if sample_collected == 'true':
b_id = list(Booking.objects.filter(center__isnull=False,org_type='homedx').values_list('id', flat=True))
for booki_id in b_id:
print("Booking ID", booki_id)
if booki_id in list(ReceivedPackageTubes.objects.values_list('booking_id', flat=True)):
packages = list(Booking.objects.filter(id=booki_id).values_list('packages__name', flat=True))
print("Packages", packages)
count_tube = []
for i in packages:
pt = package_models.PackageTubes.objects.filter(package__name=i).values_list('tubequantity__tube__name', flat=True).count()
count_tube.append(pt)
total_tubes = sum(count_tube)
print("Total Tubes", total_tubes)
collected = list(ReceivedPackageTubes.objects.filter(booking_id=booki_id).values_list('booking_id', flat=True))
print("Collected", collected)
collected_ids = []
if len(collected) == total_tubes:
collected_ids.append(booki_id)
print("Collected ID", collected_ids)
In the last line if len(collected) == total_tubes. I am trying to append **collected_id**. in collected_ids = []. Every time it is appending one. I know I need to use for loop but I am unable to do that. Can somebody help. I am learning Python and Django. Thank you !!
You're using a for loop to iterate over booki_id elements in b_id, and adding them to the collected_ids list. However, each time you process the next booki_id, you're resetting collected_ids to an empty list. Try moving the line:
collected_ids = []
outside the for loop, so that you only initialize the list once and avoid overwriting it.
Related
I'm adding a function to a class to output the item with the lowest price but what I'm getting are all the prices. See photo and code. What am I missing on the code?
def get_low_price(self):
self.get_total_toys()
#To check if toybox is empty or not
if self.total > 0:
msg = f'The toy box contains {self.total} toys\n'
for a_toy in self.all_toys:
self.get_total_cost()
msg += f'A {(a_toy.colour).lower()} {a_toy.name} which cost ${a_toy.price:.2f}\n'
for i in [a_toy.price]:
i = ([i])
print(min(i))
return f'{msg}Total cost: ${self.cost_total:.2f}'
This inner loop isn't doing anything useful:
for i in [a_toy.price]:
i = ([i])
print(min(i))
Here a_toy is already just a single toy. Looping over a new list containing only its price doesn't accomplish anything you could get just by accessing a_toy.price directly, and rebinding the loop variable i to another new list (in extraneous parentheses) doesn't add anything.
I think you want to move all of the min-finding logic outside of the earlier loop, unless you want to compare prices yourself. Instead, you can use just one min call, outside of the loop:
for a_toy in self.all_toys: # don't include the stuff below in this loop
...
cheapest = min(self.all_toys, key=lambda t: t.price) # find cheapest
# do something down here with cheapest, or cheapest.name, maybe
I didn't understand what exactly you are trying to do using the for loop in that method. If you are thinking that i = ([i]) is going to append price to a list then it's wrong. Use the below logic and rewrite your method. It will work.
toys = {"doll": 5, "hulk": 10, "teddy": 15}
cheapest_toy_name = ""
cheapest_toy_price = float("inf")
for k, v in toys.items():
if cheapest_toy_price > v:
cheapest_toy_price = v
cheapest_toy_name = k
print(cheapest_toy_name)
Below I have some strings in a list:
some_list = ['a','l','p','p','l','l','i','i','r',i','r','a','a']
Now I want to take the word april from this list. There are only two april in this list. So I want to take that two april from this list and append them to another extract list.
So the extract list should look something like this:
extract = ['aprilapril']
or
extract = ['a','p','r','i','l','a','p','r','i','l']
I tried many times trying to get the everything in extract in order, but I still can't seems to get it.
But I know I can just do this
a_count = some_list.count('a')
p_count = some_list.count('p')
r_count = some_list.count('r')
i_count = some_list.count('i')
l_count = some_list.count('l')
total_count = [a_count,p_count,r_count,i_count,l_count]
smallest_count = min(total_count)
extract = ['april' * smallest_count]
Which I wouldn't be here If I just use the code above.
Because I made some rules for solving this problem
Each of the characters (a,p,r,i and l) are some magical code elements, these code elements can't be created out of thin air; they are some unique code elements, that has some uniquw identifier, like a secrete number that is associated with them. So you don't know how to create this magical code elements, the only way to get the code elements is to extract them to a list.
Each of the characters (a,p,r,i and l) must be in order. Imagine they are some kind of chains, they will only work if they are together. Meaning that we got to put p next to and in front of a, and l must come last.
These important code elements are some kind of top secrete stuff, so if you want to get it, the only way is to extract them to a list.
