I have recently built a password generator but wanted to include an aspect where if the user types in a letter instead of a number when defining the length of the password and number of passwords then the output would be to loop back in. If not the password generator would continue if numbers were inputted.
This is my code so far:
import random
char = "abcdefghijklmnopqrstuvwkyzABCDEFGHIJKLMNOPQRSTUVWXYZ123456789!#£$%^&*"
while True:
password_length = input("how long do you want your password? ")
password_count = input("how many passwords do you want? ")
if password_length and password_count != type(int):
print("Please can you enter a number")
elif password_length and password_count == type(int):
for x in range(0,int(password_count)):
password = ""
for y in range(0,int(password_length)):
random_letters = random.choice(char)
password += random_letters
print(password)
Try this:
while True:
try:
password_length = int(input("how long do you want your password? "))
except:
print("Invalid input")
else:
break
while True:
try:
password_count = int(input("how many passwords do you want? "))
except:
print("Invalid input")
else:
break
And then you can go on with the rest of your code
Python offers a better way to check if a string is a digit or not.
From w3:
The isdigit() method returns True if all the characters are digits, otherwise False.
import random
char = "abcdefghijklmnopqrstuvwkyzABCDEFGHIJKLMNOPQRSTUVWXYZ123456789!#£$%^&*"
while True:
password_length = input("how long do you want your password? ")
password_count = input("how many passwords do you want? ")
if password_count.isdigit() and password_length.isdigit():
password_int = int(password_count)
password = ""
for x in range(0,password_int):
for y in range(0,int(password_length)):
random_letters = random.choice(char)
password += random_letters
print(password)
else:
print("Please enter a valid input in numbers")
Output:
how long do you want your password? 8
how many passwords do you want? 1
ABZEG66j
Related
I am trying to create a login and register program in simple console python, however when trying to make a loop that will check if the username contains a digit I keep getting the error, ("UnboundLocalError: local variable 'includesDigit' referenced before assignment") the code is:
def register():
incluesDigit = False
print("")
print("Create Account")
print("~~~~~~~~~~~~~~")
print("Username: ")
registerUsername = input("")
for char in registerUsername:
if char.isdigit():
includesDigit = True
if includesDigit == True:
print("Please enter a username that does not contain a number")
register()
print("Password: ")
registerPassword = input("")
if len(registerPassword) < 5:
print("Please enter a password that is atleast 5 characters")
register()
if len(registerPassword) > 15:
print("Please enter a password that is less than or fifteen character")
logCreate = open("C:\\Desktop\\Login Program\\Accounts\\" + registerUsername + ".txt", "w")
logCreate.write(registerPassword)
logCreate.close()
login()
There is a typo in line 2.
incluesDigit = False
Should be
includesDigit = False
I going through a python course and am stuck at trying to use a while loop properly in my code
My code is supposed to check a password if it has min length =6 and max length =14, it will also check if the password only has numbers or letters. If it has a combination of both its supposed to print "strong password" if it only has numbers or letters it will print "weak password".
MIN_PASSWORD_LENGTH = 6
MAX_PASSWORD_LENGTH = 14
while password_length >= MIN_PASSWORD_LENGTH or password_length <= MAX_PASSWORD_LENGTH:
password_length = len(password)
password = input("Enter your password: ")
if password.isalpha():
print("Your password is weak!")
elif password.isnumeric():
print("Your password is weak!")
else:
print("Your password is strong!")
print("Number of characters used in password: ", password_length,"the min length expected is: ",MIN_PASSWORD_LENGTH,
"the max length is: ", MAX_PASSWORD_LENGTH)
When I run my code, it comes with error message: 'name password_length is not defined'. I am not sure what to do? Is my code even correct? Am I supposed to put the password_length outside the while loop?
You have, more or less, the right idea. It's just that you need to assign a value to password_length outside your loop.
Think about this: when your code is run, the interpreter hits the while loop and attempts to make a comparison involving password_length. However, at that point password_length doesn't exist yet, since the first time it gets a value is inside the loop. Therefore, you should initialise it to a sensible value, such as 0, before entering the loop.
