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Selenium Python3 - Unable to find element by its name

The code of the HTML element is as follows:
<input aria-label="Phone number, username, or email" aria-required="true" autocapitalize="none" autocorrect="off" maxlength="75" name="username" type="text" class="_2hvTZ pexuQ zyHYP" value="">
selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element: [name="username"]
I get the error above when I execute this code:
from selenium.webdriver import Firefox
class Efrit:
#Initializing the bot
def __init__(self, username, password):
self.username = username # it could also be e-mail or phone number
self.password = password
#Credentials to log into Instagram:
def log(self):
driver = Firefox('/usr/local/bin')
driver.get("https://www.instagram.com/")
username_location = driver.find_element_by_name('username')
password_location = driver.find_element_by_name('password')
bot = Efrit('test, 'test')
bot.log()

As said in the comments by JaSON, the login form is not in page source and it takes time to render. You have to use wait
Explicit Wait
from selenium.webdriver import Firefox
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException
class Efrit:
#Initializing the bot
def __init__(self, username, password):
self.username = username # it could also be e-mail or phone number
self.password = password
#Credentials to log into Instagram:
def log(self):
driver = Firefox('/usr/local/bin')
driver.get("https://www.instagram.com/")
delay = 6 # seconds
try:
username_location = WebDriverWait(driver, delay).until(EC.presence_of_element_located((By.NAME, 'username')))
password_location = driver.find_element_by_name('password')
print(username_location, password_location)
except TimeoutException:
print("Loading took too much time!")
driver.quit()
bot = Efrit('test', 'test')
bot.log()

You can use explicit wait:
from selenium.webdriver.support.wait import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
driver.get("https://www.instagram.com/")
wait = WebDriverWait(driver, 20)
wait.until(EC.visibility_of_element_located((SelectBy.CSS, "/input[name=username]")))
username_location = driver.find_element_by_css_selector('input[name=username]')
password_location = driver.find_element_by_css_selector('input[name=password]')
To wait for login button use element_to_be_clickable
wait.until(EC.element_to_be_clickable(
(SelectBy.CSS_SELECTOR, ".sqdOP.L3NKy.y3zKF")))
login = driver.find_element_by_css_selector(".sqdOP.L3NKy.y3zKF")
login.click()
You can also set the global implicit wait.
https://selenium-python.readthedocs.io/waits.html (refer to P.5.2 for instructions).

Message: Unable to locate elemen? [duplicate]

I want to log in to instagram using selenium, but I can't seem to enter values into the fields.
Here's my script:
#go to this address
browser.get('https://www.instagram.com')
#sleep for 1 seconds
sleep(1)
#find the 'login' button on homepage
login_elem = browser.find_element_by_xpath(
'//*[#id="react-root"]/section/main/article/div[2]/div[2]/p/a')
#navigate to login page
login_elem.click()
Having trouble from here onwards:
#locate the username field within the form
unform = browser.find_element_by_xpath(
'//*[#id="f3b8e6724a27994"]')
#clear the field
textunform.clear()
#enter 'test' into field
unform.send_keys('test')

There is a trick in this, instead of searching for the Button (Log In) there is a better way to log in without it. how? let's see:
Import the packages you need:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from time import sleep
#Select the driver, In our case we will use Chrome.
chromedriver_path = 'chromedriver.exe' # Change this to your own chromedriver path!
webdriver = webdriver.Chrome(executable_path=chromedriver_path)
sleep(2)
webdriver.get('https://www.instagram.com/accounts/login/?source=auth_switcher')
sleep(3)
username = webdriver.find_element_by_name('username')
username.send_keys('yourUsername')
password = webdriver.find_element_by_name('password')
password.send_keys('yourPassword')
#instead of searching for the Button (Log In) you can simply press enter when you already selected the password or the username input element.
submit = webdriver.find_element_by_tag_name('form')
submit.submit()
You can copy the code and run it directly (even without a real username or password)
To get the webdriver (chromedriver.exe) from ChromeDriver