Below are some examples of a incorrect way to do this: (breaking the rules)
import re
word = 'april'
some_list = ['aaaaaaappppppprrrrrriiiiiilll']
regex = "".join(f"({c}+)" for c in word)
match = re.match(regex, text)
if match:
lowest_amount = min(len(g) for g in match.groups())
print(word * lowest_amount)
else:
print("no match")
from collections import Counter
def count_recurrence(kernel, string):
# we need to count both strings
kernel_counter = Counter(kernel)
string_counter = Counter(string)
effective_counter = {
k: int(string_counter.get(k, 0)/v)
for k, v in kernel_counter.items()
}
min_recurring_count = min(effective_counter.values())
return kernel * min_recurring_count
This might sounds really stupid, but this is actually a hard problem (well for me). I originally designed this problem for myself to practice python, but it turns out to be way harder than I thought. I just want to see how other people solve this problem.
If anyone out there know how to solve this ridiculous problem, please help me out, I am just a fourteen-year-old trying to do python. Thank you very much.
I'm not sure what do you mean by "cannot copy nor delete the magical codes" - if you want to put them in your output list you will need to "copy" them somehow.
And btw your example code (a_count = some_list.count('a') etc) won't work since count will always return zero.
That said, a possible solution is
worklist = [c for c in some_list[0]]
extract = []
fail = False
while not fail:
lastpos = -1
tempextract = []
for magic in magics:
if magic in worklist:
pos = worklist.index(magic, lastpos+1)
tempextract.append(worklist.pop(pos))
lastpos = pos-1
else:
fail = True
break
else:
extract.append(tempextract)
Alternatively, if you don't want to pop the elements when you find them, you may compute the positions of all the occurences of the first element (the "a"), and set lastpos to each of those positions at the beginning of each iteration
May not be the most efficient way, although code works and is more explicit to understand the program logic:
some_list = ['aaaaaaappppppprrrrrriiiiiilll']
word = 'april'
extract = []
remove = []
string = some_list[0]
for x in range(len(some_list[0])//len(word)): #maximum number of times `word` can appear in `some_list[0]`
pointer = i = 0
while i<len(word):
j=0
while j<(len(string)-pointer):
if string[pointer:][j] == word[i]:
extract.append(word[i])
remove.append(pointer+j)
i+=1
pointer = j+1
break
j+=1
if i==len(word):
for r_i,r in enumerate(remove):
string = string[:r-r_i] + string[r-r_i+1:]
remove = []
elif j==(len(string)-pointer):
break
print(extract,string)
I am using Python 3 / Tweepy to create a list that contains the user names associated with various Twitter handles.
My code creates an empty dictionary, loops through the handles in the list to get the user name, saves this info in a dictionary and then appends the dictionary to a new list.
I am getting IndexError: list index out of range when I run the code. When I remove the 4th line of the for loop I do not get errors. Any thoughts on how I can resolve the issue? Why is this line of code causing errors? Thanks!
Here is my code:
def analyzer():
handles = ['#Nasdaq', '#Apple', '#Microsoft', '#amazon', '#Google', '#facebook', '#GileadSciences', '#intel']
data = []
# Grab twitter handles and append the name to data
for handle in handles:
data_dict = {}
tweets = api.user_timeline(handle)
data_dict['Handle'] = handle
data_dict['Name'] = tweets[0]['user']['name']
data.append(data_dict)
i guess main issue in below code
tweets = api.user_timeline(handle)
api.user_timeline() may returns you empty list and you are trying to access
first element from this empty list.
tweets[0]
that's why you are getting 'index out of range' issue.
you can modify your code somthing like this -
for handle in handles:
data_dict = {}
tweets = api.user_timeline(handle)
data_dict['Handle'] = handle
if tweets:
data_dict['Name'] = tweets[0]['user']['name']
data.append(data_dict)
the error is occuring beacause of the empty list which you are trying to access with index 0. you can control this by checking if list is empty or not:
def analyzer():
handles = ['#Nasdaq', '#Apple', '#Microsoft', '#amazon', '#Google', '#facebook', '#GileadSciences', '#intel']
data = []
# Grab twitter handles and append the name to data
for handle in handles:
data_dict = {}
tweets = []
tweets = api.user_timeline(handle)
if tweets:
data_dict['Handle'] = handle
data_dict['Name'] = tweets[0]['user']['name']
data.append(data_dict)
I am writing a simple secret santa script that selects a "GiftReceiver" and a "GiftGiver" from a list. Two lists and an empty dataframe to be populated are produced:
import pandas as pd
import random
santaslist_receivers = ['Rudolf',
'Blitzen',
'Prancer',
'Dasher',
'Vixen',
'Comet'
]
santaslist_givers = santaslist_receivers
finalDataFrame = pd.DataFrame(columns = ['GiftGiver','GiftReceiver'])
I then have a while loop that selects random elements from each list to pick a gift giver and receiver, then remove from the respective list:
while len(santaslist_receivers) > 0:
print (len(santaslist_receivers)) #Used for testing.
