First time using playwright. Trying to log in to Pinterest.
browser = playwright.chromium.launch(headless=False)
context = browser.new_context()
page = context.new_page()
page.goto('https://pinterest.co.uk/login')
# Interact with login form
page.fill('input[name="id"]', email)
page.fill('input[name="password"]', password)
# looking for the login button. This part breaks.
page.locator('xpath=//*[#id="__PWS_ROOT__"]/div[1]/div/div[2]/div/div/div/div/div/div[4]/form/div[5]/button').click()
#open the form to create a pin
page.goto('https://www.pinterest.co.uk/pin-builder/')
I get a timeout error because it's waiting for the selector with the given xpath, but it's probably not finding it. Any ideas?
You should be able to get that button by text:
page.locator('"Log in"').click()
Try this one hope it will work for your machine too.
you cannot use xpath in all the places it leads to some unwanted errors anytime so use has-text
from playwright.sync_api import Playwright, sync_playwright, expect
def run(playwright: Playwright) -> None:
browser = playwright.chromium.launch(headless=False)
context = browser.new_context()
# Open new page
page = context.new_page()
# Go to https://www.pinterest.co.uk/login/
page.goto("https://www.pinterest.co.uk/login/")
# Click [placeholder="Email"]
page.locator("[placeholder=\"Email\"]").click()
# Fill [placeholder="Email"]
page.locator("[placeholder=\"Email\"]").fill("xxxxx#gmail.com")
# Click [placeholder="Password"]
page.locator("[placeholder=\"Password\"]").click()
# Fill [placeholder="Password"]
page.locator("[placeholder=\"Password\"]").fill("password")
# Click button:has-text("Log in")
# with page.expect_navigation(url="https://www.pinterest.co.uk/"):
with page.expect_navigation():
page.locator("button:has-text(\"Log in\")").click()
# ---------------------
context.close()
browser.close()
with sync_playwright() as playwright:
run(playwright)
Related
I have a Django app that I want to test via pytest and Selenium.
The routine I'm trying to go through is to let Selenium log in, then go to the menu, choose one of the options. This redirects to a new page, which is found fine. There, I let selenium enter data and click a button to start a submission. This, too, works, and redirects to a third page.
On this third "your submission was created successfully" page, there is a link displayed that the user can click to collect the results of their submission (this page . This link is displayed correctly, the href URL is fine. But when I let Selenium click on it, I suddenly get a Server Error 500:
<html lang="en"><head>
<title>Server Error (500)</title>
</head>
<body>
<h1>Server Error (500)</h1><p></p>
</body></html>
When I do the exact same thing manually, it works fine.
Here's my test code (slightly simplified):
#pytest.fixture(scope="class")
def chrome_driver_init(request):
options = webdriver.ChromeOptions()
options.headless = True
options.binary_location = CHROME_BIN_PATH
driver = webdriver.Chrome(service=CHROME_SERVICE, options=options)
request.cls.driver = driver
yield
driver.quit()
#pytest.mark.django_db
#pytest.mark.usefixtures("chrome_driver_init")
class SubmissionTest(LiveServerTestCase):
def test_adding_submission(self):
self.driver.get(self.live_server_url)
username = TEST_USER
pwd = TEST_USER_PWD
User = get_user_model()
user = User.objects.create_user(username=username, password=pwd)
user.save()
# click 'Login':
self.driver.find_element(By.LINK_TEXT, "Login").click()
# now on Login page, log in via Selenium:
username_field = self.driver.find_element(By.NAME, "username")
pwd_field = self.driver.find_element(By.NAME, "password")
submit_btn = self.driver.find_element(By.ID, "form_field")
username_field.send_keys(TEST_USER)
pwd_field.send_keys(TEST_USER_PWD)
submit_btn.click()
# now logged in, go to desired menu point:
self.driver.find_element(By.LINK_TEXT, "MenuPoint 1").click()
assert self.driver.title == "MenuPoint 1" # redirection works fine
## find various fields, enter stuff, click "submit"
# check successfull:
assert self.driver.title == "Added Submission" # redirection works, as expected
## more checks => yes, this is the desired page
# find link for result page:
result_link = self.driver.find_element(By.LINK_TEXT, "click here for your results")
result_link_url = result_link.get_attribute("href")
print(result_link_url) # this is indeed the correct URL
# click link:
time.sleep(10) # wait 10 seconds => more did not help, either
result_link.click()
## now we get the Server Error :-(
print(self.driver.page_source)
I have already tried to use WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.LINK_TEXT, "click here for your results"))).click(), and that doesn't seem to even click.
I know that error 500 mean's the error is on the server side. But before clicking, the server is fine. All the redirections before this step work fine. The URLs also check out. And manually, everything works as expected. I have no idea how to narrow down the problem further.
How can I investigate the reason for this error, and hopefully fix it?
The test creates only a user instance. Is that enough for the view which fails?
You need to get to server traceback to know for sure what's wrong.
from django.test import override_settings
#pytest.mark.django_db
#pytest.mark.usefixtures("chrome_driver_init")
class SubmissionTest(LiveServerTestCase):
#override_settings(DEBUG=True)
def test_adding_submission(self):
...
Take a look at Django: why i can't get the tracebacks (in case of error) when i run LiveServerTestCase tests? for more details.