Two supplementary points:
You're calculating the password length of the previous password, so if you enter a too-short/long password and then an acceptable one, the length printed will be of the unacceptable one.
In general, prefer f-strings or str.format calls to string concatenation, so, for your print, this might be better:
print(f'Number of characters used in password: {password_length}; '
'the min length expected is {MIN_PASSWORD_LENGTH} and the '
'max length expected is {MAX_PASSWORD_LENGTH}.')
Immediately before the while loop, initialize with something like "password_length = MAX_PASSWORD_LENGTH" or else the while loop cannot start. The first line inside the while loop is "password_length = len(password)", which will set the value of password_length correctly, but the while loop needs something to start with so that you can reach that point.
The problem is your calling password before the code knows what it is.
MIN_PASSWORD_LENGTH = 6
MAX_PASSWORD_LENGTH = 14
# password must be defined before you use it.
password = input("Enter your password: ")
while password_length >= MIN_PASSWORD_LENGTH or password_length <= MAX_PASSWORD_LENGTH:
password_length = len(password)
if password.isalpha():
print("Your password is weak!")
elif password.isnumeric():
print("Your password is weak!")
else:
print("Your password is strong!")
print("Number of characters used in password: ", password_length,"the min length expected is: ",MIN_PASSWORD_LENGTH,
"the max length is: ", MAX_PASSWORD_LENGTH)
You're using password and password_length variables before they are defined.
Also you can use function and rewrite it more structured:
MIN_PASSWORD_LENGTH = 6
MAX_PASSWORD_LENGTH = 14
def checkPass():
password = input("Enter your password: ")
password_length = len(password)
if password.isalpha():
print("Your password is weak!")
elif password.isnumeric():
print("Your password is weak!")
else:
print("Your password is strong!")
return password_length >= MIN_PASSWORD_LENGTH or password_length <= MAX_PASSWORD_LENGTH
while checkPass():
continue
print("Number of characters used in password: ", password_length,"the min length expected is: ",MIN_PASSWORD_LENGTH, "the max length is: ", MAX_PASSWORD_LENGTH)
Online demo
Here is a version based on what I understood
MIN_PASSWORD_LENGTH = 6
MAX_PASSWORD_LENGTH = 14
password = ""
atLeast1Apha = False
atLeast1Numeric = False
while True:
password = input("Enter your password: ")
if len(password) > MAX_PASSWORD_LENGTH or len(password) < MIN_PASSWORD_LENGTH:
print("Password could be between %s and %s long" %(MIN_PASSWORD_LENGTH, MAX_PASSWORD_LENGTH))
continue
for char in password:
if char.isalpha():
atLeast1Apha = True
if char.isdigit():
atLeast1Numeric = True
break
if atLeast1Apha and atLeast1Numeric:
print("Your password is strong!")
else:
print("Your password is weak!")
Conditions in the while loop are wrong. You may try:
MIN_PASSWORD_LENGTH = 6
MAX_PASSWORD_LENGTH = 14
password = input("Enter your password: ")
password_length = len(password)
while password_length < MIN_PASSWORD_LENGTH or password_length > MAX_PASSWORD_LENGTH:
print("Password length", password_length, "incorrect. Required between", MIN_PASSWORD_LENGTH, "and", MAX_PASSWORD_LENGTH)
password = input("Enter your password again: ")
password_length = len(password)
if password.isalpha() or password.isnumeric():
print("Your password is weak!")
else:
print("Your password is strong!")
print("Number of characters used in password:", password_length,". The min length expected is:",MIN_PASSWORD_LENGTH, ". The max length is: ", MAX_PASSWORD_LENGTH)
I am trying to create a user login system program. I am trying to make sure the password must have at least 10 characters which I have done, but I'm having trouble making sure it has at least two numbers and only underscore as a special character. I have seen some solutions about numbers and I don't get them and they rarely have at least 2 digits.
