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I'm getting this error please help
The ampersand (&) character is not allowed. The & operator is reserved for future use; wrap an ampersand in double quotation marks
("&") to pass it as part of a string.
+ CategoryInfo : ParserError: (:) [], ParentContainsErrorRecordException
+ FullyQualifiedErrorId : AmpersandNotAllowed
This is my code
import jwnet
import songList as sl
sl.downloadSongList(jwnet.ask("Name of your songlist "),
jwnet.ask("Output folder "))
I'm using custom libraries.
jwnet.ask is just like input = input("Question Here")
sl.downloadsonglist downloads a file from a txt
Check where your terminal is based.
You most likely have included an extra & in your code execution path.
e.g. &C:/Users/hello/...
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I have this code in a file called script.py
import json
myjson=json.loads(open(‘id.json’,’rb’))
[(os.makedirs(os.path.join(*v.split(‘_’))), open(os.path.join(*v.split(‘_’),‘id.txt’),’w’).write(k)) for k,v in myjson.items()]
I also have in the same folder, a file called id.json that looks like this:
{
"0":"text_test",
"1":"text_text",
"2":"test_test",
...
}
But when I try to run py script.py command on the cmd, I get this error :
File "script.py", line 2
myjson=json.loads(open(‘id.json’,’rb’))
^
SyntaxError: invalid character in identifier
I am not very familiar with Python and some guides from the web didn't help me out.
The quote you are using is invalid.
You are using: ‘
You have to use: " or '
Replace all of your ‘ with '
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I am trying to use machine learning to predict students' future grade, but am stuck at the beginning.
Seems like pandas.read_csv cannot read psv file, I got:
df = pd.read_csv(‘training.psv’)
^
SyntaxError: invalid character in identifier
How can I read psv file through python?
The problem is in the quotes symbol. You should either use ' or ".
Try:
df = pd.read_csv('training.psv')
pd.read_csv("training.psv", sep = "|", header = FALSE, stringsAsFactors = FALSE)
That should work
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A problem exists in Python 2.7.11, with the print function:
elif e=="randomize w and x":
random=randint(int(w),int(x))
print random
elif e=="randomize w and y":
random=randint(int(w,int(y))
print random
The boldfaced print shows up as a syntax error, yet all 278 others in my program do not. Why this is, and how I fix it?
The problem is that in
random=randint(int(w,int(y))
a close parenthesis after w is missing, therefore Python thinks the expression continues on next line, but print at that point is a syntax error.
Your problem is not with the print statement, rather the line right before it. The line before hass inbalanced parenthesis:
random=randint(int(w,int(y))
Make sure you balance them out (add an extra ) at the end), and your error on the next line will disappear.
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Every time I try to run these first 2 lines in python, it says:
SyntaxError: invalid syntax
And highlights the name of the variable I'm trying to define (Yname).
These are the lines I'm trying to run:
print("Hello what's your name?")\
Yname = input("your name:")
It is because of the \ at the end of the first line.
in Python \ is the line continuation character. Python is trying to parse this as
print("Hello what's your name?")Yname = input("your name:")
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import random
for i in range(1,21):
print("%10d" %(random.randrange(1,7)),
if (i % 5 == 0):
print ("")
What is wrong in this code ?
I know basic python (almost), but i am not able to figure out what could be error in this program.
it is showing this error:
Syntax Error: invalid syntax at line 6 (if statement)
The fourth line is missing bracket .. Thanks all of you
You missed a right bracket )
print("%10d" %(random.randrange(1,7))),
would be correct
You're missing a ) before the last comma on line 4.
Your parenthesis on line 4 don't match. Because you have an unclosed paren, python doesn't report this syntax error until the colon on line 6 (python ignores line breaks as long as you are inside an enclosing set of parenthesis, brackets, or braces).