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I am trying to create a blogging site kind of like medium.com. The only problem I am facing is the headings in the blog. I want to do what stack overflow does with bold text.
**text**
But I can't seem to figure out how to make this. Sorry if this question is not detailed enough and Thanks for giving this question your time.
you can find string between two subStrings using python regular expression.
import re
s = '**text**'
result = re.search('\*\*(.*)\*\*', s)
print(result.group(1)) #output :==> text
you really should learn regular expression 😀.
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I have tried using triple quotes but it only turns the code green. As if i were to print it. Not red
"""
How do i make a block comment
"""
So how can i make a block comment, or is it supposed to be green.
'''
This is a multiline
comment. I can type here whatever I want.
'''
You have too many quotes in the closing line - you have 4. It should be 3
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I want the following HTML string to be decoded with HTML tags
\u003cp\u003e\u003cstrong\u003e\u003cspan\u003eAbout the Company \u003c/span\u003e\u003c/strong\u003e\u003c/p\u003e
How can I do that in Python 2.7 ?
I am having large HTML string to decode. The above sample is just a apart of that.
PS: I have tried with many solutions available in web to decode HTML string but nothing helps me EDIT:
I have referred this https://stackoverflow.com/a/2087433/4350834
and got the result as
\u003cp\u003e\u003cstrong\u003e\u003cspan\u003eAbout the Company \u003c/span\u003e\u003c/strong\u003e\u003c/p\u003e
You can try:
>>>text = "\u003cp\u003e\u003cstrong\u003e\u003cspan\u003eAbout the Company \u003c/span\u003e\u003c/strong\u003e\u003c/p\u003e".decode('unicode-escape')
>>>print text
u'<p><strong><span>About the Company </span></strong></p>'
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I am a beginner Python programmer and I wanted to use this character: â–ˆ. I have tried just doing: print "â–ˆ" but I always got an error. I Have looked for solutions, but have found nothing that helped me.
You can print any unicode symbol by using the \uxxxx notation. For instance, 2588 is a code for unicode block.
print('\u2588')
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I have the following sentence:
Graft Concepts has partnered with\u00a0several sites\u00a0to offer customization options for backplates, so customers will be able to design their own with\u00a0
I'd like to get rid of all instances of "\u00a0", whether or not they are connected to other words, e.g. "with\u00a0several"
How would I do this using regex with python? I've tried experimenting with re.compile() and re.findall(), but I couldn't get this working?
Thanks.
You can just use .replace:
s = s.replace('\\u00a0', ' ')
This works under Python 2:
import re
st='''Graft Concepts has partnered with\u00a0several sites\u00a0to offer customization options for backplates, so customers will be able to design their own with\u00a0'''
st=re.sub(ur'\\u00a0','',st,re.UNICODE)
And this under Python 3:
st=re.sub(u'\\u00a0','',st,re.UNICODE)
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This is the package which has a webapp demo in it.
However, when I login use this demo, I get an error.
How to make this demo running on the gae-launcher?
Looks like a bug in gaema.
The line that's failing is trying to urlencode a dictionary of arguments that get passed to the OpenID endpoint. One or more of the values, perhaps your first or last name, has non-ASCII characters.
You might be able to work around it by replacing instances of this:
urllib.urlencode(args)
With this:
urllib.urlencode(dict([(k, args[k].encode('utf-8')) for k in args]))
For a more permanent fix, I would report the issue here:
http://code.google.com/p/gaema/issues/list