I get an XML file using the request module, then I want to use the xml.etree.ElementTree module to get the output of the element
core-usg-01
but I'm already confused how to do it, im stuck. I tried writing this simple code to get the sysname element, but I get an empty output.
Python code:
import xml.etree.ElementTree as ET
tree = ET.parse('usg.xml')
root = tree.getroot()
print(root.findall('sysname'))
XML file:
<rpc-reply xmlns="urn:ietf:params:xml:ns:netconf:base:1.0" message-id="1">
<data>
<system-state xmlns="urn:ietf:params:xml:ns:yang:ietf-system">
<sysname xmlns="urn:huawei:params:xml:ns:yang:huawei-system">
core-usg-01
</sysname>
</system-state>
</data>
</rpc-reply>
You need to iter() over the root to reach to the child.
for child in root.iter():
print (child.tag, child.attrib)
Which will give you the present children tags and their attributes.
{urn:ietf:params:xml:ns:netconf:base:1.0}rpc-reply {'message-id': '1'}
{urn:ietf:params:xml:ns:netconf:base:1.0}data {}
{urn:ietf:params:xml:ns:yang:ietf-system}system-state {}
{urn:huawei:params:xml:ns:yang:huawei-system}sysname {}
Now you need to loop to your desired tag using following code:
for child in root.findall('.//{urn:ietf:params:xml:ns:yang:ietf-system}system-state'):
temp = child.find('.//{urn:huawei:params:xml:ns:yang:huawei-system}sysname')
print(temp.text)
The output will look like this:
core-usg-01
Try the below one liner
import xml.etree.ElementTree as ET
xml = '''<rpc-reply xmlns="urn:ietf:params:xml:ns:netconf:base:1.0" message-id="1">
<data>
<system-state xmlns="urn:ietf:params:xml:ns:yang:ietf-system">
<sysname xmlns="urn:huawei:params:xml:ns:yang:huawei-system">
core-usg-01
</sysname>
</system-state>
</data>
</rpc-reply>'''
root = ET.fromstring(xml)
print(root.find('.//{urn:huawei:params:xml:ns:yang:huawei-system}sysname').text)
output
core-usg-01
Related
with my python script i want to iterate my xml file searching a specific element tag.
I have some problem related to the namespace of the root tag.
Below my XML structure:
<?xml version="1.0" ?>
<rootTag xmlns="blablabla">
<tag_1>
<sub_tag_1>..something..</sub_tag_1>
</tag_1>
<tag_2>
<sub_tag_2>..something..</sub_tag_2>
</tag_2>
...and so on...
</rootTag>
Below my PYTHON script:
import xml.etree.ElementTree as ET
root = ET.fromstring(xml_taken_from_web)
print(root.tag)
The problem is that output of print is:
{blablabla}rootTag
so when i iter over it all the tag_1, tag_2, and so on tags will have the {blablabla} string so i'm not able to make any check on the tag.
I tried using regular expression in this way
root = re.sub('^{.*?}', '', root.tag)
the problem is that root after that is a string type and so i cannot over it such an Element type
How can i print only rootTag ?
With that just use:
import xml.etree.ElementTree as ET
from lxml import etree
root = ET.fromstring(xml_taken_from_web)
print(etree.QName(root.tag).localname)
<?xml version="1.0" encoding="UTF-8"?>
<Document xmlns="urn:iso:std:iso:20022:tech:xsd:camt.056.001.01" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<FIToFIPmtCxlReq>
<Assgnmt>
<Id>TEST-ISO-81</Id>
<Assgnr>
<Agt>
<FinInstnId>
<BIC>CCCCGB2L</BIC>
</FinInstnId>
</Agt>
</Assgnr>
<Assgne>
<Agt>
<FinInstnId>
<BIC>MMMMGB2L</BIC>
</FinInstnId>
</Agt>
</Assgne>
<CreDtTm>2009-03-24T11:22:59</CreDtTm>
</Assgnmt>
<TxInf>
<CxlId>103012345</CxlId>
<Case>
<Id>ISO_TEST_CASE</Id>
<Cretr>
<Agt>
<FinInstnId>
<BIC>MMMMGB2L</BIC>
</FinInstnId>
</Agt>
</Cretr>
</Case>
</TxInf>
</Undrlyg>
</FIToFIPmtCxlReq>
</Document>
Here I want to get the content of "TxInf" like all its child and child of child and the data.
What I have tried is :
import xml.etree.ElementTree as ET
from xml.etree import ElementTree
tree = ET.parse('R3-CAMT.056.001.07-ISO-V.XML')
root = tree.getroot()
for element in root.iter():
if element.tag == "{urn:iso:std:iso:20022:tech:xsd:camt.056.001.01}TxInf":
tree._setroot(element.tag)
print(root.tag)
print(root.attrib)
Please suggest if I can change the root with _setroot or any other possible method
Try something along these lines on your code to see if it works:
for r in root.findall(".//*"):
if 'TxInf' in r.tag:
print(ET.tostring(r))
By the way, it may be easier to do it with lxml, if you can use it.