Here is my code:
print("Welcome ")
print('')
print('New users should enter Sign to create an account')
print('')
print('')
username = input('Enter your Username: ')
if username == 'Sign':
while True:
usernames = ['Dave','Alice','Chloe']#A list that stores usernames
create_user = input('Enter your new username: ')
if create_user in usernames:
print('This user name has been taken .Try again')
continue
else:
break
usernames.append([create_user])
while True:
create_pass = input('Enter your your user password: ')
passwords = []#A list thst stores password
pass_len = len(create_pass)
if pass_len < 10:
print('Your password must be at least 10. Try again')
continue
else:
print('')
print('You are now a verified user.')
print('Run the application again to re-login.')
print('Thank You')
break
else:
password = input('Enter your password')
print('Visit www.bitly/p8?. to continue')
If you're not wanting to use regex, you could add some simple logic like this:
num_count = 0
for character in create_pass:
if character.isdigit():
num_count += 1
if num_count < 2:
print('You must have at least 2 numbers in your password')
This is how I'd do it. You can check for the underscore with in and use regex to search for the numbers.
import re
test = 'hisod2f_1'
underscore = '_' in test
twonums = len(re.findall(r'\d', test)) >= 2
if underscore and twonums:
# your logic
The program, which assesses password strength, initially checks whether the length of the password is correct (6-12) and whether the password contains extented ASCII characters, i.e. 127-255.
The problem I have is that if the user first inputs a password which is too short or too long, the program then doesn't check for extended characters in the next password, inputted by the user and vice-versa, with checking for extended characters first.
I implemented a double while loop, if that's the correct way of calling it, however it still didn't bring the desired effect.
import re
import time
#score variable, responsible for later defining if passwords is weak, medium or strong
Score = 0
#list for improvements to password printed out with score at the end
Improvements = []
Password = ""
#defines function for checking for presence of extended characters (i.e. ascii 128-255)
def hasExtended(s):
return any(ord(i) > 127 for i in s)
#inputs password
Password = input("Please enter a password:")
Password_length = len(Password)
Extended_presence = hasExtended(Password)
#checks password length (6-12), asks user to re-input until password is within boundaries
#checks if password contains extended characters
#double while loops to allow for two conditions simultaneously
while Password_length < 6 or Password_length > 12:
if Password_length < 6:
Outputted_length = "too short"
Outputted_criteria = "no shorter than 6 characters"
else:
Outputted_length = "too long"
Outputted_criteria = "no longer than 12 characters"
print("Your password is", Outputted_length, ". It has to be", Outputted_criteria, ".")
Password = input("Please enter a password:")
Password_length = len(Password)
while Extended_presence:
print("Your password contains characters from the extended ASCII list. Please don't use these.")
Password = input("Please enter a password:")
Extended_presence = hasExtended(Password)
while Extended_presence:
print("Your password contains characters from the extended ASCII list. Please don't use these.")
Password = input("Please enter a password:")
Extended_presence = hasExtended(Password)
while Password_length < 6 or Password_length > 12:
if Password_length < 6:
Outputted_length = "too short"
Outputted_criteria = "no shorter than 6 characters"
else:
Outputted_length = "too long"
Outputted_criteria = "no longer than 12 characters"
print("Your password is", Outputted_length, ". It has to be", Outputted_criteria, ".")
Password = input("Please enter a password:")
Password_length = len(Password)
else:
#defines function for checking for presence of numbers
def hasNumbers(s):
return any(i.isdigit() for i in s)
#defines function for checking for presence of letters
def hasLetters(s):
return any(i.isalpha() for i in s)
#defines function for checking for presence of special characters
def hasSpecial(s):
return any(ord(i) < 48 for i in s)
#checks if password contains letters
Letter_presence = hasLetters(Password)
if not Letter_presence:
Score = Score - 1
Improvements.append("letters")
else:
Score = Score + 1
#checks if password is all upper case
Is_upper = Password.isupper()
if not Is_upper:
Score = Score + 1
else:
Score = Score - 1
Improvements.append("upper and lower case letters")
#checks if passwords is all lower case
Is_lower = Password.islower()
if not Is_lower:
Score = Score + 1
else:
Score = Score - 1
Improvements.append("upper and lower case letters")
#checks if password contains a number
Number_presence = hasNumbers(Password)
if not Number_presence:
Score = Score + 0
Improvements.append("numbers")
else:
Score = Score + 1
#checks if password is just numbers
Only_numbers = Password.isdigit()
if not Only_numbers:
Score = Score + 0
else:
Score = Score - 1
Improvements.append("other characters")
#checks if password contains special characters
Special_presence = hasSpecial(Password)
if not Special_presence:
Score = Score + 0
Improvements.append("special characters, such as '$'")
else:
Score = Score + 1
#outputs weak, medium or strong password to user and suggest improvements
if Score <= 2:
print("The program is processing your password...")
