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Splitting large xml file into multiple files by using beautifulsoup

I am trying to split large xml file into smaller ones, first I started off beautifulsoup:
from bs4 import BeautifulSoup
import os
# Core settings
rootdir = r'C:\Users\XX\Documents\Grant Data\2010_xml'
extension = ".xml"
to_save = r'C:\Users\XX\Documents\all_patents_as_xml'
index = 0
for root, dirs, files in os.walk(rootdir):
for file in files:
if file.endswith(extension):
print(file)
file_name = os.path.join(root,file)
with open(file_name) as f:
data = f.read()
texts = data.split('?xml version="1.0" encoding="UTF-8"?')
for text in texts:
index += 1
filename = to_save + "\\"+ str(index) + ".txt"
with open(filename, 'w') as f:
f.write(text)
However, I got a memory error. Then I switched to xml etree:
from xml.etree import ElementTree as ET
import re
file_name = r'C:\Users\XX\Documents\Grant Data\2010_xml\2010cat_xml.xml'
with open(file_name) as f:
xml = f.read()
tree = ET.fromstring(re.sub(r"(<\?xml[^>]+\?>)", r"\1<root>", xml) + "</root>")
parser = ET.iterparse(tree)
to_save = r'C:\Users\Yilmaz\Documents\all_patents_as_xml'
index = 0
for event, element in parser:
# element is a whole element
if element.tag == '?xml version="1.0" encoding="UTF-8"?':
index += 1
filename = to_save + "\\"+ str(index) + ".txt"
with open(filename, 'w') as f:
f.write(ET.tostring(element))
# do something with this element
# then clean up
element.clear()
and I get the following error:
OverflowError: size does not fit in an int
I am using windows operating system, I know in Linux you can split the xmls from consule but in my case I don't know what to do.

If your XML can not be loaded because of memory limits, you should consider using SAX.
With SAX you will read "small bites" of the document, do what ever you want to do with them (Example: Save every N elements to a new file).
Python SAX example 1.
Python SAX example 2.

There are major issues with your question and your attempts at solving it:
You mention using Beautiful Soup. However, while you import Beautiful Soup in your code, you don't actually do anything with it.
The code you show that uses xml.etree is grossly incorrect. At the line parser = ET.iterparse(tree), tree is an XML tree already parsed with ET.fromstring, but the argument to iterparse must either be a file name or a file object. An XML tree is neither of those. So that attempt is dead on arrival.
But more importantly, it looks like what you are trying to process is a file which contains a bunch of concatenated XML files. In your xml.etree attempt you have this test:
element.tag == '?xml version="1.0" encoding="UTF-8"?'
The only intent I can imagine for this test is that you think that xml.etree will somehow interpret <?xml version="1.0" encoding="UTF-8"?> as an XML element which has a name of '?xml version="1.0" encoding="UTF-8"?'. However, the structure <?xml version="1.0" encoding="UTF-8"?> is not an XML element, it is an XML declaration.
And since your code seems to be attempting to split every time an XML declaration is encountered, it seems that your input is a file that contains multiple XML declarations. This file is not valid XML. The XML specification allows the XML declaration to appear once, and only once at the beginning of an XML file. (Don't confuse the XML declaration with a processing instruction. They look similar because they are both delimited by <? and ?>, but the XML declaration is not a processing instruction.) If you use an XML parser on your input file, and this parser conforms to the XML specification, then it has to reject your file as being not XML because XML does not allow XML declarations to appear at random positions in documents.
Where does that leave you? If all XML declarations present in your source document are the same, there's a relatively easy way to make your document parsable by an XML parser. (The attempts you made suggest that they are all the same since you do not use a regular expressions to match different forms of the XML declaration (e.g. one that would specify the standalone parameter).) You can just remove all XML declarations from your source document, wrap it in a new root element, and parse that with xml.etree. (This assumes that the individual XML documents that were concatenated to make up your source document were all individually well-formed. If they weren't then this won't work.)
Note, however, that the string <?xml version="1.0" encoding="UTF-8"?> can appear in an XML document in contexts where this string is not actually an XML declaration. Here is a well-formed XML document that would throw off an algorithm that just looks for a string that looks like an XML declaration:
<?xml version = "1.0" encoding = "UTF-8"?>
<a>
<![CDATA[
<?xml version = "1.0" encoding = "UTF-8"?>
]]>
<?q <?xml version = "1.0" encoding = "UTF-8"?> ?>
<!-- <?xml version = "1.0" encoding = "UTF-8"?> -->
</a>
If you know how your source file was created, you may already be able to know for sure that you don't have any of the cases above. Otherwise, you may want to examine your source to make sure none of the above happens.
Once you take care of this, then using a strategy based on ET.iterparse, or SAX should work.

