I'm relatively new to web scraping so I'm not sure about which approach I should use to collect informations in a specific scenario in which the informations are stored on a map and displayed in popups, such as : https://utils.ocim.fr/cartocim2/
Basically :
the website shows a map,
contact informations are displayed in popups,
a popup will appear when clicking on a geo-tag button,
targeted informations are those lines stored in that popup
I was thinking of using selenium + xpath method but I'm unsure regarding the way to deal :
with this amount of buttons that have to be clicked on
with the popups.
Would you have any resources / tips to advise me to know where to start ?
With great difficulty
Here's a start but it gets a little more complicated as the markers start overlapping so clicking the elements fails, might need to add a step to zoom in etc
from selenium import webdriver
import requests
import pandas as pd
url_base = r'https://utils.ocim.fr/cartocim2/'
driver = webdriver.Chrome(r'C:\Users\username\Downloads\chromedriver_win32\chromedriver.exe')
driver.get(url_base) #open page
#find all the icons
links = driver.find_elements_by_css_selector('div.leaflet-pane.leaflet-marker-pane > img')
import time
output = [] #temp table to append into
for i in range(5): #chaneg to len(links) when done
links[i].click() #click on first icon
output.append(driver.find_elements_by_xpath('//*[#id="popup-header"]')[0].text) #get the text of the name
time.sleep(1) #sleep
driver.find_element_by_css_selector('#initmap').click() #reset the map - needed as without it the next icon might not be on the screen due to map relocation or popup overlap
time.sleep(1)
I'm writing a bot with Python/Selenium.
In my process, I want :
to right click on a picture
open it in a new chrome tab
I tried the following :
def OpenInNewTab(self):
content = self.browser.find_element_by_class_name('ABCD')
action = ActionChains(self.browser)
action.move_to_element(content).perform();
action.context_click().perform()
action.send_keys(Keys.DOWN).perform()
action.send_keys(Keys.ENTER).perform()
However, the problem is that my bot :
open the contextual menu
scroll down on the page and not on the contextual menu
After a lot of researches, I tried with :
import win32com.client as comclt
wsh = comclt.Dispatch("WScript.Shell")
wsh.SendKeys("{DOWN}")
wsh.SendKeys("{ENTER}")
However, it's not really working.
I saw many other topics, like this one (supposing there is href associated to the pic)
Then, i'm a little lost to be able to do tthis simple thing : open a righ click on contextual an element and select open in a new tab. I'm open to any advice / new road to follow.
In my experience it will be difficult to achieve a perfect "one fits all" solution involving the (context menu - new tab) combination, and I tend to keep clear of all the headache it can bring.
My strategy would be a bit different, and, on a case by case basis, I'd use something like:
base_window = driver.current_window_handle # this goes after you called driver.get(<url here>)
my_element=driver.find_element_by_xpath(...) #or whatever identification method
my_element.send_keys(Keys.CONTROL + Keys.ENTER)
driver.switch_to.window(driver.window_handles[1]) #switch to newly opened tab
driver.switch_to.window(base_window) # switch back to the initial tab
An alternative workaround is using hrefs - first open a new tab, then load the fetched href(s). Here's an example:
url='https://www.instagram.com/explore/tags/cars/?hl=en'
driver.get(url)
base_window = driver.current_window_handle
a_tags=driver.find_elements_by_xpath("//div[#class='v1Nh3 kIKUG _bz0w']//a")
hrefs=[a_tag.get_attribute('href') for a_tag in a_tags] #list of hrefs
driver.execute_script("window.open();") #open new tab
driver.switch_to.window(driver.window_handles[1]) #switch to new tab
driver.get(hrefs[0]) #get first href for example
driver.close() #close new tab
driver.switch_to.window(base_window) #back to initial tab
I'm currently using chrome(selenium) to automate something for me. For some reason I cannot get selenium to open up another webpage.
def gotoInventory():
#WebDriverWait(driver,5)
inventoryPS = driver.switch_to.window(driver.window_handles[1])
inventoryPS
openInventoryTab = driver.execute_script("window.open('https://sellercentral.amazon.com/inventoryplanning/dashboard','new window')")
openInventoryTab
def loginProton():
#Need to create a new tab to open proton mail
ActionChains(driver).key_down(Keys.CONTROL).send_keys('t').key_up(Keys.CONTROL).perform()
#above code did not work
#also tried browser.find_element_by_tag_name('body').send_keys(Keys.CONTROL + 't')
openProtonTab = driver.execute_script("window.open('https://mail.protonmail.com/login','new window')")
openProtonTab
For some reason selenium always opens the webpage on the inventory tab which is not what I want. protonMail has to be opened on its own tab and not on the inventory tab.
Any help would be greatly apperciated
The issue happens due to using the same window name in both cases which is 'new window'. You may try using different window names in inventory and proton cases. Also note that window.open creates a browser window.