The instagram is applying some method to leave the dynamic id, xpath and css, every time a reload happens on the page the attributes change their values, being more difficult to click or to set values:

I solved it:
#Locate the username field
unform = browser.find_element_by_name("username")
#Locate the password field
pwform = browser.find_element_by_name('password')
ActionChains(browser)\
.move_to_element(unform).click()\
.send_keys('test')\
.move_to_element(pwform).click()\
.send_keys('test')\
.perform()
#Locate login button
login_button = browser.find_element_by_xpath(
'//*[#id="react-root"]/section/main/article/div[2]/div[1]/div/form/span/button')
#Click login button
login_button.click()

The username field on Instagram is a ReactJS so you have to induce WebDriverWait and then invoke send_keys() method as follows :
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
options = Options()
options.add_argument("start-maximized")
options.add_argument("disable-infobars")
options.add_argument("--disable-extensions")
browser = webdriver.Chrome(chrome_options=options, executable_path=r'C:\path\to\chromedriver.exe')
browser.get('https://www.instagram.com')
login_elem = browser.find_element_by_xpath('//*[#id="react-root"]/section/main/article/div[2]/div[2]/p/a')
login_elem.click()
WebDriverWait(browser, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input[name='username']"))).send_keys("anon")
Browser Screenshot :

In this case IMHO it's better to use this: browser.find_element_by_name("Bermil18") / browser.find_element_by_name("1q56y3w5t9k0p3es8i1q")

Here's my solution for Sign In on Instagram
def login(self, username, password):
""" Methods that log in to Instagram by taking user's credentials as parameters"""
self.driver.get("https://www.instagram.com/accounts/login/")
try:
self.driver.find_element_by_xpath("//input[#name=\"username\"]").send_keys(username) # filling username
self.driver.find_element_by_xpath("//input[#name=\"password\"]").send_keys(password) # filling password
self.driver.find_element_by_xpath("//button[#type=\"submit\"]").click() # submit form
except NoSuchElementException:
print("Failed to log in: Unable to locate Username/Password/LogIn element(s)")
# If login is unsuccessful, Instagram will show a message "Sorry, your password was incorrect. Please double-check your password."
success = self.driver.find_elements_by_xpath("//p[#id = \"slfErrorAlert\"]")
if len(success) == 0:
print("Login successful!")
else:
print("Sorry, sign in unsuccessful. Please double-check your credentials.")
See my Github repo for more: https://github.com/mlej8/InstagramBot

def login(username,password):
driver.get(base_url)
time.sleep(3)
detail = driver.find_elements_by_class_name('_2hvTZ')
detail[0].clear()
detail[1].clear()
detail[0].send_keys(username)
detail[1].send_keys(password)
driver.find_element_by_class_name('L3NKy').click()
time.sleep(3)
for i in driver.find_elements_by_tag_name('button'):
if i.text=='Not Now':
i.click()
break
time.sleep(3)
driver.find_element_by_class_name('HoLwm').click()
base url is intagram url .
I have a made an instabot and you can find the code for logging in ,follow, unfollow ,like ,check posts in recent day ,etc in the following github link.
https://github.com/Devanshchowdhury2212/Instagram-Web-scraping-

This worked for me:
def login(self, username):
self.driver = webdriver.Chrome()
self.driver.get('https://www.instagram.com/')
sleep(1)
username_input = self.driver.find_element_by_xpath(
"//input[#name='username']")
username_input.send_keys(username)
password_input = self.driver.find_element_by_xpath(
"//input[#name='password']")
password_input.send_keys(pw)
submit_btn = self.driver.find_element_by_xpath(
"//button[#type='submit']")
submit_btn.click()
sleep(2)
save_your_login_info_not_now = self.driver.find_element_by_xpath("/html/body/div[1]/section/main/div/div/div/div/button")
save_your_login_info_not_now.click()
You will notice that i am sending the variable pw instead of my actual password. This is for security reasons. Make a new file called secrets.py and inside it, declare your password in the following format:
pw = '*********'