time.sleep(2)
print("Your password isn't acceptable! Please try again.")
print("Next time, remember to include", Improvements)
if Score == 3:
print("The program is processing your password...")
time.sleep(2)
print("Your password is weak, you should try again.")
print("Next time, remember to include", Improvements)
elif Score == 4:
print("The program is processing your password...")
time.sleep(2)
print("Your password is medium, it should be OK.")
print("Next time, remember to include", Improvements)
elif Score == 5:
print("The program is processing your password...")
time.sleep(2)
print("Your password is strong, it is absolutely fine.")
I would suggest you to write validator, a function that looks like this:
def validate_password(password):
... # check score, symbols and other, print whatever you want
return score
And then call it in a way like that one:
pass = input('Enter your password')
score = validate_password(pass)
while score <= 3:
pass = input('Enter another password')
score = validate_password(pass)
You can implement such scenario like below:
check_pass function will check for length of function
def hasExtended(s):
return any(ord(i) > 127 for i in s)
check_pass = lambda x: x>=6 and x<=12 # check for range of input value
password=input("Password: ")
if check_pass(len(password)) and not hasExtended(password):
print("Valid password")
else:
print("Do not use extended ascii characters, use password with minimum length of 6 and maximum length of 12")
to be more precise about error you can use nesting in below way:
if check_pass(len(password)) and not hasExtended(password):
print("Valid password")
elif check_pass(len(password)) and hasExtended(password):
print("do not use extended ascii character")
elif not check_pass(len(password)) and hasExtended(password):
print("password length should be between 6 to 12")
similarly if you want to check for invalid length of minimum lenght and maximum length separately.
If you wish to check all condition separately and then show success or failure you can do like below:
def verify_password(password):
if len(password) < 6:
print("require minimum 6 characters")
if len(password) > 12:
print("can not use more then 12 characters")
if hasExtended(password):
print("use only valid ascii characters")
else:
print("valid password")
return True
while not verify_password(password): # loop will never stops unless valid password or used break statement within
password = input("Password: ")
The function will check for three different condition if condition satisfied message will be printed else it will continue executing, at the end if it is valid password instead of printing anything it will print valid password and return True instead of None.
Try this code , and instead of while just use if in first checking codition of Extended_presence , You don't need while there because its already in the scope of previous while loop :
import re
print([chr(i) for i in range(127,200)])
import re
import time
#score variable, responsible for later defining if passwords is weak, medium or strong
Score = 0
#list for improvements to password printed out with score at the end
Improvements = []
Password = ""
#defines function for checking for presence of extended characters (i.e. ascii 128-255)
def hasExtended(s):
return any(ord(i) > 127 for i in s)
#inputs password
Password = input("Please enter a password:")
Password_length = len(Password)
Extended_presence = hasExtended(Password)
#checks password length (6-12), asks user to re-input until password is within boundaries
#checks if password contains extended characters
#double while loops to allow for two conditions simultaneously
while Password_length < 6 or Password_length > 12:
if Password_length < 6:
Outputted_length = "too short"
Outputted_criteria = "no shorter than 6 characters"
else:
Outputted_length = "too long"
Outputted_criteria = "no longer than 12 characters"
print("Your password is", Outputted_length, ". It has to be", Outputted_criteria, ".")
Password = input("Please enter a password:")
Password_length = len(Password)
if Extended_presence:
print("Your password contains characters from the extended ASCII list. Please don't use these.")
Password = input("Please enter a password:")
Extended_presence = hasExtended(Password)
while Extended_presence:
print("Your password contains characters from the extended ASCII list. Please don't use these.")
Password = input("Please enter a password:")
Extended_presence = hasExtended(Password)
output:
Please enter a password:hel¢
Your password is too short . It has to be no shorter than 6 characters .