Write Open Office XML (e.g. docx) with XML that matches the OOXML namespace

I have a python program that edits the XML in a .docx file. I'd like to edit the XML with ETree.
When I read the XML from the .docx file, it begins like this:
b'<?xml version="1.0" encoding="UTF-8" standalone="yes"?>\r\n<w:document xmlns:wpc="http://schemas.micro'...
This is in a variable called data. I create the element tree with:
import xml.etree.ElementTree as ElementTree
tree = ElementTree.XML(data)
I convert it back with:
data = ElementTree.tostring(tree)
However, there have been subtle changes to the XML. It now looks like this:
b'<ns0:document xmlns:ns0="http://schemas.openxmlformats.org/wordprocessingml/2006/main" xmlns:ns1="ht...
Word won't read this, even though it is standard XML.
EDIT: I tried adding the string to my XML, just to get it to round-trip:
XML_HEADER=b'<?xml version="1.0" encoding="UTF-8" standalone="yes"?>\r\n'
tree = ElementTree.XML(data)
data = XML_HEADER + ElementTree.tostring(tree)
But I still get the error:
We're sorry. We can't open <filename>.docx because we found a problem with its contents.
Details:
The XML data is invalid according to the schema.
Location: Part: /word/document.xml, Line: 0, Column:0
I can't fix word. I've got to generate XML that looks exactly like the XML that I started with. How do I get ETree to generate that?

Find all titles in an XML with Elementree from a bz2 file

I'm new to parsing in XML and am stuck with my code regarding finding all titles (title tags) in an XML. This is what I came up with, but it is returning just an empty list, while there should be titles in there.
import bz2
from xml.etree import ElementTree as etree
def parse_xml(filename):
with bz2.BZ2File(filename) as f:
doc = etree.parse(f)
titles = doc.findall('.//{http://www.mediawiki.org/xml/export-0.7/}title')
print titles[:10]
Can someone tell me why this is not working properly? Just to be clear; I need to find all text inside title tags stored in a list, taken from an XML wrapped in a bz2 file (as far as I read the best way is without unzipping).

Python parse XML files with HTML content

I use an API to get some XML files but some of them contain HTML tags without escaping them. For example, <br> or <b></b>
I use this code to read them, but the files with the HTML raise an error. I don't have access to change manually all the files. Is there any way to parse the file without losing the HTML tags?
from xml.dom.minidom import parse, parseString
xml = ...#here is the api to receive the xml file
dom = parse(xml)
strings = dom.getElementsByTagName("string")

Read the xml file as a string, and fix the malformed tags before you parse it:
import xml.etree.ElementTree as ET
with open(xml) as xml_file: # open the xml file for reading
text= xml_file.read() # read its contents
text= text.replace('<br>', '<br />') # fix malformed tags
document= ET.fromstring(text) # parse the string
strings= document.findall('string') # find all string elements

If you can use third-party libs I suggest you to use Beautiful Soup it can handle xml as well as html and also it parses broken markup, also providing easy to use api.

Python:JS: How to parse multiple kml node in one xml file?

<xml>
<mapshape title="Bar" extras="">
<kml></kml>
</mapshape>
<mapshape title="Foo" extras="">
<kml></kml>
</mapshape>
</xml>
I've got a xml doc like that, multiple mapshape nodes in one xml, and each contains one valid kml file. I need to plot them all on google maps.
I have tried libraries like geoxml(3), they can parse one kml file, but my document has many kmls, how can I deal with this?

You can use lxml to extract the kml sections and then pass them on to the other library:
doc = """<xml>
<mapshape title="Bar" extras="">
<kml></kml>
</mapshape>
<mapshape title="Foo" extras="">
<kml></kml>
</mapshape>
</xml>"""
import lxml.etree as etree
xml = etree.fromstring(doc)
for mapshape in xml:
kml = etree.tostring(mapshape.getchildren()[0])
parseKML(kml)