Try to select the field with
unform = browser.find_element_by_xpath("//input[#name='username']")
unform.send_keys(<username>)
and for password
browser.find_element_by_xpath("//input[#name='password']")

Find elements by input type

I'm trying Python and Selenium. My goal is to log myself into Discord (https://discordapp.com/login. But here is the problem. I can't manage to get the email and password box selected. But the worst part is trying to select a textbox on a server... I tried everything, even locating by XPath, but I can't seem to do it right. Also, doing it on ATOM is probably not the best idea since I don't get any error messages :P. Here is a snippet to select the email textbox.
from selenium
import webdriver
from selenium.webdriver.common.keys
import Keys
browser = webdriver.Firefox()
browser.get('https://discordapp.com/login')
assert 'discordapp' in browser.title
elem = browser.find_element_by_name('textarea')# this is the part where i need help
elem.send_keys('test' + Keys.ENTER)

For email this css selector should work :
input[type='email']
For password :
input[type='password']
I've tested this code :
browser.get("https://discordapp.com/login")
elem = browser.find_element_by_css_selector("input[type='email']")# this is the part where i need help
elem.send_keys("itsolidude#imail.com")
elem1 = browser.find_element_by_css_selector("input[type='password']")# this is the part where i need help
elem1.send_keys("password")
login_button = browser.find_element_by_xpath("//div[text()='Login']/parent::button")
login_button.click()
This worked fine on my machine.

you need to check the div container and add them into the xpath.
Try the following code and please debug the indents, in case that stackoverflow is not transferring them properly (well, I don't know how to do it nice and correctly.)
from selenium import webdriver
from selenium.webdriver.common.by import By
import time
class loginPage():
def test(self):
baseUrl = 'https://discordapp.com/login'
driver = webdriver.Firefox(executable_path="G:\\webdriver/geckodriver.exe")
driver.maximize_window()
driver.implicitly_wait(5)
driver.get(baseUrl)
mail = driver.find_element(By.XPATH, "//div[3]/div[1]/div/input[contains(#type,'email')]")
time.sleep(5)
mail.send_keys("test#gmail.com")
time.sleep(3)
print("Enter mail adress")
password = driver.find_element(By.XPATH, "//div[3]/div[2]/div/input[contains(#type,'password')]")
time.sleep(5)
password.send_keys("123456789")
time.sleep(3)
print("Enter password")
time.sleep(10)
driver.quit()
ff = loginPage()
ff.test()

Login To Discord Website using Python and Selenium:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import Select
driver = webdriver.Chrome()
driver.get("https://discord.com/login")
time.sleep(6)
username_input = driver.find_element_by_name('email')
username_input.send_keys("enter-your-username-here")
password_input = driver.find_element_by_name('password')
password_input.send_keys("Enter-your-password-here")
login_button = driver.find_element_by_xpath('//*[#id="app-mount"]/div[2]/div/div[2]/div/div/form/div/div/div[1]/div[3]/button[2]')
login_button.click()