Please enter a password:hello¢
Your password contains characters from the extended ASCII list. Please don't use these.
Please enter a password:hello¢
Your password contains characters from the extended ASCII list. Please don't use these.
Please enter a password:hellllo#
Why don't you delegate your password check to a function and separate the user input from checking the password? That way you can ask the user as many times as you want without complex jumps. Something like:
def validate_password(password):
if len(password) < 6:
return 0, "Your password is too short, it has to be no shorter than 6 characters."
elif len(password) > 12: # why, tho?
return 0, "Your password is too long, it has to be no longer than 12 characters."
# these can be optimized but I'll leave that as an exercise for you
if any(ord(i) > 127 for i in password): # again, why?!
return 0, ("Your password contains characters from the extended ASCII list. "
"Please don't use these.")
score = 0
improvements = []
if any(i.isalpha() for i in password):
score += 1
if password.isupper() or password.islower():
score -= 1
improvements.append("upper and lower case letters")
else:
score += 1
else:
score -= 1
improvements.append("letters")
if any(i.isdigit() for i in password):
score += 1
if password.isdigit():
score -= 1
improvements.append("other characters")
else:
# score -= 1 # are you sure you don't want to reduce the score?
improvements.append("numbers")
if any(ord(i) < 48 for i in password):
score += 1
else:
# score -= 1 # are you sure you don't want to reduce the score?
improvements.append("special characters such as '$'")
return score, "Next time remember to include: {}".format(", ".join(improvements))
And now you can call it from wherever you want, as many times as you need:
while True:
candidate = input("Please enter a password: ")
print("The program is processing your password...") # why? this happens in an instant
score, message = validate_password(candidate)
time.sleep(2) # why are we making people wait for no reason?
if score <= 1:
print(message)
print("Please try again.")
elif score == 2:
print("Your password is weak, you should try again.")
print(message)
elif score == 3:
print("Your password is medium, it should be OK.")
print(message)
break
elif score == 4:
print("Your password is strong, it is absolutely fine.")
break
print("Accepted password: " + candidate)
And you can get an output as:
Please enter a password: dfld
The program is processing your password...
Your password is too short, it has to be no shorter than 6 characters.
Please try again.
Please enter a password: dfldsadlslads
The program is processing your password...
Your password is too long, it has to be no longer than 12 characters.
Please try again.
Please enter a password: dflds°
The program is processing your password...
Your password contains characters from the extended ASCII list. Please don't use these.
Please try again.
Please enter a password: ddlllsd
The program is processing your password...
Next time remember to include: upper and lower case letters, numbers, special characters
such as '$'
Please try again.
Please enter a password: ddlllsd12
The program is processing your password...
Next time remember to include: upper and lower case letters, special characters such as '$'
Please try again.
Please enter a password: Ddlllsd12
The program is processing your password...
Your password is medium, it should be OK.
Next time remember to include: special characters such as '$'
Accepted password: Ddlllsd12
In the programme the user must enter a password, if he gets it wrong the programme will prompt him 2 more times and if he does not get right those 2 times the programme will expire. How do I go about doing this. This is my programme so far...
password=input("Enter password:")
while password != 'cat':
print ("password is wrong, try it again")
password= input ("Enter your password:")
print ("Password correct be happy")
The charitable programmer
for trial in range(3):
print ("Attempt no.",trial, end=" ")
passw = input('. Enter password > ')
if passw == 'cat' : break
else:
passw = 'cat'
Yes, also the humble for loop has an else clause: "Loop statements may have an else clause; it is executed when the loop terminates through exhaustion of the list (with for) or when the condition becomes false (with while), but not when the loop is terminated by a break statement.".
try this:
import sys
max_tries = 3; current_tries = 0
password=input("Enter password:")
while password != 'cat':
if current_tries > max_tries:
print "too many tries"
sys.exit(0)
print ("password is wrong, try it again")
password= input ("Enter your password:")
current_tries +=1
print ("Password correct be happy")
max_tries = 3
password = None
for i in range(max_tries):
password = input("Enter Password:")
if password == "cat": break
if password != "cat":
print ("ERROR TOO MANY TRIES!")
else:
print ("You Win!")
is a simple way to do it ...