I have (lat,long) coordinate describing the position of a point in a .geotiff image.
I wish to find the equivalent pixel coordinates of the lat,long ones inside the image.
I succeded using gdaltransform from the command line with the following instruction :
gdaltransform -i -t_srs epsg:4326 /path/imagename.tiff
-17.4380493164062 14.6951949085676
But i would like to retrieve such type of equivalence from python code. I tried the following :
from osgeo import osr
source = osr.SpatialReference()
source.ImportFromUrl(path + TIFFFilename)
target = osr.SpatialReference()
target.ImportFromEPSG(4326)
transform = osr.CoordinateTransformation(target,source )
point_xy = np.array(transform.TransformPoint(-17.4380493164062,14.6951949085676))
But it returns this error :
NotImplementedError: Wrong number or type of arguments for overloaded function 'CoordinateTransformation_TransformPoint'.
Possible C/C++ prototypes are:
OSRCoordinateTransformationShadow::TransformPoint(double [3])
OSRCoordinateTransformationShadow::TransformPoint(double [3],double,double,double)
What am i doing wrong ? I tried to work around this error but without any success. Is there an other way to do it ?
EDIT 1 :
I achieved a single transformation via gdaltransform commands in terminal :
gdaltransform -i -t_srs epsg:4326 /path/image.tiff
-17.4380493164062 14.6951949085676
As i need to retrieve the pixel in a pythonic way, i tried calling the command using subprocess like :
# TRY 1:
subprocess.run(['gdaltransform','-i',' -t_srs','epsg:4326','/pat/img.tiff\n'], stdout=subprocess.PIPE)
# TRY 2 :
cmd = '''gdaltransform -i -t_srs epsg:4326 /home/henri/Work/imdex_visio/AllInt/Dakar_X118374-118393_Y120252-120271_PHR1A_2016-03-10T11_45_39.781Z_Z18_3857.tiff
-17.4380493164062 14.6951949085676'''
subprocess.Popen(cmd,stdout=subprocess.PIPE, shell=True)
But it does not work. Maybe because of the way the command itself behaves, like not actually returning a result and ending itself, but displaying the result and staying busy.
According to the cookbook you are flipping the use of transform and point. You should call transform on the point given the transform, not the other way around. It also seems like you are flipping source and target, but you do that two times, so it will work.
However I believe that target.ImportFromUrl(path + TIFFFilename) will not work. Instead you can extract the spatial reference from the geotiff using gdal.
Something like the following should work
from osgeo import osr, ogr, gdal
# Extract target reference from the tiff file
ds = gdal.Open(path + TIFFFilename)
target = osr.SpatialReference(wkt=ds.GetProjection())
source = osr.SpatialReference()
source.ImportFromEPSG(4326)
transform = osr.CoordinateTransformation(source, target)
point = ogr.Geometry(ogr.wkbPoint)
point.AddPoint(-17.4380493164062, 14.6951949085676)
point.Transform(transform)
print(point.GetX(), point.GetY())
This provides you with the coordinates in your geotiffs reference, however this is not pixel coordinates.
