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Cannot POST using Rest API

So I can retrieve my data perfectly fine but when I try to post I get
{"detail":"Method \"POST\" not allowed."}
views.py
class ClubFullList(generics.ListAPIView):
serializer_class = ClubSerializer
def get_queryset(self):
return Club.objects.all()
class ClubList(generics.ListAPIView):
serializer_class = ClubSerializer
def get_queryset(self):
username = self.kwargs['username']
return Club.objects.filter(abv=username)
models.py
class Club(models.Model):
name = models.CharField(max_length=255)
abv = models.CharField(max_length=255)
serializers.py
class ClubSerializer(serializers.HyperlinkedModelSerializer):
class Meta:
model = Club
fields = ['name', 'abv']
How can I solve this?

You are sending POST request on an endpoint which only allows GET request.
ListAPIView is a read-only generic view. To create model objects using POST request, use CreateAPIView or ListCreateAPIView.

From the docs for ListApiView:
Used for read-only endpoints to represent a collection of model instances.
If you want to post to your endpoint, you'll need to use a different view class.

How to update a user profile field using rest API

I am new to django and very confused. I am using django as the backend API for my angular application.
I want to add few more details to the User model so I added the following to my models.py
from django.db import models
from django.contrib.auth.models import User
class UserProfile(models.Model):
user = models.OneToOneField(User)
company_name = models.CharField(max_length=100)
I am using an application to add rest authentication support: https://github.com/Tivix/django-rest-auth
Using this application I can edit a users profile with this URL doing a POST request: http://localhost:8080/rest-auth/user/
Question
How can I update the custom field company_name? while editing a users profile?
What I've tried
I tried to override the UserDetailsSerializer that the application provides but it isn't having any effect.
This is what I tried adding to my applications serializers.py
class UserProfileSerializer(serializers.ModelSerializer):
class Meta:
model = models.UserProfile
fields = ('company_name',)
class UserDetailsSerializer(serializers.ModelSerializer):
profile = UserProfileSerializer(required=True)
class Meta:
model = models.User
fields = ('id', 'username', 'first_name', 'last_name', 'profile')

If you are using django rest framework, then you basically want to have an update method on your view class for UserProfile that takes in the user id as a request param. Then in that method you want to use the ORM to get a model object for the given userprofile id, set the property that was also passed as a param, and save the changed model object. Then generate a success response and return it.
You can read more about how to do this here: http://www.django-rest-framework.org/api-guide/views/

How to declare child resources in Tastypie?

I have this models.py:
from django.db import models
class Item(models.Model):
text = models.TextField()
class Note(models.Model):
text = models.TextField()
items = models.ManyToManyField(Item)
And this api.py:
import tastypie
from tastypie.resources import ModelResource
from tastypie.api import Api
from main.models import Item, Note
class ItemResource(ModelResource):
class Meta:
resource_name = 'items'
queryset = Item.objects.all()
class NoteResource(ModelResource):
items = tastypie.fields.ToManyField(ItemResource, 'items', full=True)
class Meta:
resource_name = 'notes'
queryset = Note.objects.all()
api = Api(api_name='v1')
api.register(NoteResource())
I want the only endpoint to items be:
/api/v1/notes/4/items
/api/v1/notes/4/items/2
And no /api/v1/items/?note=4
I've been reading Tastypie documentation and i didn't found any info on this.
This document recommends the URL form i post here.
How can i accomplish this?

Using Django REST Framework (posterity, see comments on OP), child resources are declared as follows (simple example):
class AddressSerializer(ModelSerializer):
"""
A serializer for ``Address``.
"""
class Meta(object):
model = Address
class OrderSerializer(ModelSerializer):
"""
A serializer for ``Order``.
"""
address = AddressSerializer()
class Meta(object):
model = Order
To get started, I highly recommend simply following this tutorial. It will get you 100% of what you need, in terms of customizing your URLs, customizing your serialized output, etc.
Tasty pie is a great project, and the creator, Daniel Lindsley, is a really smart guy (I worked with him for a short while), but just like every other great project, somebody came along and blew our socks off with something new that has learned from the good and bad parts of the existing framework.

