I am trying to create a function that loops through specific columns in a dataframe and replaces the values with the column names. I have tried the below but it does not change the values in the columns.
def value_replacer(df):
cols = ['Account Name', 'Account Number', 'Maintenance Contract']
x= [i for i in df.columns if i not in cols]
for i in x:
for j in df[i]:
if isinstance(j,str):
j.replace(j,i)
return df
What should be added to the function to change the values?
Similar to #lazy's solution, but using difference to get the unlisted columns and using a mask instead of the list comprehension:
df = pd.DataFrame({'w': ['a', 'b', 'c'], 'x': ['d', 'e', 'f'], 'y': [1, 2, '3'], 'z': [4, 5, 6]})
def value_replacer(df):
cols_to_skip = ['w', 'z']
for col in df.columns.difference(cols_to_skip):
mask = df[col].map(lambda x: isinstance(x, str))
df.loc[mask, col] = col
return df
Output:
Loop through only the columns of interest once, and only evaluate each row within each column to see if it is a string or not, then use the resulting mask to bulk update all strings with the column name.
Note that this will change the dataframe inplace, so make a copy if you want the original, and you don't necessarily need the return statement.
Related
I have a csv as follows:
I need the "Term"s and the "DocID"s for which the "DocFreq" is greater than 5. And I need to store it as a dictionary where the Term is the key and the "DocID"s separated by the comma make individual values for that key in a list.
For example, I need
{"Want to be with":[doc100.txt,doc8311.txt,...doc123.txt], "and has her own": [doc100.txt,doc9286.txt...doc23330.txt]....}
So far, I've got this:
df1 = df[(df['DocFreq'] > 5)][['Term','DocFreq','Ngram','DocID']]
But I can't get the format I need. Doing df.to_dict() gives me a dictionary of dictionaries that include column names and I don't want that.
Please help!!
Thank you!!
I would do something like that:
data = pd.DataFrame({'Term': ['a', 'b', 'c', 'd', 'e'],
'DocFreq': [1, 2, 2, 6, 7],
'Ngram': [4, 4, 4, 4, 4],
'DocId': ['11, 123, 222', '22', '33', '44, 303, doa0', '55, 9393, idid']
})
filt = data[data['DocFreq'] > 5][['Term', 'DocId']]
result = {row['Term']: row['DocId'] for _, row in filt.iterrows()}
You are almost there. Just select DocID column before calling to_dict.
You may use
dict1 = df.loc[(df['DocFreq'] > 5), ['Term','DocID']].set_index('Term')['DocID'].to_dict()
I have a data frame that looks like this:
df = pd.DataFrame({"A":['a','a','a','b','b','c','c','c'],
"B":['he','she',None,'I',None,None,'them','our']})
and I have a list
lst = ['a','b','c']
I would like to filter the dataframe (or get a dictionary) where only the first matching value in column "B" is returned.
my_dict = {'a':'he', 'b':'I','c':'them'}
You can dropna, drop_duplicates, convert to Series and then to_dict:
lst = ['a','b','c']
my_dict = (df.dropna(subset=['B'])
.drop_duplicates(subset=['A'])
.set_index('A')
.loc[lst, 'B'].to_dict()
)
Alternative:
my_dict = df.dropna(subset='B').groupby('A')['B'].first().to_dict()
output: {'a': 'he', 'b': 'I', 'c': 'them'}
I am trying to assign all the three unique groups from the group column in df to different variables (see my code) using Python. How do I incorporate this inside a for loop? Obviously var + i does not work.
import pandas as pd
data = {
'group': ['a', 'a', 'a', 'b', 'b', 'c', 'c'],
'num': list(range(7))
}
df = pd.DataFrame(data)
unique_groups = df['group'].unique()
# How do I incorporate this logic inside a for loop??
var1 = df[df['group'] == unique_groups[0]]
var2 = df[df['group'] == unique_groups[1]]
var3 = df[df['group'] == unique_groups[2]]
# My approach:
for i in range(len(unique_groups)):
var + i = df[df['group'] == unique_groups[i]] # obviously "var + i" does not work
From your comment it seems it is okay for all_vars to be a list so that all_vars[0] is the first group, all_vars[1] the second, etc. In that case, consider using groupby instead:
all_vars = [group for name, group in df.groupby("group")]
You can do this using a dictionary, basically:
all_vars ={}
for i in range(len(unique_groups)):
all_vars[f"var{i}"] = df[df['group'] == unique_groups[i]]
I am fairly new to python and coding. I am looking for a way to optimize a nested for loop.
The nested for loop I have written works perfectly fine, but it takes a lot of time to run.
I have explained the basic idea behind my original code and what I have tried to do, below:
data = [['a', '35-44', 'male', ['b', 'z', 'x']], ['b', '15-24', 'female', ['a', 'z', 'q']], \
['r', '35-44', 'male', ['z', 'a', 'd']], ['q', '15-24', 'female', ['u', 'k', 'b']]]
df = pd.DataFrame(data, columns= ['ID', 'age_group', 'gender', 'matching_ids'])
df is the Dataframe that I am working on.