I try to use selenium to mimic my action on a website to convert PDF files to EXCEL files. There are three steps to complete the conversion:
Upload the PDF file.
Input email address.
Click the 'convert' button.
I wrote the code as below. However, every time I click the button the page just refreshes without actually converting the file.
from selenium import webdriver
import time
driver = webdriver.Chrome()
driver.get("https://pdftoexcelonline.com/en/")
# Upload file
el_upload = driver.find_element_by_name("file")
el_upload.send_keys("/path/to/the/file")
# Input email
el_email = driver.find_element_by_name("email")
el_email.clear()
el_email.send_keys("<email address>")
# Convert button
el_button = driver.find_element_by_id("convert_now")
el_button.click()
time.sleep(10)
driver.close()
This page works well when I completed the steps manually. What is reason that my code did not trigger the conversion?
One possible reason is the not enough execution time. You can add some sleep after each action to verify. Treat it as workaround if work.
How to upload a picture on a web application with the selenium testing tool? I am using python.
I tried many things, but nothing worked.
What I'm doing is this (make sure drv is an instance of webdriver):
drv.find_element_by_id("IdOfInputTypeFile").send_keys(os.getcwd()+"/image.png")
and then find your submit button and click it.
A very easy way to control components like windows file selector (or just your OS in general) is by using pyautogui. You can install pyautogui through pip
import pyautogui
... # set the webdriver etc.
...
...
element_present = EC.presence_of_element_located((By.XPATH, "//button[#title='Open file selector']")) # Example xpath
WebDriverWait(self.driver, 10).until(element_present).click() # This opens the windows file selector
pyautogui.write('C:/path_to_file')
pyautogui.press('enter')
I am using fine-uploader, running selenium tests with pytest and this worked for me:
elm = driver.find_element_by_xpath("//input[#type='file']")
elm.send_keys(os.getcwd() + "/tests/sample_files/Figure1.tif")
No form submission or Enter key is needed in my case.
I added an answer for anyone looking to use deal with the annoying msofiledialogs. This is working off of saravanan's proposed solution, but more fleshed out for Python.
I had a similar problem with a script I'm working on for a company on the side. I'm attempting to upload documents for a company's clients, but due to the way their site worked, I could not utilize send_keys to directly send the path, so I had to rely on msofiledialog.
You only need to install AutoIt
https://pypi.python.org/pypi/PyAutoIt/0.3 or just "pip install -U pyautoit" through the cmd screen
type "import autoit" on your script page
Type the following before the file dialog pops up in your script:
autoit.win_active("Open")
autoit.control_send("Open","Edit1",r"C:\Users\uu\Desktop\TestUpload.txt")
autoit.control_send("Open","Edit1","{ENTER}")
It will look for the open file dialog window and fill it out and press enter.
"Open" is the title of my file dialog screen. Put the title of yours in place of "Open". There are more creative ways to utilize AutoIt's functions, but this is an easy, straightforward way for beginners.
Edit: DO NOT. DO NOT use control_send on most things if you can avoid it. It has a well-known issue of sending erroneous text. In my case, the colon in my file path was being turned into a semi colon. If you need to send input keys, it should be fine, however if you need to send text, use control_set_text. It has the same syntax.
autoit.control_set_text("Open","Edit1",r"C:\Users\uu\Desktop\TestUpload.txt")
All these approach wont work with modern image uploaders in olx !!!
Alternative approach (only for windows )
1. Automation of windows can be done using Autoit
2. Install Autoit and SciTe Script editor
3. Autoit code :(imageupload.au3)
WinActivate("File Upload"); for chrome use "open" that is the name of the window that pops
send("D:\images\image1.png"); path of the file
Send("{ENTER}")
4. compile it to get an .exe file(imageupload.exe)
5. Now from python call the .exe file like
import os
import os.system('C:\images\imageupload.exe') #path of the .exe file
Upload input control opens a native dialog (it is done by browser) so clicking on the control or browse button via Selenium will just pop the dialog and the test will hang.
The workaround is to set the value of the upload input via JavaScript (in Java it is done via JavascriptExecutor) and then submit the form.
See this question for sample in C#, I am sure there's also a way to call JavaScript in Python but I never used Selenium Python bindings
Here is the code that i used:
Imagepath = "C:\User\Desktop\image.png"
driver.find_element_by_xpath('//html/body/input').send_keys(Imagepath)
driver.find_element_by_xpath('//html/body/button').click()
I accept the Answer by karloskar. Note It is not working for FireFox (59). And it is works with Chrome Driver only.
import win32com.client
shell = win32com.client.Dispatch("WScript.Shell")
shell.Sendkeys("C:\text.txt")
shell.Sendkeys("~")
Will resolve the issue
You can easily add this one line of code to solve the problem:
driver.find_element_by_xpath("your fullpath").send_keys("C://1.png(your file root")
But pay attention, sometimes maybe you put a wrong xpath in first field. follow below steps for reach to rightful xpath:
open the inspect and click exactly on the box which you want to
upload the file.
right click on the html code and select xpath full address from copy
sub menu.
paste the root in xpath field in the code.
full code to achieve file upload using autoit tool.
u can just copy paste this and u can run, it will work since it is a acti-time demo.