Django Rest Framework - Could not resolve URL for hyperlinked relationship using view name "user-detail"

I am building a project in Django Rest Framework where users can login to view their wine cellar.
My ModelViewSets were working just fine and all of a sudden I get this frustrating error:
Could not resolve URL for hyperlinked relationship using view name "user-detail". You may have failed to include the related model in your API, or incorrectly configured the lookup_field attribute on this field.
The traceback shows:
[12/Dec/2013 18:35:29] "GET /bottles/ HTTP/1.1" 500 76677
Internal Server Error: /bottles/
Traceback (most recent call last):
File "/Users/bpipat/.virtualenvs/usertest2/lib/python2.7/site-packages/django/core/handlers/base.py", line 114, in get_response
response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "/Users/bpipat/.virtualenvs/usertest2/lib/python2.7/site-packages/rest_framework/viewsets.py", line 78, in view
return self.dispatch(request, *args, **kwargs)
File "/Users/bpipat/.virtualenvs/usertest2/lib/python2.7/site-packages/django/views/decorators/csrf.py", line 57, in wrapped_view
return view_func(*args, **kwargs)
File "/Users/bpipat/.virtualenvs/usertest2/lib/python2.7/site-packages/rest_framework/views.py", line 399, in dispatch
response = self.handle_exception(exc)
File "/Users/bpipat/.virtualenvs/usertest2/lib/python2.7/site-packages/rest_framework/views.py", line 396, in dispatch
response = handler(request, *args, **kwargs)
File "/Users/bpipat/.virtualenvs/usertest2/lib/python2.7/site-packages/rest_framework/mixins.py", line 96, in list
return Response(serializer.data)
File "/Users/bpipat/.virtualenvs/usertest2/lib/python2.7/site-packages/rest_framework/serializers.py", line 535, in data
self._data = [self.to_native(item) for item in obj]
File "/Users/bpipat/.virtualenvs/usertest2/lib/python2.7/site-packages/rest_framework/serializers.py", line 325, in to_native
value = field.field_to_native(obj, field_name)
File "/Users/bpipat/.virtualenvs/usertest2/lib/python2.7/site-packages/rest_framework/relations.py", line 153, in field_to_native
return self.to_native(value)
File "/Users/bpipat/.virtualenvs/usertest2/lib/python2.7/site-packages/rest_framework/relations.py", line 452, in to_native
raise Exception(msg % view_name)
Exception: Could not resolve URL for hyperlinked relationship using view
name "user-detail". You may have failed to include the related model in
your API, or incorrectly configured the `lookup_field` attribute on this
field.
I have a custom email user model and the bottle model in models.py is:
class Bottle(models.Model):
wine = models.ForeignKey(Wine, null=False)
user = models.ForeignKey(User, null=False, related_name='bottles')
My serializers:
class BottleSerializer(serializers.HyperlinkedModelSerializer):
class Meta:
model = Bottle
fields = ('url', 'wine', 'user')
class UserSerializer(serializers.ModelSerializer):
class Meta:
model = User
fields = ('email', 'first_name', 'last_name', 'password', 'is_superuser')
My views:
class BottleViewSet(viewsets.ModelViewSet):
"""
API endpoint that allows bottles to be viewed or edited.
"""
queryset = Bottle.objects.all()
serializer_class = BottleSerializer
class UserViewSet(ListCreateAPIView):
"""
API endpoint that allows users to be viewed or edited.
"""
queryset = User.objects.all()
serializer_class = UserSerializer
and finally the url:
router = routers.DefaultRouter()
router.register(r'bottles', views.BottleViewSet, base_name='bottles')
urlpatterns = patterns('',
url(r'^', include(router.urls)),
# ...
I don't have a user detail view and I don't see where this issue could come from. Any ideas?
Thanks

Because it's a HyperlinkedModelSerializer your serializer is trying to resolve the URL for the related User on your Bottle.
As you don't have the user detail view it can't do this. Hence the exception.
Would not just registering the UserViewSet with the router solve your issue?
You could define the user field on your BottleSerializer to explicitly use the UserSerializer rather than trying to resolve the URL. See the serializer docs on dealing with nested objects for that.