What I want to do is compare each 'ID' in df with every other 'ID' in the same df and check if it follows certain conditions.
If the age_group is equal.
If the gender is the same.
If the 'ID' is in 'matched_ids'.
If these conditions are met I need to append that row to a separate dataframe (sample_df)
This is the code with the nested for loop that works fine:
df_copy = df.copy()
sample_df = pd.DataFrame()
for i in range(len(df)):
for j in range(len(df)):
if (i!=j) and (df.iloc[i]['ID'] in df_copy.iloc[j]['matching_ids']) and \
(df.iloc[i]['gender'] == df_copy.iloc[j]['gender']) and\
(df.iloc[i]['age_group'] == df_copy.iloc[j]['age_group']):
sample_df = sample_df.append(df_copy.iloc[[j]])
I tried simplifying it by writing a function and using df.apply(func), but it still takes almost the same amount of time.
Below is the code written with using a function:
sample_df_func = pd.DataFrame()
def func_extract(x):
for k in range(len(df)):
if (x['ID'] != df_copy.iloc[k]['ID']) and (x['ID'] in df_copy.iloc[k]['matching_ids']) and \
(x['gender'] == df_copy.iloc[k]['gender']) and\
(x['age_group'] == df_copy.iloc[k]['age_group']):
global sample_df_func
sample_df_func = sample_df_func.append(df_copy.iloc[[k]])
df.apply(func_extract, axis = 1)
sample_df_func
I am looking for ways to simplify this and optimize it further.
Forgive me, if the solution to this is very simple and I am not able to figure it out.
Thanks
PS: I've just started coding 2 months back.
We can form groups over age_group and gender to obtain subsets where first two conditions hold automatically. For the third condition, we can explode the matching_ids and then check if any of the ids isin the ID and keep those rows within groups only with boolean indexing:
out = (df.groupby(["age_group", "gender"])
.apply(lambda s: s[s.matching_ids.explode().isin(s.ID).groupby(level=0).any()])
.reset_index(drop=True))
where lastly we reset the index to get rid of grouping variables as index,
to get
>>> out
ID age_group gender matching_ids
0 b 15-24 female [a, z, q]
1 q 15-24 female [u, k, b]
2 r 35-44 male [z, a, d]
I have a piece of code as below:
a = df[['col1', 'col2_1', 'col2_2', 'col2_3', 'col3]]
a_indices = np.argmax(a.ne(0).values, axis=1)
a_df = pd.DataFrame(a.values[np.arange(len(a)), a_indices])
b = df[['col2_1', 'col2_2', 'col2_3', 'col3', 'col1]]
b_indices = np.argmax(b.ne(0).values, axis=1)
b_df = pd.DataFrame(b.values[np.arange(len(b)), b_indices])
....
This code is repetitive, and I am hoping to loop them through. The idea is to have all the combination of different orders of cal_1, col_2(col2_1, col2_2, col2_3), and col_3. The return should be a combined dataframe of a_df and b_df.
Note: col2_1, col2_2, and col2_3 can have different orders, but they always stay next to each other. Anyways to make this piece of code simpler?
What you can do so far is to define the maximum number of iterations to loop on. So far you have 5 columns to loop on.
list_columns = ['col1', 'col2_1', 'col2_2', 'col2_3', 'col3']
print(len(list_columns)) # returns 5
Then, you can define your column names based on what you want to put in your dataframe. Suppose you have 5 iterations to make. Your column names would be ['A', 'B', 'C', 'D', 'E']. This is the column argument of your dataframe. An easier way to concatenate several columns at once is to create a dictionary first, with each column name being the key and each of them having a list the same size as a value.
list_columns = ['col1', 'col2_1', 'col2_2', 'col2_3', 'col3']
new_columns = ['A', 'B', 'C', 'D', 'E']
# Use a dictionary comprehension in my case
data_dict = {column: [] for column in new_columns}
n = 50 # Assume the number of loops is arbitrary there
for i in range(n):
for col in new_columns:
# do something
data_dict[col].append(something)
In your case it looks like you can directly operate on the lists by providing a NumPy array instead. Therefore:
list_cols = ['col1', 'col2_1', 'col2_2', 'col2_3', 'col3']
new_cols = ['A', 'B', 'C', 'D', 'E']
data_df = {}
for i, (col, new_col) in enumerate(zip(list_cols, new_cols)):
print(col, list_cols[0:i] + list_cols[i+1:])
temp_df = df[[col] + list_cols[0:i] + list_cols[i+1:]]
temp_indices = np.argmax(temp_df.ne(0).values, axis=1)
data_df[new_col] = b.values[np.arange(len(temp_df)), temp_indices]
final_df = pd.DataFrame(data_df)
What I basically did was a double unpacking combining enumerate to get the index and zip to get your final result. The columns are there selected and placed before the rest of the list in no particular order.