To convert the point to pixels you could use something like the following (the minus for the line might have to be flipped, based on where in the world you are)
def world_to_pixel(geo_matrix, x, y):
"""
Uses a gdal geomatrix (gdal.GetGeoTransform()) to calculate
the pixel location of a geospatial coordinate
"""
ul_x= geo_matrix[0]
ul_y = geo_matrix[3]
x_dist = geo_matrix[1]
y_dist = geo_matrix[5]
pixel = int((x - ul_x) / x_dist)
line = -int((ul_y - y) / y_dist)
return pixel, line
So your final code would look something like
from osgeo import osr, ogr, gdal
def world_to_pixel(geo_matrix, x, y):
"""
Uses a gdal geomatrix (gdal.GetGeoTransform()) to calculate
the pixel location of a geospatial coordinate
"""
ul_x= geo_matrix[0]
ul_y = geo_matrix[3]
x_dist = geo_matrix[1]
y_dist = geo_matrix[5]
pixel = int((x - ul_x) / x_dist)
line = -int((ul_y - y) / y_dist)
return pixel, line
# Extract target reference from the tiff file
ds = gdal.Open(path + TIFFFilename)
target = osr.SpatialReference(wkt=ds.GetProjection())
source = osr.SpatialReference()
source.ImportFromEPSG(4326)
transform = osr.CoordinateTransformation(source, target)
point = ogr.Geometry(ogr.wkbPoint)
point.AddPoint(-17.4380493164062, 14.6951949085676)
point.Transform(transform)
x, y = world_to_pixel(ds.GetGeoTransform(), point.GetX(), point.GetY())
print(x, y)
The proposed solution might work in most of the cases as row/column rotation is typically zero, but it should be at least checked or better included:
import numpy as np
from osgeo import gdal
def world_to_pxl(gt, x, y):
# 'Affine transformation': W = A * pxl + ul
# world[2, 1] = a[2, 2] * pxl[2, 1] + upper_left[2,1]
world = np.array([[x], [y]]) # world coordinates
upper_left = np.array(
[
[gt[0]], [gt[3]] # upper left corner of image
]
)
a = np.array([[gt[1], gt[2]],
[gt[4], gt[5]]])
# Reformulate: A^-1 * (W - ul) = pxl
pxl = np.matmul(np.linalg.inv(a), (world - upper_left))
row = pxl[0] # x_pixel
col = pxl[1] # y_line
return row, col
Background
I am attempting to slice a NetCDF file using a bounding box of lat/lons. The relevant information of this file is listed below (variables, shape, dimensions):
Per most answers here and standard tutorials, this should be very straightforward, and my interpretation is that you just find the indices of the lat/lons and slice the variable array by those indices.
Attempt/Code
def netcdf_worker(nc_file, bbox):
dataset = Dataset(nc_file)
for variable in dataset.variables.keys():
if (variable != 'lat') and (variable != 'lon'):
var_name = variable
break
# Full extent of data
lats = dataset.variables['lat'][:]
lons = dataset.variables['lon'][:]
if bbox:
lat_bnds = [bbox[0], bbox[2]] # min lat, max lat
lon_bnds = [bbox[1], bbox[3]] # min lon, max lon
lat_inds = np.where((lats > lat_bnds[0]) & (lats < lat_bnds[1]))
lon_inds = np.where((lons > lon_bnds[0]) & (lons < lon_bnds[1]))
var_subset = dataset.variables[var_name][:, lat_inds[0], lon_inds[0]]
# would also be great to slice the lats and lons too for visualization
Problem
When attempting to implement the solutions found in other answers listed on SO via the above code, I am met with the error:
File "/Users/XXXXXX/Desktop/Viewer/viewer.py", line 41, in netcdf_worker
var_subset = dataset.variables[var_name][:, lat_inds[0], lon_inds[0]]
File "netCDF4/_netCDF4.pyx", line 4095, in netCDF4._netCDF4.Variable.__getitem__
File "/Users/XXXXXX/Viewer/lib/python3.6/site-packages/netCDF4/utils.py", line 242, in _StartCountStride
ea = np.where(ea < 0, ea + shape[i], ea)
IndexError: tuple index out of range
I believe there is something minor I am missing/not understanding about slicing multidimensional arrays and would appreciate any help. I am not interested in any solutions that bring any other packages or operate external to python (no CDO or NCKS answers please!). Thank you for your help.
In Python, I think that the easiest solution is to use xarray. Minimal example (using some ERA5 data):
import xarray as xr
f = xr.open_dataset('model_fc.nc')
print(f['latitude'].values) # [52.771 52.471 52.171 51.871 51.571 51.271 50.971]
print(f['longitude'].values) # [3.927 4.227 4.527 4.827 5.127 5.427 5.727]
f2 = f.sel(longitude=slice(4.5, 5.4), latitude=slice(52.45, 51.5))
print(f2['latitude'].values) # [52.171 51.871 51.571]
print(f2['longitude'].values) # [4.527 4.827 5.127]
As an example I'm only showing the latitude and longitude variables, but all variables in the NetCDF file which have latitude and longitude dimensions are sliced automatically.
Alternatively, if you want to select the box manually (using NetCDF4):
import netCDF4 as nc4
import numpy as np
f = nc4.Dataset('model_fc.nc')
lat = f.variables['latitude'][:]
lon = f.variables['longitude'][:]
# All indices in bounding box:
where_j = np.where((lon >= 4.5) & (lon <= 5.4))[0]
where_i = np.where((lat >= 51.5) & (lat <= 52.45))[0]
# Start and end+1 indices in each dimension:
i0 = where_i[0]
i1 = where_i[-1]+1
j0 = where_j[0]
j1 = where_j[-1]+1
print(lat[i0:i1]) # [52.171 51.871 51.571]
print(lon[j0:j1]) # [4.527 4.827 5.127]
Now of course you have to slice each data array manually, using e.g. var_slice = var[j0:j1, i0:i1]
Would there be a way to plot the borders of the continents with Basemap (or without Basemap, if there is some other way), without those annoying rivers coming along? Especially that piece of Kongo River, not even reaching the ocean, is disturbing.
EDIT: I intend to further plot data over the map, like in the Basemap gallery (and still have the borderlines of the continents drawn as black lines over the data, to give structure for the worldmap) so while the solution by Hooked below is nice, masterful even, it's not applicable for this purpose.
Image produced by:
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
fig = plt.figure(figsize=(8, 4.5))
plt.subplots_adjust(left=0.02, right=0.98, top=0.98, bottom=0.00)
m = Basemap(projection='robin',lon_0=0,resolution='c')
m.fillcontinents(color='gray',lake_color='white')
m.drawcoastlines()
plt.savefig('world.png',dpi=75)
For reasons like this i often avoid Basemap alltogether and read the shapefile in with OGR and convert them to a Matplotlib artist myself. Which is alot more work but also gives alot more flexibility.
Basemap has some very neat features like converting the coordinates of input data to your 'working projection'.
If you want to stick with Basemap, get a shapefile which doesnt contain the rivers. Natural Earth for example has a nice 'Land' shapefile in the physical section (download 'scale rank' data and uncompress). See http://www.naturalearthdata.com/downloads/10m-physical-vectors/
You can read the shapefile in with the m.readshapefile() method from Basemap. This allows you to get the Matplotlib Path vertices and codes in the projection coordinates which you can then convert into a new Path. Its a bit of a detour but it gives you all styling options from Matplotlib, most of which are not directly available via Basemap. Its a bit hackish, but i dont now another way while sticking to Basemap.
So:
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
from matplotlib.collections import PathCollection
from matplotlib.path import Path
fig = plt.figure(figsize=(8, 4.5))
plt.subplots_adjust(left=0.02, right=0.98, top=0.98, bottom=0.00)
# MPL searches for ne_10m_land.shp in the directory 'D:\\ne_10m_land'
m = Basemap(projection='robin',lon_0=0,resolution='c')
shp_info = m.readshapefile('D:\\ne_10m_land', 'scalerank', drawbounds=True)
ax = plt.gca()
ax.cla()
paths = []
for line in shp_info[4]._paths:
paths.append(Path(line.vertices, codes=line.codes))
coll = PathCollection(paths, linewidths=0, facecolors='grey', zorder=2)
m = Basemap(projection='robin',lon_0=0,resolution='c')
# drawing something seems necessary to 'initiate' the map properly
m.drawcoastlines(color='white', zorder=0)
ax = plt.gca()
ax.add_collection(coll)
plt.savefig('world.png',dpi=75)
Gives:
How to remove "annoying" rivers:
If you want to post-process the image (instead of working with Basemap directly) you can remove bodies of water that don't connect to the ocean:
import pylab as plt
A = plt.imread("world.png")
import numpy as np
import scipy.ndimage as nd
import collections
# Get a counter of the greyscale colors
a = A[:,:,0]
colors = collections.Counter(a.ravel())
outside_and_water_color, land_color = colors.most_common(2)
# Find the contigous landmass
land_idx = a == land_color[0]
# Index these land masses
L = np.zeros(a.shape,dtype=int)
L[land_idx] = 1
L,mass_count = nd.measurements.label(L)
# Loop over the land masses and fill the "holes"
# (rivers without outlays)
L2 = np.zeros(a.shape,dtype=int)
L2[land_idx] = 1
L2 = nd.morphology.binary_fill_holes(L2)
# Remap onto original image
new_land = L2==1
A2 = A.copy()
c = [land_color[0],]*3 + [1,]
A2[new_land] = land_color[0]
# Plot results
plt.subplot(221)
plt.imshow(A)
plt.axis('off')
plt.subplot(222)
plt.axis('off')
B = A.copy()
B[land_idx] = [1,0,0,1]
plt.imshow(B)
plt.subplot(223)
L = L.astype(float)
L[L==0] = None
plt.axis('off')
plt.imshow(L)
plt.subplot(224)
plt.axis('off')
plt.imshow(A2)
plt.tight_layout() # Only with newer matplotlib
plt.show()
The first image is the original, the second identifies the land mass. The third is not needed but fun as it ID's each separate contiguous landmass. The fourth picture is what you want, the image with the "rivers" removed.
Following user1868739's example, I am able to select only the paths (for some lakes) that I want:
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
fig = plt.figure(figsize=(8, 4.5))
plt.subplots_adjust(left=0.02, right=0.98, top=0.98, bottom=0.00)
m = Basemap(resolution='c',projection='robin',lon_0=0)
m.fillcontinents(color='white',lake_color='white',zorder=2)
coasts = m.drawcoastlines(zorder=1,color='white',linewidth=0)
coasts_paths = coasts.get_paths()
ipolygons = range(83) + [84] # want Baikal, but not Tanganyika
# 80 = Superior+Michigan+Huron, 81 = Victoria, 82 = Aral, 83 = Tanganyika,
# 84 = Baikal, 85 = Great Bear, 86 = Great Slave, 87 = Nyasa, 88 = Erie
# 89 = Winnipeg, 90 = Ontario
for ipoly in ipolygons:
r = coasts_paths[ipoly]
# Convert into lon/lat vertices
polygon_vertices = [(vertex[0],vertex[1]) for (vertex,code) in
r.iter_segments(simplify=False)]
px = [polygon_vertices[i][0] for i in xrange(len(polygon_vertices))]
py = [polygon_vertices[i][2] for i in xrange(len(polygon_vertices))]
m.plot(px,py,linewidth=0.5,zorder=3,color='black')
plt.savefig('world2.png',dpi=100)
But this only works when using white background for the continents. If I change color to 'gray' in the following line, we see that other rivers and lakes are not filled with the same color as the continents are. (Also playing with area_thresh will not remove those rivers that are connected to ocean.)
m.fillcontinents(color='gray',lake_color='white',zorder=2)
The version with white background is adequate for further color-plotting all kind of land information over the continents, but a more elaborate solution would be needed, if one wants to retain the gray background for continents.
I frequently modify Basemap's drawcoastlines() to avoid those 'broken' rivers. I also modify drawcountries() for the sake of data source consistency.
Here is what I use in order to support the different resolutions available in Natural Earth data:
from mpl_toolkits.basemap import Basemap
class Basemap(Basemap):
""" Modify Basemap to use Natural Earth data instead of GSHHG data """
def drawcoastlines(self):
shapefile = 'data/naturalearth/coastline/ne_%sm_coastline' % \
{'l':110, 'm':50, 'h':10}[self.resolution]
self.readshapefile(shapefile, 'coastline', linewidth=1.)
def drawcountries(self):
shapefile = 'data/naturalearth/countries/ne_%sm_admin_0_countries' % \
{'l':110, 'm':50, 'h':10}[self.resolution]
self.readshapefile(shapefile, 'countries', linewidth=0.5)
m = Basemap(llcrnrlon=-90, llcrnrlat=-40, urcrnrlon=-30, urcrnrlat=+20,
resolution='l') # resolution = (l)ow | (m)edium | (h)igh
m.drawcoastlines()
m.drawcountries()
Here is the output:
Please note that by default Basemap uses resolution='c' (crude), which is not supported in the code shown.
If you're OK with plotting outlines rather than shapefiles, it's pretty easy to plot coastlines that you can get from wherever. I got my coastlines from the NOAA Coastline Extractor in MATLAB format:
http://www.ngdc.noaa.gov/mgg/shorelines/shorelines.html
To edit the coastlines, I converted to SVG, then edited them with Inkscape, then converted back to the lat/lon text file ("MATLAB" format).
All Python code is included below.
# ---------------------------------------------------------------
def plot_lines(mymap, lons, lats, **kwargs) :
"""Plots a custom coastline. This plots simple lines, not
ArcInfo-style SHAPE files.
Args:
lons: Longitude coordinates for line segments (degrees E)
lats: Latitude coordinates for line segments (degrees N)
Type Info:
len(lons) == len(lats)
A NaN in lons and lats signifies a new line segment.
