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Converting multiple zip files into regular folders

Can anyone help me to convert a lot of zip files at once using python?
I have "Years" folder which has 3 folders of "2019","2020" and "2021". Folder "2019" has folders of "1","2","3" folders. Folder "1" has "attachment.zip", Folder "2" has "attachment.zip" and Folder "3" has "attachment.zip. I want to go through each folder in order to convert all zip files and extract them to "Extracted" folder.
Result should look like this:
Folder "1" has "attachment.zip" and folder of "Extracted".

Below is the code that worked for me:
import os, zipfile
dir_name = 'C:\\SomeDirectory'
extension = ".zip"
os.chdir(dir_name) # change directory from working dir to dir with files
for item in os.listdir(dir_name): # loop through items in dir
if item.endswith(extension): # check for ".zip" extension
file_name = os.path.abspath(item) # get full path of files
zip_ref = zipfile.ZipFile(file_name) # create zipfile object
zip_ref.extractall(dir_name) # extract file to dir
zip_ref.close() # close file
os.remove(file_name) # delete zipped file
Looking back at the code I had amended, the directory was getting
confused with the directory of the script.
The following also works while not ruining the working directory.
First remove the line
os.chdir(dir_name) # change directory from working dir to dir with files
Then assign file_name as
file_name = dir_name + "/" + item

Python zipfile and os

I have some code to export all files within a zipfile to a path but what I want to do is create a new folder with the same name as the zipfile minus the ".zip" just like the windows explorer option does. I have commented out the code that doesn't work. It seems to be the os.makedirs that doesn't work.
File "C:/Users/brentond/Documents/Python/Unzip all zip files in path.py", line 12
Output = os.path.join(path, filename.replace(".zip", "")) # get new folder path name
^
SyntaxError: invalid syntax
the code:
import os, zipfile
# Define path of zip files to variable
path = r'C:\Users\brentond\Documents\TA2\HA GDMS'
for foldername, subfolders, filenames in os.walk(path): # walk directory
for filename in filenames: # loop through files
if filename.endswith(".zip"): # find zip files
filepath = os.path.join(foldername, filename) # get zip file abs path
#os.makedirs(os.path.join(path, filename.replace(".zip", "")) # create new folder same name as zip file
#Output = os.path.join(path, filename.replace(".zip", "")) # get new folder path name
ZipRef = zipfile.ZipFile(filepath) # create zip file object
ZipRef.extractall(path) # extract all. This to put everything in the path folder
#ZipRef.extractall(Output) # This to put the zip file contents into a folder with same name
ZipRef.close() # close zip

I have resolved this now and simplified the code a little
import os, zipfile
# Define path of zip files to variable
path = r'C:\Users\brentond\Documents\TA2\HA GDMS'
for foldername, subfolders, filenames in os.walk(path): # walk directory
for filename in filenames: # loop through files
if filename.endswith(".zip"): # find zip files
filepath = os.path.join(foldername, filename) # get zip file abs path
filefolder = filename.replace(".zip","")
os.makedirs(os.path.join(path, filefolder)) # create new folder same name as zip file
Output = os.path.join(path, filefolder) # get new folder path name
ZipRef = zipfile.ZipFile(filepath) # create zip file object
#ZipRef.extractall(path) # extract all. This to put everything in the path folder
ZipRef.extractall(Output) # This to put the zip file contents into a folder with same name
ZipRef.close() # close zip

Python zipfile extract files from directory inside a zip file

I need to extract some files inside a directory in a zip file.
The main problem is that I want to extract only the contents from this directory, not the directory itself with all the files inside.
I've tried by iterating on them using namelist() or tweaking it with zipfile.Path(), unsuccessfully.
This works but it extracts the directory with the files (like extractall() does). Path doesn't work because raises KeyError saying that the item doesn't exist yet it does.
for zip_file in zip_files:
with zipfile.ZipFile(os.path.join(home_path, zip_file), 'r') as zip_ref:
files = [n for n in zip_ref.namelist()]
zip_ref.extractall(os.path.join(home_path, 'dir'), members=files)

written from my mobile but I expect it to work:
from pathlib import Path
with ZipFile(zipfile_path, "r") as zf:
for f in zf.namelist():
if f.startswith('/'):
continue
source = zf.open(f)
target = open(target_dir / Path(f).name, "wb")
with source, target:
shutil.copyfileobj(source, target)

Python doesn't recognize zip files as zip files

I iterate through the directories and want to find all zip files and add them to download_all.zip
I am sure there are zip files, but Python doesn't recognize those zip files as zip files. Why is that?
my code:
os.chdir(boardpath)
# zf = zipfile.ZipFile('download_all.zip', mode='w')
z = zipfile.ZipFile('download_all.zip', 'w') #creating zip download_all.zip file
for path, dirs, files in os.walk(boardpath):
for file in files:
print file
if file.endswith('.zip'): # find all zip files
print ('adding', file)
z.write(file) # error shows: doesn't file is a str object, not a zip file
z.close()
z = zipfile.ZipFile("download_all.zip")
z.printdir()
I tried:
file.printdir()
# I got the following error: AttributeError: 'str' object has no attribute 'printdir'

zipfile.Zipfile.write(name), name actually stands for full file path, not just filename.
import os #at the top
if file.endswith('.zip'): # find all zip files
filepath = os.path.join(path, file)
print ('adding', filepath)
z.write(filepath) # no error

As stated in the ZipFile.write's doc, the filename argument must be relative to the archive root. So the following line:
z.write(file)
Should be:
z.write(os.path.relpath(os.path.join(path, file)))

The files that os/walk() yields are lists of filenames. These filenames are just strings (which don't have a printdir() method).

You want to use the context management while opening up the zip file archive and writing to it for each file that you find, hence the use of with. In addition, since you're walking through a directory structure, you need to full qualify each file's path.
import os
import Zipfile
with zipfile.ZipFile('download_all.zip', 'w') as zf:
for path, dirs, files in os.walk('/some_path'):
for file in files:
if file.endswith('.zip'):
zf.write(os.path.join(path, file))

Archive oldest date modified folder and move to another folder

I am trying to archive the oldest date modified folder and move to another folder.
My folder structure is currently c:\test\test1 (latest folder) and c:\test\test2 and c:\test\test3
I would like to zip test2 and test 3 as they are oldest modified folders and move them to another location i.e c:\archive
I have managed to get it working to zip the oldest folder but it does not move it and also does not move to another folder location which I would like it to keep my archive tidy.
Also a nice to have would be to have the zipfolder with archive_date.zip
import glob
import os
import zipfile
files_dir = r'c:\test\' # here should be path to directory with your files
files = glob.glob(files_dir + '\*')
# find all files that located in specified directory
files_modify_dt = [os.path.getmtime(file) for file in files]
# take files except last modified file
files_to_zip = [file for _, file in sorted(zip(files_modify_dt, files))][:-1]
# zip of selected files
with zipfile.ZipFile(os.path.join(files_dir, 'archive.zip'), 'w', zipfile.ZIP_DEFLATED) as zip_obj:
for file in files_to_zip:
zip_obj.write(file, os.path.basename(file))
os.remove(file)