If I had a print() statement, for example:
print('https://www.google.com')
Is there a way to make a link clickable? And would the same apply for a file path, like this:
print('path/to/file')
What I need is a way to print a link/path to a terminal and then to be able to open it by clicking on it. Is this possible? If yes, how?
Python itself has nothing to do with this behavior- its functionality provided by your terminal emulator.
However, you can open a link programmatically in the browser within python using the builtin webbrowser module, for instance:
from webbrowser import open_new_tab
open_new_tab("https://www.google.com")
In some scenarios, this may be sufficient.
Related
So, with python i've seen that you can open a website using the code
import webbrowser
webbrowser.open("http://www.example.com", new=2)
but i really want to know how you could close the same specific tab using python.
If you can help please do. Thank you.
webbrowser module has no methods to close browser's tabs
I don't think you can. You might wanna try Selenium though.
How to open and close a website using default browser with python
I'm wondering if it is possible to use Selenium to write to the Chrome console with python. I do not mean by using send_keys to press F12 and open the console then send more keys to write. If this isn't possible, are they any libraries or APIs that would let me do this? Thanks!
You can look at the problem with another view, try to use browser.execute_script and pass console.log("whatever you want to write in the console") , this will print that sentence in the console
You can of course change it to your own needs but you get the idea
I wanted to make a python 3 program that types something in another window, such as Google Chrome.
Is this possible, and if so, how?
This question is a little open ended, but it sounds like you want an http server. You can use either SimpleHTTPServer or make your own from scratch. A basic HelloWorld for using python3's http module is here. I used this simple guide to help me understand the basics of web servers in python. Hope this helps!
import pyautogui
searchbar = (x, y)
text_or_url = "hello word!"
pyautogui.click(searchbar)
pyautogui.typewrite(text_or_url)
pyautogui.typewrite([Enter])
Use pywinauto lib
It is very easy.
For example you have opened notepad window and opened 'Save as' dialog and want to type filename:
from pywinauto import application
app = application.Application()
app.connect(title='test1.txt - Notepad')
app.SaveAs.Edit1.type_keys("C:\\test2.txt")
Use pywinauto lib
filePath.set_text('D:\\aa.txt')
inpuMsg.type_keys('D:\\aa.txt')
set_text
type_keys
So my App needs to be able to open a single webpage(and it must be from the internet and not saved) in it, and specifically I'd like to use the Tkinter GUI toolkit since it's the one i'm most comfortable with. On top of that though, I'd like to be able to generate events in the window(say a mouse click) but without actually using the mouse. What's a good method to go about this?
EDIT: I suppose to clarify this a bit, I need a way to load a webpage, or maybe even a specific java applet into a tkinter widget or window. Or if not that perhaps another method to do this where I can generate mouse and keyboard events without using either the mouse of the keyboard.
If you want it to be opened inside your GUI use Bryans suggestion, if you just want to open a webpage you can use:
import webbrowser
webbrowser.open("page.html")
Tkinter does not have a widget that can render a web page.
So i found this module named pywebview
pip install pywebview
sample code:-
import webview
webview.create_window('duckduckgo', 'https://www.duckduckgo.com')
webview.start() #this will open the webpage in a new window
You should use pywebview it is very easy only code three lines .
I used it but in my case it didn't work everywhere. Comment and let me know if it works for you.
The best option that works everywhere is PyQt's QtWebview module. You might run into one problem that is to rename the window, so here is the solution
web.setWindowTitle(title)
You can use all the functions as it is but just replace window or self with web like the above code.
I am relatively new to the mac world. My question concerns opening an application using python on mac osx. From what I've found so far, it seems as if applications are stored in app format that are actually directories. Are these parsed somehow by the OS when opening the app? I would like to open Safari using python and it is in my /Applications/Safari.app directory. Is there a specific binary I should be passing to os.system or should I be going about it in a completely different way? My end goal is to have safari open a local html file, close it then open another local html file.
Thanks,
-John
The Python standard library includes the webbrowser module which allows you to open a new browser window or tab in a platform-independent way. It does support Safari on OS X if it is the user's default:
>>> import webbrowser
>>> webbrowser.open("http://stackoverflow.com")
But webbrowser does not support closing a browser window. For that level of control, you are best off using Safari's Apple Event scripting interface by installing py-appscript.
>>> from appscript import *
>>> safari = app("Safari")
>>> safari.make(new=k.document,with_properties={k.URL:"http://stackoverflow.com"})
>>> safari.windows.first.current_tab.close()
If you just want to change the web page displayed in the tab you opened:
>>> safari.windows.first.current_tab.URL.set("http://www.google.com")
>>> safari.windows.first.current_tab.URL.set("http://www.python.com")
Safari's Apple Events interface is somewhat non-intuitive (unfortunately, that's not unusual with Mac applications). There are references out there if you need to do more complex stuff. But Python and py-appscript give you a solid base to work from.
os.system("open -a /Applications/Safari.app http://www.google.com")
for this to work when safari is not the default add -a after open.
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This works for me:
os.system("open /Applications/Safari.app http://www.google.com")