I came across this error too and solved it as follows:
The reason is I forgot giving "**-detail" (view_name, e.g.: user-detail) a namespace. So, Django Rest Framework could not find that view.
There is one app in my project, suppose that my project name is myproject, and the app name is myapp.
There is two urls.py file, one is myproject/urls.py and the other is myapp/urls.py. I give the app a namespace in myproject/urls.py, just like:
url(r'', include(myapp.urls, namespace="myapp")),
I registered the rest framework routers in myapp/urls.py, and then got this error.
My solution was to provide url with namespace explicitly:
class UserSerializer(serializers.HyperlinkedModelSerializer):
url = serializers.HyperlinkedIdentityField(view_name="myapp:user-detail")
class Meta:
model = User
fields = ('url', 'username')
And it solved my problem.

Maybe someone can have a look at this : http://www.django-rest-framework.org/api-guide/routers/
If using namespacing with hyperlinked serializers you'll also need to ensure that any view_name parameters on the serializers correctly reflect the namespace. For example:
urlpatterns = [
url(r'^forgot-password/$', ForgotPasswordFormView.as_view()),
url(r'^api/', include(router.urls, namespace='api')),
]
you'd need to include a parameter such as view_name='api:user-detail' for serializer fields hyperlinked to the user detail view.
class UserSerializer(serializers.HyperlinkedModelSerializer):
url = serializers.HyperlinkedIdentityField(view_name="api:user-detail")
class Meta:
model = User
fields = ('url', 'username')

Another nasty mistake that causes this error is having the base_name unnecessarily defined in your urls.py. For example:
router.register(r'{pathname}', views.{ViewName}ViewSet, base_name='pathname')
This will cause the error noted above. Get that base_name outta there and get back to a working API. The code below would fix the error. Hooray!
router.register(r'{pathname}', views.{ViewName}ViewSet)
However, you probably didn't just arbitrarily add the base_name, you might have done it because you defined a custom def get_queryset() for the View and so Django mandates that you add the base_name. In this case you'll need to explicitly define the 'url' as a HyperlinkedIdentityField for the serializer in question. Notice we are defining this HyperlinkedIdentityField ON THE SERIALIZER of the view that is throwing the error. If my error were "Could not resolve URL for hyperlinked relationship using view name "study-detail". You may have failed to include the related model in your API, or incorrectly configured the lookup_field attribute on this field." I could fix this with the following code.
My ModelViewSet (the custom get_queryset is why I had to add the base_name to the router.register() in the first place):
class StudyViewSet(viewsets.ModelViewSet):
serializer_class = StudySerializer
'''custom get_queryset'''
def get_queryset(self):
queryset = Study.objects.all()
return queryset
My router registration for this ModelViewSet in urls.py:
router.register(r'studies', views.StudyViewSet, base_name='studies')
AND HERE'S WHERE THE MONEY IS! Then I could solve it like so:
class StudySerializer(serializers.HyperlinkedModelSerializer):
url = serializers.HyperlinkedIdentityField(view_name="studies-detail")
class Meta:
model = Study
fields = ('url', 'name', 'active', 'created',
'time_zone', 'user', 'surveys')
Yep. You have to explicitly define this HyperlinkedIdentityField on itself for it to work. And you need to make sure that the view_name defined on the HyperlinkedIdentityField is the same as you defined on the base_name in urls.py with a '-detail' added after it.

This code should work, too.
class BottleSerializer(serializers.HyperlinkedModelSerializer):
user = UserSerializer()
class Meta:
model = Bottle
fields = ('url', 'wine', 'user')

Today, I got the same error and below changes rescue me.
Change
class BottleSerializer(serializers.HyperlinkedModelSerializer):
to:
class BottleSerializer(serializers.ModelSerializer):

I ran into this error after adding namespace to my url
url('api/v2/', include('api.urls', namespace='v2')),
and adding app_name to my urls.py
I resolved this by specifying NamespaceVersioning for my rest framework api in settings.py of my project
REST_FRAMEWORK = {
'DEFAULT_VERSIONING_CLASS':'rest_framework.versioning.NamespaceVersioning'}