Log into gmail using Selenium in Python

I am trying to log into gmail using Selenium. In the new gmail log in, first you type your email id and then a next page comes where you type your password. URL of email page and password page, both are different. So, when I am passing the password URL in driver.get it is reloading the page and it redirects to email page if you refresh the URL without entering password. Because of this, it is missing the password field selector. current_url is still the previous url, i.e, url of email page. This is my code. I am using chrome driver and python 2.X
import os
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
chromedriver = "/Documents/chromedriver" # Path to chrome-driver
os.environ["webdriver.chrome.driver"] = chromedriver
driver = webdriver.Chrome(chromedriver)
# Email insert
driver.get("https://accounts.google.com/signin/v2/identifier?service=mail&passive=true&rm=false&continue=https%3A%2F%2Fmail.google.com%2Fmail%2F&ss=1&scc=1&ltmpl=default&ltmplcache=2&emr=1&osid=1&flowName=GlifWebSignIn&flowEntry=ServiceLogin") #URL of email page
username = driver.find_element_by_id("identifierId")
username.send_keys("myemail")
driver.find_element_by_id("identifierNext").click()
# Password Insert
driver.get("https://accounts.google.com/signin/v2/identifier?service=mail&passive=true&rm=false&continue=https%3A%2F%2Fmail.google.com%2Fmail%2F&ss=1&scc=1&ltmpl=default&ltmplcache=2&emr=1&osid=1&flowName=GlifWebSignIn&flowEntry=ServiceLogin") # URL of password page
password = driver.find_element_by_id("password")
password.send_keys("mypassword")
driver.find_element_by_id("passwordNext").click()
#driver.quit()

Here is the Answer to your Question:
When we work with Selenium 3.4.3, geckodriver v0.17.0 and Mozilla Firefox 53.0 using Python 3.6.1, we can use either of the locators xpath or css_selector to log into our respective Gmail accounts through Gmail's signin module v2.
Using XPATH :
Here is the sample code to log into Gmail using xpath:
from selenium import webdriver
from selenium.webdriver.firefox.firefox_binary import FirefoxBinary
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
binary = FirefoxBinary('C:\\Program Files\\Mozilla Firefox\\firefox.exe')
caps = DesiredCapabilities().FIREFOX
caps["marionette"] = True
driver = webdriver.Firefox(capabilities=caps, firefox_binary=binary, executable_path="C:\\Utility\\BrowserDrivers\\geckodriver.exe")
driver.get("https://accounts.google.com/signin")
email_phone = driver.find_element_by_xpath("//input[#id='identifierId']")
email_phone.send_keys("your_emailid_phone")
driver.find_element_by_id("identifierNext").click()
password = WebDriverWait(driver, 5).until(
EC.element_to_be_clickable((By.XPATH, "//input[#name='password']"))
)
password.send_keys("your_password")
driver.find_element_by_id("passwordNext").click()
Using CSS_SELECTOR:
Here is the sample code to log into Gmail using css_selector:
from selenium import webdriver
from selenium.webdriver.firefox.firefox_binary import FirefoxBinary
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
binary = FirefoxBinary('C:\\Program Files\\Mozilla Firefox\\firefox.exe')
caps = DesiredCapabilities().FIREFOX
caps["marionette"] = True
driver = webdriver.Firefox(capabilities=caps, firefox_binary=binary, executable_path="C:\\Utility\\BrowserDrivers\\geckodriver.exe")
driver.get("https://accounts.google.com/signin")
email_phone = driver.find_element_by_css_selector("#identifierId")
email_phone.send_keys("your_emailid_phone")
driver.find_element_by_css_selector(".ZFr60d.CeoRYc").click()
password = WebDriverWait(driver, 5).until(
EC.element_to_be_clickable((By.CSS_SELECTOR, "input[class='whsOnd zHQkBf'][type='password']"))
)
password.send_keys("your_password")
driver.find_element_by_css_selector(".ZFr60d.CeoRYc").click()

<input class="whsOnd zHQkBf"
jsname="YPqjbf"
autocomplete="current-password"
spellcheck="false"
tabindex="0"
aria-label="Enter your password"
name="password"
autocapitalize="off"
autocorrect="off"
dir="ltr"
data-initial-dir="ltr"
data-initial-value=""
badinput="false"
type="password">

Fill username and password using selenium in python

How can I auto fill the username and password over the link below:
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
chromedriver = 'C:\\chromedriver.exe'
browser = webdriver.Chrome(chromedriver)
browser.get('http://www.example.com')
After that I really do not know:
username = Select(browser.find_element_by_name('Username'))
password = Select(browser.find_element_by_name('Password'))
username.select_by_visible_text("text")
password.select_by_visible_text("text")