I have an XML file which has many elements. I would like to create a list/array of all the values which have a specific element name, in my case "pair:ApplicationNumber".
I've gone over a lot of the other questions however I am not able to find an answer. I know that I can do this by loading the text file and going over it using pandas however, I'm sure there's a much better way.
I was unsuccessful trying ElementTree as well as XML.Dom using minidom
My code currently looks as follows:
import os
from xml.dom import minidom
WindowsUser = os.getenv('username')
XMLPath = os.path.join('C:\\Users', WindowsUser, 'Downloads', 'ApplicationsByCustomerNumber.xml')
xmldoc = minidom.parse(XMLPath)
itemlist = xmldoc.getElementsByTagName('pair:ApplicationNumber')
for s in itemlist:
print(s.attributes['pair:ApplicationNumber'].value)
an example XML file looks as follows:
<?xml version="1.0" encoding="UTF-8"?>
<pair:PatentApplicationList xsi:schemaLocation="urn:us:gov:uspto:pair PatentApplicationList.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:pair="urn:us:gov:uspto:pair">
<pair:FileHeader>
<pair:FileCreationTimeStamp>2017-07-10T10:52:12.12</pair:FileCreationTimeStamp>
</pair:FileHeader>
<pair:ApplicationStatusData>
<pair:ApplicationNumber>62383607</pair:ApplicationNumber>
<pair:ApplicationStatusCode>20</pair:ApplicationStatusCode>
<pair:ApplicationStatusText>Application Dispatched from Preexam, Not Yet Docketed</pair:ApplicationStatusText>
<pair:ApplicationStatusDate>2016-09-16</pair:ApplicationStatusDate>
<pair:AttorneyDocketNumber>1354-T-02-US</pair:AttorneyDocketNumber>
<pair:FilingDate>2016-09-06</pair:FilingDate>
<pair:LastModifiedTimestamp>2017-05-30T21:40:37.37</pair:LastModifiedTimestamp>
<pair:CustomerNumber>122761</pair:CustomerNumber><pair:LastFileHistoryTransaction>
<pair:LastTransactionDate>2017-05-30</pair:LastTransactionDate>
<pair:LastTransactionDescription>Email Notification</pair:LastTransactionDescription> </pair:LastFileHistoryTransaction>
<pair:ImageAvailabilityIndicator>true</pair:ImageAvailabilityIndicator>
</pair:ApplicationStatusData>
<pair:ApplicationStatusData>
<pair:ApplicationNumber>62292372</pair:ApplicationNumber>
<pair:ApplicationStatusCode>160</pair:ApplicationStatusCode>
<pair:ApplicationStatusText>Abandoned -- Incomplete Application (Pre-examination)</pair:ApplicationStatusText>
<pair:ApplicationStatusDate>2016-11-01</pair:ApplicationStatusDate>
<pair:AttorneyDocketNumber>681-S-23-US</pair:AttorneyDocketNumber>
<pair:FilingDate>2016-02-08</pair:FilingDate>
<pair:LastModifiedTimestamp>2017-06-20T21:59:26.26</pair:LastModifiedTimestamp>
<pair:CustomerNumber>122761</pair:CustomerNumber><pair:LastFileHistoryTransaction>
<pair:LastTransactionDate>2017-06-20</pair:LastTransactionDate>
<pair:LastTransactionDescription>Petition Entered</pair:LastTransactionDescription> </pair:LastFileHistoryTransaction>
<pair:ImageAvailabilityIndicator>true</pair:ImageAvailabilityIndicator>
</pair:ApplicationStatusData>
<pair:ApplicationStatusData>
<pair:ApplicationNumber>62289245</pair:ApplicationNumber>
<pair:ApplicationStatusCode>160</pair:ApplicationStatusCode>
<pair:ApplicationStatusText>Abandoned -- Incomplete Application (Pre-examination)</pair:ApplicationStatusText>
<pair:ApplicationStatusDate>2016-10-26</pair:ApplicationStatusDate>
<pair:AttorneyDocketNumber>1526-P-01-US</pair:AttorneyDocketNumber>
<pair:FilingDate>2016-01-31</pair:FilingDate>
<pair:LastModifiedTimestamp>2017-06-15T21:24:13.13</pair:LastModifiedTimestamp>
<pair:CustomerNumber>122761</pair:CustomerNumber><pair:LastFileHistoryTransaction>
<pair:LastTransactionDate>2017-06-15</pair:LastTransactionDate>
<pair:LastTransactionDescription>Petition Entered</pair:LastTransactionDescription> </pair:LastFileHistoryTransaction>
<pair:ImageAvailabilityIndicator>true</pair:ImageAvailabilityIndicator>
</pair:ApplicationStatusData>
</pair:PatentApplicationList>
The XML in your example is expanding the "pair:" part of the tags according to the schema you've used, so it doesn't match 'pair:ApplicationNumber', even though it looks like it should.