TL;DR: It may be as simple as removing a trailing 's' from the router basename. No need to define a url field in your serializer.
For the original poster, the issue was resolved simply by registering the UserViewSet, as suggested in the top answer.
However, if anyone else has this issue even with all ViewSets registered, I think I've figured out what's going wrong, and I've found a solution that's cleaner than a lot of the others here.
In my case, I encountered this issue after trying to create a ViewSet with a custom get_queryset() function. When I replaced the ViewSet's queryset field with a custom get_queryset() function, I was then hit with this error:
AssertionError: `basename` argument not specified, and could not automatically determine the name from the viewset, as it does not have a `.queryset` attribute.
So, of course, I went to urls.py and modified my registration to include a basename as such:
router.register(r'messages', MessageViewSet, basename='messages')
But then I was hit with this error (as we see in the original post):
Could not resolve URL for hyperlinked relationship using view name "message-detail". You may have failed to include the related model in your API, or incorrectly configured the `lookup_field` attribute on this field.
After reading the DRF docs on routers, I learned that the router automatically generates two url patterns for you, which have names:
'basename-list'
'basename-detail'
Because I set my basename='messages' (note the 's' at the end), my url patterns were named:
'messages-list'
'messages-detail'
Since DRF was looking a url pattern named 'message-detail' (note here the lack of 's'), I realized that I could resolve this simply by removing the trailing 's' from my basename as such:
router.register(r'messages', MessageViewSet, basename='message')
My final serializer and ViewSet implementations were as simple as this!
class MessageSerializer(serializers.HyperlinkedModelSerializer):
class Meta:
model = Message
fields = ['url', 'message', 'timestamp', 'sender', ...]
class MessageViewSet(viewsets.ModelViewSet):
serializer_class = MessageSerializer
def get_queryset(self):
return Message.objects.filter(...)

It appears that HyperlinkedModelSerializer do not agree with having a path namespace. In my application I made two changes.
# rootapp/urls.py
urlpatterns = [
# path('api/', include('izzi.api.urls', namespace='api'))
path('api/', include('izzi.api.urls')) # removed namespace
]
In the imported urls file
# app/urls.py
app_name = 'api' // removed the app_name
Hope this helps.

Same Error, but different reason:
I define a custom user model, nothing new field:
from django.contrib.auth.models import (AbstractUser)
class CustomUser(AbstractUser):
"""
custom user, reference below example
https://github.com/jonathanchu/django-custom-user-example/blob/master/customuser/accounts/models.py
# original User class has all I need
# Just add __str__, not rewrite other field
- id
- username
- password
- email
- is_active
- date_joined
- method, email_user
"""
def __str__(self):
return self.username
This is my view function:
from rest_framework import permissions
from rest_framework import viewsets
from .models import (CustomUser)
class UserViewSet(viewsets.ModelViewSet):
permission_classes = (permissions.AllowAny,)
serializer_class = UserSerializer
def get_queryset(self):
queryset = CustomUser.objects.filter(id=self.request.user.id)
if self.request.user.is_superuser:
queryset = CustomUser.objects.all()
return queryset
Since I didn't give queryset directly in UserViewSet, I have to set base_name when I register this viewset. This is where my error message caused by urls.py file:
from myapp.views import (UserViewSet)
from rest_framework.routers import DefaultRouter
router = DefaultRouter()
router.register(r'users', UserViewSet, base_name='customuser') # <--base_name needs to be 'customuser' instead of 'user'
You need a base_name same as your model name - customuser.

