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How do I receive the updated time every time it is called in this function?

import time
seconds = time.time()
local_time = time.ctime(seconds)
print("Start Time:", local_time)
def bot():
x = 0
while x < 16:
time.sleep(1)
print("Time:", local_time)
x += 1
When I run this code it prints the initial time take before the function every time, I would like it to show the updated time every time local time is printed, can someone point me in the right direction?

Using a variable will not re-evaluate it. You'll need to calculate the time again each loop iteration
import time
def bot():
for x in range(16):
time.sleep(1)
seconds = time.time()
local_time = time.ctime(seconds)
print("Time:", local_time)
bot()

should i use for loop or while loop to make a break timer in python?

I have this code to stop a function at a specific time. I would loop through the function and then break the function, if it takes too long, is there a better way to do it?
import time
def function_one()
rec = (time.time())
print("im starting")
ans = str(time.time() - rec)
ans = (round(float(ans), 15))
print("this is where im doing something code")
while ans < 10:
return function_one()
break

You can make it simpler like this:
import time
def function_one():
start_time = time.time()
while True:
print('Function doing something ...')
if time.time() - start_time > 10:
break
function_one()
Here, I'm using a while loop just to keep the function running, but that depends on the details of your function.
In general, what you need is:
set the start time
do whatever the function is supposed to be doing;
check if it's been running for too long and, in case it has, you can simply return.
So, something like:
import time
def function_one():
start_time = time.time()
# do your job
if time.time() - start_time > 10:
return something
function_one()

If you want to stop a function after a set amount of time has passed I would use a while loop and do something like this.
import time
def function_one():
start = (time.time()) #start time
limit = 1 #time limit
print("im starting")
while (time.time() - start) < limit:
#input code to do here
pass
print(f"finished after {time.time() - start} seconds")
function_one()

create a timer using python.i cant understand the logic used to build a timer that prints "ok" after every 2 seconds in python. #while_loop

i cant understand the logic used to build a timer that prints "ok" after every 2 seconds in python. Also the body of the while loop . please explain
import time print("start") start=time.time() while True: end = time.time() if (end-start)>=2: print("ok") start=time.time()

There is two methods of doing that:
FIRST:
import time
while True:
time.sleep(2)
print('ok')
SECOND:
import time
oldtime = time.time()
while True:
if oldtime + 2 == time.time(): #time.time() means current time
print('ok')
oldtime = time.time()
If your program must not pause(need to do other things) use the SECOND method if not try the FIRST one it is easy.
If you have any questions just comment this post.

Stopping Stopwatches

I am trying to create a stopwatch that starts and stops through the user pressing the enter. Once to start and again to stop. The start works perfectly but the stopping section is not working. I've tried creating a variable called stop that is like so:
stop = input("stop?")
But it's still not working.
import time
def Watch():
a = 0
hours = 0
while a < 1:
for minutes in range(0, 60):
for seconds in range(0, 60):
time.sleep(1)
print(hours,":", minutes,":", seconds)
hours = hours + 1
def whiles():
if start == "":
Watch()
if start == "":
return Watch()
def whiltr():
while Watch == True:
stop = input("Stop?")
#Ask the user to start/stop stopwatch
print ("To calculate your speed, we must first find out the time that you have taken to drive from sensor a to sensor b, consequetively for six drivers.")
start = input("Start?")
start = input("Stop")
whiles()

Perhaps all you need is something simple like:
import time
input('Start')
start = time.time()
input('Stop')
end = time.time()
print('{} seconds elapsed'.format(end-start))

Should probably use the time function instead of
def Watch():

printing out letter every min Python

so i am trying to figure this out for school. Im trying to print x out every minute and every ten min it will print on a new line. so far i cant get the "printing x" every min down. can someone please help.
this is my code
import time;
inTime = float(input("type in how many second"))
oldTime = time.time()-inTime
print (time.time())
def tenMin(oldTime):
newTime = time.time()
if ((newTime - oldTime)>= 25):
return True
else:
False
while (True):
if (tenMin==True):
print ("x")
newTime = time.time()
oldtime = time.time()
else:
oldTime = time.time()
continue

Your first problem is in the line
if (tenMin==True):
You compare a function reference to a boolean, clearly the answer would be False. You have to pass a parameter
if (tenMIn(oldTime)):
...

First you have some issues with you code:
else:
False - This is not true syntax in python.
If you want timer, why are you asking the user for input?
You have a logic problem:
inTime = float(input("type in how many second"))
oldTime = time.time()-inTime
time.time is float yes, but can a user really know what to print in UnixTime?
I'll suggest a simple solution it's not the very best but it works.
It will print "x" every 1 Min and after 10 Min it will print "\n" (new line)
import time
def main():
#both timers are at the same start point
startTimerTen = time.time()
startTimerMin = startTimerTen
while True:
getCurrentTime = time.time()
if getCurrentTime - startTimerTen >= 600:
# restart both parameters
startTimerTen = getCurrentTime
startTimerMin = getCurrentTime
print "This in 10 min!\n"
if getCurrentTime - startTimerMin >= 60:
# restart only min parameter
startTimerMin = getCurrentTime
print "x"
#end of main
if __name__ == "__main__":
main()