, even that it could work eventually.
Yes! Anything (or almost everything) in Python is possible. You should use os.walk() in order to get all folders, subfolders and files within your apps path in order to get all of your apps including the nested ones.
def get_installed_apps():
from os import walk, chdir, getcwd
previous_path = getcwd()
master = []
APPS_ROOT_PATH = '/my/project/apps/folder'
chdir(APPS_ROOT_PATH)
for root, directories, files in walk(top=getcwd(), topdown=False):
for file in files:
if 'apps.py' in file:
app_path = f"{root.replace(BASE_DIR + '/', '').replace('/', '.')}.apps"
print(app_path)
master.append(app_path)
chdir(previous_path)
return master
print(get_installed_apps())
I'm trying to set up auto documentation generation using tastypie swagger, as documented here. However, Django doesn't seem to be a fan of the following line in my setup:
TASTYPIE_SWAGGER_API_MODULE = 'mainsite.urls.api'
as evidenced by this error when I try to hit /api/doc:
ImproperlyConfigured at /api/doc/
mainsite.urls is not a valid python path
I am working off of a Django 1.4 project I found online to introduce myself to some of the technologies. The Django structure looks like this:
project_directory
src
urls.py
manage.py
settings.py
etc...
app
models.py
views.py
api.py
etc...
Any ideas?
You're not supposed to cut and paste 'mainsite.urls.api'. You're supposed to replace it with your tastypie api that you created according to the tastypie docs.
Specifically, see here:
http://django-tastypie.readthedocs.org/en/latest/tutorial.html#adding-to-the-api
If you blindly copied the tastypie setup instructions, you should have something like:
TASTYPIE_SWAGGER_API_MODULE = 'urls.v1_api'
I had this error with the current (March 2016) version of tastypie-swagger. The setting for me that worked was this:
from tastypie.api import Api
v1_api = Api(api_name='v1')
v1_api.register(MyResource())
urlpatterns = [
...
url(r'^api/', include(v1_api.urls)),
url(r'api/v1/doc/',
include('tastypie_swagger.urls', namespace='api_tastypie_swagger'),
kwargs={"tastypie_api_module": v1_api, "namespace": "api_tastypie_swagger"}
),
]
so tastypie_api_module is v1_api without quotes