I have an empty dataframe that I've loaded into my code. If the user says a keyword, it'll append their value to a specific column in the dataframe. However, whenever the user says the keyword, it's not appending it. This is my code:
c3 = pd.read_csv('c3_homework.csv')
homework = input("")
homework = homework.lower().split()
grade_class = homework[0]
subject = homework[1]
work = homework[2:]
work = ' '.join(work)
print(grade_class)
if grade_class == 'c3':
if subject == 'math':
print(work)
c3 = c3.append({'math':work}, ignore_index=True)
Do you have to make an empty csv?
You can create an empty data frame and save it as a csv file.
below is my suggestion code:
df = pd.DataFrame()
homework = input("")
homework = homework.lower().split()
grade_class = homework[0]
subject = homework[1]
work = homework[2:]
work = ' '.join(work)
print(grade_class)
if grade_class == 'c3':
if subject == 'math':
print(work)
df = df.append({'math':work}, ignore_index=True)
df.to_csv('c3_homework.csv')
Related
I'm having some doubts with the following function. I want it to show me the result in a single excel tab but I can't.
def create_df_from_table(c,tab, excelWriter):
list_name = str(c)+"_result_list"
list_name = []
for i,each_row in enumerate(each_tab.rows):
text = (each_cell.text for each_cell in each_row.cells)
if i == -1:
keys = tuple(text)
else:
each_dict_val = tuple(text)
list_name.append(each_dict_val)
list_name_copy = list_name.copy()
result_df = pd.DataFrame(list_name)
print(result_df)
result_df.to_excel(excelWriter, sheet_name=str(c))
return result_df
excelWriter = pd.ExcelWriter('tablasFromDocx1.xlsx')
for c, each_tab in enumerate(file.tables):
globals()[f'result_df_{c}'] = create_df_from_table(c,each_tab, excelWriter)
excelWriter.save()
The code above in line 14 (result_df.to_excel() ) passes the dataframe to excel but in more than one tab and I need only all the data in one
I am trying to update a rating row by row. I have one dataframe of players, that all start with the same rating. For each match, I want the rating to change. Another dataframe contains results of each match.
import pandas as pd
gamesdata = [['paul','tom'],['paul','lisa'],['tom','paul'],['lisa','tom'],['paul','lisa'],['lisa','tom'],['paul','tom']]
games = pd.DataFrame(gamesdata, columns = ['Winner', 'Looser'])
playersdata= ['lisa','paul','tom']
players = pd.DataFrame(playersdata, columns = ['Name'])
mean_elo = 1000
elo_width = 400
k_factor = 64
players['elo'] = mean_elo
def update_elo(winner_elo, loser_elo):
expected_win = expected_result(winner_elo, loser_elo)
change_in_elo = k_factor * (1-expected_win)
winner_elo += change_in_elo
loser_elo -= change_in_elo
return winner_elo, loser_elo
def expected_result(elo_a, elo_b):
expect_a = 1.0/(1+10**((elo_b - elo_a)/elo_width))
return expect_a
for index, row in games.iterrows():
winnername = row['Winner']
losername = row['Looser']
web = players['elo'].loc[players['Name'] == winnername].values[0]
wIndex = players.loc[players['Name'] == winnername]
#I want to return just the index, so I can update the value
print(wIndex)
leb = players['elo'].loc[players['Name'] == losername].values[0]
print('Winner Elo before: ' + str(web))
winner_elo, looser_elo = update_elo(web, leb)
print('Winner Elo after: ' + str(winner_elo))
#here I want to update value
#players.at[wIndex,'elo']=winner_elo
I am trying to update the value in the players table using
players.at[wIndex,'elo']=winner_elo
but i struggle to get the index with this code:
wIndex = players.loc[players['Name'] == winnername]
Found a sollution:
wIndex = players.loc[players['Name'] == winnername].index.values
Can't believe i missed that
I have a Pandas dataframe, numeric_df, with a bunch of columns. I have this function:
def textstat_stats(text):
difficulty = textstat.flesch_reading_ease(text)
grade_difficulty = textstat.flesch_kincaid_grade(text)
gfog = textstat.gunning_fog(text)
smog = textstat.smog_index(text)
ari = textstat.automated_readability_index(text)
cli = textstat.coleman_liau_index(text)
lwf = textstat.linsear_write_formula(text)
dcrs = textstat.dale_chall_readability_score(text)
return pd.Series([difficulty, grade_difficulty, gfog, smog, ari, cli, lwf, dcrs])
which returns a Pandas Series. Now I'm trying this:
numeric_df[['difficulty', 'grade_difficulty','gfog','smog','ari','cli','lwf','dcrs']] = textstat_stats(text)
However, I get this Error:
KeyError: "['difficulty' 'grade_difficulty' 'gfog' 'smog' 'ari' 'cli' 'lwf' 'dcrs'] not in index"
What am I doing incorrectly?
