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Not instantly getting out a loop with break [closed]

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When I run this easy program and want to exit it, I need to type exit 2 times (at line 7).
def registration():
def username_registration():
entering_username = True
while entering_username:
print("Type exit to leave the registration.")
usernam_from_registration = input("Enter username: ")
if usernam_from_registration == "exit":
break
lenght_usernam_from_registration = len(usernam_from_registration)
if lenght_usernam_from_registration > 15:
print("too long")
else:
return usernam_from_registration
username_registration()
print(username_registration())
registration()
Why is this and how can I make it so I only need to write it one time?

This is because you are calling the username_registration() function twice.
username_registration()
print(username_registration())
The first time you call it, nothing happens because you are not doing anything with the result.

if line similar to var then execute function [closed]

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for event in longpoll.listen():
if event.type == VkEventType.MESSAGE_NEW and event.to_me:
if event.from_user:
request = event.text
line = request.lower()
user = event.user_id
if str(line) == "!add <args>" :
print("Data has updated.")
i need if var line has arguments, like !add setting, function executes

The question "how to make if the line similar to /change admin the function was performed?" is not clear. Also the code expect to have indent.
If understood correctly you need to check if the line has "/change admin" or you want to check if there is "/change" and "admin" in line, although both being same.
If above is the case, considering line has "/change <admin/others>"
if "/change admin" in line: # if "/change" in line and line.split(' ')[1] == "admin":
print("Admin Changed")
else:
print("Usage")
If you are running a command line, suggest you to use, sys module. Using sys.argv for catching command line args.
Also look into arg_parser if looking to make some tool or utility to run command line, that gives fancy usage.

How do make text in print() and input() appear one by one? [closed]

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Almost like an RPG game, I want to make text appear as if someone is typing them. I have an idea of how to do it with the print() function in python, something involving the sleep() and maybe with sys.stdout.flush?
How would I do it text coming before an input function?
For example, I want What is your name? to be typed out, and then the user would input his name.

You can use this:
text = 'What is your name? '
for x in text:
sys.stdout.write(x)
sys.stdout.flush()
time.sleep(0.00001)
name = input()
you can randomize the sleep time per loop as well to mimic typing even better like this:
import time,sys,random
text = 'What is your name? '
for x in text:
sys.stdout.write(x)
sys.stdout.flush()
time.sleep(random.uniform(.000001, .000019))
name = input()
as Tomerikoo pointed out, some systems have faster/slow delays so you may need to use uniform(.01, .5) on another system. I use OS/X.
On windows this probably works better. Thanks Tomerikoo:
import time,sys,random
text = 'What is your name? '
for x in text:
print(x, end="", flush=True)
time.sleep(random.uniform(.000001, .000019))
# or smaller sleep time, really depends on your system:
# time.sleep(random.uniform(.01, .5))
name = input()

You can use the following code:
import time,sys
def getinput(question):
text = input(question)
for x in text:
sys.stdout.write(x)
sys.stdout.flush()
time.sleep(0.00001) #Sets the speed of typing, depending on your system
Now everytime you call getinput("Sample Question"), you would get the user's input based on the question you passed to the function.

Call function at any time on input, python 3.x [closed]

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If you made a function like this:
def show():
print(something)
How would you make it so that, on any input, if the user typed a specific thing, this would be called? I want multiple functions like this to be able to be called whenever the user wants. Would I just have to have it as an option every time I ask for an input?
EDIT: sorry, this wasn't very clear. Say I have a variable in a game, like money. When I ask for an input as the game goes along, the inputs being about unrelated things, I want the user to be able to type eg. gold and the show() function will activate. Then the input will go on as usual. Would I be able to do this without just have it as an option for each input, eg.
variable = input("type something")
if variable == "gold":
do stuff
elif variable == other things
do other things

Do you mean something like this:
def thing1(): # Random command
print('stuff')
def thing2(): # Random command
print('More stuff')
def check(command):
'''Checks if the users command is valid else it does a default command'''
if command == 'thing1':
thing1()
elif command == 'thing2':
thing2()
else:
default_thing()
while True: # Loop going on forever
userinput = input('') # Lets the user input their command
check(userinput)

you could put all your functions in a dictionary: {"<some user input>":func_to_call} and see if it matches any
something like:
def gold():
print("gold")
input_options = {"gold":gold}
variable = input("type something:")
if variable in input_options:
input_options[variable]()

Doing something after for loop finishes in same function? [closed]

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Is this possible? I'm doing an bukkit plugin now (in Python, yes :D), and I'm forced to do this within one function, so I can't separate it and call it later... For example, if I have loop that loops through players on server and adds everyone except one player, I want it to finish, and then teleport i.e. "Player1" to random player. At the moment, it teleports "Player1" to random player every time because of for loop... I'll give you just little of code, since It looks messy in preview due to many things that are not involved in problem and could be confusable to you... Here it is:
listica = []
for p1 in org.bukkit.Bukkit.getWorld(nextvalue).getPlayers():
if p1.getName() not in listica:
try:
listica.remove(event.getPlayer().getName())
randomtarget = choice(listica)
randomtargetreal = org.bukkit.Bukkit.getPlayer(randomtarget)
event.getPlayer().teleport(randomtargetreal)
event.getPlayer().sendMessage("%sYou teleported to: %s%s"% (bukkit.ChatColor.GREEN, bukkit.ChatColor.DARK_GREEN, randomtarget))
except ValueError:
randomtarget = choice(listica)
randomtargetreal = org.bukkit.Bukkit.getPlayer(randomtarget)
if event.getPlayer().getLocation() != randomtargetreal.getLocation():
event.getPlayer().teleport(randomtargetreal)
event.getPlayer().sendMessage("%sYou teleported to: %s%s"%(bukkit.ChatColor.GREEN, bukkit.ChatColor.DARK_GREEN, randomtarget))
What I want is:
run for loop:
when there is no more players to add a.k.a it finishes
do try loop
P.S. I can't do it in separate function.
Thanks in advance! :)

Do you mean:
def func(args):
for item in loop:
do something
try: # note indentation
something else