How do I send a photo to chat without compression, as a file. When I implement it with the current method, the file is sent as a document without an extension.
bot = TeleBot("API")
#bot.message_handler(content_types=['text'])
def send(message):
with open("5.jpg", "rb") as file:
f = file.read()
bot.send_document(message.chat.id, document=f)
bot.polling(True)
When you do
f = file.read()
Combined with document=f, Telegram will receive the content of the file.
To send the file with the original filenamem, pass the file variable from open():
with open("/tmp/ccatt.jpeg", "rb") as file:
bot.send_document(123456789, document=file)
Related
Im creating an api using flask where zip file should be downloaded at client side. The zip file is converted in to binary files and sent to client. The client regenerates the binary file back in to zip file. The server side is working fine and a zip file is downloaded but inside the file is empty. How to fix this?
this is server side
'''
#app.route('/downloads/', methods=['GET'])
def download():
from flask import Response
import io
import zipfile
import time
FILEPATH = "/home/Ubuntu/api/files.zip"
fileobj = io.BytesIO()
with zipfile.ZipFile(fileobj, 'w') as zip_file:
zip_info = zipfile.ZipInfo(FILEPATH)
zip_info.date_time = time.localtime(time.time())[:6]
zip_info.compress_type = zipfile.ZIP_DEFLATED
with open(FILEPATH, 'rb') as fd:
zip_file.writestr(zip_info, fd.read())
fileobj.seek(0)
return Response(fileobj.getvalue(),
mimetype='application/zip',
headers={'Content-Disposition': 'attachment;filename=files.zip'})
# client side
bin_data=b"response.content" #Whatever binary data you have store in a variable
binary_file_path = 'files.zip' #Name for new zip file you want to regenerate
with open(binary_file_path, 'wb') as f:
f.write(bin_data)
I need to save a file which was sent to telegram bot.
import telebot
bot = "Here is my token"
#bot.message_handler(content_types='') #IDK what content type I need to use to receive every file
def addfile(message):
#Here I need to save file which was sent
That would look something like this:
#bot.message_handler(content_types=['document', 'photo', 'audio', 'video', 'voice']) # list relevant content types
def addfile(message):
file_name = message.document.file_name
file_info = bot.get_file(message.document.file_id)
downloaded_file = bot.download_file(file_info.file_path)
with open(file_name, 'wb') as new_file:
new_file.write(downloaded_file)
I have this code for server
#app.route('/get', methods=['GET'])
def get():
return send_file("token.jpg", attachment_filename=("token.jpg"), mimetype='image/jpg')
and this code for getting response
r = requests.get(url + '/get')
And i need to save file from response to hard drive. But i cant use r.files. What i need to do in these situation?
Assuming the get request is valid. You can use use Python's built in function open, to open a file in binary mode and write the returned content to disk. Example below.
file_content = requests.get('http://yoururl/get')
save_file = open("sample_image.png", "wb")
save_file.write(file_content.content)
save_file.close()
As you can see, to write the image to disk, we use open, and write the returned content to 'sample_image.png'. Since your server-side code seems to be returning only one file, the example above should work for you.
You can set the stream parameter and extract the filename from the HTTP headers. Then the raw data from the undecoded body can be read and saved chunk by chunk.
import os
import re
import requests
resp = requests.get('http://127.0.0.1:5000/get', stream=True)
name = re.findall('filename=(.+)', resp.headers['Content-Disposition'])[0]
dest = os.path.join(os.path.expanduser('~'), name)
with open(dest, 'wb') as fp:
while True:
chunk = resp.raw.read(1024)
if not chunk: break
fp.write(chunk)
This is the code for the screenshot:
im = ImageGrab.grab()
im.save(r'C:\screen.jpg')
I am suppposed to return the image but i dont know how to.
I've tried to open it as a file and read it in 1024 pieces but these are two different def so the response spose to be the file name.
with open (response, 'w') as filename:
data = filename.read()
file_name = "r1.csv"
client = storage.Client()
bucket = client.get_bucket('upload-testing')
blob = bucket.get_blob(file_name)
blob.download_to_filename("csv_file")
Want to Open r1.csv file in read only Mode.
Getting this Error
with open(filename, 'wb') as file_obj:
Error: [Errno 30] Read-only file system: 'csv_file'
so the function download_to_filename open files in wb mode is there any way threw which i can open r1.csv in read-only mode
As mentioned in previous answer you need to use the r mode, however you don't need to specify that since that's the default mode.
In order to be able to read the file itself, you'll need to download it first, then read its content and treat the data as you want. The following example downloads the GCS file to a temporary folder, opens that downloaded object and gets all its data:
storage_client = storage.Client()
bucket = storage_client.get_bucket("<BUCKET_NAME>")
blob = bucket.blob("<CSV_NAME>")
blob.download_to_filename("/tmp/test.csv")
with open("/tmp/test.csv") as file:
data = file.read()
<TREAT_DATA_AS_YOU_WISH>
This example is thought to run inside GAE.
If you want to open a read only file you should use 'r' mode, 'wb' means write binary:
with open(filename, 'r') as file_obj: