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Catching exceptions within Pika callback stops callback from working

I have a callback associated with a rabbitmq queue through pika's basic_consume like so.
channel.basic_consume(queue=REQUESTS_QUEUE,
on_message_callback=request_callback, auto_ack=False)
And the request callback function is:
def request_callback(channel, method, properties, body):
try:
readings = json_util.loads(body)
location_updater.update_location(readings)
channel.basic_ack(delivery_tag=method.delivery_tag)
except Exception:
logger.exception('EXCEPTION: ')
Whenever the code inside the except block is executed, this particular callback stops working (i.e. it stops being called when a message is sent to its associated queue). All the other callbacks I have associated with other queues keep working fine. If I comment out the try...except logic the callback keeps working fine for further requests, even after a exception occurs.
I'm still getting used to Python, so it might be something simple. Can anyone help?

I'm assuming the exception comes from a statement before channel.basic_ack, and I'm also assuming you're calling channel.basic_qos to set a prefetch value.
The exception prevents the call to basic_ack, which prevents RabbitMQ from removing the message from the queue. If you have reached the prefetch value, no further messages will be delivered to that client because RabbitMQ assumes your client is still processing them.
You need to decide what to do with that message when an exception happens. I'm assuming that the message can't be considered to be processed, so you should reject (nack) the message (https://www.rabbitmq.com/nack.html). Do this in the except block. This will cause the message to be re-enqueued and re-delivered, potentially to a different consumer.
Closing the channel and/or the connection will also have the same effect. This ensures that clients that crash do not permanently "hold onto" messages.
NOTE: the RabbitMQ team monitors the rabbitmq-users mailing list and only sometimes answers questions on StackOverflow.

How to listen for incoming websocket messages from multiple places using Tornado?

Let's say I have an infinite while loop that awaits the read_message() method of a WebSocket Tornado client connection. Then, I externally trigger a function that sends a message and should get an immediate response.
Since everything is asynchronous, I would assume that when that external call takes place, the execution goes over to it. But when I try to listen for a response inside that call, it throws an AssertionError stating that self.read_future is not None, when it should be.
Here are the methods of the client application. A little earlier, it connects to a server and places the connection in the self.conn variable:
async def loop(self):
while True:
print(await self.conn.read_message())
async def ext_call(self):
self.conn.write_message('Hello, World!')
response = await self.conn.read_message() # This line fails
Why can't I listen for messages in two separate places?

What you're asking for is ambiguous - which messages would go to which place? It looks like you probably mean for the next message to arrive after you send "Hello world" to be handled in ext_call, and all others to be printed in loop. But how could the system know that? Consider that the "Hello world" message could be sent to the client and the response received before the python interpreter has executed the read_message call in ext_call, so it would be routed to the waiting read_message in loop.
In general, you want to use one of these patterns but not both at the same time. If you always have matched request/response pairs of messages, you can read after you send as in ext_call. But if you may have messages that are not a part of request/response pairs, you need one loop that reads all the messages and decides what to do with them (perhaps splitting them up by type and emitting them on one or more queues using the tornado.queues module).

Polling for RabbitMQ messages using Pika client

I am wanting to create a RabbitMQ receiver/consumer in Python and am not sure how to check for messages. I am trying to do this in my own loop, not using the call-backs in pika.
If I understand things, in the Java client I can use getBasic() to check to see if there are any messages available without blocking. I don't mind blocking while getting messages, but I don't want to block until there is a message.
I don't find any clear examples and haven't yet figured out the corresponding call in pika.

If you want to do it synchronously then you will need to look at the pika BlockingConnection
The BlockingConnection creates a layer on top of Pika’s asynchronous
core providng methods that will block until their expected response
has returned. Due to the asynchronous nature of the Basic.Deliver and
Basic.Return calls from RabbitMQ to your application, you are still
required to implement continuation-passing style asynchronous methods
if you’d like to receive messages from RabbitMQ using basic_consume or
if you want to be notified of a delivery failure when using
basic_publish.
More info and an example here
https://pika.readthedocs.org/en/0.9.12/connecting.html#blockingconnection

You can periodically check the queue size using the example of this answer Get Queue Size in Pika (AMQP Python)

Queue processing loop can be done iteratively with the help of process_data_events():
import pika
# A stubborn callback that still wants to be in the code.
def mq_callback(ch, method, properties, body):
print(" Received: %r" % body)
connection = pika.BlockingConnection(pika.ConnectionParameters("localhost"))
channel = connection.channel()
queue_state = channel.queue_declare(queue="test")
# Configure a callback.
channel.basic_consume(mq_callback, queue="test")
try:
# My own loop here:
while(True):
# Do other processing
# Process message queue events, returning as soon as possible.
# Issues mq_callback() when applicable.
connection.process_data_events(time_limit=0)
finally:
connection.close()

RabbitMQ: can both consuming and publishing be done in one thread?

can both consuming and publishing be done in one Python thread using RabbitMQ channels?

