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I'm working on a calculated but I have hit a brick wall. I'm seeing this error "TypeError: string indices must be integers" [closed]

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def add (n1, n2):
return n1 + n2
def subtract(n1, n2):
return n1 - n2
def multiply(n1, n2):
return n1 * n2
def divide(n1, n2):
return n1 / n2
operations = {"+": "add",
"-": "subtract",
"*": "multiply",
"/": "divide"
}
num1 = int(input("What's your first number?: "))
num2 = int(input("What's your second number?: "))
for symbol in operations:
print(symbol)
operation_symbol = input("Pick an operation from line above: ")
calculation_function = operations[operation_symbol]
answer = calculation_function[num1, num2] # This is line where the string induces must be integers is happening
print(f"{num1} {operation_symbol} {num2} = {answer}")
I am expecting to see the out put of the calculation.

max function not returning right ouput [closed]

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(I am pretty new to python)
Hey guys, so I was trying to code a simple python program which finds the HCF of two numbers, but I am getting an error when the two numbers are co-prime and the actual HCF is not showing for the two numbers
(Ex: The HCF for 12 and 24 should be 12 but python is showing 4
Here is the code, can any of you guys help me?
factors = []
print("Enter first number")
num1 = int(input())
print("Enter second number")
num2 = int(input())
if num1 < num2:
lesser = num1
else:
lesser = num2
for i in range(2, lesser + 2):
if num1 % i == 0 and num2 % i == 0:
factors.append(i)
if not factors:
print(num1, "and", num2, "are co-prime numbers, so they don't have any common factors")
str_factors = ', '.join(map(str, factors))
hcf = max(str_factors)
print(hcf)

You are turning factors into a comma separated string and using max on the string. It's giving you the max of the string lexicographically. You need to use max on the factors variable.
Say for a string '2, 12, 42, 13' max will return '4' because it loops through all characters in a string
Fix this line and it should produce you expected output
hcf = max(factors)

TypeError: 'int' object is not callable (While working on google colaboratory) [closed]

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Closed last year.
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In python I got a "TypeError: 'int' object is not callable" during execution.
I had read other posts but I still can't figure out why it is like this.
# Python code to find if a number is
# prime or not using divmod()
# Given integer
n = int(input("Enter a number"))
x = n
# Initialising counter to 0
count = 0
while x != 0:
p, q = divmod(n, x)
x -= 1
if q == 0:
count += 1
if count > 2:
print(n, 'is Not Prime')
else:
print(n, 'is Prime')
And, please note that it doesn't gives any error by replacing:
n = int(input("Enter a number")) to n = int(input("Enter a number"))
I have also provided a screenshot regarding my problem 👇
image
Answer if anybody knows, Appreciation for any suggestions and comments.

Have you tried something like this?
z = input("Enter a number")
n = int(z)
x = n

i am trying to print out this simply equation, but it says float object is not callable [closed]

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I have been trying to print out this very simple equation but I cannot figure out why it will not print?
fc = float(input("first cycle is "))
fp = float(input("first percent is "))
sc = float(input("second cycle is "))
sp = float(input("second percent is "))
tc = float(input("third cycle is "))
tp = float(input("third percent is "))
mem = float(input("the memory is "))
first_part = (fc * fp + (sc(1-fp)))
print(first_part)
It gives me the error "TypeError: 'float' object is not callable"

The * multiplication operator cannot be omitted as it can in an algebraic equation. The interpreter thinks sc(1-fp) is a function call.
first_part = (fc * fp + (sc * (1-fp)))

If/Elif Python Statement [closed]

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New to this. My autochecker says that line 3 is incorrect.
score = input("Enter Score: ")
s = float(score)
if s >= 0.9
("A")
elif s >= 0.8
print ("B")
elif s >=0.7
print ("C")
elif s >=0.6
print ("D")
elif s < 0.5
print ("F")
else
print ("Enter number")

You need a colon after each if/elif/else line.
You need to add print before "A".