See:
giss.noaa.drawcoastline_file()
"""
# Project onto the map
x, y = mymap(lons, lats)
# BUG workaround: Basemap projects our NaN's to 1e30.
x[x==1e30] = np.nan
y[y==1e30] = np.nan
# Plot projected line segments.
mymap.plot(x, y, **kwargs)
# Read "Matlab" format files from NOAA Coastline Extractor.
# See: http://www.ngdc.noaa.gov/mgg/coast/
lineRE=re.compile('(.*?)\s+(.*)')
def read_coastline(fname, take_every=1) :
nlines = 0
xdata = array.array('d')
ydata = array.array('d')
for line in file(fname) :
# if (nlines % 10000 == 0) :
# print 'nlines = %d' % (nlines,)
if (nlines % take_every == 0 or line[0:3] == 'nan') :
match = lineRE.match(line)
lon = float(match.group(1))
lat = float(match.group(2))
xdata.append(lon)
ydata.append(lat)
nlines = nlines + 1
return (np.array(xdata),np.array(ydata))
def drawcoastline_file(mymap, fname, **kwargs) :
"""Reads and plots a coastline file.
See:
giss.basemap.drawcoastline()
giss.basemap.read_coastline()
"""
lons, lats = read_coastline(fname, take_every=1)
return drawcoastline(mymap, lons, lats, **kwargs)
# =========================================================
# coastline2svg.py
#
import giss.io.noaa
import os
import numpy as np
import sys
svg_header = """<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<!-- Created with Inkscape (http://www.inkscape.org/) -->
<svg
xmlns:dc="http://purl.org/dc/elements/1.1/"
xmlns:cc="http://creativecommons.org/ns#"
xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
xmlns:svg="http://www.w3.org/2000/svg"
xmlns="http://www.w3.org/2000/svg"
version="1.1"
width="360"
height="180"
id="svg2">
<defs
id="defs4" />
<metadata
id="metadata7">
<rdf:RDF>
<cc:Work
rdf:about="">
<dc:format>image/svg+xml</dc:format>
<dc:type
rdf:resource="http://purl.org/dc/dcmitype/StillImage" />
<dc:title></dc:title>
</cc:Work>
</rdf:RDF>
</metadata>
<g
id="layer1">
"""
path_tpl = """
<path
d="%PATH%"
id="%PATH_ID%"
style="fill:none;stroke:#000000;stroke-width:1px;stroke-linecap:butt;stroke-linejoin:miter;stroke-opacity:1"
"""
svg_footer = "</g></svg>"
# Set up paths
data_root = os.path.join(os.environ['HOME'], 'data')
#modelerc = giss.modele.read_modelerc()
#cmrun = modelerc['CMRUNDIR']
#savedisk = modelerc['SAVEDISK']
ifname = sys.argv[1]
ofname = ifname.replace('.dat', '.svg')
lons, lats = giss.io.noaa.read_coastline(ifname, 1)
out = open(ofname, 'w')
out.write(svg_header)
path_id = 1
points = []
for lon, lat in zip(lons, lats) :
if np.isnan(lon) or np.isnan(lat) :
# Process what we have
if len(points) > 2 :
out.write('\n<path d="')
out.write('m %f,%f L' % (points[0][0], points[0][1]))
for pt in points[1:] :
out.write(' %f,%f' % pt)
out.write('"\n id="path%d"\n' % (path_id))
# out.write('style="fill:none;stroke:#000000;stroke-width:1px;stroke-linecap:butt;stroke-linejoin:miter;stroke-opacity:1"')
out.write(' />\n')
path_id += 1
points = []
else :
lon += 180
lat = 180 - (lat + 90)
points.append((lon, lat))
out.write(svg_footer)
out.close()
# =============================================================
# svg2coastline.py
import os
import sys
import re
# Reads the output of Inkscape's "Plain SVG" format, outputs in NOAA MATLAB coastline format
mainRE = re.compile(r'\s*d=".*"')
lineRE = re.compile(r'\s*d="(m|M)\s*(.*?)"')
fname = sys.argv[1]
lons = []
lats = []
for line in open(fname, 'r') :
# Weed out extraneous lines in the SVG file
match = mainRE.match(line)
if match is None :
continue
match = lineRE.match(line)
# Stop if something is wrong
if match is None :
sys.stderr.write(line)
sys.exit(-1)
type = match.group(1)[0]
spairs = match.group(2).split(' ')
x = 0
y = 0
for spair in spairs :
if spair == 'L' :
type = 'M'
continue
(sdelx, sdely) = spair.split(',')
delx = float(sdelx)
dely = float(sdely)
if type == 'm' :
x += delx
y += dely
else :
x = delx
y = dely
lon = x - 180
lat = 90 - y
print '%f\t%f' % (lon, lat)
print 'nan\tnan'
Okay I think I have a partial solution.