gift_receiver = random.choice(santaslist_receivers)
santaslist_receivers.remove(gift_receiver)
print (len(santaslist_receivers)) #Used for testing.
gift_giver = random.choice(santaslist_givers)
while gift_giver == gift_receiver: #While loop ensures that gift_giver != gift_receiver
gift_giver = random.choice(santaslist_givers)
santaslist_givers.remove(gift_giver)
dummyDF = pd.DataFrame({'GiftGiver':gift_giver,'GiftReceiver':gift_receiver}, index = [0])
finalDataFrame = finalDataFrame.append(dummyDF)
The final dataframe only contains three elements instead of six:
print(finalDataframe)
returns
GiftGiver GiftReceiver
0 Dasher Prancer
0 Comet Vixen
0 Rudolf Blitzen
I have inserted two print lines within the while loop to investigate. These print the length of the list santaslist_receivers before and after the removal of an element. The expected return is to see original list length on the first print, then minus 1 on the second print, then the same length again on the first print of the next iteration of the while loop, then so on. Specifically I expect:
6,5,5,4,4,3,3... and so on.
What is returned is
6,5,4,3,2,1
Which is consistent with the DataFrame having only 3 rows, but I do not see the cause of this.
What is the error in my code or my approach?
You can solve it by simply changing this line
santaslist_givers = santaslist_receivers
to
santaslist_givers = list(santaslist_receivers)
Python variables are pointers essentially so they refer to the same list , ie santaslist_givers and santaslist_receivers were accessing the same location in memory in your implementation . To make them different use a list function
And for some extra information , you can refer copy.deepcopy
You should make an explicit copy of your list here
santaslist_givers = santaslist_receivers
there are multiple options for doing this as explained in this question.
In this case I would recommend (if you have Python >= 3.3):
santaslist_givers = santaslist_receivers.copy()
If you are on an older version of Python, the typical way to do it is:
santaslist_givers = santaslist_receivers[:]
I want to generate a JSON type object for a HttpResponse and in order to build it i´m using a nested "for" structure. I wrote down some code, tried it with my python interpreter but when I used it on my django view it refuses to work correctly.
My structure is something like this:
tarifas = ['2.0A','2.0DHA','2.0DHSA']
terminos = ['Dia','Hora','GEN','NOC','VHC','COFGEN','COFNOC','COFVHC','PMHGEN','PMHNOC','PMHVHC','SAHGEN','SAHNOC','SAHVHC','FOMGEN','FOMNOC','FOMVHC','FOSGEN','FOSNOC','FOSVHC','INTGEN','INTNOC','INTVHC','PCAPGEN','PCAPNOC','PCAPVHC','TEUGEN','TEUNOC','TEUVHC']
data_json = {}
data_json['datos_TOT'] = []
data_json['datos_TEU'] = []
data_json['fecha'] = fecha
for i in range(3):
data_json['datos_TOT'].append({})
data_json['datos_TEU'].append({})
data_json['datos_TOT'][i]['tarifa'] = tarifas[i]
data_json['datos_TEU'][i]['tarifa'] = tarifas[i]
for j in range(0,24):
data_json['datos_TEU'][i]['values'] = []
data_json['datos_TEU'][i]['values'].append({})
data_json['datos_TEU'][i]['values'][j]['periodo'] = "{0}-{1}".format(j,j+1)
return HttpResponse(json.dumps(data_json), content_type="application/json")
In fact it has one more depth level but as the second don´t work I didn´t put it here.
With this nested structure I expected a JSON object with (b-a) entries in the first level with (d-c) entries each one. But what I see is that the second loop only returns the last value! So if the "j" loop goes from 0 to 24 it will just return "23" and nothing more. Seems like it just works one "lap".
Is there any limit in nesting loops in the views? If there is, where could I place them? I´m trying to keep the models.py free from logic.
Your problem is that you reset data_json['datos_TEU'][i]['values'] to an empty list at the beginning of every iteration of the j loop, so it will only ever have one element. Move that line to before the nested loop.
Note that your code could be written much more Pythonically:
for tarifa in tarifas:
tot = {'tarifa': tarifa}
data_json['datos_TOT'].append(tot)
teu = {'tarifa': tarifa}
values = []
for j, termino in enumerate(terminos):
value = {'termino': termino, 'periodo': "{0}-{1}".format(j,j+1)}
values.append(value)
teu['values'] = values
data_json['datos_TEU'].append(teu)