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as ec
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
import time
import os
def fileUploading():
driver = webdriver.Firefox()
driver.implicitly_wait(20)
wait = WebDriverWait(driver, 10)
driver.get("https://demo.actitime.com/login.do");
driver.find_element(By.ID,"username").send_keys("admin")
driver.find_element(By.NAME, "pwd").send_keys("manager")
driver.find_element(By.XPATH, "//div[.='Login ']").click()
wait.until(ec.element_to_be_clickable((By.XPATH, "(//div[#class='popup_menu_icon'])[3]")))
driver.find_element(By.XPATH, "(//div[#class='popup_menu_icon'])[3]").click()
wait.until(ec.element_to_be_clickable((By.XPATH, "//a[contains(text(),'Contact actiTIME Support')]")))
driver.find_element(By.XPATH, "//a[contains(text(),'Contact actiTIME Support')]").click()
wait.until(ec.element_to_be_clickable((By.XPATH,"//div[#class='dz-default dz-message']")))
driver.find_element(By.XPATH,"//div[#class='dz-default dz-message']").click()
os.system("C:\\Users\\mallikar\\Desktop\\screenUpload.exe")
time.sleep(2000)
fileUploading()
below is the content of autoit code:
WinWaitActive("File Upload")
Send("D:\SoftwareTestingMaterial\UploadFile.txt")
Send("{ENTER}")
download autoIt and autoIt SCITE editor tool.
once done install autoit and the open the scite editor and paste the above code and save it with .au3 extension and once saved, right click on the file and select complile script(x64), now .exe file is created.
now use the below code:
os.system("C:\\Users\\mallikar\\Desktop\\screenUpload.exe")
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
driver = webdriver.Firefox()
driver.get("http://www.example.org")
def upload_file():
upload_file = driver.find_element_by_id("paste here id of file which
is
enter code here`shown in html code...")
upload_file.send_keys("copy the path of file from your pc with name and
paste here...")
if toast message is disappeared within seconds you can use Chropath extension in chrome to find its xpath
This is a pure python code.
Instead of using control_send, use control_set_text to resolve inconsistencies present in the string sent to the window. See this link for reference: https://www.autoitscript.com/forum/topic/85929-incorrect-string-being-sent-via-controlsend/
import autoit
autoit.win_wait_active("Open")
autoit.control_set_text("Open", "Edit1", imgPath)
autoit.send("{ENTER}")
Use PyAutoGui if sendkeys function is not working on buttons.
sample code:
import pyautogui
driver.find_element_by_xpath("Enter Xpath of File upload button").click()
time.sleep(4) #waiting for window popup to open
pyautogui.write(r"C:\Users\AmarKumar\FilesForUploading\image.jpg") #path of File
pyautogui.press('enter')
I have used below script format to upload the images. This may help you.
Imagepath=os.path.abspath('.\\folder1\\subfolder2\file1.jpg')
driver.find_element_by_id("Id of the element").clear()
driver.find_element_by_id("Id of the element").send_keys(Imagepath)
if you do not have ID of the object ,then you can use xpath or css selector accordingly.
Using splinter :
browser.attach_file('file_chooser_id',fully_qualified_file_path)
If you are using service you will get an exception
service = Service('driver_path')
service.start()
driver = webdriver.Remote(service.service_url)
choose_image = driver.find_element(By.ID, 'id')
choose_image.send_keys(os.getcwd()+'/image.jpg')
Exception :
selenium.common.exceptions.WebDriverException: Message: unknown command: unknown command: session/$sessionId/se/file
Working code (suggestion - use id of the element instead of other)
driver=webdriver.Chrome(executable_path=driver_path)
choose_image=driver.find_element(By.ID, 'id')
choose_image.send_keys(os.path.join(os.getcwd(), 'image.jpg'))
In case you want to upload multiple pictures, you can alter the single image answer as follows:
images = ["/path/to/image1.png", "/path/to/image2.png","/path/to/image3.png"]
drv.find_element_by_id("IdOfInputTypeFile").send_keys("\n".join(images))
Note that the input form should have the multiple attribute set to True.
I post a solution that i consider best. it is a modification on solution by #sherlock (see my comment on that post)
import autoit
autoit.win_wait_active("Open")
autoit.control_set_text("Open", "Edit1", imgPath)
autoit.control_click("Open", "Button1")
Install these three
sudo apt-get install python3-tk python3-dev
pip install tk
pip install PyAutoGUI
use these two line of code.
pyautogui.write('/home/image.jpg')
pyautogui.press('enter')