The basic idea is that the paths used by drawcoastlines() are ordered by the size/area. Which means the first N paths are (for most applications) the main land masses and lakes and the later paths the smaller islands and rivers.
The issue is that the first N paths that you want will depend on the projection (e.g., global, polar, regional), if area_thresh has been applied and whether you want lakes or small islands etc. In other words, you will have to tweak this per application.
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
mp = 'cyl'
m = Basemap(resolution='c',projection=mp,lon_0=0,area_thresh=200000)
fill_color = '0.9'
# If you don't want lakes set lake_color to fill_color
m.fillcontinents(color=fill_color,lake_color='white')
# Draw the coastlines, with a thin line and same color as the continent fill.
coasts = m.drawcoastlines(zorder=100,color=fill_color,linewidth=0.5)
# Exact the paths from coasts
coasts_paths = coasts.get_paths()
# In order to see which paths you want to retain or discard you'll need to plot them one
# at a time noting those that you want etc.
for ipoly in xrange(len(coasts_paths)):
print ipoly
r = coasts_paths[ipoly]
# Convert into lon/lat vertices
polygon_vertices = [(vertex[0],vertex[1]) for (vertex,code) in
r.iter_segments(simplify=False)]
px = [polygon_vertices[i][0] for i in xrange(len(polygon_vertices))]
py = [polygon_vertices[i][1] for i in xrange(len(polygon_vertices))]
m.plot(px,py,'k-',linewidth=1)
plt.show()
Once you know the relevant ipoly to stop drawing (poly_stop) then you can do something like this...
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
mproj = ['nplaea','cyl']
mp = mproj[0]
if mp == 'nplaea':
m = Basemap(resolution='c',projection=mp,lon_0=0,boundinglat=30,area_thresh=200000,round=1)
poly_stop = 10
else:
m = Basemap(resolution='c',projection=mp,lon_0=0,area_thresh=200000)
poly_stop = 18
fill_color = '0.9'
# If you don't want lakes set lake_color to fill_color
m.fillcontinents(color=fill_color,lake_color='white')
# Draw the coastlines, with a thin line and same color as the continent fill.
coasts = m.drawcoastlines(zorder=100,color=fill_color,linewidth=0.5)
# Exact the paths from coasts
coasts_paths = coasts.get_paths()
# In order to see which paths you want to retain or discard you'll need to plot them one
# at a time noting those that you want etc.
for ipoly in xrange(len(coasts_paths)):
if ipoly > poly_stop: continue
r = coasts_paths[ipoly]
# Convert into lon/lat vertices
polygon_vertices = [(vertex[0],vertex[1]) for (vertex,code) in
r.iter_segments(simplify=False)]
px = [polygon_vertices[i][0] for i in xrange(len(polygon_vertices))]
py = [polygon_vertices[i][1] for i in xrange(len(polygon_vertices))]
m.plot(px,py,'k-',linewidth=1)
plt.show()
As per my comment to #sampo-smolander
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt
fig = plt.figure(figsize=(8, 4.5))
plt.subplots_adjust(left=0.02, right=0.98, top=0.98, bottom=0.00)
m = Basemap(resolution='c',projection='robin',lon_0=0)
m.fillcontinents(color='gray',lake_color='white',zorder=2)
coasts = m.drawcoastlines(zorder=1,color='white',linewidth=0)
coasts_paths = coasts.get_paths()
ipolygons = range(83) + [84]
for ipoly in xrange(len(coasts_paths)):
r = coasts_paths[ipoly]
# Convert into lon/lat vertices
polygon_vertices = [(vertex[0],vertex[1]) for (vertex,code) in
r.iter_segments(simplify=False)]
px = [polygon_vertices[i][0] for i in xrange(len(polygon_vertices))]
py = [polygon_vertices[i][1] for i in xrange(len(polygon_vertices))]
if ipoly in ipolygons:
m.plot(px,py,linewidth=0.5,zorder=3,color='black')
else:
m.plot(px,py,linewidth=0.5,zorder=4,color='grey')
plt.savefig('world2.png',dpi=100)
I have a raster file and a WGS84 lat/lon point.