If you're extending the GenericViewSet and ListModelMixin classes, and have the same error when adding the url field in the list view, it's because you're not defining the detail view. Be sure you're extending the RetrieveModelMixin mixin:
class UserViewSet (mixins.ListModelMixin,
mixins.RetrieveModelMixin,
viewsets.GenericViewSet):

A bit late but in Django 3 and above, include doesn't support namespace without specifying the app_name. Checking the source code for include, we see that the condition
if namespaces and not app_name:
....
is checked. And still from the source code, app_name is gotten like;
urlconf_module, app_name = arg
where arg is the first argument of the include. This tells us that, our include should be defined as
include((app.urls, app_name), namespace='...')
Example
Say you have a project myproject and an app myapp. Then you want to establish an address. You should use a viewset and define a router as below
myapp.urls
router.register('address', exampleviewset, basename='address')
myproject.urls
path('api/v1/', include(('myapp.urls', 'myapp'), namespace='myapp')),
serializers.py
class AddressSerializer(serializers.HyperlinkedModelSerializer):
url = serializers.HyperlinkedIdentityField(view_name="myapp:address-detail")
class Meta:
model = Address
fields = ('url',...)
Apparently, we can't use fields='__all__'. We must include url explicitly and list the remaining fields we need.

I ran into the same error while I was following the DRF quickstart guide
http://www.django-rest-framework.org/tutorial/quickstart/ and then attempting to browse to /users. I've done this setup many times before without problems.
My solution was not in the code but in replacing the database.
The difference between this install and the others before was when I created the local database.
This time I ran my
./manage.py migrate
./manage.py createsuperuser
immediately after running
virtualenv venv
. venv/bin/activate
pip install django
pip install djangorestframework
Instead of the exact order listed in the guide.
I suspected something wasn't properly created in the DB. I didn't care about my dev db so I deleted it and ran the ./manage.py migrate command once more, created a super user, browsed to /users and the error was gone.
Something was problematic with the order of operations in which I configured DRF and the db.
If you are using sqlite and are able to test changing to a fresh DB then it's worth an attempt before you go dissecting all of your code.

Bottle = serializers.PrimaryKeyRelatedField(read_only=True)
read_only allows you to represent the field without having to link it to another view of the model.

I got that error on DRF 3.7.7 when a slug value was empty (equals to '') in the database.

I ran into this same issue and resolved it by adding generics.RetrieveAPIView as a base class to my viewset.

I was stuck in this error for almost 2 hours:
ImproperlyConfigured at /api_users/users/1/
Could not resolve URL for hyperlinked relationship using view name "users-detail". You may have failed to include the related model in your API, or incorrectly configured the lookup_field attribute on this field.
When I finally get the solution but I don't understand why, so my code is:
#models.py
class Users(models.Model):
id = models.AutoField(primary_key=True)
name = models.CharField(max_length=50, blank=False, null=False)
email = models.EmailField(null=False, blank=False)
class Meta:
verbose_name = "Usuario"
verbose_name_plural = "Usuarios"
def __str__(self):
return str(self.name)
#serializers.py
class UserSerializer(serializers.HyperlinkedModelSerializer):
class Meta:
model = Users
fields = (
'id',
'url',
'name',
'email',
'description',
'active',
'age',
'some_date',
'timestamp',
)
#views.py
class UserViewSet(viewsets.ModelViewSet):
queryset = Users.objects.all()
serializer_class = UserSerializer
#urls_api.py
router = routers.DefaultRouter()
router.register(r'users',UserViewSet, base_name='users')
urlpatterns = [
url(r'^', include(router.urls)),
]
but in my main URLs, it was:
urlpatterns = [
url(r'^admin/', admin.site.urls),
#api users
url(r'^api_users/', include('usersApi.users_urls', namespace='api')),
]
So to finally I resolve the problem erasing namespace:
urlpatterns = [
url(r'^admin/', admin.site.urls),
#api users
url(r'^api_users/', include('usersApi.users_urls')),
]
And I finally resolve my problem, so any one can let me know why, bests.

If you omit the fields 'id' and 'url' from your serializer you won't have any problem. You can access to the posts by using the id that is returned in the json object anyways, which it makes it even easier to implement your frontend.

I had the same problem , I think you should check your
get_absolute_url
object model's method input value (**kwargs) title.
and use exact field name in lookup_field

It is worth noting that if you create an action with detail=False (typo?) then this errors will be raised, replace it with detail=True:
#action(detail=True)
...