I've used element tree to extract the application numbers as follows (I've just used a local XML file in my examples, rather than the full path in your code)
Example 1:
from xml.etree import ElementTree
tree = ElementTree.parse('ApplicationsByCustomerNumber.xml')
root = tree.getroot()
for item in root:
if 'ApplicationStatusData' in item.tag:
for child in item:
if 'ApplicationNumber' in child.tag:
print child.text
Example 2:
from xml.etree import ElementTree
tree = ElementTree.parse('ApplicationsByCustomerNumber.xml')
root = tree.getroot()
for item in root.iter('{urn:us:gov:uspto:pair}ApplicationStatusData'):
for child in item.iter('{urn:us:gov:uspto:pair}ApplicationNumber'):
print child.text
Hope this may be useful.
I am parsing an XML output from VCloud, however I am not able to reach to the values
<?xml version="1.0" encoding="UTF-8"?>
<SupportedVersions xmlns="http://www.vmware.com/vcloud/versions" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.vmware.com/vcloud/versions http://10.10.6.12/api/versions/schema/versions.xsd">
<VersionInfo>
<Version>1.5</Version>
<LoginUrl>https://api.vcd.portal.skyscapecloud.com/api/sessions</LoginUrl>
<MediaTypeMapping>
<MediaType>application/vnd.vmware.vcloud.instantiateVAppTemplateParams+xml</MediaType>
<ComplexTypeName>InstantiateVAppTemplateParamsType</ComplexTypeName>
<SchemaLocation>http://api.vcd.portal.skyscapecloud.com/api/v1.5/schema/master.xsd</SchemaLocation>
</MediaTypeMapping>
<MediaTypeMapping>
<MediaType>application/vnd.vmware.admin.vmwProviderVdcReferences+xml</MediaType>
<ComplexTypeName>VMWProviderVdcReferencesType</ComplexTypeName>
<SchemaLocation>http://api.vcd.portal.skyscapecloud.com/api/v1.5/schema/vmwextensions.xsd</SchemaLocation>
</MediaTypeMapping>
<MediaTypeMapping>
<MediaType>application/vnd.vmware.vcloud.customizationSection+xml</MediaType>
<ComplexTypeName>CustomizationSectionType</ComplexTypeName>
<SchemaLocation>http://api.vcd.portal.skyscapecloud.com/api/v1.5/schema/master.xsd</SchemaLocation>
</MediaTypeMapping>
this is what I have been using
import xml.etree.ElementTree as ET
data = ET.fromstring(content)
versioninfo = data.findall("VersionInfo/Version")
print len(versioninfo)
print versioninfo.text
however this gives a blank output...any suggestions?
Try this:
import xml.etree.ElementTree as ET
data = ET.fromstring(content)
versioninfo = data.find(
"ns:VersionInfo/ns:Version",
namespaces={'ns':'http://www.vmware.com/vcloud/versions'})
print versioninfo.text
Use .find(), not .findall() to return a single element
Your XML uses namespaces. The full path to your desired object is: '{http://www.vmware.com/vcloud/versions}VersionInfo/{http://www.vmware.com/vcloud/versions}Version' By passing in the namespaces parameter, you are able to use the shortcut syntax: ns:VersionInfo/ns:Version.
I have a sample xml file like this:
<root>
She
<opt>went</opt>
<opt>didn't go</opt>
to school.
</root>
I want to create a subelement named of , and put all the contents of into it. That is,
<root>
<sentence>
She
<opt>went</opt>
<opt>didn't go</opt>
to school.
</sentence>
</root>
I know hot to make a subelement with ElementTree or lxml, but I have no idea of how to select from "She" to "shools." all at once.
import lxml.etree as ET
ET.SubElement(root, 'sentence')
I'm lost...
You could go about it in reverse: (Instead of adding a subelement, add a new parent.) By that I mean, change the root tag to sentence, create a new root element, and insert the old root (now sentence) into the new root:
import lxml.etree as ET
content = '''\
<root>
She
<opt>went</opt>
<opt>didn't go</opt>
to school.
</root>'''
root = ET.fromstring(content)
root.tag = 'sentence'
newroot = ET.Element('root')
newroot.insert(0,root)
print(ET.tostring(newroot))
# <root><sentence>
# She
# <opt>went</opt>
# <opt>didn't go</opt>
# to school.
# </sentence></root>