Docs: https://selenium-python.readthedocs.io/navigating.html
For versions 4.3.0 (released in June 2022) and later, calls to find_element_by_* and find_elements_by_* were removed from Selenium. You need to use the new API:
from selenium.webdriver.common.by import By
driver = webdriver.Firefox(...) # Or Chrome(), or Ie(), or Opera()
# To catch <input type="text" id="passwd" />
password = driver.find_element(By.ID, "passwd")
# To catch <input type="text" name="passwd" />
password = driver.find_element(By.NAME, "passwd")
password.send_keys("Pa55worD")
driver.find_element(By.NAME, "submit").click()
The original response, for API versions 4.2.0 or previous:
driver = webdriver.Firefox(...) # Or Chrome(), or Ie(), or Opera()
username = driver.find_element_by_id("username")
password = driver.find_element_by_id("password")
username.send_keys("YourUsername")
password.send_keys("Pa55worD")
driver.find_element_by_name("submit").click()
A note to your code: Select() is used to act on a Select Element (https://developer.mozilla.org/en-US/docs/Web/HTML/Element/select).

Use WebElement.send_keys method to simulate key typing.
name in the code (Username, Password) does not match actual name of the elements (username, password).
username = browser.find_element_by_name('username')
username.send_keys('user1')
password = browser.find_element_by_name('password')
password.send_keys('secret')
form = browser.find_element_by_id('loginForm')
form.submit()
# OR browser.find_element_by_id('submit').click()

user = driver.find_element_by_name("username")
password = driver.find_element_by_name("password")
user.clear()
user.send_keys("your_user_name")
password.clear()
password.send_keys("your_password")
driver.find_element_by_name("submit").click()
Note:
we useuser.clear() in order to clear the input field.
for locating submit button you can use any other method based on the page source code. for info see locating elements

In some cases when the element is not interactable, sendKeys() doesn't work and you're likely to encounter an ElementNotInteractableException.
In such cases, you can opt to execute javascript that sets the values and then can post back.
Example:
url = 'https://www.your_url.com/'
driver = Chrome(executable_path="./chromedriver")
driver.get(url)
username = 'your_username'
password = 'your_password'
#Setting the value of email input field
driver.execute_script(f'var element = document.getElementById("email"); element.value = "{username}";')
#Setting the value of password input field
driver.execute_script(f'var element = document.getElementById("password"); element.value = "{password}";')
#Submitting the form or click the login button also
driver.execute_script(f'document.getElementsByClassName("login_form")[0].submit();')
print(driver.page_source)
Reference:
https://www.quora.com/How-do-I-resolve-the-ElementNotInteractableException-in-Selenium-WebDriver

Here is the complete answer.
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.chrome.service import Service
from selenium.webdriver.common.by import By
chrome_driver_path = 'C:\\chromedriver.exe'
browser = webdriver.Chrome(service=Service(chrome_driver_path))
browser.get('http://www.example.com')
username = browser.find_element(By.NAME, 'Username')
password = browser.find_element(By.NAME, 'Password')
username.send_keys("yourUsername") #type your own username here
password.send_keys("yourPassword") #type your own password here
browser.find_element(By.NAME, 'submit').click()
Since find_element_by_name() is deprecated, you can use find_element(By.NAME, 'name').
Also you have to import from selenium.webdriver.common.by import By

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import Select
from selenium.webdriver.support.ui import WebDriverWait
# If you want to open Chrome
driver = webdriver.Chrome()
# If you want to open Firefox
driver = webdriver.Firefox()
username = driver.find_element_by_id("username")
password = driver.find_element_by_id("password")
username.send_keys("YourUsername")
password.send_keys("YourPassword")
driver.find_element_by_id("submit_btn").click()

I am new to selenium and I tried all solutions above but they don't work.
Finally, I tried this manually by
driver = webdriver.Firefox()
import time
driver.get(url)
time.sleep(20)
print (driver.page_source.encode("utf-8"))
Then I could get contents from web.