Actually this isn't a problem at all and you can do it quite easily with for example pika the problem is however that you'd have to stop the consuming since it's a blocking loop or do the producing during the consume of a message.
Consuming and producing is a normal usecase, especially in pika since it isn't threadsafe, when for example you'd want to implement some form of filter on the messages, or, perhaps a smart router, which in turn will pass on the messages to another queue.

I don't think you should want to. MQ means asynch processing. Doing both consuming and producing in the same thread defeats the purpose in my opinion.

I'd recommend taking a look at Celery (http://celery.readthedocs.org/en/latest/) to manage worker tasks. With that, you won't need to integrate with RMQ directly as it will handle the the producing and consuming for you.
But, if you do desire to integrate with RMQ directly and manage your own workers, check out Kombu (http://kombu.readthedocs.org/en/latest/) for the integration. There are non-blocking consumers and producers that would permit you to have both in the same event loop.

I think the simple answer to your question is yes. But it depends on what you want to do. My guess is you have a loop that is consuming from your thread on one channel and after some (small or large) processing it decides to send it on to another queue (or exchange) on a different channel then I do not see any problem with that at all. Though it might be preferable to dispatch it to a different thread it is not necessary.
If you give more details about your process then it might help give a more specific answer.

Kombu is a common python library for working with RabbitMQ (Celery uses it under the hood). It is worth pointing out here that the answer to your question for the simplest use of Kombu that I tried is "No - you can't receive and publish on the same consumer callback thread."
Specifically if there are several messages in the queue for a consumer that has registered a callback for that topic and that callback does some processing and publishes the results then the publishing of the result will cause the 2nd message in the queue to hit the callback before it has returned from the publish from 1st message - so you end up with a recursive call to the callback. If you have n message on the queue your call stack will end up n message deep before it unwinds. Obviously that explodes pretty quickly.
One solution (not necessarily the best) is to have the callback just post the message into a simple queue internal to the consumer that could be processed on the main process thread (i.e. off the callback thread)
def process_message(self, body: str, message: Message):
# Queue the message for processing off this thread:
print("Start process_message ----------------")
self.do_process_message(body, message) if self.publish_on_callback else self.queue.put((body, message))#
print("End process_message ------------------")
def do_process_message(self, body: str, message: Message):
# Deserialize and "Process" the message:
print(f"Process message: {body}")
# ... msg processing code...
# Publish a processing output:
processing_output = self.get_processing_output()
print(f"Publishing processing output: {processing_output}")
self.rabbit_msg_transport.publish(Topics.ProcessingOutputs, processing_output)
# Acknowledge the message:
message.ack()
def run_message_loop(self):
while True:
print("Waiting for incoming message")
self.rabbit_connection.drain_events()
while not self.queue.empty():
body, message = self.queue.get(block=False)
self.do_process_message(body, message)
In this snippet above process_message is the callback. If publish_on_callback is True you'll see recursion in the callback n deep for n message on rabbit queue. If publish_on_callback is False it runs correctly without recursion in the callback.
Another approach is to use a second Connection for the Producer Exchange - separate from the Connection used for the Consumer. This also works so that callback from consuming a message and publishing the result completes before the callback is again fired for the next message on queue.

Twisted irc python bot - buffering messages

"Why does it take a long time for data I send with transport.write to arrive at the other side of the connection?"
Twisted can only send data after you give up control of execution to the reactor. For example, if you have an infinite loop writing data to a transport, the data will never actually be sent since control will never leave your code and return to the reactor."
I found this in the twisted FAQ, it is exactly as my problem. Is there a way to fix this so I can send messages instantly and not wait for the loop to finish?

No. You cannot send messages instantly. Control must return to the event loop. Fortunately, the problem you're really trying to solve (inferred from comments on the question), rate limiting the messages you send, doesn't require being able to do this. Instead, stop using time.sleep in a loop and start using reactor.callLater to delay the execution of code. Or use features of the IRC API which do these things for you (which you seem to have discovered already, lineRate).