I would like to know what value in the raster corresponds with the point.
My feeling is that I should use GetSpatialRef() on the raster object or one of its bands and then apply a ogr.osr.CoordinateTransformation() to the point to map it to the raster's space.
My hope would then be that I could simply ask the rasters' bands what is at that point.
However, the raster object doesn't seem to have a GetSpatialRef() or a way to access a geo-located point, so I'm somewhat at a loss for how to do this.
Any thoughts?
Say i have a geotiff file test.tif. Then followin code should look up value somewhere near the pixel. I am not that confident for the part looking up cell, and will fix there is error. This page should help, "GDAL Data Model"
Also, you may go to gis.stackexchange.com to find experts, if you haven't.
import gdal, osr
class looker(object):
"""let you look up pixel value"""
def __init__(self, tifname='test.tif'):
"""Give name of tif file (or other raster data?)"""
# open the raster and its spatial reference
self.ds = gdal.Open(tifname)
srRaster = osr.SpatialReference(self.ds.GetProjection())
# get the WGS84 spatial reference
srPoint = osr.SpatialReference()
srPoint.ImportFromEPSG(4326) # WGS84
# coordinate transformation
self.ct = osr.CoordinateTransformation(srPoint, srRaster)
# geotranformation and its inverse
gt = self.ds.GetGeoTransform()
dev = (gt[1]*gt[5] - gt[2]*gt[4])
gtinv = ( gt[0] , gt[5]/dev, -gt[2]/dev,
gt[3], -gt[4]/dev, gt[1]/dev)
self.gt = gt
self.gtinv = gtinv
# band as array
b = self.ds.GetRasterBand(1)
self.arr = b.ReadAsArray()
def lookup(self, lon, lat):
"""look up value at lon, lat"""
# get coordinate of the raster
xgeo,ygeo,zgeo = self.ct.TransformPoint(lon, lat, 0)
# convert it to pixel/line on band
u = xgeo - self.gtinv[0]
v = ygeo - self.gtinv[3]
# FIXME this int() is probably bad idea, there should be
# half cell size thing needed
xpix = int(self.gtinv[1] * u + self.gtinv[2] * v)
ylin = int(self.gtinv[4] * u + self.gtinv[5] * v)
# look the value up
return self.arr[ylin,xpix]
# test
l = looker('test.tif')
lon,lat = -100,30
print l.lookup(lon,lat)
lat,lon =28.816944, -96.993333
print l.lookup(lon,lat)
Yes, the API isn't consistent. The raster (the data source) has a GetProjection() method instead (which returns WKT).
Here is a function that does what you want (drawn from here):
def extract_point_from_raster(point, data_source, band_number=1):
"""Return floating-point value that corresponds to given point."""
# Convert point co-ordinates so that they are in same projection as raster
point_sr = point.GetSpatialReference()
raster_sr = osr.SpatialReference()
raster_sr.ImportFromWkt(data_source.GetProjection())
transform = osr.CoordinateTransformation(point_sr, raster_sr)
point.Transform(transform)
# Convert geographic co-ordinates to pixel co-ordinates
x, y = point.GetX(), point.GetY()
forward_transform = Affine.from_gdal(*data_source.GetGeoTransform())
reverse_transform = ~forward_transform
px, py = reverse_transform * (x, y)
px, py = int(px + 0.5), int(py + 0.5)
# Extract pixel value
band = data_source.GetRasterBand(band_number)
structval = band.ReadRaster(px, py, 1, 1, buf_type=gdal.GDT_Float32)
result = struct.unpack('f', structval)[0]
if result == band.GetNoDataValue():
result = float('nan')
return result
Its documentation is as follows (drawn from here):
spatial.extract_point_from_raster(point, data_source, band_number=1)
data_source is a GDAL raster, and point is an OGR point object. The
function returns the value of the pixel of the specified band of
data_source that is nearest to point.
point and data_source need not be in the same reference system, but
they must both have an appropriate spatial reference defined.
If the point does not fall in the raster, RuntimeError is raised.
project = self.ds.GetProjection()
srPoint = osr.SpatialReference(wkt=project)
done... with that, the vector file has adopted the projection from input raster file