import numpy as np
import matplotlib.pyplot as plt
data = np.genfromtxt("traffic.csv", delimiter=',', encoding="utf8",dtype=None)
plt.hist(data[1:,2])
plt.show()
So, basically it overlaps, and I want it to be simplified.
csv link
You can use MaxNLocator to set the maximum number of ticks that will fit on nicely.
Related
I am creating a joyplot using joypy.
All my data is between[0,1].
But I get a big range of negative values in the graph:
import joypy
import pandas as pd
from matplotlib import pyplot as plt
from matplotlib import cm
import matplotlib.ticker as ticker
import matplotlib
matplotlib.use('TkAgg')
iris = pd.read_csv("1_5.csv")
fig, axes = joypy.joyplot(iris)
x = [0,0.25,0.5,0.75,1]
plt.xticks(x)
plt.show()
It isn't clear that your xticks are in any way tied to the actual joyplot itself (ie, you've created arbitrary x-ticks and placed them on the plot).
Are tick marks not represented on the plot originally (similar plots I've seen all have them by default)?
If I use the following code I end up with an overcrowded x-axis. I would like to show only every 10th number on the x axis. Meaning [0,10,...].
Any idea how to do this?
import pandas as pd
import numpy as np
import pandas as pd
import seaborn as sns
from matplotlib import pyplot as plt
a = pd.DataFrame({'y':np.random.randn(100)})
a['time']=a.index
ax = sns.pointplot(x='time', y="y", data=a)
plt.show()
You may decide not to use a pointplot at all. A usual lineplot seems to suffice.
import pandas as pd
import numpy as np
from matplotlib import pyplot as plt
a = pd.DataFrame({'y':np.random.randn(100)})
plt.plot(a.index, a.y)
plt.show()
Now this gives ticks at steps of 20. The easiest option here would be to use
plt.xticks(range(0,101,10))
to get the steps of 10. Or equally possible,
plt.gca().locator_params(nbins=11)
to devide the axis into 11 bins.
Of course the use of an appropriate locator would be equally possible.
i am having some trouble with a seaborn pointplot.
I am to plot the Temperature vs. growth rate of four kinds of bacteria, so that each type has its own graph, but all four are in the same plot. The thing is, i cannot connect the individual points, i can only get the individual points.
My code:
import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
from scipy import stats, integrate
import matplotlib.pyplot as plt
import matplotlib.ticker as ticker
import seaborn as sns
dataSorted=data.sort_values(['Temperature','Growth_rate'],ascending=[True,True])
plt.subplots()
ax2=sns.pointplot(x='Temperature',y='Growth_rate', hue='Bacteria' ,data=dataSorted,scale=0.7,join=True)
axes2=ax2.axes
axes2.set_xlim(10,60)
axes2.set_ylim(0,1.5)
axes2.set_xticks(np.arange(1,7)*10)
axes2.set_xticklabels(np.arange(1,7)*10)
The output is exactly as specified, apart from the lines between points:
My plot - without lines
I have no idea how to fix this, i have even set the "join" parameter manually, even though it is set as True by default.
I have a 200x3 matrix in python which I would like to plot. However, by using Matplotlib I get the following figure. How can I plot an image which looks nicer?
my code:
import matplotlib.pyplot as plt
plt.imshow(spectrum_matrix)
plt.show()
You can use set_aspect():
import matplotlib.pyplot as plt
import numpy as np
spectrum_matrix = np.random.rand(200,3)
plt.imshow(spectrum_matrix)
plt.axes().set_aspect('auto')
plt.show()
Output:
Basically, I'm doing scalability analysis, so I'm working with numbers like 2,4,8,16,32... etc and the only way graphs look rational is using a log scale.
But instead of the usual 10^1, 10^2, etc labelling, I want to have these datapoints (2,4,8...) indicated on the axes
Any ideas?
There's more than one way to do it, depending on how flexible/fancy you want to be.
The simplest way is just to do something like this:
import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl
x = np.exp2(np.arange(10))
plt.semilogy(x)
plt.yticks(x, x)
# Turn y-axis minor ticks off
plt.gca().yaxis.set_minor_locator(mpl.ticker.NullLocator())
plt.show()
If you want to do it in a more flexible manner, then perhaps you might use something like this:
import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl
x = np.exp2(np.arange(10))
fig = plt.figure()
ax = fig.add_subplot(111)
ax.semilogy(x)
ax.yaxis.get_major_locator().base(2)
ax.yaxis.get_minor_locator().base(2)
# This will place 1 minor tick halfway (in linear space) between major ticks
# (in general, use np.linspace(1, 2.0001, numticks-2))
ax.yaxis.get_minor_locator().subs([1.5])
ax.yaxis.get_major_formatter().base(2)
plt.show()
Or something like this:
import numpy as np
import matplotlib.pyplot as plt
import matplotlib as mpl
x = np.exp2(np.arange(10))
fig = plt.figure()
ax = fig.add_subplot(111)
ax.semilogy(x)
ax.yaxis.get_major_locator().base(2)
ax.yaxis.get_minor_locator().base(2)
ax.yaxis.get_minor_locator().subs([1.5])
# This is the only difference from the last snippet, uses "regular" numbers.
ax.yaxis.set_major_formatter(mpl.ticker.ScalarFormatter())
plt.show()