I wanted to stay with everything as-is out of the box so I just added a User serializer:
class UserSerializer(serializers.HyperlinkedModelSerializer):
class Meta:
model = User
fields = ['id', 'username']
A Viewset:
class UserViewSet(viewsets.ModelViewSet):
queryset = User.objects.all()
serializer_class = UserSerializer
And added to urls:
router.register(r'users', UserViewSet)

From DRF Docs:
drf docs note source
Note: If using namespacing with hyperlinked serializers you'll also need to ensure that any view_name parameters on the serializers correctly reflect the namespace. In the examples above you'd need to include a parameter such as view_name='app_name:user-detail' for serializer fields hyperlinked to the user detail view.
The automatic view_name generation uses a pattern like %(model_name)-detail. Unless your models names actually clash you may be better off not namespacing your Django REST Framework views when using hyperlinked serializers.
Solution
example of setting view_name
from rest_framework import serializers
from myapp.models import Post
from django.contrib.auth.models import User
class PostSerializer(serializers.HyperlinkedModelSerializer):
url = serializers.HyperlinkedIdentityField(view_name="api:post-detail")
author = serializers.HyperlinkedRelatedField(view_name="api:user-detail", read_only=True)
viewers = serializers.HyperlinkedRelatedField(view_name="api:user-detail", read_only=True, many=True)
class Meta:
model = Post
fields = ('id', 'title', 'url', 'author', 'viewers')
class UserSerializer(serializers.ModelSerializer):
class Meta:
model = User
fields = "__all__"

How to include in queryset details fields of a foreign key (django and rest_api)

I use rest_api in django in order to display a queryset of "chats".
I tried to get it done for a while, without success...
in angularjs controller I call a function which do the following:
$scope.conversations = $http.get('/api/chats/').then(function(response){
return response.data;
});
in urls.py of the rest_api app I put this:
url(r'^chats/$', login_required(views.chatsViewSet.as_view()) ),
in view.py of the rest_api I put this:
from rest_framework.generics import ListCreateAPIView
from serializers import ChatsSerializer
class ChatsViewSet(ListCreateAPIView):
serializer_class = ChatsSerializer
def get_queryset(self):
return Message.objects._folder(('sender', 'recipient'), {},order_by='-sent_at')
and in serializers.py in the rest_api I put this:
from postman.models import Message
from rest_framework import serializers
class ChatsSerializer(serializers.ModelSerializer):
class Meta:
model = Message
fields = ('id', 'sender', 'recipient','thread','subject','moderation_reason','body')
ordering =['-thread']
The 'sender' and the 'recipient' fields in the Message of postman model are foreign keys.
Here is the definition of sender, for instance, in the Message Model in postman:
sender = models.ForeignKey(get_user_model(), related_name='sent_messages', null=True, blank=True, verbose_name=_("sender"))
I would like that the queryset in rest_api include not only the ID of the sender but also its username field...
I tried to read some posts like using 'extra' in rest_api but I didn't figure it out.
I will be grateful if somebody could write me explicit instruction how to do it...

You can make a property on your model:
class Message(models.Model):
# some code...
#property
def sender_name(self):
return self.sender.name # username or whatever
Then is you serializer you create a custom field:
class ChatsSerializer(serializers.ModelSerializer):
# some code...
sender_name = serializers.Field(source = 'sender_name') # source = 'name of property or method' you dont have to pass it in this example becouse model property has the same name as this serializer attribute
class Meta:
fields = ('sender_name', 'id', 'sender', 'recipient','thread','subject','moderation_reason','body')
Now you have an 'sender_name' object in your JSON response.
That's just one method I hope it helps :)
The second one is to add an UserModelSerializer:
class UserModelSerializer(serializers.ModelSerializer):
class Meta:
model = get_user_model()
class ChatsSerializer(serializers.ModelSerializer):
# some code...
sender = UserModelSerializer()
recipient = UserModelSerializer()
class Meta:
fields = ('sender_name', 'id', 'sender', 'recipient','thread','subject','moderation_reason','body')
Retriving is ok. But creating and updating with it is a hard piece of coding.
You can always create an Angular service for your 'sender' object and after reciving your chat messages with only foreign keys, request data from a 'UserModelView' with those 'FK' and bind them together. That's a third method.