Thanks!
It seems you need add index to Series which create columns names:
def textstat_stats(text):
difficulty = textstat.flesch_reading_ease(text)
grade_difficulty = textstat.flesch_kincaid_grade(text)
gfog = textstat.gunning_fog(text)
smog = textstat.smog_index(text)
ari = textstat.automated_readability_index(text)
cli = textstat.coleman_liau_index(text)
lwf = textstat.linsear_write_formula(text)
dcrs = textstat.dale_chall_readability_score(text)
idx = ['difficulty', 'grade_difficulty','gfog','smog','ari','cli','lwf','dcrs']
return pd.Series([difficulty, grade_difficulty, gfog, smog, ari, cli, lwf, dcrs],
index=idx)
df = textstat_stats(text)
print (df)
I got "Pandas ValueError Arrays Must be All Same Length"
Before I start, I checked answers to similar problems and folks suggest to use something like:
DataFrame(dict([ (k,Series(v)) for k,v in d.iteritems() ]))
if you have only two values in dictionary or,
a = {'Links' : lines ,'Titles' : titles , 'Singers': finalsingers , 'Albums':finalalbums , 'Years' : years}
df = pd.DataFrame.from_dict(a, orient='index')
df.transpose()
But neither of them worked for me. What my code does is, goes to file in directory, captures the name and last_modified time, opens the file and use it in function called phash and returns a value. I think there could be a problem with phash function, maybe sometimes it returns a null value.
So in my case data is something like this:
raw_data = {}
hash_11 = []
time_1 = []
file_name_1 = []
for file in date_file_list:
try:
#print(file[1])
y = file[1]
file_name = os.path.basename(y) # extract just the filename or #file_name = os.path.split(file[1])
file_name = file_name.split('_-_')[0]
file_name_1.append(file_name)
#print(file_name)
# convert date tuple to MM/DD/YYYY HH:MM:SS format
#file_date = time.strftime("%m/%d/%y %H:%M:%S", file[0])
time = file[0]
time_1.append(time)
img = Image.open(str(file[1]))
hash_1 = imagehash.dhash(img)
hash_11.append(hash_1)
#hash_1 = str(hash_1)
#data = [hash_1, time, file_name]
#hamming_list.append(data)
#print(file_name, hash_1, file_date)
data ={'hash_1': hash_11,'time': time_1, 'file_name': file_name_1}
raw_data.update(data)
except:
pass
df = pd.DataFrame(raw_data, columns = ['hash_1', 'time','file_name'])
This is the portion of the code that's causing trouble:
import pandas as pd
import re
df
df.columns = ['Campaigns', 'Impressions', 'Attempts', 'Spend']
Campaigns = df['Campaigns']
IDs = []
for c in Campaigns:
num = re.search(r'\d{6}',c).group()
IDs.append(num)
pieces = [df,pd.DataFrame(IDs)]
frame = pd.concat(pieces, axis=1, join='outer',ignore_index=False)
frame['ID'] = frame[0]
del frame[0]
frame
This is the error:
Error: 'NoneType' object has no attribute 'group'
When I try things individually in ipython everything works, for example:
in>> test = 'YP_WON2_SP8_115436'
in>> num = re.search(r'\d{6}',test)
in>> num.group()
out>> '115436'
I've tried splitting up the code as above and it still throws the same error.
Fixed the code:
df
df.columns = ['Campaigns', 'Impressions', 'Attempts', 'Spend']
Campaigns = df['Campaigns']
ID = []
for c in Campaigns:
m = re.search(r'\d{6}',c)
if m:
num = re.search(r'\d{6}',c).group()
ID.append(num)
else:
ID.append('No ID')
pieces = [df,pd.DataFrame(ID)]
frame = pd.concat(pieces, axis=1, join='outer',ignore_index=False)
frame['ID'] = frame[0]
del frame[0]
frame