I am using Selenium to simulate login with Chrome browser. The login page has Slider button which needs to be dragged to complete the login process.
The weird thing is that if I open the web page using driver.get(page). Then sliding verification code will always fail even I manually enter the username, pwd and drag the slider.
I tried to add user-agent but no help.
Is there any other way? I understand that we can add user-data to skip this part but I just want to figure it out first.
The slider verification code will display if you try to log in more than once. It seems that the web page just detect you are using the script to log in.
The error will be like:" ops, failed to verify. Please refresh again". Then I use driver.find_element_by_xpath("//*[#id='nocaptcha']/div/span/a").click() to refresh the slider.
Thanks in advance.
driver = webdriver.Chrome()
driver.get("https://login.taobao.com/member/login.jhtml?spm=a21bo.2017.754894437.1.5af911d95pqPfs&f=top&redirectURL=https%3A%2F%2Fwww.taobao.com%2F")
action = ActionChains(driver)
login()
def login():
driver.find_element_by_class_name("login-switch").click()
driver.find_element_by_id('TPL_username_1').clear()
driver.find_element_by_id('TPL_username_1').send_keys('xxx')
driver.find_element_by_id('TPL_password_1').clear()
driver.find_element_by_id('TPL_password_1').send_keys("xxx")
time.sleep(1.5)
# driver.find_element_by_id('J_SubmitStatic').click()
Slider()
def Slider():
#Sliding verification code
while True:
try:
slip=driver.find_element_by_xpath("//*[#id='nc_1_n1z']")
action.click_and_hold(slip).perform()
action.move_by_offset(150,0)
time.sleep(0.8)
action.move_by_offset(148,0)
action.release().perform()
time.sleep(2)
text = driver.find_element_by_xpath("//*[#id='nc_1__scale_text']/span")
if text.text.startswith("请在下方"):
print("Successful")
break
if text.text.startswith("请点击"):
print("Successful")
break
if text.text.startswith("请按住"):
print("Failed. Try again")
continue
except Exception:
##Error occurs, click the "Refresh" button to refresh the sliding verification code again
driver.find_element_by_xpath("//*[#id='nocaptcha']/div/span/a").click()
driver.find_element_by_id('J_SubmitStatic').click()
i used this code to check splinter's clicking button option:
from splinter import Browser
with Browser() as browser:
# Visit URL
url = "http://www.google.com"
browser.visit(url)
browser.fill('q', 'splinter - python acceptance testing for web applications')
# Find and click the 'search' button
button = browser.find_by_name('btnG')
# Interact with elements
button.click()
if browser.is_text_present('splinter.readthedocs.org'):
print("Yes, the official website was found!")
else:
print("No, it wasn't found... We need to improve our SEO techniques")
and i got exception:
Element is not currently visible ans so may not be interacted.
waiting for the browser is not the solution (becuase i made sleep method for long time and still doesnt work).
this is sample code shown in https://splinter.readthedocs.org/en/latest/#sample-code , but is doesnt work for me
If you want to wait for an element to become invisible, you can use wait function:
wait = WebDriverWait(self.driver, 30)
wait.until(EC.invisibility_of_element_located((By.XX, "something")))
I used Selenium webdriver in Python to input some text in search field and look for it. I'd now like to parse that page/ use something like BeautifulSoup on it. But I'm confused about how to call the resulting page.
My code so far:
textinput = open("1.txt", "r").read()
url = "http://www.example.com"
driver = webdriver.Chrome(executable_path='path/chromedriver.exe')
driver.get(url)
sbox = driver.find_element_by_name("a")
sbox.send_keys(textinput)
submit = driver.find_element_by_xpath('//*[#id="maincontent"]/form/input[5]')
submit.click()
Once you have clicked on the submit button using:
submit.click()
It automatically goes to the next page. So, to parse the resulting page, just make another:
whatimlookingfor = driver.find_element_by_id("myid")
submit = driver.find_element_by_xpath('//*[#id="maincontent"]/form/input[5]')
# You are still on the first page
submit.click()
# You are now on the second page
whatimlookingfor = driver.find_element_by_id("myid")
I am trying to log into a website and then once logged in navigate to a different page on the website remaining logged in, using Selenium. However, when I try to navigate to the different page, I found I have become logged off.
I believe this is because I do not understand how the webdriver.Firefox().get() function works exactly.
My code:
from selenium import webdriver
from Code.Other import XMLParser
#Initialise driver and go to webpage
driver = webdriver.Firefox()
URL = 'http://www.website.com'
driver.get(URL)
#Login
UserName = XMLParser.XMLParse('./Config.xml','UserName')
Password = XMLParser.XMLParse('./Config.xml','Password')
element = driver.find_elements_by_id('UserName')
element[0].send_keys(UserName)
element = driver.find_elements_by_id('Password')
element[0].send_keys(Password)
element = driver.find_elements_by_id('Submit')
element[0].click()
#Go to new page
URL = 'http://www.website.com/page1'
driver.get(URL)
Unfortunately I am navigated to the new page but I am no longer logged in. How do I fix this?
Looks like website doesn't have enough time to react on your submit in authorization form. You click submit but you don't wait for response and open another url.
Wait until some event after login (like getting cookies or some changes in DOM or just time.sleep) and only then go to another page.
P.S.: if it won't help, try to check your cookies after login and after you open new url, maybe it's problem with authorization backend or webdriver